Thank you SO much, Phillip ! You're truly a godsend. Really appreciate how you explain everything in detail. It's very kind of you to avail all this high quality material to us for free :D
Hey Philip! It's been around 2 weeks that I've started watching your videos for my GRE and THANK GOD I found your videos. Every single video has sooo much to learn from and your tricks are just amazing. Thankyou so so much for being an angel :)
Following your previous methods thoroughly, I could answer all the questions easily and quickly, even though I’ve been away from math for around six years. You’re a fantastic teacher, Philip! Hats off to you!
This is amazing! After watching the previous Rates video, I was able to do all the problems in this video by myself! And I'm particularly scared of this topic!
Yes, me too Shweta, When I watched this exercises goosebumps inmediately, But I know, this is a process, thanks for amazing videos Phillip. Greetings from Peru
Great content! Phillip. For these questions, I do always follow this trick and may be you can share this trick with others as well, in case you haven't already. Trick is to always assume work as multiple of time figures in the question. Let's say for the last questions instead of choosing 1 widget work as 1.. take a multiple like 6. This ensures your rate to never be in fractions and enables you to add rates easily.
Hi Buddy, I love the way you explain things, Gained a lot of wisdom in these couple of weeks. Just wanted to add a standard format as it helped me understand the problem much better. Prepare a table for all WAT related problems and Use the formula : T*A = W for calculating Average Time Average Work 4 1/8 1/2 16 1/4 4 ? 3/8 5 Explanation for the values below. As he mentioned we can add averages and not time. 1/8+1/4 = 3/8 Therefore, T = 5*8/3 = 40/3
Thank you so much for these videos Philip, can’t thank you enough for them. I have my test on the 10th of this month and your videos have been incredibly helpful.
I just started watching your videos they r amazing. Kindly help me where can find hardest problems on almost every topic. Preferably, free material for practice.
There is a short-cut with the final question: 1st: Work out both rates: (1) R1 = 1/6 (2) R2 = 1/4 2nd: The difference between these two rates (i.e. Joel's double speed!) is (1/4 - 1/6 = 1/12) 3rd: Work out Joel's rate: 1/12 x 2 = 1/6 4th: His time is simply the reciprocal = 6 = Answer
Hey Philip! On the last one I didn't quite use your method, but I'm curious to know if you think it's valid It made sense to me to set it up like J + V = 1/3 2J + V = 1/2 rearrange, then subtract 2J + V = 3/6 J + V = 2/6 ------------------- J = 1/6 J = 6/1 (individual time)
@The Tested Tutor Hi Philip! The question is asking for hours that Joel takes "currently" to finish the work on his own. His speed is doubled means it will now take 6/2 hours= 3hours to finish the work individually.????????
Please do a video on Coordinate geometry with a graph given and we have to get the equation out of the graph ....finding it very difficult to solve them in the 5lb book
I am really enjoying your tips and tricks. Thank You. I have a question regarding the final exercise in this video. I wrote the first equation as x+y = 1\2 and the second one as 2x+y = 1\3 and found the same result. Is it okay that way?
Great video! Thanks for uploading it! Do you have a video about factorizing polinomials? I have seen your video of prime factorizing and it really helped me! Thanks for your work
Hi Philip, thank you for all of your videos. For the last question I set up my equation as (1/3) -J = (1/2) - 2J basically doing the combined rates minus Joel's rate. I got the same answer. Is this a correct way of doing it or did I just get lucky?
For the third question I solved a simultaneous equation with Rj and Rv. I sometimes get confused with 1/j and 1/v. I have my GRE in 2 weeks, I hope it goes well :)
Hey! Thanks for your videos! Can you clarify this for me: I have been using the formula " Output = (No. of workers) (Sum of each worker's Individual rate) (No. of hours) " , but not sure why this doesn't seem to work in your problems.. For example, in the first example of Ana and Samaiyaara, I wrote down the formula as: Output = (No. of workers) (Sum of each worker's Individual rate) (No. of mins) 1/2 task= (1 worker) (Ana's Individual Rate) (4mins) 4 tasks= (1 worker) (Samaiyara's Individual Rate) (16mins) which implies, Ana's Individual rate = 1/8 and Sumaiyaara Individual rate = 1/4 Working together, their combined rate is 3/8, so now the formula becomes 5 tasks = (2 workers) (3/8) (No. of minutes) Solving for time, I am getting 20/3mins unlike 40/3. Can you point me out where I am going wrong? Thanks!
I don't know where that formula comes from, seems wrong to me. Why would 3 workers with a combined rate of 3/8 be any different to 2 workers with a combined rate of 3/8? We have already combined them. Maybe that formula works if you do average instead of sum. My method is totally different as you can see.
Hey Philip! It's a great video. Thanks once again for such wonderful video. I have been told by someone that's in December set the GRE questions are always difficult than other time. Is it true? I am thinking about giving test by the end of this month. Please tell me. I will schedule my test accordingly. As I am looking for fall 2021 intake.
Hi Philip. Hope you are having a good day. 🙏For gre, is it sufficient to learn Magoosh 1000 words and 333 barrons high frequency words??? Or do we need to learn any other words ? And also I have my gre exam scheduled on day after tomorrow. Any last minute suggestions from your side ?
Sir, Please make video on multiple workers problem( Ex. 20 workers pack 20 boxes at constant rate in T time how much time will 30 workers will take to pack 100 boxes)
Re the problem with Joel and Vivek -- I used your rule about combined rates being a sum and, rather than resorting to algebra, I subtracted the old rate from the new rate: 1/2 - 1/3 = 1/6. Is this acceptable?
Q- in a garrison there are 600 soldiers and food supply they have is sufficient for 30 days. After 10 days, 200 more soldiers join. If rate of food consumption is same for every soldier, how long will the food supply last after these 200 soldiers joined? A - 15 Unable to apply the concepts learnt here, can u help out!
You can do it like:- Total amount of food for 30 days= 600×30=18000 portions In 10 days 600 soldiers will eat = 600×10= 6000 portions So we left with 18000-6000 =12000 portions After that 200 new soldiers joined so total soldiers will be 800 Therefore, Number of days it will last = 12000/800 I.e. 15 days Hope this helps 🙂
PHILIPPP!!!!!!! THANK YOU SOOOOO MUCHHHHH!!!! i GAVE MY GRE SECOND TIME JUST BY WATCHING YOUR VIDEOS !!! I WENT FROM 297 TO STRAIGHT 313!!THANK YOU !
Nice! Great work MM, you deserve it
@@TheTestedTutor YOU PARTIALLY MADE MY CAREER!
@@MickeyMouse-fy7dv You did it MM! But thank you.
I like your videos a lot, and I will pass them on to my nephew who will be taking the GRE in the next two years.
Thank you SO much, Phillip ! You're truly a godsend. Really appreciate how you explain everything in detail. It's very kind of you to avail all this high quality material to us for free :D
You're welcome Nameera
Phillip! You have been a pillar of knowledge these past few days. I'm grateful for all the help you provided.
Hey Philip! It's been around 2 weeks that I've started watching your videos for my GRE and THANK GOD I found your videos. Every single video has sooo much to learn from and your tricks are just amazing. Thankyou so so much for being an angel :)
Wow thanks Tvisha!
How much did manage to score then?
Following your previous methods thoroughly, I could answer all the questions easily and quickly, even though I’ve been away from math for around six years. You’re a fantastic teacher, Philip! Hats off to you!
Your videos are the best for last minute preparations.
Thanks a lot 😊
This is amazing! After watching the previous Rates video, I was able to do all the problems in this video by myself! And I'm particularly scared of this topic!
That's great to hear Shweta!
Yes, me too Shweta, When I watched this exercises goosebumps inmediately, But I know, this is a process, thanks for amazing videos Phillip. Greetings from Peru
Great content! Phillip. For these questions, I do always follow this trick and may be you can share this trick with others as well, in case you haven't already. Trick is to always assume work as multiple of time figures in the question. Let's say for the last questions instead of choosing 1 widget work as 1.. take a multiple like 6. This ensures your rate to never be in fractions and enables you to add rates easily.
I’ve been watching your videos for days now and I wish I had found your channel earlier! Thank you so much for the great content
Haha glad to hear it
I was waiting ages for this video ... I wasn't getting Work Rates questions right in my practice tests, u gave me hope and ways to solve them ...❤️❤️
Best technique ever! Thank you so much.
This is so helpful Phillip. and yes I see your favorite word there...nuances...Many thanks
yes well spotted!
I cant thank you enough for your brilliant tricks and videos
OMG! Your techniques are just amazing. Thanks a lot for creating these videos, super helpful!
your vidios explain tricky questions in a very simple way , love it !
That was just GENIUSSS!! Philip.
Hi Buddy,
I love the way you explain things,
Gained a lot of wisdom in these couple of weeks.
Just wanted to add a standard format as it helped me understand the problem much better.
Prepare a table for all WAT related problems and Use the formula : T*A = W for calculating Average
Time Average Work
4 1/8 1/2
16 1/4 4
? 3/8 5
Explanation for the values below.
As he mentioned we can add averages and not time.
1/8+1/4 = 3/8
Therefore, T = 5*8/3 = 40/3
Brilliant. So much easier to follow than the approach I had been using. Thank you, Philip!
Am truly thankful for the insights gained in your teaching of mathematics questions. Thank you so much.
You are very welcome Callistus
Thank you so much for these videos Philip, can’t thank you enough for them. I have my test on the 10th of this month and your videos have been incredibly helpful.
Yay! Good luck Swathi!
@@TheTestedTutor I managed to score only 312😔 was expecting 320.
@@swathiii_ How much did you score in Quants?
@@misahasunke5914 162
Great Method, Thanks Philip.
I just started watching your videos they r amazing. Kindly help me where can find hardest problems on almost every topic. Preferably, free material for practice.
There is a short-cut with the final question:
1st: Work out both rates: (1) R1 = 1/6 (2) R2 = 1/4
2nd: The difference between these two rates (i.e. Joel's double speed!) is (1/4 - 1/6 = 1/12)
3rd: Work out Joel's rate: 1/12 x 2 = 1/6
4th: His time is simply the reciprocal = 6 = Answer
Thanks Philip !
phillip your videos are amazing ..... keep up the good work
Thanks shanmukh!
Your content is amazing, Keep up the good work brother!
Hi Philip, Great video! AND Great Composure.
Thanks for listening
Thank you so much, Philip!
Hey Philip! On the last one I didn't quite use your method, but I'm curious to know if you think it's valid
It made sense to me to set it up like
J + V = 1/3
2J + V = 1/2
rearrange, then subtract
2J + V = 3/6
J + V = 2/6
-------------------
J = 1/6
J = 6/1 (individual time)
excellent and thanks
Thank you Philip!
@The Tested Tutor
Hi Philip! The question is asking for hours that Joel takes "currently" to finish the work on his own. His speed is doubled means it will now take 6/2 hours= 3hours to finish the work individually.????????
Thank u!!!.🎉
Thank u nice explanation a man with zero haters plz answer by doubt in one of my comment.
Hey Phillip, could you please make a video on those filling the pool/draining the pool problems?
Please do a video on Coordinate geometry with a graph given and we have to get the equation out of the graph ....finding it very difficult to solve them in the 5lb book
Killing it bro 🙌🏼💯
I am really enjoying your tips and tricks. Thank You.
I have a question regarding the final exercise in this video. I wrote the first equation as x+y = 1\2 and the second one as 2x+y = 1\3 and found the same result. Is it okay that way?
Great video! Thanks for uploading it! Do you have a video about factorizing polinomials? I have seen your video of prime factorizing and it really helped me! Thanks for your work
Yes but only one, called best quant formula
Good job done!!
You are master the blaster!
Great job!
Brilliant!!
Thank you👍😀
Hi Philip, thank you for all of your videos. For the last question I set up my equation as (1/3) -J = (1/2) - 2J basically doing the combined rates minus Joel's rate. I got the same answer. Is this a correct way of doing it or did I just get lucky?
yes
For the third question I solved a simultaneous equation with Rj and Rv. I sometimes get confused with 1/j and 1/v. I have my GRE in 2 weeks, I hope it goes well :)
Never knew the hero of Scotland could do simultaneous equations!
First Comment 😁
Eagerly waiting for your next video😊
Yay! Did you see your name? :)
@@TheTestedTutor
Yeap sir i saw my name in 1st math
Thank You Sir❤️
Hey Philip , do you have a video on mixtures problems, if not, it would help a lot, if you could do one
Did you see my recent one?
Hey! Thanks for your videos! Can you clarify this for me:
I have been using the formula " Output = (No. of workers) (Sum of each worker's Individual rate) (No. of hours) " , but not sure why this doesn't seem to work in your problems..
For example, in the first example of Ana and Samaiyaara, I wrote down the formula as:
Output = (No. of workers) (Sum of each worker's Individual rate) (No. of mins)
1/2 task= (1 worker) (Ana's Individual Rate) (4mins)
4 tasks= (1 worker) (Samaiyara's Individual Rate) (16mins)
which implies, Ana's Individual rate = 1/8 and Sumaiyaara Individual rate = 1/4
Working together, their combined rate is 3/8, so now the formula becomes
5 tasks = (2 workers) (3/8) (No. of minutes)
Solving for time, I am getting 20/3mins unlike 40/3.
Can you point me out where I am going wrong?
Thanks!
I don't know where that formula comes from, seems wrong to me. Why would 3 workers with a combined rate of 3/8 be any different to 2 workers with a combined rate of 3/8? We have already combined them. Maybe that formula works if you do average instead of sum. My method is totally different as you can see.
@The Tested Tutor For the last question why the rate doesn't become 1/3 because, the question mentioned doubling the rate right??
Hey Philip! It's a great video. Thanks once again for such wonderful video. I have been told by someone that's in December set the GRE questions are always difficult than other time. Is it true? I am thinking about giving test by the end of this month. Please tell me. I will schedule my test accordingly. As I am looking for fall 2021 intake.
That cannot be true or GRE/ETS would be sued for discrimination. The test is equal at all times. Glad you liked the vid!
@@TheTestedTutor thank you so much... I am going to give my test in this month. Your videos helped me so much in preparation.
Hi Philip. Hope you are having a good day. 🙏For gre, is it sufficient to learn Magoosh 1000 words and 333 barrons high frequency words??? Or do we need to learn any other words ?
And also I have my gre exam scheduled on day after tomorrow. Any last minute suggestions from your side ?
The more the better. If you did those two, plus my vocal videos, I would say you are mostly prepared vocabwise
can you pls do advanced arithmetic means problems?
Such as?
or we can take the lcm of 3 numbers and then divide each number by lcm to get each fraction of work piece , thanks :)
For Indians, maths is not that challenging. However, could you please give me some advice about how to deal with vocab section.
How do you solve the working the against each other things like filling the tank?
You subtract the work rates. Otherwise just the same
Sir,
Please make video on multiple workers problem( Ex. 20 workers pack 20 boxes at constant rate in T time how much time will 30 workers will take to pack 100 boxes)
Re the problem with Joel and Vivek -- I used your rule about combined rates being a sum and, rather than resorting to algebra, I subtracted the old rate from the new rate: 1/2 - 1/3 = 1/6. Is this acceptable?
yes
Q- in a garrison there are 600 soldiers and food supply they have is sufficient for 30 days. After 10 days, 200 more soldiers join. If rate of food consumption is same for every soldier, how long will the food supply last after these 200 soldiers joined?
A - 15
Unable to apply the concepts learnt here, can u help out!
You can do it like:-
Total amount of food for 30 days= 600×30=18000 portions
In 10 days 600 soldiers will eat = 600×10= 6000 portions
So we left with 18000-6000 =12000 portions
After that 200 new soldiers joined so total soldiers will be 800
Therefore, Number of days it will last = 12000/800
I.e. 15 days
Hope this helps 🙂
I found these easy tho😊
Nice
Do you think that advanced work rate questions are a common occurrence on the GRE quant?
Only at the highest level
👌👌👍👍
why not this 1/2+1/3= 1/6 (RATE) , THEN FLIP IT 6 hours
This kind of question is the most annoying one
Hopefully not as much now Khoai