PV diagrams - part 1: Work and isobaric processes | Chemical Processes | MCAT | Khan Academy

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[@amonahud3250]

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[@ECOMMUSK]

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[@khozikahmed2168]

amazing . fisrt time understanding those 4 processes

[@leahevelee]

thank you!

[@Incrue]

Anyway thanks dude, i tough i understand this thing for the first time in my life

[@FeynmanAcademics]

Lolz. Me too

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[@jaehoahn4810]

At 10:22, is it the work done should be positive? because the final volume is greater than the initial volume..

[@ShannTsaikf]

If it's an isobar compression, then shouldn't the work done be negative? And vice versa? Since for the isobar compression graph the change in vol would be negative.

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[@vihaanmenon7175]

No, because positive work is work being done on the system. So a compression is net positive, because you add energy to the system. While expansion is negative, since the system does work and thus loses internal energy. I think so, atleast. Learning this subject myself right now. Thought this might help someone else with the same question.

[@parkmin-su4793]

@@vihaanmenon7175 I'm sorry but aren't the conventions for work different in physics and chem?
Like if work is done by the system=+W
If work is done on the system= -W ?
I'm confused about this part :")

[@carultch]

@@parkmin-su4793 Sign conventions are arbitrary, and set for the convenience of the context in which you are using them. You need to learn follow the sign convention given to you in your class. Ultimately, it's better to know how to state your answer with words, to explain the meaning of the sign you get, so that your answer is objective, regardless of what sign convention you are using. Not all physics and not all chemistry classes/books, are guaranteed to use the same sign convention as a standard.
I'm accustomed to the heat engine sign convention, such that heat added to a system is positive, and work done by a system is positive, for thermodynamics problems. For the original definition of work, work done on an object is positive, and work done by an object is negative, so it is opposite.

[@amaderjonnomathematics4288]

Sir i am not understanding anything what to do

[@suryatejayalla3502]

Super

[@abhinabasaikia6377]

liked it

[@haroldgaring8468]

please make TS diagram about these processes

[@bleuemoone8710]

excellent!

[@nthumara6288]

the world is runing on above 4 prosses approsimately

[@Incrue]

@11:30 you mean: because if its not equal the piston will move AND MAKE IT EQUAL AGAIN, right?

[@zubaer73]

if the temperature in isobaric process increases then why the internal energy reduces? i found some maths refering the decrease of internal energy in isobaric process.

[@gtrslayer1]

Zubaer Ahmed because the gas inside the piston has to use energy to push all of that area upwards, like he explained in the video, a force is exerted through a distance.

[@gtrslayer1]

The examples of the isobaric processes you saw must have been ones where you remove some pressure from your piston and the gas inside pushed it up a distance without the need of heating it up. Thus decreasing the internal energy (U) of the system.

[@ParveenKumar-pg3ps]

nys

[@mshahzadaslam7357]

thats it

[@itsasecret2132]

Delta Q = Delta U + Delta W right???

[@Incrue]

@10:43 you make them be at equilibrium but just in the initial state, right?

[@merkov8715]

I need help. So what formula should I use? A=F/A(hA) or A=F/A(vf-vi)?

[@pulkitraju7034]

merkov ∆hA = Vf - Vi

[@joslyns6671]

Isn't work done on the system + and work done by the system -?

[@TMPChem]

Unfortunately this convention tends to vary among various scientific disciplines and even individual lecturers, so often it is necessary to carefully observe and note the sign convention being used in each particular case.

[@anon_ninja]

Sorry but if it moves to the left it’s positive work?? But isn’t change in volume negative? (Decrease in volume) and vice versa

[@bjhu9031]

What software/app are you using for your presentation?

[@FeynmanAcademics]

When you know let me know too

[@KA1blow]

06:12 if h changes, doesnt that mean the area does too

[@Mobimobipopo]

It's the area of the piston ( the lid, the circle part of the cylinder) not the area of the cylinder itself so it won't change when the h changes.

[@arthikalexander316]

is it u=q+w or is it u=q-w?

[@AnirbanDas7]

+Arthik Alexander It can be both. Consider the expression: U= Q+W.
1. When work is done "ON" the system (e.g. External pressure applied to a gas in a piston-cylinder configuration to compress the gas), W= +W. Therefore, U= Q+ (+W)= Q+W.
2. When work is done "BY" the system ( e.g In a piston-cylinder configuration, when the gas exerts pressure on the piston, the piston moves upward), W= -W. Therefore, U= Q+ (-W)= Q-W.
In short. Work done ON the system is always positive in nature (+W) and Work done BY the system is always negative (-W).

[@usamaqamar5562]

+Anirban Das Hey! does temperature increase in isobaric expansion?

[@AnirbanDas7]

Yes, it does.

[@Sjsime827]

Are you God?

[@prashamranjan5638]

no

[@vortyx090]

Thanks.

[@abhinabasaikia6377]

liked it