This video was IMMENSELY helpful. Every time I have a mixture question I get it right after watching this! THANK YOU for breaking this down in an engaging and helpful manner.
I always found mixtures to be miserable and I cannot solve those questions until now. You have explained all types of questions so coherently that I can solve any of these now easily. Thanks for saving me!
This is one of your best videos. You do a great job explaining and the repetition is great for me. This video has been an amazing confident booster as I get ready for the GMAT
Philip your videos are really great. I watched majority of them. I had my exam a while ago. Got my unofficial scores Quants 159 Verbal 153. Keep posting. Thankyou.
Your tricks and tips are so useful! I was super bad at Quant and your videos made me so much better! I had my exam yesterday and I scored 317 (156V, 161Q) and hopefully these scores are good enough for the universities I'm applying to. BIG Thank You, Philip! 😀 Couldn't have done it without you.
Those tough questions where you are reversing the mixture-trick - Instead you could just calculate the litres of orange juice/water (depending on the question) and finally dividing by total fluid volume. It just made it a little easier. Other than that thank you for helping me iron out mistakes and completing my mixture syllabus... 1yr late - but your content is bomb!
Woah, so helpful!! I am preparing for my GMAT and I really struggle with Quant. This video literally helped me with my basics for Mixture Problems. Thank you so so so so much!!
Thank you so much sir! This video was really helpful. You are a legend and your explanation is fabulous. This channel is so underrated and I really wonder how come you have so less subscribers? Keep growing and may god bless you!
I love this method -- so easy to remember, graphically. The inversion reason I don't fully get, but I will mull over the distance being inversely proportional to the weighted average
I have my GRE in less than 36 hours and I just forgot that this topic is in GRE syllabus, although I gave 18 mock tests, I never came across a mixture question. But you never know, what might come in the real test, so this method just saved my time and now I feel very confident
Thank you so much, Allegation and mixtures topic was a great problem for me. But this video solved it like a magic. Concepts were explained easily and simple to understand. Questions were awesome. once again thank you for the video!!
Hey Philip, thank you SO MUCH for all of your incredible videos! Could you PLEASE do that last cistern question where the 5 litres of water is removed and replaced by 5 litres of wine, and then 5 litres of the resulting mixture are removed and 5 more litres of wine are added. What is the ammount of waterin the resulting mixture?
thanks for the video i used it for the questions, i found the formula C1V1+C2V2=C3V3 and V1+V2=V3 easier. when the applications of these formulas didnt appear straightforward, i do a diagram to get my equations. I was able to solve all the ones you posted with little trouble. thanks again
@TheTestedTutor Hi, thank you so much this video really helped me understand mixture problems! I have a follow-up question about the last question around 26:35. How did you know to use the 20 litres on the 10% side of the mixture? I thought is was the total litres for the mixture not a ratio.
17:52 Here is my logic, 7 liters contains 40% water - - > (7)(0.40) = x 18 liters contains 20% water - - > (18)(0.20) = y Now, the mixture will contain - - > x + y = 2.8 + 3.6 = 6.4 liters of water We have to answer in percentage, so the total water in both solutions = 25 hence, 6.4 / 25 * 100 = 25.6
Thank you so much for the name. I searched it and learnt it in my native language first and then solve these math problems from this video. So it became easier to understand
Can you make more videos on "mixture" and "Words to Algebra" Questions please. How many of these questions appear on the GRE ??? If possible please do other types of "words to algebra" question which maybe has a pattern. That would be so helpful.
You did a magoosh test where alcohol and water were 4 Oz to 4 Oz. They wanted to add water to get to a 3/5 ratio. I tired to use this method, but got the wrong answer. I used 50% Water and 5/8 or 62.5% desired of water. Then added 100% water to 8oz.
Thank you! This was really helpful. I was trying the following exercise with your method but I am getting 9:1 water: CA , ( the correct answer is 7:1 ) any suggestions? The problem is : Chloric acid and phosphoric acid will be mixed to make a solution of 10% chloric acid and 20% phosphoric acid. How many liters of chloric acid should be added to a liter of distilled water to make the solution?
no, It is 19:81.... Here is the solution books.google.com.bd/books?id=76szEAAAQBAJ&pg=PA20&lpg=PA20&dq=a+cistern+contains+50+L+of+water.5L+of+water+is+taken+out+and+replaced+by+wine.The+process+is+repeated+again.Find+the+proportion+of+wine+and+water+in+the+mixture&source=bl&ots=_GY-TGVKhy&sig=ACfU3U1-chyG4-SOxfK6yvqoTWjEQWPfiw&hl=en&sa=X&ved=2ahUKEwi4xvGBjbD6AhWwFbcAHQYjCAEQ6AF6BAgIEAM#v=onepage&q=a%20cistern%20contains%2050%20L%20of%20water.5L%20of%20water%20is%20taken%20out%20and%20replaced%20by%20wine.The%20process%20is%20repeated%20again.Find%20the%20proportion%20of%20wine%20and%20water%20in%20the%20mixture&f=false
I'm confused on how the 3:2 ratio got us the answer for how much water should be added to produce the 10% saline. Can you further explain? Thank you so much for your videos. I find your tips so helpful.
I can explain it to you. First of all, you are given that he found 20 ounce bottle of 25 percent saline solution. What does this mean in plain terms? Well, you have a mixture that is 25 percent of the volume saline and 75 percent of the volume water. So if you have 20 ounces of total liquid volume, then 25 % of 20 ounces is 5 ounces of saline, and therefore 15 ounces of water in that total 20 ounces of the entire liquid. So, write this down: 5 ounces of saline and 15 ounces of water. Hope it makes sense so far. Now we need to add some water to this same mixture of 5 ounces and 15 ounces of saline to water respectively, so that the total volume of saline is 10 % of the new combined volume of the entire liquid. Let’s call this new total X. Now what number X should you multiply by 0.1 to get 5 ounces of saline? Well it is 5 / 0.1 which is 50. Think about this, if the total amount of all liquid is 50 ounces, and we know that 5 ounces of this liquid consists of saline, then this represents 10 percent of the total amount. Now in the original mixture we had 15 ounces of water. Since we calculated that the new mixture contains the same 5 ounces of saline, then for the total volume to be 50 ounces, it must be the case that 45 ounces should be water. And here is the final piece of the puzzle: before we had 15 ounces of water, now we must have 45 ounces, so how many ounces of water should you add to 15 ounces already contained in the original mixture to get 45 ounces of water? Well it is 45 -15 =30. I hope that this explained the problem. Let me know if you find this explanation useful. (One advise is the following: when you solve these mixture problems draw them on a piece of paper as a big rectangle, then divide this rectangle with a horizontal line and label the volumes of different types of liquids with numbers that you are given. For this problem, you could draw a rectangle, then draw a horizontal line that splits this rectangle at 1/3 and 2/3 parts, and label 5 ounces the smaller part of the rectangle with saline, and then label 2/3 parts of this rectangle as water and give it 15 ounces. This way you always separate different compounds from each other and you will see everything very cleanly)
For the vinegar and oil one, the 7.2 is the final ounces of oil to make it 25% right? But what about the oil that was already there in the mixture? The question is asking how much we'd need to add...
Hey, just had a doubt in these two questions. Can you help solve it with your method If a portion of a half water/half alcohol mix is replaced with 25% alcohol solution, resulting in a 30% alcohol solution, what percentage of the original alcohol was replaced? A 5-liter jug contains 4 liters of a saltwater solution that is 15 percent salt. If 1.5 liters of the solution spills out of the jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?
I just have to stop and say, wow, you are giving all these for free? You're truly a blessing for all of us!
Such a life saver! Always had a problem with mixture questions but this helped a lot.Thank you
You're very welcome!
exactly the case with me.
This video was IMMENSELY helpful. Every time I have a mixture question I get it right after watching this! THANK YOU for breaking this down in an engaging and helpful manner.
I always found mixtures to be miserable and I cannot solve those questions until now.
You have explained all types of questions so coherently that I can solve any of these now easily. Thanks for saving me!
This is one of your best videos. You do a great job explaining and the repetition is great for me. This video has been an amazing confident booster as I get ready for the GMAT
Thanks Alex! :)
I got these questions wrong on my mock GRE test!!! YOU ARE A SAVIOUR!!!
Answer for the last question is 19:81. (wine : water).
Thanks Philip for the wonderful method. God bless you!
Thanks man, I'm glad to know I got correct answer to that.
Philip your videos are really great. I watched majority of them. I had my exam a while ago. Got my unofficial scores Quants 159 Verbal 153. Keep posting. Thankyou.
Great job wij!
How long did you study for quant?
Your tricks and tips are so useful! I was super bad at Quant and your videos made me so much better! I had my exam yesterday and I scored 317 (156V, 161Q) and hopefully these scores are good enough for the universities I'm applying to.
BIG Thank You, Philip! 😀 Couldn't have done it without you.
Hey Kritika, can you share study material for verbal?
@@AkhilKumar-cw1mehow much did u score
Never thought mixtures would be this easy. Philip you are a genius ❤️❤️
Those tough questions where you are reversing the mixture-trick - Instead you could just calculate the litres of orange juice/water (depending on the question) and finally dividing by total fluid volume. It just made it a little easier.
Other than that thank you for helping me iron out mistakes and completing my mixture syllabus... 1yr late - but your content is bomb!
Best tutor for FREE!! I mean what more can one ask 💗
I have my exam in 2 days, and these mixtures have baffled me, thank you so much Philip
Woah, so helpful!!
I am preparing for my GMAT and I really struggle with Quant. This video literally helped me with my basics for Mixture Problems. Thank you so so so so much!!
"The Achilles' Heel" . Thanks Philip for this emPOWERING method
mixtures was my weakness, and now my confidence is boosted! Thanks man. :)
Thanks a bunch, Philip! Your method and numerous examples gave me a much better understanding of mixtures.
This was so useful, I never understood the "why" part of allegations and mixtures and this video really helped.
You have been saving lives. Kudos to you sir
Thank you so much sir! This video was really helpful. You are a legend and your explanation is fabulous. This channel is so underrated and I really wonder how come you have so less subscribers? Keep growing and may god bless you!
You don't have it better than this! Thanks, Philip
You are really a great teacher , Sir. salute
I love this method -- so easy to remember, graphically. The inversion reason I don't fully get, but I will mull over the distance being inversely proportional to the weighted average
Thank you Philip for this gem of a video. Indebted.
I have my GRE in less than 36 hours and I just forgot that this topic is in GRE syllabus, although I gave 18 mock tests, I never came across a mixture question. But you never know, what might come in the real test, so this method just saved my time and now I feel very confident
Thank you so much, Allegation and mixtures topic was a great problem for me. But this video solved it like a magic. Concepts were explained easily and simple to understand. Questions were awesome. once again thank you for the video!!
Bro this is gold! 💯💯💯
Thank you!
Thanks so much for the comment Aadesh! You the man.
Was really struggling on mixture questions but now they seem like a piece of cake. Thankyou so so much Philip❤❤❤
Hey Philip, thank you SO MUCH for all of your incredible videos! Could you PLEASE do that last cistern question where the 5 litres of water is removed and replaced by 5 litres of wine, and then 5 litres of the resulting mixture are removed and 5 more litres of wine are added. What is the ammount of waterin the resulting mixture?
Thanks Philips. I improved my quants score because of you
thanks for the video i used it for the questions, i found the formula C1V1+C2V2=C3V3 and V1+V2=V3 easier. when the applications of these formulas didnt appear straightforward, i do a diagram to get my equations. I was able to solve all the ones you posted with little trouble.
thanks again
Thank you so much! I was looking for this exact method, and found your video. It was very helpful!
Thank you so much. Your content is really helpful, especially, for students whose mother tongues are not English.
@TheTestedTutor Hi, thank you so much this video really helped me understand mixture problems! I have a follow-up question about the last question around 26:35. How did you know to use the 20 litres on the 10% side of the mixture? I thought is was the total litres for the mixture not a ratio.
thanks a lot for this video. This helped me overcome my fear of mixtures!
Thank you so much for making difficult topics easier!! Can you please make a video on successive replacements in Mixture and Alligation?
hi, I m from India I know its late to comment as this Vedio was posted last year, but it helped me a lot for my Gmat exam revision
You have escaped the MATRIX
Beautiful Walkthrough. Thank you. I found this really helpful
Amazing technique.
Thankyou so much Sir !! Have my exam on 15th Oct 10am , wish me luck
Your method is just amazing. Thank you sir!!😄
Wow ..the method is really amazing and effective 🔥🔥Thanks Philip keep up the good work 👍👍
Very nice practise set of mixture problems!
Thanks, sir. I need this kind of video for solving my problem which was I faced in the maximum mixture problem.
Happy to help MD
you are such a life saver!
This is simply brilliant!
Thank you so much for this!!! Was struggling all weekend.
17:52
Here is my logic,
7 liters contains 40% water - - > (7)(0.40) = x
18 liters contains 20% water - - > (18)(0.20) = y
Now, the mixture will contain - - > x + y = 2.8 + 3.6 = 6.4 liters of water
We have to answer in percentage, so the total water in both solutions = 25
hence, 6.4 / 25 * 100 = 25.6
Amazing. Thank you Philip.
Mixtures made very simple. Thanks for the help.
Please do a video on data interpretation, pie chart, bar chart and line graph.
LIFESAVER!!! Really well explained!
Absolutely great video and explanation
I really like your explanations...
This video is absolutely amazing. Thank you a lot
This method is called as alligation.
Thank you so much for the name. I searched it and learnt it in my native language first and then solve these math problems from this video. So it became easier to understand
thanks for the amazing explanation. Life made much simpler.
You are a savior !!
best video by best teacher
Watching this 1 day before my gre. :)
Hope it went well
thank god i found your video, wonderfull examples and explanation thanks a lot🤓
Very helpful method. thanks a lot!
such an good video - mixture question always scared me but this was extremely helpful :)
Can you make more videos on "mixture" and "Words to Algebra" Questions please. How many of these questions appear on the GRE ??? If possible please do other types of "words to algebra" question which maybe has a pattern. That would be so helpful.
such a great trick, thank you for this!!
thank you so much!!!! youre the GOAT!
Thank you! great video keep it up
You did a magoosh test where alcohol and water were 4 Oz to 4 Oz. They wanted to add water to get to a 3/5 ratio. I tired to use this method, but got the wrong answer. I used 50% Water and 5/8 or 62.5% desired of water. Then added 100% water to 8oz.
Omg you are a saviour!
Thanks Shriya! :)
Thanks a lot !! super helpful
Very insightful
BEST VIDEO EVER ❤️
awesome technique . i went through magoosh question they used simultaneous equations to solve this. but your method cuts the time in half
Thank you so much! You made it simple as water.
I like the one I learned in chemistry C1*v1=C2*v2
Thanks for your trick. It cuts the time in half at least ❤
Thank you! This was really helpful. I was trying the following exercise with your method but I am getting 9:1 water: CA , ( the correct answer is 7:1 ) any suggestions? The problem is : Chloric acid and phosphoric acid will be mixed to make a solution of 10% chloric acid and 20% phosphoric acid. How many liters of chloric acid should be added to a liter of distilled water to make the solution?
excellent and thanks
Thank you so much! for this!!!!
You are great!
Loved it, thanks!
Hello Philip! Thank you so much for this video! How would you actually solve the very last question? (the question on Cistern)?
Thank you Philip. It's wonderful.
Can you please tell whether the last question's answer was 1:4?
no, It is 19:81.... Here is the solution books.google.com.bd/books?id=76szEAAAQBAJ&pg=PA20&lpg=PA20&dq=a+cistern+contains+50+L+of+water.5L+of+water+is+taken+out+and+replaced+by+wine.The+process+is+repeated+again.Find+the+proportion+of+wine+and+water+in+the+mixture&source=bl&ots=_GY-TGVKhy&sig=ACfU3U1-chyG4-SOxfK6yvqoTWjEQWPfiw&hl=en&sa=X&ved=2ahUKEwi4xvGBjbD6AhWwFbcAHQYjCAEQ6AF6BAgIEAM#v=onepage&q=a%20cistern%20contains%2050%20L%20of%20water.5L%20of%20water%20is%20taken%20out%20and%20replaced%20by%20wine.The%20process%20is%20repeated%20again.Find%20the%20proportion%20of%20wine%20and%20water%20in%20the%20mixture&f=false
For the first question, simply come up with the equations 0.2X+0.45Y=0.35 and X+Y=1, then solve for X.
Wow,thank you
I'm confused on how the 3:2 ratio got us the answer for how much water should be added to produce the 10% saline. Can you further explain? Thank you so much for your videos. I find your tips so helpful.
I can explain it to you. First of all, you are given that he found 20 ounce bottle of 25 percent saline solution. What does this mean in plain terms? Well, you have a mixture that is 25 percent of the volume saline and 75 percent of the volume water. So if you have 20 ounces of total liquid volume, then 25 % of 20 ounces is 5 ounces of saline, and therefore 15 ounces of water in that total 20 ounces of the entire liquid. So, write this down: 5 ounces of saline and 15 ounces of water. Hope it makes sense so far. Now we need to add some water to this same mixture of 5 ounces and 15 ounces of saline to water respectively, so that the total volume of saline is 10 % of the new combined volume of the entire liquid. Let’s call this new total X. Now what number X should you multiply by 0.1 to get 5 ounces of saline? Well it is 5 / 0.1 which is 50. Think about this, if the total amount of all liquid is 50 ounces, and we know that 5 ounces of this liquid consists of saline, then this represents 10 percent of the total amount. Now in the original mixture we had 15 ounces of water. Since we calculated that the new mixture contains the same 5 ounces of saline, then for the total volume to be 50 ounces, it must be the case that 45 ounces should be water. And here is the final piece of the puzzle: before we had 15 ounces of water, now we must have 45 ounces, so how many ounces of water should you add to 15 ounces already contained in the original mixture to get 45 ounces of water? Well it is 45 -15 =30. I hope that this explained the problem. Let me know if you find this explanation useful. (One advise is the following: when you solve these mixture problems draw them on a piece of paper as a big rectangle, then divide this rectangle with a horizontal line and label the volumes of different types of liquids with numbers that you are given. For this problem, you could draw a rectangle, then draw a horizontal line that splits this rectangle at 1/3 and 2/3 parts, and label 5 ounces the smaller part of the rectangle with saline, and then label 2/3 parts of this rectangle as water and give it 15 ounces. This way you always separate different compounds from each other and you will see everything very cleanly)
Thank you so much!!
we can also solve the ones for which middle number is not given by using weighted average formula right?
As in thr examples at the end yep
can you please explain the concepts hidden behind this short cut method.
Thank you phillip
What about the percent of soap from Detergent A in the final mixture? Sorry for anything I might have missed
For the vinegar and oil one, the 7.2 is the final ounces of oil to make it 25% right? But what about the oil that was already there in the mixture? The question is asking how much we'd need to add...
Thank you very much 😊
Excellent
Hey, just had a doubt in these two questions. Can you help solve it with your method
If a portion of a half water/half alcohol mix is replaced with 25% alcohol solution, resulting in a 30% alcohol solution, what percentage of the original alcohol was replaced?
A 5-liter jug contains 4 liters of a saltwater solution that is 15 percent salt. If 1.5 liters of the solution spills out of the jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?
Awesome!!!!!
Thankyou Sir.
ans for the last question water 40.5,wine 9.5 L
Please explain the math
How to choose the percent for pure oil or pure water or pure alcohol? Is it based on the question or is it like chosen values?
Can you please explain?
Please solve the last one