Already 3 min in and confusing concepts become so clear. The example of a laptop plugged in or not is SO easy to follow -wish my professor could talk sense like this:)
Whether it be physics or chemistry, you're really great at teaching topics when my teachers can't. Thanks for the last minute prep before AP exams man.
I CAN'T STOP SMILING! In 7 minutes you explained and introduced a technique a text book took 30 PAGES and didn't reach to a 100th of what you surmounted to. Deep and Grateful THANKS!!!!
I am here to thank you)) a few months ago, I was almost zero in chemistry, but with the help of your videos I could pass my general chemistry exam from the first attempt. even if I got the minimum passing score, I still did it, I can't believe it. I thought I will take a re-exam... thanks a lot sir🙏 to everyone reading this: do not be lazy, do not leave everything on the last days. good luck everyone)
Your videos have help me so much for the last year. Thank you so much for really taking your time and and providing so many examples. You have helped me on every test I've taken for my past 3 chem classes. I appreciate it very much.
I'm in my third year of a chemistry degree because of this guy. I used to hate chem in highschool until I started understanding it. Nobody put in the time to help me but I put the time into myself and ochem tutor is a real one for that.
At 58:26, If you multiply the reaction by 2, wouldn't the half reaction then be 1.54V? And the new total would be 1.77V? edit: 1:03:12 The answer is no.
At 34.26 minutes of video, ∆G = ∆G^o - RT lnQ I have 2 textbook here of Gen Chemistry saying that ∆G = ∆G^o + RT lnQ ^o is to superscript, to set delta G in standard state I am learning a lot from you but I like to clarify this formula..Thank you. The textbooks are: Fundamentals of Chemistry, 4th Ed. by Frank Brescia etc. page 311 Principles of General Chemistry, 3rd edition by Martin S. Silberberg, page 676
Coronavirus shuts down your university + forced to do online school + didn't know what the hell was going on to begin with when you were in school = finding this channel on UA-cam
you've really help me to understand science in all its branches, we deeply appreciate you sir for the knowledge you share ...ive been watching your lecture videos. i find that i understand you more than my own lecturers continue helping people ..Steve (Zambia) ...
You’ve always been the best💯 Thank you for always making my studies easy🙏 Don’t know what I would have done without your knowledge, You’re truly gifted. I’ve been your student for 3 years now.
2:16 What if We plug in the battery to outlet and to my device at the same time..... it's (the battery) is receiving energy (electrolytic) and also supplying energy (galvanic).....how does this work ?
13:20 I dont know wen it comes to electro chemistry whether or not my syllabus is different from what you are teaching here .I check my textbook and this what you're explaining ain't in there . But overall you're the best 🔥🔥🤟
@@heavenlyway108 Yess ...you see I go to a public school and we Do Caps I know private schools they do Cambridge or something idk what its called but we might have the same syllabus but theirs are more little more harder and different from what we do
Mistake at 32:52, this is not a product-favoured system, Q is the initial concentration ratio. However, the positive standard cell potential is indicating that it is a product-favoured system since the reaction is spontaneous. Am I correct?
Thank you very very much, I watched your video before reading my notes from my prof, now everything is clear and easy. Thanks again, appreciate your hard works!!!
Thanks these videos are really helpful, I hope you have tutorials about Unit operations as well. Me and my batch mates are able to study solution manuals but it would be really helpful if there are tutorials or explanations as well ( especially Unit operations )
Sexiest tutor voice ever. Every time I don't get something on chimestry class im like he got ma back. Relax xD Thanks man sending love and appreciation from Puerto Rico ♡♡♡ keep making vids
at minute 11:27 you said that zinc is being oxidized, thus is the reducing agent and that copper is being reduced, thus is the oxidizing agent.... but isn't it backward? ( zinc is being reduced since is going from 0 to +2(gains), thus is the oxidizing agent..... and copper is being oxidized since is doing from +2 to 0 (losing), thus is the reducing agent).... I'm confused now!... OIL (oxidation is loss of electrons) RIG (reduction is gain of electrons)... can someone clarify, please?
Diana P Desai He is right actually. you are making a mistake with the oxidation numbers. when zinc goes from 0 to 2+ it is becoming more positive and is therefore losing electrons. As a result it is going through oxidation and is the reducing agent! (Like you said, oxidation is losing; OIL)
the opposite goes for copper. it goes from +2 to 0, meaning it is becoming more negative. Therefore it is gaining electrons and is reducing (RIG) and is the oxidizing agent!
31:59 into the video how do I get the answer 25080. 1.1v - 0.97 ÷ 0.0591 can't get the answer as he not say if you multiple by 2 or 10 or just 1.1v - 0.97. Help
Mark Keith, this reaction is not about product or reactant. It's electro chemical reaction pertaining to cell. We call them product/reactant only to simplify. :Peace ~A TOCT Fan
No you see for you to understand this you have to looks at your standards reduction potential table 4B Zn is above Cu if you look on your table . So the metal that is on top of the other one will be oxidized and the metal below would be reduced.My teacher thought us the Big C method that we use to figure out which metal is oxidized and reduced and what would the half reaction be for that metal being oxidized Big C method :
Electrochemistry - Free Formula Sheet: bit.ly/3NLeylq
Chemistry 2 Final Exam Review: ua-cam.com/video/lSmJN1_uVpI/v-deo.html
Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html
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I watch 1 video of this guy and I instantly turn into the guy other people ask for help from on the morning of the exam
Already 3 min in and confusing concepts become so clear.
The example of a laptop plugged in or not is SO easy to follow
-wish my professor could talk sense like this:)
Whether it be physics or chemistry, you're really great at teaching topics when my teachers can't. Thanks for the last minute prep before AP exams man.
I CAN'T STOP SMILING!
In 7 minutes you explained and introduced a technique a text book took 30 PAGES and didn't reach to a 100th of what you surmounted to.
Deep and Grateful THANKS!!!!
I am here to thank you)) a few months ago, I was almost zero in chemistry, but with the help of your videos I could pass my general chemistry exam from the first attempt. even if I got the minimum passing score, I still did it, I can't believe it. I thought I will take a re-exam... thanks a lot sir🙏 to everyone reading this: do not be lazy, do not leave everything on the last days. good luck everyone)
damn i am writing tomorrow, looks like ill just have to take the re-exam
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Your videos have help me so much for the last year. Thank you so much for really taking your time and and providing so many examples. You have helped me on every test I've taken for my past 3 chem classes. I appreciate it very much.
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At 58:26, If you multiply the reaction by 2, wouldn't the half reaction then be 1.54V? And the new total would be 1.77V?
edit: 1:03:12 The answer is no.
If the reaction is multiplied by a coefficient the cell potential won't be affected or altered.
It is only altered when the reaction is reversed.
At 34.26 minutes of video,
∆G = ∆G^o - RT lnQ
I have 2 textbook here of Gen Chemistry saying that
∆G = ∆G^o + RT lnQ
^o is to superscript, to set delta G in standard state
I am learning a lot from you but I like to clarify this formula..Thank you.
The textbooks are:
Fundamentals of Chemistry, 4th Ed. by Frank Brescia etc. page 311
Principles of General Chemistry, 3rd edition by Martin S. Silberberg, page 676
You r right bro ; he forgot to see his mistake
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Got an exam in three hours 😭😭I don’t know what I’d do without your channel
I also watched this 2 hours before my exam ❇️
Am in your shoes now
Coronavirus shuts down your university + forced to do online school + didn't know what the hell was going on to begin with when you were in school = finding this channel on UA-cam
true
You sir are doing a great thing. Thanks to you I've aced three chemistry classes so far.
you've really help me to understand science in all its branches, we deeply appreciate you sir for the knowledge you share ...ive been watching your lecture videos. i find that i understand you more than my own lecturers continue helping people ..Steve (Zambia) ...
I couldnt understand this subject anywhere else but here ❤❤ love how you tell us the logic behind everything
I knew nothing about electrochem before this vid and my AP test is tomorrow. God bless u
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58:14 it is 1 volt
yes I also got 1.0 V
Thx for being so good at explaining this. Gonna be taking my AP Chem exam later today!
Thanks....will be taking my chem 101later tomorrow
How was it
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Hello, thank you so much for the video. In response to question 3 45:57, should it be 1776.61 hours?
no
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2:16 What if We plug in the battery to outlet and to my device at the same time..... it's (the battery) is receiving energy (electrolytic) and also supplying energy (galvanic).....how does this work ?
13:20 I dont know wen it comes to electro chemistry whether or not my syllabus is different from what you are teaching here .I check my textbook and this what you're explaining ain't in there .
But overall you're the best 🔥🔥🤟
south africa learner?
@@heavenlyway108 Yess ...you see I go to a public school and we Do Caps I know private schools they do Cambridge or something idk what its called but we might have the same syllabus but theirs are more little more harder and different from what we do
You're amazing couldn't have done it without you
Bro your better then my professor at explaining this. Thanks you very much!!!
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Mistake at 32:52, this is not a product-favoured system, Q is the initial concentration ratio. However, the positive standard cell potential is indicating that it is a product-favoured system since the reaction is spontaneous.
Am I correct?
You have always made me to love chemistry. I like the content yo you deliver
I can’t say how much I appreciate your videos. Thanks sooo much I really mean that:)
Always a pleasure.
Thankyou!
Hey you! Long time no see!
Anyone else studying for AP exams
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The best teacher♥️
Thank you very very much, I watched your video before reading my notes from my prof, now everything is clear and easy. Thanks again, appreciate your hard works!!!
Great stuff honestly
Thanks these videos are really helpful, I hope you have tutorials about Unit operations as well. Me and my batch mates are able to study solution manuals but it would be really helpful if there are tutorials or explanations as well ( especially Unit operations )
Thank you so much for breaking down the trends of the components!
34:34, shouldn't it be PLUS RTlnQ
Yes it is plus
At 59:13 you did their sum wrong its supposed to be 1 volt 0.23+0.77=1
What a great explanation!
Literally, have a final tomorrow. Wish me luck guys!
good luck
@59:00 how is the E =1,1V? Shouldn't that be 1,0 V? Because 0,77 + 0,23 = 1,0 V
Sexiest tutor voice ever. Every time I don't get something on chimestry class im like he got ma back. Relax xD
Thanks man sending love and appreciation from Puerto Rico ♡♡♡ keep making vids
I though I was the only one that thought he sounded sexy lol
at minute 11:27 you said that zinc is being oxidized, thus is the reducing agent and that copper is being reduced, thus is the oxidizing agent.... but isn't it backward? ( zinc is being reduced since is going from 0 to +2(gains), thus is the oxidizing agent..... and copper is being oxidized since is doing from +2 to 0 (losing), thus is the reducing agent)....
I'm confused now!... OIL (oxidation is loss of electrons) RIG (reduction is gain of electrons)...
can someone clarify, please?
Diana P Desai He is right actually. you are making a mistake with the oxidation numbers. when zinc goes from 0 to 2+ it is becoming more positive and is therefore losing electrons. As a result it is going through oxidation and is the reducing agent! (Like you said, oxidation is losing; OIL)
the opposite goes for copper. it goes from +2 to 0, meaning it is becoming more negative. Therefore it is gaining electrons and is reducing (RIG) and is the oxidizing agent!
Ur the best at everything
Your videos are amazing thank you.
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31:59 into the video how do I get the answer 25080. 1.1v - 0.97 ÷ 0.0591 can't get the answer as he not say if you multiple by 2 or 10 or just 1.1v - 0.97. Help
This man is shaving my A levels
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14:58 Why it's 212 Joules when you calculated -212267 J/mol?
Remember "Red Cat An Ox" reduction, cathode, anode oxidation
@John Wayne yes
omg, thanks😻
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How is zinc the product and copper is the reactant if the copper is gaining mass in the cell?
Mark Keith, this reaction is not about product or reactant. It's electro chemical reaction pertaining to cell. We call them product/reactant only to simplify.
:Peace
~A TOCT Fan
Thank for your services sir
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God bless you.
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Amazing video! It helped me a lot. Thanks you!
Could you write what you say on the video because l dont speak English well
No
If you turn on captions by pressing on cc you’ll see it
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22:22 isn’t the Zn ->Zn 2+ actually reduced since it gains to electrons and the Cu oxidized because it loses 2?
No you see for you to understand this you have to looks at your standards reduction potential table 4B
Zn is above Cu if you look on your table . So the metal that is on top of the other one will be oxidized and the metal below would be reduced.My teacher thought us the Big C method that we use to figure out which metal is oxidized and reduced and what would the half reaction be for that metal being oxidized
Big C method :
OIL RIG
Oxidation is losing electrons
Reduction is gaining electrons.
A wonderful lecture!
Thank you for the videos! Keep up the good work
I like your method of teaching and crystal clear explanation. But one major demerits of your video is the very low volume of voice
Love your big videos! Thx a lot
How do you know the standard potentials? Most have more than one possible charge so how do we go about choosing the correct one?