PV Diagrams, How To Calculate The Work Done By a Gas, Thermodynamics & Physics

This physics video tutorial provides a basic introduction into PV diagrams. It explains how to calculate the work done by a gas for an isobaric process, isochoric process, isothermal process, and an adiabatic process. It also explains how to calculate work done for a cyclic process. This video explains how to calculate the work performed by the gas given pressure and volume values in units of Pa and m^3 as well as atm and L. The first problem explains how to calculate work done during an isobaric expansion and the second problem discusses the work done for an isochoric compression. This thermodynamics video tutorial contains many examples and practice problems.
Open Vs Closed Vs Isolated System:
• Open System, Closed Sy...
First Law of Thermodynamics:
• First Law of Thermodyn...
Isobaric Process:
• Isobaric Process Therm...
Isochoric Process:
• Isochoric Process Ther...
Isothermal Process:
• Isothermal process The...
Internal Energy of an Ideal Gas:
• Internal Energy of an ...
_________________________
Adiabatic Process:
• Adiabatic Process - Wo...
Thermodynamics Review:
• Thermodynamics, PV Dia...
2nd Law of Thermodynamics:
• Second Law of Thermody...
Heat Engines:
• Heat Engines, Thermal ...
Converting Heat Into Electricity:
• Thermodynamics - Conve...
________________________
Carnot Cycle:
• Carnot Cycle & Heat En...
Otto Cycle:
• Otto Cycle of Internal...
Refrigerators and Heat Pumps:
• Refrigerators, Heat Pu...
Entropy:
• Entropy Change For Mel...
Heat Engines and Refrigerators Review:
• Carnot Heat Engines, E...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...

[@TheOrganicChemistryTutor]

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[@Sp44ppel]

In problem 6 at around 12:00 I think the answer is wrong. Not sure if someone mentioned that before. "A gas is compressed from 0.01 m^3 to 0.10 m^3" But point A is at 0.10 and point B is that 0.01, but it should be the other way around

[@rohan2024]

The pv diagram should have been an inverted one from this

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@The Organic Chemistry Tutor with the example at 4:33 there is no need to convert the volume unit to m3? Because the SI unit for volume is m3.

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[@olcayergul]

In fact, at 13:50, instead of trying to find of n value from the PV = nRT formula, you could just have put the P.V to the place of nRT on the W = n.R.T.ln[Vf/Vo] . if you had put PV to the place of nRT in the work formula, it would have been W = P . V . ln [Vf/Vo] . That formula would give same result for the work, and would be less effortless.

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* more effortless

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"Less effortless" as in "more work"? Lol
These diagrams show while we can have a clear understanding of work done and heat transferred, we still need to account for time and sequence. Is there no graphical method of showing the rate of energy flow?

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Make a video on how to find change in internal energy on pv graph
Its was a nice video

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[@LanternFlea]

hello! i know im late to the party but arent u supposed to use R= 0.08214 if the pressure = atm, and volume = litres?

[@eyobmeskelu1938]

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[@user-ki9cs7ww6b]

Is there a video of thermodynamics for chemistry because the workdone signs is different in Chemistry

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[@ZarafshanAkmal-hn8ht]

In problem 7, while calculating the work from C to A, why have we used 1/2[Po+Pf] delV ? Why not nRTln [Vf/Vo] ?

[@thriveyourself7775]

Thanks

[@narghile7594]

Do you have videos where you actually calculate the pressure.

[@user-gw2vp8eg5c]

Can someone please explain why when googled the work done formula it comes out as W=-PV (negative pressure) but for PV diagrams we use W=PV (positive pressure) instead?

[@shahiya5444]

Sir....i have a doubt....if clockwise....sign is negative or positive...mY teacher said that if anticlockwise work done is positive?plz reply

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[@brucejohnson5786]

Thanks again man. Why do I feel so confused doing this stuff though? Simple things like Work done ON the gas vs work done BY the gas, gets me tripping

[@BeaCamilotes]

Is the PV diagram in no. 5 wrong? Because the situation stated from .01 to .10?

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[@marshlegions7487]

Question 6 description needs to be corrected to indicate the gas compressed from 0.10. Similarly, expands isothermally back to 0.10. Otherwise very well explained.

[@vn8162]

So, when we find the work done of an isobaric process, either the pressure and volume units are in (atm-L) or (Pa-m^3), right?

[@carultch]

That's correct. The units of Pascal-meters^3 is equivalent to Joules. Liter-atmospheres would require a conversion factor to get what we usually consider an energy unit.

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[@jungjuchan241]

great video, i think tge question #6 on the direction of volume should be oppsosite

[@ouibutno]

18:25 why average pressure..?

[@jayashreeg8116]

Did you miss negative sign for work done due to expansion in the 3rd problem?

[@zulqarnainchaughtai]

During the isochoric process, when pressure is decreased from 4 atm to 2 atm, why is the volume of the gas not increased according to Boyle's law? I mean, how is this process done physically?

[@laurencromwell9601]

This may be that Im wrong, but shouldn't the overall work be negative? because fro A->D volume is decreasing and it was the smaller area under the curve. If the volume is decreasing that means that the environment is doing work on the system so Work is (+). But for B->C the volume is increasing- meaning the system is doing work on the environment in order to expand. If the system is doing work then work is leaving the system making Work (-). Because B->C has a bigger area under the curve the total work should be negative. I think you missed that because W=-PDV but you wrote W=PDV. If i'm wrong then just forget what I said haha

[@de-grafthazard9081]

I actually agree Lauren. I had the same confusion so I'm thinking he used different conventions for the signs maybe...Maybe he considered work done by the system as positive. So we actually have to reverse his conventions to get ours

[@KellieJo93]

is this the same for chemistry