Thank you for your valuable feedback. So you liked the way how the questions are answered. I am happy that the presentation is also reflecting your questions.
Thank you very much for your encouraging words. All the best. Let me know if you like video on ClF3 too.... Find the link: ua-cam.com/video/dvBn1PG1q3Y/v-deo.html
thank you. yes. I made it especially for novice learners. For advanced learners like you........it is a bit slow. I will make some arrangements in the future.
yes sir class 11 level means i was trying to say that please relate it with xef4 and other compounds that changing of the axial and equatorial position this and that.i said it class 11 because ray dutta twist is taught in our class but not in a detailed and a approaching way.and as it was taught with relating to xef4 hbridization and twisting of bonds ,i meant to say the level of class 11.sincerly adway tarafdar
I struggled with this topic when I learn it in class but now I understand it clearer. Thank you! I got some question from class and cannot do it. Which orbital or hybrid orbital that the lone-paired electrons of Xe in XeF4 are located?😢 Is it just sp3d2 or other that much more complicated?
Nice video! But I have a query , we chose to place the lone pairs at 180 degrees to avoid excessive repulsion in xef4 . In case of molecules like clf3 (trigonal bipyramidal geometry)we place the lone pairs at equatorial position and not the axial position , why is this so? Won't this increase the lone pair lone pair repulsion?pls help me with this...
Yes. You have to consider the repulsions from the ligand atoms too. When at axial positions, there are 2*3 repulsions at 90 degrees. At equatorial, there are only 2*2.
Good question! When you look into the ec of Xe in ground state, there are no unpaired electrons. Hence it requires energy to promote one or more electrons. Here 2 electrons. Actually it is a simplified picture. Exactly what is happening may be different.
It is true that for every molecule there is elongation twist etc.but I want to know about the ray Dutta twist by applying in Xef4 molecule .and about the change of the equatorial and axial position of the bonds in only the molecule of Xef4 thank you sir
Depending on how much energy is supplied to Xe atom it can get either one or two or three or four electrons...... If it gets one electron then it will form only two bonds with fluorine atoms.... That is it will form xef2.... And if d sublevel gets two electrons then xef4 is formed.... And so on....
but sir hybridization of xef4 is octahedral(sp3d2) and shape is square planer whereas structure is octahedral.therby leading to ray dutta twist.i may be wrong but please clarify
yes. so called structure is octahedral. But the questions what do you want to prove with Ray dutta twist? Actually for every molecule, there are rotations, twists, elongations, vibrations etc.
SIR PLEASE UPLOAD THE RAY DUTTA TWIST AS FAST AS POSSIBLE BECAUSE WE ALL STUDENTS ARE WAITING FOR YOU.AND THE NEXT THING IS THAT THERE IS NO DETAILED GOOD CONTENT OF THIS IN UA-cam SO FAR.WITH REGARDS ADWAY TARAFDAR
Sir how do we know to which orbital the electron excite Bcz after 5p orbital we use 6s orbital( afbuh principal )if we. want to fill electron then we we considerd 5d orbital in excited state of 5p orbitals
Yes. You are right. You raised a good point. May be there is a reason for choosing 5d instead of 6s. Either we are missing something somewhere or perhaps you are right in accepting the textbooks without digging deeper. Let me search for the answer. I will post it as soon as I get it.
Good question. It can. For example, if it enters into 1st excited state, then it can have only two unpaired electrons only which are sufficient for making two bonds only as in case of XeF2. In 3rd it can form XeF6
As already mentioned in the video it is octahedral with two lone pairs at 180 degrees or you can say the shape is square planar. Watch the video once again.
The only video I can find on UA-cam to explain the hybridization of sp3d2, amazing, love you!😘
Glad you enjoyed! All the best. Thank you.
I have a ton of respect for you. People that share knowledge for free and make it accessible to everyone are amazing. Thank you for your work
My pleasure!
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
very well explained. almost every question you have answered that came into mind.
Thank you for your valuable feedback. So you liked the way how the questions are answered. I am happy that the presentation is also reflecting your questions.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
This is awsome its one of the best chemestry lesson i have been given
Thank you very much for your encouraging words. All the best. Let me know if you like video on ClF3 too.... Find the link: ua-cam.com/video/dvBn1PG1q3Y/v-deo.html
All questions are explained in outstanding way. Only one request can you make next videos on optical isomerism in coordination complexes-adi sir
sure.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Well explained. No doubt. Thank you.
Thank you all the best
Bundle of thanks sir ap bahot acha clear krty ho i really inspired from you
Most welcome
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Well explained video Sir, and interesting way to teach... Thankyou Sir :)
Thank you very much. You are most welcome.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Well said sir.... your explanation is too good and your voice is very clear🥰👏👏👏
Thanks and welcome. Keep watching.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
sir.. it's impressive...your explanations are very nice.
thank you. yes. I made it especially for novice learners. For advanced learners like you........it is a bit slow. I will make some arrangements in the future.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Thanks sir you have assisted in my unknown topic
Glad to hear that
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Your teaching method is different and effective 😊 ^_^
Helps a lot
Thank you so much sure🙏🙏🙇
Thank you very much for your positive feedback which encourage me to prepare more videos.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
yes sir class 11 level means i was trying to say that please relate it with xef4 and other compounds that changing of the axial and equatorial position this and that.i said it class 11 because ray dutta twist is taught in our class but not in a detailed and a approaching way.and as it was taught with relating to xef4 hbridization and twisting of bonds ,i meant to say the level of class 11.sincerly adway tarafdar
I dont know why Ray dutta twist is connected to XeF4. It is for racemization of octahedral complexes. XeF4 is not octahedral. It is square planar.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
excellent presentation....
Glad you liked it
Nicely described. What is the temperature at which it is formed? I will be waiting for such more examples. Thank you.
Thank you. I will keep your suggestions in my mind while making videos in the future.
@@AdiChemAdi sir please make presentation on ray and Dutta twist .That will be the best
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Sir make presentation on ray dutta twist
Please visit: www.chemtube3d.com/tm-bailartwistray-dutt/
very nice dear sir
So nice
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
I struggled with this topic when I learn it in class but now I understand it clearer. Thank you! I got some question from class and cannot do it. Which orbital or hybrid orbital that the lone-paired electrons of Xe in XeF4 are located?😢
Is it just sp3d2 or other that much more complicated?
yes. in sp3d2 hybrid orbitals.....
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Good teacher
Thank you! 😃
Nice video! But I have a query , we chose to place the lone pairs at 180 degrees to avoid excessive repulsion in xef4 . In case of molecules like clf3 (trigonal bipyramidal geometry)we place the lone pairs at equatorial position and not the axial position , why is this so? Won't this increase the lone pair lone pair repulsion?pls help me with this...
Yes. You have to consider the repulsions from the ligand atoms too. When at axial positions, there are 2*3 repulsions at 90 degrees. At equatorial, there are only 2*2.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Well explained
Thank you and welcome.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Sir, how do I know if the Xe atom reaches excitation state for the Xef4 molecule? Thanks
Good question! When you look into the ec of Xe in ground state, there are no unpaired electrons. Hence it requires energy to promote one or more electrons. Here 2 electrons. Actually it is a simplified picture. Exactly what is happening may be different.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Thank you!!
You're welcome! Thank you. All the best.
Please explain the xef2
Sure
It is true that for every molecule there is elongation twist etc.but I want to know about the ray Dutta twist by applying in Xef4 molecule .and about the change of the equatorial and axial position of the bonds in only the molecule of Xef4 thank you sir
ok. I will try without using 3d animation software. If successful, I will upload.
Sir why xe get only 2 electrons into d orbital
Depending on how much energy is supplied to Xe atom it can get either one or two or three or four electrons...... If it gets one electron then it will form only two bonds with fluorine atoms.... That is it will form xef2.... And if d sublevel gets two electrons then xef4 is formed.... And so on....
Thank u for giving me this information sir
You are welcome
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
but sir hybridization of xef4 is octahedral(sp3d2) and shape is square planer whereas structure is octahedral.therby leading to ray dutta twist.i may be wrong but please clarify
yes. so called structure is octahedral. But the questions what do you want to prove with Ray dutta twist? Actually for every molecule, there are rotations, twists, elongations, vibrations etc.
SIR PLEASE UPLOAD THE RAY DUTTA TWIST AS FAST AS POSSIBLE BECAUSE WE ALL STUDENTS ARE WAITING FOR YOU.AND THE NEXT THING IS THAT THERE IS NO DETAILED GOOD CONTENT OF THIS IN UA-cam SO FAR.WITH REGARDS ADWAY TARAFDAR
I am a little bit busy nowadays. It requires 3d software, which I have to learn. May I know for which level do you want this? Class 11?
Thanks sir
Welcome
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Also Watch ua-cam.com/video/JvgX-QNc8gU/v-deo.html for activation energy
please make presentaion on ray dutta twist.that will be better
ok
Sir how do we know to which orbital the electron excite
Bcz after 5p orbital we use 6s orbital( afbuh principal )if we. want to fill electron then we we considerd 5d orbital in excited state of 5p orbitals
good point. it can be 6s also.........I too wonder why not this......
@@AdiChemAdi if 6s den hybridization changes right? Some times chemistry want us to accept as it is😅
Yes. You are right. You raised a good point. May be there is a reason for choosing 5d instead of 6s. Either we are missing something somewhere or perhaps you are right in accepting the textbooks without digging deeper. Let me search for the answer. I will post it as soon as I get it.
@@AdiChemAdi sure sir
Thanks for considering my doubt 😊
You are welcome.
Sir, how will the angle be exactly 90° between F-F, wouldn't it be less than that 90 due to lone pair-bond pair repulsion?
Well. A good question. Look at the structure. There are two lone pairs and each will repel equally from opposite sides.
Thanks for the explanation sir! Do you take doubts?
Yes. You can post your queries here.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Sir would u please upload about molecular orbital theory . Class11
sure. sooner.............
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Sir what kind of d orbitals we used here in hybridization
d orbitals which have almost same energy as that of s & p orbitals.
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
Sir I cannot understand sir please make video on ray dutta.that will be better for everyone
I am trying. It requires 3d animation software. I have to learn that. It will take time. My computer is not supporting it.
SIR PLEASE PLEASE PLEASE TEACH THE RAY AND DUTTA TWIST RELATED TO THIS XeF4
en.wikipedia.org/wiki/Ray%E2%80%93Dutt_twist.... If not happy with this link, let me know.... I will make a presentation.
@@AdiChemAdi sir please make presentation on ray dutta twist
Who agree with me this voice seems to be like the voice of abj Abdul kalam sir
:)
Find the structure and hybridization of ClF3 at: ua-cam.com/video/Jlf59prPJnc/v-deo.html
SIR I HAVE SEARCHED WITH YOUR LINK,BUT I CANNOT UNDERSTAND.SIR YOU MAKE ON PRESENTATION WITH RELATED TO XEF4
for XeF4?
Is all bond equal???
good question. yes. the average is so. but at any given instance of time, they may or may not be so.
AND SIR PLEASE MAKE RAY DUTTA IN LEVEL AND STANDARD OF CLASS 11
Class 11???
Why xe excited to only 2nd state not only 1 or upto 3
Good question. It can. For example, if it enters into 1st excited state, then it can have only two unpaired electrons only which are sufficient for making two bonds only as in case of XeF2. In 3rd it can form XeF6
@@AdiChemAdi okk sir .
What is the geometry of XeF4?
As already mentioned in the video it is octahedral with two lone pairs at 180 degrees or you can say the shape is square planar. Watch the video once again.
Thanks.. Octahedral and Square bipyramidal are the same, right?
yes
Zabbarrrrrdssssst
Thank you. All the best. Please share this with your friends.