The Equilibrium Constant

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  • Опубліковано 6 лип 2024
  • 065 - The Equilibrium Constant
    In this video Paul Andersen defines the equilibrium constant (K) and explains how it can be calculated in various reversible reactions. The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants. If the K value is less than one the reaction will move to the left and if the K value is greater than one the reaction will move to the right.
    Do you speak another language? Help me translate my videos:
    www.bozemanscience.com/transla...
    Music Attribution
    Title: String Theory
    Artist: Herman Jolly
    sunsetvalley.bandcamp.com/trac...
    All of the images are licensed under creative commons and public domain licensing:
    "File:Lightning Hits Tree.jpg." Wikipedia, the Free Encyclopedia. Accessed January 2, 2014. en.wikipedia.org/wiki/File:Lig....
    "File:Nitric-Oxide-3D-vdW.png." Wikipedia, the Free Encyclopedia. Accessed January 2, 2014. en.wikipedia.org/wiki/File:Nit....
    "File:Phosgene Poster ww2.jpg." Wikipedia, the Free Encyclopedia. Accessed January 2, 2014. en.wikipedia.org/wiki/File:Pho....
    "Reversible Reactions." PhET. Accessed January 2, 2014. phet.colorado.edu/en/simulatio....
    "Reversible Reactions." PhET. Accessed January 2, 2014. phet.colorado.edu/en/simulatio....

КОМЕНТАРІ • 291

  • @alfredlin3637
    @alfredlin3637 9 років тому +1548

    This guy is single-handedly keeping my GPA in equilibrium.

  • @soccerismylife514
    @soccerismylife514 7 років тому +549

    you were there for me when no one else was

    • @siobhanquinn4635
      @siobhanquinn4635 4 роки тому +1

      Lol

    • @angelado6726
      @angelado6726 3 роки тому +1

      Omg yes

    • @soccerismylife514
      @soccerismylife514 3 роки тому +29

      I commented this in undergrad and as a now medical student I can honestly say you are still there for me when no one else is

    • @usmanafridix
      @usmanafridix 3 роки тому +3

      Steffy Martinez queen

    • @lauramanuel895
      @lauramanuel895 3 роки тому +3

      @@soccerismylife514 ohh how cute

  • @DannyandPatty
    @DannyandPatty 10 років тому +281

    One thing missing: solid and liquid exceptions.

    • @colincaver15
      @colincaver15 6 років тому +7

      Was just looking for this to confirm it's real, should be higher in the comments

    • @Kim-mu7gw
      @Kim-mu7gw 6 років тому +41

      solid and liquid should not be included in the equilibrium because only gas has pressure.

    • @starf1are505
      @starf1are505 4 роки тому +1

      Others should know👍

    • @laurdesz9050
      @laurdesz9050 4 роки тому +4

      @@Kim-mu7gw This is what I was looking for thank you!!!

    • @ChuuNebyou
      @ChuuNebyou 4 роки тому

      @@Kim-mu7gw wait what about aq?

  • @TheGr1ffinator
    @TheGr1ffinator 8 років тому +60

    How can he explain things so fast but so well?! Keep up the amazing work Mr Andersen you're the best!

  • @shwetakur1
    @shwetakur1 10 років тому +11

    Thank you soooooo much!!! I love the way you simplify complex concepts and I love the stimulations! I think everyone should watch your videos and benefit from them!!!

  • @nickkraw1
    @nickkraw1 8 років тому +85

    Thank you Mr. Andersen, your videos are wonderful!

    • @thisisnotmyfinalform7856
      @thisisnotmyfinalform7856 7 років тому +3

      Does Kc value tell about the reaction rate???

    • @JihadAlAnsari
      @JihadAlAnsari 7 років тому +3

      No it doesn't. Only the concentration of reactants and products. If it's >1 that means there are more products than reactants. We also say that the equilibrium lies on the right. When its

    • @shta6400
      @shta6400 2 роки тому

      @@thisisnotmyfinalform7856 No, it doesn't. It tells us whether we'll have more products or more reactants when we reach equilibrium.

  • @trishalmeida3496
    @trishalmeida3496 4 роки тому +4

    love this guy's teaching, especially his concise yet detailed explanations. thanks Paul.

  • @carolineklevemann2787
    @carolineklevemann2787 8 років тому +4

    Thank you for helping me through chemistry's difficult concepts. I feel hopeful even when things are hazy in class as I know I can look up the concept on your channel and find clarity! Cheers to you for sharing your knowledge and gift as a teacher!

  • @amrutvani2
    @amrutvani2 10 років тому +13

    Wow thanx for a beautiful lecture. Never knew the meaning of K value. No chemistry book has shown such simplified meaning.

  • @flakiss997
    @flakiss997 6 років тому

    I watch your videos all the time, and I would just like to thank you for taking the time to post them. You are an excellent teacher, easy to follow and understand. Once again thank you so much!

  • @juliajohnson3494
    @juliajohnson3494 4 роки тому +2

    Perfect. Just what I needed to share with my students while teaching from home. Thank you for all you do!

  • @essammccain9994
    @essammccain9994 8 років тому +33

    dude i fucking love you

  • @kristianwilliams441
    @kristianwilliams441 9 років тому +6

    First your videos helped me with AP biology as a senior in high school. Now they're helping me with chemistry in college. I love these.

  • @braedonvangorkom3308
    @braedonvangorkom3308 5 років тому +2

    Thank you sir. Simple, effective, insightful and fun. Just what education should be.

  • @dooham1383
    @dooham1383 8 років тому +3

    Thank you for the videos! Really clarified important concepts!

  • @teknodisko
    @teknodisko 4 роки тому

    Very helpful! I learned this a week ago and completely forgot the concept. After watching this video however, I was able to jog my memory!

  • @Leestella2
    @Leestella2 10 років тому +1

    Didn't take chemistry yet, but still understood it. Thanks for the extra knowledge!

  • @BrysonRhodesChannel
    @BrysonRhodesChannel 7 років тому

    you are super helpful man bless you and all the generations that come behind you!

  • @bongplayda8178
    @bongplayda8178 3 роки тому

    Thank you Mr. ANderson...I have watched your videos lately and I really learned a lot

  • @samuelhodgesv9532
    @samuelhodgesv9532 8 років тому

    Your videos are so helpful! Thanks so much! Keep up the good work.

  • @TheLivirus
    @TheLivirus 3 роки тому

    Thanks! You make the whole thing very understandable.

  • @sheikhs.mahmud4020
    @sheikhs.mahmud4020 9 років тому

    Of course that was helpful...thanks! You are the best, Andersen..

  • @gingerlove9085
    @gingerlove9085 7 років тому +1

    is it the same if it ask you to writ an equation for equilibrium constant for forward reaction

  • @skiidzman
    @skiidzman 6 років тому +80

    I wish he would have covered how to calculate the equilibrium constant...

    • @laurdesz9050
      @laurdesz9050 4 роки тому +3

      me too man, me too

    • @frodobaggins7227
      @frodobaggins7227 4 роки тому +8

      Products/reactants
      Equilibrium constant uses molarity so before you set up the equation you need to balance the equation, find the molarity of each product and reactant. Then you set up an equation that multiplies the molarity of all the products with exponents that are the coefficients in the reaction. This has to be over the molarity of the reactants multiplied together with exponents that are the coefficients. Should look like this:
      (C)^c(D)^d
      -----------------
      (A)^a(B)^b
      If Keq < 1 it favors reactants in the left direction. If Keq > 1 it favors products in the right direction.
      By the way solids and liquids are not in the equation.

    • @Thekingjuliann
      @Thekingjuliann 3 роки тому +2

      Bro I a mega test tomorrow and hace to learn this in 4 hours

    • @LaLa-he3ln
      @LaLa-he3ln 3 роки тому +1

      @@frodobaggins7227 the molarity, Why multiply without adding up?
      can you please explain it for me

    • @kouchiee
      @kouchiee 2 роки тому

      Equilibrium constant (K) is equal to (C)^c x (D)^d / (A)^a x (B)^b. There is an invisible multiplication sign in the middle, so you have to multiple the molarities/concentrations of the products and divide that over by the molarities/concentrations of the reactants to get K. (And you get molarity by using C = n/V)

  • @alandawat6476
    @alandawat6476 8 років тому

    thank you so much but i have a question! we dont write the liquids and solids in the equation becuz it doesnt affect the concentration but what about aqueous substances? do we include them in the equation? does it affect the concentration

  • @mattpresti9456
    @mattpresti9456 10 років тому +1

    Always enjoy these videos. I am still confused on one thing. At nine minutes during an ICE table the change in H2O is shown as .038 mols. The initial value is zero and the equilibrium value is .138. So why is the change not .138?

  • @abdulrehmankhan3428
    @abdulrehmankhan3428 6 років тому

    Thanks Mr.Andersen this is really helpful

  • @leann6933
    @leann6933 5 років тому

    Mr. Andersen saving my but again. First in high school now in my senior year of college.

  • @nasgrp2437
    @nasgrp2437 8 років тому +2

    mr anderson can you do more practiced questions and examples please???

  • @marvinabuli4487
    @marvinabuli4487 7 років тому +1

    can you do a video on how to find the equilibrium constant in electrolysis

  • @istarzgirl
    @istarzgirl 9 років тому +15

    Thank you! K>1,P>R,arrow points to the right indicating a right shift while K

  • @xisaabtv8082
    @xisaabtv8082 7 років тому

    Thank you very much.
    You say if Kc is greater than 1, it moves from reactants to the products side. And if the Kc is less than 1, it moves products to reactants. My question is when can we have the equilibrium mixture for an appreciable concentration of both reactants and products ?

  • @codezmister
    @codezmister 7 років тому

    The song in the beginning of the video is so cool!

  • @brettstefanishin574
    @brettstefanishin574 8 років тому +1

    Wow thanks! That was so helpful!

  • @ajsim
    @ajsim 7 років тому

    Very helpful. Great job, and thank you!

  • @anthonyrichard1365
    @anthonyrichard1365 9 місяців тому

    Great video! I wonder why the temperature has an impact on what will be produced more, the reactant or the product, and therefore, what the K value is. What role does temperature play in the way that at one moment the product can be produced more than the reactant (thus, favoring the forward reaction)? Conversely, how does a lower temperature of the same reaction make it favor the reverse reaction?

  • @pofficial-qi6es
    @pofficial-qi6es 7 років тому +1

    Very very helpful thanks... And very easy language....

  • @Ahnoss
    @Ahnoss 10 років тому +5

    You're helping me get a degree!

  • @twokidsmovies
    @twokidsmovies 25 днів тому +1

    So is the K value the same as Log K? Like when modeling in the GWB, each reaction has Log K values at different temperatures

  • @chitranjansingh2196
    @chitranjansingh2196 4 роки тому

    You teach very well. I like your teaching

  • @Niki-cf3tr
    @Niki-cf3tr Рік тому

    Thank you so much I really needed this 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

  • @marklandau365
    @marklandau365 7 років тому +1

    i've been watching your videos since my first intro. chem class a 1.5 years ago. i'm in chem 2 now and you are still doing god's work (i'm atheist btw). can't thank you enough for this invaluable resource, sir

  • @eleanormystim1641
    @eleanormystim1641 5 років тому

    Thanks so much, got Chem sac tomorrow and I finally understand the concept :)

  • @janahany1481
    @janahany1481 2 роки тому

    THANK YOU SOO MUCH I LOVE YOUR VIDEOS THEY ARE SUPER HELPFUL

  • @Christaxio
    @Christaxio 8 років тому

    Fantastically explained!

  • @sehmio
    @sehmio 7 років тому

    This was so helpful!!
    Thank you so much :)

  • @samsunnahar9175
    @samsunnahar9175 3 роки тому

    Thanks a lot for your clear explanation!

  • @alphanguyen2901
    @alphanguyen2901 5 років тому

    u r the goat & teach sm better than my teacher thank u sir

  • @ASteel-yo8em
    @ASteel-yo8em 6 років тому

    Thank you very much for this helpful video!

  • @normalperson5317
    @normalperson5317 Рік тому

    It was really helpful. keep going!

  • @vitorfernandobarro6343
    @vitorfernandobarro6343 4 роки тому

    it really helped me a lot, thank you

  • @GabrielDayot
    @GabrielDayot 8 років тому

    What if I'm asked to solve for the Kc and Kp and the given is only the molarities of all the substance given at a certain temperature?

  • @msabbasi01
    @msabbasi01 2 місяці тому

    How can we solve units of concentration for the followinv reaction? I have tried so hard on it but couldn't understand that how do we get moldm‐³ as its answer. When nitrogen reacts with hydrogen to form ammonia, the equilibrium mixture contains 0.31 mol dm‐³ and 0.50 mol dm‐³ of nitrogen and hydrogen respectively. If the Kc is 0.50 mol‐²dm⁶, what is the equilibrium concentration of NH3?

  • @clairenime
    @clairenime Рік тому

    Thank you sooooo much, great videos

  • @KC-ke1vp
    @KC-ke1vp 4 місяці тому

    oh my! thank you sm! hoping it will help me in my prelim exam in cellular and molecular biology!! taking the test in a few! ❤️‍🔥

  • @hafsanoor7556
    @hafsanoor7556 7 років тому

    man this was soooo helpful! thanks!!

  • @crazyotaku5754
    @crazyotaku5754 6 років тому

    excellent.... splendid explanation

  • @matildemateus3977
    @matildemateus3977 3 роки тому

    Hi, I just have one doubt: why do we multiply ( the products by the products and the reactants by the reactants) instead of adding, when calculating the equilibrium constant?

  • @patriciaherr4974
    @patriciaherr4974 7 років тому

    This is helpful, thank you!

  • @schnarfel
    @schnarfel 8 років тому

    thank you! it feels like you did it all on one breath though!

  • @farouqalsalih619
    @farouqalsalih619 4 роки тому

    If a reaction has a very low K value, would that mean that the reaction at that temperature is non spontaneous as there are very few products. Also, if the k value is very large, would that mean that the reaction is spontaneous as there are many products?

  • @QUITEthegamer
    @QUITEthegamer 8 років тому

    this was just beautiful!!!

  • @michaelmcfarlane3067
    @michaelmcfarlane3067 5 років тому

    thank you so much!!! you are a great teacher!!!!

  • @queenzht
    @queenzht 3 роки тому

    Time to review ... Thank you for your video.

  • @mosessaleh6406
    @mosessaleh6406 10 років тому +1

    Very helpful, thank you

  • @soap143
    @soap143 Рік тому

    you explain WAYYY better than my chem teacher

  • @jeffmartineau8479
    @jeffmartineau8479 5 років тому

    You sir are a gentleman and a scholar

  • @rmulenga
    @rmulenga 4 роки тому +1

    At 3 min, the expression should be aA + bB cC + dD (missing PLUS sign on RHS)

  • @moath5569
    @moath5569 8 років тому

    What if there are solids or liquid in products and reactants . Do I have to put their concentrations in the equation ?

  • @aneeshvaidya7838
    @aneeshvaidya7838 5 років тому

    Thank you soooooooooo much. U r an amazing teacher.

  • @asifhussain6298
    @asifhussain6298 8 років тому

    Daym every problem I have in chem and physics this guy has already done it

  • @sukitvirathana7151
    @sukitvirathana7151 8 років тому

    you just practically save my life

  • @oneSpok
    @oneSpok 8 років тому

    That was superhelpful :) Thanks!

  • @princessmary103
    @princessmary103 2 роки тому

    Love this. Thank you

  • @a23457b
    @a23457b 9 років тому

    Does it matter if the concentrations are in mM as opposed to M?

  • @EmRatHien
    @EmRatHien 10 років тому

    Thank you! Very helpful!

  • @100percentjoy
    @100percentjoy 9 років тому

    Thank you Mr. Anderson

  • @gabrielbadea1143
    @gabrielbadea1143 9 років тому

    And phosgene is made by simply let them sit togheter or ignite the mixture?

  • @royc7421
    @royc7421 5 років тому +1

    Wish they had UA-cam videos when I was in college taking chemistry.

  • @anthonyokpara2117
    @anthonyokpara2117 8 років тому

    am finally getting smething BOZEMAN yuh the best...thkz alot

    • @nasgrp2437
      @nasgrp2437 8 років тому

      +Anthony okpara or that your just dumb and took this guy for u to actually get something and get you to use one of your brain cell on

  • @BigChungusthe3rd
    @BigChungusthe3rd 7 років тому

    How does temperature affect the equilibrium constant?

  • @srikantadash4603
    @srikantadash4603 3 роки тому

    Actually I didn't get u yarrr. How can u explain so nicely... Equilibrium constant was a doubt in my mind for 6 years.. U just cleared in a 6 min.... But u r lilbit fast.. I watched at 0.75X .. it was so helpful... Love u bro 😎. From INDIA 🇮🇳

  • @teaninja12
    @teaninja12 9 років тому

    how do you know the concentration of the substances that youre putting into the K value equation ? is this information usually given ? (high school chemistry btw)

  • @farahratrout537
    @farahratrout537 5 років тому

    how do you know which side is the product and which side is the reactant?

  • @queensffanah
    @queensffanah 10 років тому

    That was VERY helpful thx.

  • @A-Noodles
    @A-Noodles 8 років тому

    So helpful, thanks!

  • @dakhemyst
    @dakhemyst 22 дні тому

    Excellent. Thank you

  • @pboyzzadventures3185
    @pboyzzadventures3185 Місяць тому

    In equilibrium constant the reaction is reversible hence the double arrows, meaning reactants can be products and products can be reactants. But we try to figure out if we have one more than the other by our constant K. Constant K measures out if we have more reactants or if we have more products at equilibrium. K represents the concentration of our products over our reactants. K>>1 reactant to product, K

  • @micahbendicion8444
    @micahbendicion8444 6 років тому +1

    4:03 You said "standard temperature and pressure", but then the box said 25 degrees Celsius, which is room temperature. Which did you intend?

    • @yahiazaatit7679
      @yahiazaatit7679 5 років тому

      overall the chemical reaction's entourage

  • @jarrodlowe07
    @jarrodlowe07 10 років тому

    Great video, very well explained

  • @rainakumari5126
    @rainakumari5126 2 роки тому

    Thanks a lot ✨ it really helped!!!

  • @ibensince2
    @ibensince2 10 років тому

    It was very helpful sir.

  • @kanpitcharakwong4443
    @kanpitcharakwong4443 3 роки тому

    at 3.37 Is H2O taken into account for this equation? I thought this is only for gases and aqueous ?

  • @tyson6695
    @tyson6695 8 років тому

    I already knew how to solve it,but the question that was annoying me was that what is k constant and what does its value represent,thanks very much sir,definitely subscribing👍👍👍👍

  • @WanSyazlina
    @WanSyazlina 7 років тому +1

    can someone help me... if the product I have in the reaction is in (aq) aqueous state, should I leave it out when calculating for Kp?

    • @cincaulim6479
      @cincaulim6479 7 років тому +1

      Syazlina Aasim yes, you only use the gaseous stuff in your calculations :)

    • @cincaulim6479
      @cincaulim6479 7 років тому

      Bavley Guerguis Do you mind explaining?

    • @cincaulim6479
      @cincaulim6479 7 років тому

      Michael Malize could you please explain

    • @cincaulim6479
      @cincaulim6479 7 років тому

      Bavley Guerguis I am not a very bright student. It would mean a lot if someone else were to explain it to me. I'm not able to comprehend from internet sources

  • @idreesiqbal561
    @idreesiqbal561 9 років тому

    thanks mr.Anderson , it was os usefull

  • @053_abdulhannanbhat8
    @053_abdulhannanbhat8 6 років тому

    Damn this sure was helpful thanks brother

  • @J_232
    @J_232 9 років тому

    why does only temperature affect k, and not pressure, concentation etc?

  • @LithiumSensation
    @LithiumSensation 6 років тому

    is k value given to us on the exam because I​ cannot find it on my periodic table

  • @annalois3279
    @annalois3279 4 роки тому

    Do you have a note version of this?