Quantitative Description of Isothermal (Constant Temperature) Process with Ideal Gas on P-V Diagram
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- Опубліковано 10 лип 2024
- A piston (containing an ideal gas) undergoing an isothermal process is represented on the P-V diagram. The work, heat and internal energy are discussed.
#Thermodynamics
#Isothermal
#KonstantinLakic - Наука та технологія
Thank you so much for explaining it so clearly, i was very lost until I found your video. Thank you very much!!
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Finally found a satisfying explanation.
Thanks a lot, my friend.
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Subbed!
Thanks Samar
@@Elucyda you are very good but I didn't understood why is the internal energy (change) is zero.
Finally found a good explanation. Thanks man!
Thank you, I was having a confusion in that! You are amazing!
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You speak so clearly thanks. .well understood
Nice video bro👍 well understood keep going 🙏
Amazing!! helps me to understand easily😄
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Thanku for teaching us in such a easy way..
nice .great explanation sir ,thank u .
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Nice explanation
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Now I understood the concept
Thank you for this.. 😊
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I am from India
I am a student of class 11th
To which classes thermodynamics is most appropriate to teach in your country?
I am indian but your explanation is so better
???
Hi! I'm a new fan.. Thank you for your lectures. I like the way how you explain things. Your voice is also very calm.
Thank you!
what if I want to do the isothermal curve on a P - v (specific volume) diagram? I don't know in witch table I should seek for the values to do the curve.
Can you help me? How much heat needs to be rejected during a true isothermal compression of 3,000 cubic feet of air, when compressed from 15 psi to 4,500 psi using a 3-stage compressor?
Ooh thankyou so much 😍👍
Great video!
Glad you enjoyed it
Thanks
Definitely deserves more subscribers
0:06
Hi matey, thanks for the explanation what problem completely doll I cannot understand basic sing why if you’re applying heat temperature remain constant this I believe this is basic stink of iso thermic process but I cannot understand could you please explain
If I compress the piston, my work is converted into thermal energy inside the box. Then the heat sink takes that energy away. how can then the piston go back up, the energy should have been lost ?
Good men
Thank you so much!!!
You're welcome!
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Thank you. Sir
Welcome!
I know this every thing but i still can't understand how we can apply heat if temperature is constant
Baby brother of AK lectures.
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Akoa aben😂. (Very intelligent)
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air.
A. -80.35 J
B. 80.35 J
C. -811.93 J
D. 811.93 J
(please show calculation)
can use this formula W=nRT ln(p1/p2)
Can you help me..everyone doesnt know how to solve this..i must present this question to my lect..please notice me
Eu tentando estudar para termoquimica e voce apareceu kkk
Bro but in google Δu= Q-W so, when internal energy is zero, it becomes Q=W
Both sign conventions are correct as long as they are used consistently.
Here,∆U=0. Explain further.
Why not 𝑊=𝑛𝑅𝑇 ln (𝑉f/Vi)? Why have negative?
The negative sign comes from a sign convention for the work done. It is fine to use a different sign convention as long as you are consistent.