Last week our lecture gave us an assignment to explain about the Carnot cycle and I took note of exactly what our organic tutor is explaining guess what,,? I got an 100 %
After a proper revision your videos are such an icing on the cake for me bro it's just so perfect I had all my doubts cleared especially from the numericals ty so much my dear organic chemistry tutor you're an all rounder my buddy 💖💓
What majors did The Organic Chemistry Tutor select at college because everything you explain it becomes clear . Everything Maths , Biology, Chemistry , Physics , which ones were your majors ?
I love u dude I was dealing with a hard problem with carnot graph I was trying the question for 2 days and now after ur video 🤗🤗🤗I came up with the answer😍😘😘😘
In Step 2 of the Carnot Cycle, the Equation for Change in internal energy used is dU = n(Cv)dT, why do we use Cv (molar heat capacity at constant volume) if we are talking about an adiabatic expansion where the volume is not constant?
Why do chemists want to impose a sign convention that only meshes well with chemistry problems? The laws of thermodynamics are supposed to be universal. Why do some people want to tailor them for specialized cases?
Hello, Can I clarify if in 18:08, should the it be Q=-W? since the Work is(-) from the compression giving you delta U = Q - (-W)? and also in 19:12, isnt the delta U = +W because Work is (-) from the compression giving you delta U = Q - (-W)? Or am i wrong?
Near the end of the video when you are calculating the work done by the adiabatic expansion between B and C you use the constant Cv. Isn't Cv a constant used when the volume is constant? In the same way Cp is used in a process where the pressure is constant?
You don't necessarily need constant volume for Cv to apply, or constant pressure for Cp to apply. They relate to the special case where these specific heat capacities are the constants of proportionality between change in temperature and heat added to the system, but they apply outside this context as well. Cv is the proportionality constant between temperature an internal energy, while Cp is the proportionality constant between temperature and enthalpy. And this is true, regardless of whether volume or pressure is constant in any situation. And since both enthalpy and internal energy are state functions, it doesn't matter what path we take. The difference in these thermodynamic energy values still applies. Cv and Cp do have some dependence on temperature, so it isn't an exact proportionality. But it is close, and these values aren't very temperature sensitive, so you still get meaningful results by assuming they are constant with temperature. In this particular application, U=Cv*T is the way we calculate internal energy at each point of interest. We then take changes in internal energy, and equate them to account for work done by or on the system, associated with each adiabatic process.
Professor I have a question here. Is Carnot cycle totally isothermal? I mean there are two isothermal processes, which are isothermal compression and isothermal expansion. Others are adiabatic compression and adiabatic expansion. These adiabatics are also isothermal, at the same time ?
I don't understand why you're using dU = n*Cv*dT where Cv is used for constant volume but volume is not constant during adiabatic expension/compression?
@@frostbite07 Carnot engine doesn't have the efficiency equal to one. Before proceeding remember that "thermodynamic temperature" just means we're using a temperature scale with 0 being the absolute zero like Kelvin or Rankine. Let T_h be the thermodynamic temperature of the heat source, and T_c be the temperature of the heat sink. Then, the thermal efficiency of Carnot engine equals 1 - T_c/T_h. So even the perfect thermal engine cannot have the thermal efficiency of one. Imagine that your engine takes heat from the source at 100°C (373.15 K) and dispenses of it into a sink at 0°C (273.15 K). Than your engine can never be more efficient than (1 - 273.15/373.15) * 100% ≈ 27%.
Thermodynamics gives you bounds on real engines. Moreover, the explosion of the fuel mixture is not even approximately reversible. How can thermodynamics be of any use in designing real world internal combustion engines?
It gives you an idea for what efficiency you can expect, in a given engine design. It also gives you guidance for how to fine-tune the geometry of the engine for the greatest efficiency. This way, given a target power rating of the engine, you can determine the stroke, the bore, and the clearance volume, from the theoretical efficiency of the Otto cycle. And when you monitor the pressure and volume at every point along the way in a real engine, it does closely follow the theoretical curve of the Otto cycle.
The change in internal energy. In other words, the change in the sum total of all the modes of internal kinetic energy of gas molecules, in translation, rotation and vibration. Don't ask why it's called U, it just is.
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13:14 for Carnot Cycle
Thanks a bunch
Thank you
you made the carnot cycle easy for me to understand,i passed in my thermodynamics exam.thank you
i am so grateful for this elegant and simple explanation of the carnot cycle. it saved me from losing so many marks in my exams!
absolute chad, thanks mr. organic chemistry tutor. If I pass my thermodynamics class, It's mostly thanks to you!
did you pass?
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This really helped me connect all the ideas together. Thank you so much!
i'm trying to connect with you hihi
You are excellent bro! Even my lecturer isn't able to tell in this way! You are a great person!
You explained better than my lecturer thankyou
Your Thumbnails alone are so informative; respect mann
Last week our lecture gave us an assignment to explain about the Carnot cycle and I took note of exactly what our organic tutor is explaining guess what,,? I got an 100 %
Thank you for your valuable lecture! I'll do my best in the finals.
Less than a week before my exams I I just learnt more than what was taught over a semester
After a proper revision your videos are such an icing on the cake for me bro it's just so perfect I had all my doubts cleared especially from the numericals ty so much my dear organic chemistry tutor you're an all rounder my buddy 💖💓
Something about your voice just puts me in "learning mode". It's so soothing, and clear like I can understand what I'm being told
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What majors did The Organic Chemistry Tutor select at college because everything you explain it becomes clear . Everything Maths , Biology, Chemistry , Physics , which ones were your majors ?
Hi, at 18:08, I think you missed a negative sign. Q(c)=-nRT(c)ln(Vd/Vc) Your videos really help a lot!!
God bless you. If I ever make it, it will be a lot thanks to you.
I love u dude I was dealing with a hard problem with carnot graph I was trying the question for 2 days and now after ur video 🤗🤗🤗I came up with the answer😍😘😘😘
Great! I was looking for how to calculate the net work.. It took only few minutes💯💥
Exam time fears this man fr!
Thanks man
Very thorough
thank-you, studying for thermal physics and we are using Daveil V. shreoders book, this is a great complement to it.
am really loving the way he explains. i do understand
On Question 2, why did you use a different variant for the efficiency, and when do you know to use which one?
this is 2 years late but if helps anyone they are equivalent
*4 months late
divide the numerator by the denominator and it goes from (Th - Tc)/Th to 1 - (Tc/Th)
Great job professor,,grateful for your good job
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I am very interested in physics and related subjects. This video is simple for me to understand
i've watched your videos from my freshman year of undergrad through my physics PhD courses when I get confused lol. Thanks
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6:38 Wouldn't Qc be -6000 J?
Very clear, thanks man
Thank you lecture
Who else is here few hours to exam. Thank you O.C❤️😩
Great video - thanks
In Step 2 of the Carnot Cycle, the Equation for Change in internal energy used is dU = n(Cv)dT, why do we use Cv (molar heat capacity at constant volume) if we are talking about an adiabatic expansion where the volume is not constant?
Well explained. Thank you very much
Thank you so much I really appreciate it.
Saved my day
Umm as a chemist I would prefer the sign convention (Delta U = Q + W ) but the rest are fine
Why do chemists want to impose a sign convention that only meshes well with chemistry problems? The laws of thermodynamics are supposed to be universal. Why do some people want to tailor them for specialized cases?
@@gustavopaz5453 the sign convention of chemistry can be used in physics and vice versa
Both of them are universal
Ah yes, Physical Chemistry. The bane of my undergraduate GPA
Exam time in 18 minutes, let’s see what we get
Hello, Can I clarify if in 18:08, should the it be Q=-W? since the Work is(-) from the compression giving you delta U = Q - (-W)? and also in 19:12, isnt the delta U = +W because Work is (-) from the compression giving you delta U = Q - (-W)? Or am i wrong?
im a little bit confused about that one too
thank you very much once again
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Wherever you got your examples from please keep it coming my test was the exact same thing no difference ❤️❤️❤️
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Near the end of the video when you are calculating the work done by the adiabatic expansion between B and C you use the constant Cv. Isn't Cv a constant used when the volume is constant? In the same way Cp is used in a process where the pressure is constant?
You don't necessarily need constant volume for Cv to apply, or constant pressure for Cp to apply. They relate to the special case where these specific heat capacities are the constants of proportionality between change in temperature and heat added to the system, but they apply outside this context as well. Cv is the proportionality constant between temperature an internal energy, while Cp is the proportionality constant between temperature and enthalpy. And this is true, regardless of whether volume or pressure is constant in any situation. And since both enthalpy and internal energy are state functions, it doesn't matter what path we take. The difference in these thermodynamic energy values still applies.
Cv and Cp do have some dependence on temperature, so it isn't an exact proportionality. But it is close, and these values aren't very temperature sensitive, so you still get meaningful results by assuming they are constant with temperature.
In this particular application, U=Cv*T is the way we calculate internal energy at each point of interest. We then take changes in internal energy, and equate them to account for work done by or on the system, associated with each adiabatic process.
Helpful video
Thank you ☺️
I have my chemistry exam tomorrow
I hope it helps 😩
Professor I have a question here. Is Carnot cycle totally isothermal? I mean there are two isothermal processes, which are isothermal compression and isothermal expansion. Others are adiabatic compression and adiabatic expansion. These adiabatics are also isothermal, at the same time ?
POWERFUL EXPLANATION BUT PLS CAN U ANSWER FELIPE GARCIA'S QUESTION. i am really interested in it
They are equivalent
divide the numerator by the denominator and it goes from (Th - Tc)/Th to 1 - (Tc/Th)
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my glorious king
if any expanssion gives a +w ... then how the work will be positive in second step of carnot cycle ??
because the work= - ncv deltaT
∆T is negative beacuse temperature is reduced in the second step hence the work is positive.
shahzan ahmad ohhh! Now it makes sense, thanks a lot.
Please sir upload the diesel cycle curve.
Sir at problem 4
What is the exhaust temp?
Is it the Tc=266.7?
not the Th=666.7?
I think there's something wrong in number 3. 🤔
Thanks man
Please for help in homogeneity
1:36 how'd you solve the 0.26?
I am also questioning that
I get it now
You need to minus Tc and TH after that Minus the Answer to TC again to get the answer and multiply by 100 to get the percentage
@@UnknownUser049 just think of 1.00 as 100% .
where is the entropy do you have anything with that??
Which textbook is this?
😄 Thank You!
Why is the work done by the system in question number 2 not minus ?
김다민 it should be minus, since it’s leaving the system
I don't understand why you're using dU = n*Cv*dT where Cv is used for constant volume but volume is not constant during adiabatic expension/compression?
I responded to this same question to a user named Andrew Dave on this video.
Carnot Engine eh? More like a Cannot Engine am I right! Cuz it Cannot exist ha!……crickets
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Eyvallah hocam
What does n represent?
Awat kat slide kami takdak, nanti time explain memang aku jawab according to youtube
A mistake if Qh - Qc and Qc= -8000 then it should be 14000 - (-8000) = 14,000 + 8000 =22,000 not 14,000 - 800
I love you man
When is engine an ideal one?
Carnot engine is an ideal engine, its efficiency is 1. It’s impossible for a real engine to have efficiency equal to 1.
@@frostbite07 Carnot engine doesn't have the efficiency equal to one.
Before proceeding remember that "thermodynamic temperature" just means we're using a temperature scale with 0 being the absolute zero like Kelvin or Rankine.
Let T_h be the thermodynamic temperature of the heat source, and T_c be the temperature of the heat sink. Then, the thermal efficiency of Carnot engine equals 1 - T_c/T_h. So even the perfect thermal engine cannot have the thermal efficiency of one. Imagine that your engine takes heat from the source at 100°C (373.15 K) and dispenses of it into a sink at 0°C (273.15 K). Than your engine can never be more efficient than (1 - 273.15/373.15) * 100% ≈ 27%.
If W=/QH/-/QC/
Then W= /14000/- /-8000/
Which is W= 22000j
Thermodynamics gives you bounds on real engines. Moreover, the explosion of the fuel mixture is not even approximately reversible. How can thermodynamics be of any use in designing real world internal combustion engines?
It gives you an idea for what efficiency you can expect, in a given engine design. It also gives you guidance for how to fine-tune the geometry of the engine for the greatest efficiency. This way, given a target power rating of the engine, you can determine the stroke, the bore, and the clearance volume, from the theoretical efficiency of the Otto cycle.
And when you monitor the pressure and volume at every point along the way in a real engine, it does closely follow the theoretical curve of the Otto cycle.
What’s delta U
The change in internal energy. In other words, the change in the sum total of all the modes of internal kinetic energy of gas molecules, in translation, rotation and vibration.
Don't ask why it's called U, it just is.
Why don't you include the negative sign of - 26 %
isn't delta u = w+q not q-w?
u=q-w in physics
u=q+w in chimestry
Sign convention preferences vary, depending on application and context.
کدوم دانشگاه درس خوندی
why TH is divided by TC?
I’d probably be better off watching your videos rather than reviewing my notes
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Mark Wahlberg?
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