every single time, I come here panicking cause I don't understand what the question is asking off me, and every single time you never fail to be exactly what I need. Honestly I probably owe so much of my degree to these videos. This video is like 4 years old now so I doubt you'll see this, but I'm genuinely so glad for your work and effort. Thank you so much.
Exactly true;that work is supposed to be negative since it is being done by the system which would be the opposite of it was the sorrounding performing work against the system!
1:30 am and I'm watching this to help me with my physics homework and its not even due tomorrow, or better said, today Sunday. Physics rules. Thank you.
the sign conventions are opposite in chemistry. expansion work is negative n compression is + 've. dU = q + w. using ur conventions ans is coming wrong sir.
i think its because the ratio of [Vf/Vo] will be the same even if they are converted into m^3 since the liters would have been divided by 1000 to convert it to m^3, so it would have cancelled out, so it doesnt matter if they are in liters or meter cube. but the 8.314 constant is a must for calculating joules so that is indispensable, but that's just what i speculate
Hi there. I always watch all your videos and I appreciate your hard working. All of videos are so helpful. I have a question, do you also do biochemistry?
According to the first law of thermodynamics, Q=dU+W Q=Heat supply on the system or heat lost from the system dU= Change of internal energy (Increase or decrease) W=Work done by the system or done on the system Internal energy depends on the change in temperature and work done depends on the change in volume... That means if we increase the volume of a system and with the increment of volume temperature falls that means temperature changes... So, here two things occur, work done and internal energy change... Now come to the question, in the above problem, temperature is constant..As temperature changes, internal energy changes... No temperature change, so internal energy change zero... As volume changes, so here only work done... Q=dU+W Q=0+W Q=W=nRT[ln(V2)-ln(V1)] Thank you...
In physics (we want the system to work for us) Wd by the system (gas) +ve Wd on the system -ve In chemistry (we want to do work on the system ) Wd by the system(gas) -ve Wd on the system +ve
does it matter that the pressure is not constant? W=integral(PdV) so wouldnt W=nRTln(v2/v1) only hold true if the P could be pulled out of the integral?
I don't see how you can find that W=Integral(P*dV) where P is Constant. And then when you find W=nRTln(Vf/Vi), you assume P is not constant and substitute in Pi/Pf. If P is constant, how can you substitute in Pi/Pf?
In 2nd question gas is being compressed meaning work is being done on gas so W should be positive right? and in 1st question gas is doing the work so W should be negative. Can anyone explain me why? Or is he referring surrounding for symbols and not system. @ThrOrganicChemistryTutor
Please findout actual work done by an aneroid barometer in joules per unit volume changing For actual model. Of an aneroid barometer made of nispan metal cell cylinder ? For one year In joules ?? Please Please Please
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every single time, I come here panicking cause I don't understand what the question is asking off me, and every single time you never fail to be exactly what I need. Honestly I probably owe so much of my degree to these videos. This video is like 4 years old now so I doubt you'll see this, but I'm genuinely so glad for your work and effort. Thank you so much.
Yes, this presenter has contributed to educating science which is very difficult topic to teach.
I stared at my homework/notes for nearly an hour without progress. One minute into this video answered my question. This man is a legend.
I don't think this man knows how much I love him.
Isnt that supposed to be -12,233 J? because it is done by the gas? and isothermal expansion is always w
Yeah in my textbook W= - p dV
No, the sign notation changes when you're doing physics or chemistry. Watch this video ua-cam.com/video/NyOYW07-L5g/v-deo.html
I was confused from that side
Exactly true;that work is supposed to be negative since it is being done by the system which would be the opposite of it was the sorrounding performing work against the system!
1:30 am and I'm watching this to help me with my physics homework and its not even due tomorrow, or better said, today Sunday. Physics rules. Thank you.
The professors should learn from you
the sign conventions are opposite in chemistry.
expansion work is negative n compression is + 've.
dU = q + w.
using ur conventions ans is coming wrong sir.
Correct for chemistry, however this video is addressing thermodynamic processes, which rely on a physics basis
he clearly states in the description that its a physics video.
@PRAVEEN TOMAR
So,, chemistry and physic is different in the sign??
I'm studying chemistry,,but the sign is different..!!
@@alnajah6750 they have different perspective chemistry perspective is surrounding physics perspective is system
Good work Mr sir
why is the value of R in the first question is 8.3145 instead of 0.08206 L•atm/mol•k?
yea , how to know when to use which value...?
i think its because the ratio of [Vf/Vo] will be the same even if they are converted into m^3 since the liters would have been divided by 1000 to convert it to m^3, so it would have cancelled out, so it doesnt matter if they are in liters or meter cube. but the 8.314 constant is a must for calculating joules so that is indispensable, but that's just what i speculate
Thank You
VERY GOOD LECTURE
Ive just realized this is more of physics and not chemistry since the negative and positive signs will differ
Hi there. I always watch all your videos and I appreciate your hard working. All of videos are so helpful. I have a question, do you also do biochemistry?
goodwork sir,i really appreciate your work
Thank you so much 👌
Curious about when you used deltaU=nCvdeltaT...why would you state constant V when it is expanding from 3L to 8 L? Thanks
According to the first law of thermodynamics, Q=dU+W
Q=Heat supply on the system or heat lost from the system
dU= Change of internal energy (Increase or decrease)
W=Work done by the system or done on the system
Internal energy depends on the change in temperature and work done depends on the change in volume...
That means if we increase the volume of a system and with the increment of volume temperature falls that means temperature changes...
So, here two things occur, work done and internal energy change...
Now come to the question, in the above problem, temperature is constant..As temperature changes, internal energy changes... No temperature change, so internal energy change zero... As volume changes, so here only work done...
Q=dU+W
Q=0+W
Q=W=nRT[ln(V2)-ln(V1)]
Thank you...
tnx sir that was very helpful
THANK YOU SO MUCH.GOD BLESS YOU😍😘🤗😄😀😁😊♥
thanks babe
Absolutely beautiful. Thank you.
Now give bro his Nobel prize 😂🎉❤
u are really helping man
haw can u wrait in such fuked manner?
Thanks you bro........
shouldnt work for compression bbe positive
I don't understand how the work done formula is +ve
As work done is done by the system, shouldn't it have -ve sign
Please explain 🙏
1:13 i thought when w is done by the gas w is negative
In physics (we want the system to work for us)
Wd by the system (gas) +ve
Wd on the system -ve
In chemistry (we want to do work on the system )
Wd by the system(gas) -ve
Wd on the system +ve
@@poppylanuwu ahhh
God bless you
pls tell me how did you calculate q2 4:36 😥its only positive
Use
hc/λ = nRT.
Do it correctly
Next Nobel Prize is 20 50 30
does it matter that the pressure is not constant? W=integral(PdV) so wouldnt W=nRTln(v2/v1) only hold true if the P could be pulled out of the integral?
Have you found the anwer man? Asking for a friend
Nevermind, i guess it makes sense now, he was pulling out the nrt which is constant, not p ^^
PV = nrT
W = integral(PdV)
P = nrT/V
W = nrT*integral(dV/V) from V1 to V2
W = nrT(lnV2 - lnV1)
The result in here 5:00 is not correct? I calculated it and this result appeared(5820.15)
How do you find work in an isothermal process if temperature is not known
May I ask how you arrived in your answer at your problem 1 letter b. Thank you.
Guys I need help what math process he used in 2:21 and he get 12,233?
Remember this is opposite work if you are studying for p chem
I don't see how you can find that W=Integral(P*dV) where P is Constant. And then when you find W=nRTln(Vf/Vi), you assume P is not constant and substitute in Pi/Pf. If P is constant, how can you substitute in Pi/Pf?
But why didn’t you convert the kelvin to Celsius ???
Kelvin is the ultimate unit for temperature hence no need for conversion.
what if we do not have gas and we have i liquid for example what equation we need ?
for the answer of number 1, it is not 12,233J sir, its 12,388J?
where is the ISOTHERMAL COMPRESSION FORMULA IN HERE?
If moles were not given how to find no of moles here using given conditions
In 2nd question gas is being compressed meaning work is being done on gas so W should be positive right? and in 1st question gas is doing the work so W should be negative. Can anyone explain me why? Or is he referring surrounding for symbols and not system. @ThrOrganicChemistryTutor
Você é especial, muito obrigado!!
I don't know why but reading course materials doesn't stick to me. After watching once your video I understand most of it.
Help me ask him I don't understand also my answer is different
I don't understand how you calculated question two 😓
جميل Nice
What if there is no mole?
it's so strange, the temperature is not change but Q is not equal 0
বাংলা ভার্সনে বিএসসি ফিজিক্স এর লেকচার পেতে ভিজিট করো। Miraj Khan science tutorial.
Please findout actual work done by an aneroid barometer in joules per unit volume changing
For actual model. Of an aneroid barometer made of nispan metal cell cylinder ?
For one year
In joules ??
Please
Please
Please
What is the use of studying those things if everyone s not gonna be scientist
Hello, is ur name Julio Gonzalez by any chance?
May I ask how you arrived in your answer at your problem 1 letter b. Thank you.