I have created a course, structural design of buildings using Etabs software which includes structural analysis and design of a five-sorey RCC building(Real project) and is now available on udemy. Kindly use the below link to avail the full course. www.udemy.com/course/structural-design-of-buildings-using-etabs-software/?referralCode=14883FDBBD95A1ADAC02
I think there could be a better logic for load per unit length that: so to obtain the load per unit length, you need to consider the distribution of the load along the length of the material. The load per unit length is essentially the force or load applied to the material per unit distance along its length. To Determine the load per unit area on the slab. This value is typically provided by design codes or specifications. Measure the width of the slab, which is the dimension perpendicular to the load or force being applied. Multiply the load per unit area by the width of the slab to obtain the load per unit length. Mathematically, the relationship can be expressed as: Load per Unit Length = (Load per Unit Area) x (Width)
Thanks for your reply. I got through with the calculation. Do you have a video on how you calculate the amount of Reinforcement required for a beam and column knowing the load that the beam and column will be carrying?
@@CivilEngineeringMastery Thank you for your latest reply to me. Can you tell me what safe live load per square foot you would recommend when designing a concrete wharf for commercial use?
The beam load is different and the load on the slab is different (B1-5.64 kN/m, B2- 4.416 kN/m). The load on the slab is 6.625 kN/m2 on both the one-way and two-way slabs. When load is applied on the slab it tends to bend in a shorter direction, so the main reinforcement is provided in the shorter direction to resist the bending.
Could you please explain a little more how you arrived at the answer for the weight of the Trapezoidal load distribution on beam B1 in your video, as when I use the figures you used, I do not get the answer you have for the load on B1. Thanks in advance, and looking forward to an early reply.
To calculate the trapezoidal load the formula is wlx/2(1-1/3k^2), where w is the total load on a slab, lx is the shorter span distance and k is the ratio between ly & lx. Please apply all the values in the given formula you will get the answer 5.64 kN/m on B1. Hope this clears your query.
How to take crank length and continues one ways and two way slab how much extra length rod provided in Continues slab joining for resisting negative bending moment ..
Thanks for the explanation. Please give me reference in IS Code and BS 8110 Code (if you do have it) for trapezoidal load from Slab to UDL Load on Beam. Also I wanted to know more about k (the aspect ratio). Clearly the standard is Ly/Lx to determine whether the slab is one-way or two-way. However, in some formula regarding trapezoidal load covnersion I see Lx/Ly in some I see Ly/Lx also load itelf is sometimes represented by n, w and the UDL sometimes represented by Wu or P. Your thoughts on this will be much appreciated. My formula is (n.lx)/6 x (3 - k^2) where k is Lx/Ly.
The aspect ratio is Ly/Lx to determine whether the slab is one-way or two-way. The load can be represented by P or W(unfactored), whereas Pu & Wu represents the factored load.
@@CivilEngineeringMastery Thank you. I did not know you answered my question. I got it that you are talking about triangular, rectangular and trapezoidal load distribution and not their equivalent UDL. Apparently you can get moments directly from those load distribution and no need to conversion to UDL which seemingly makes thing easier. Please correct me if I am wrong. I also gott the source for the conversion. It is in Reynold. Again, thank you very much.
Very nice and clear explain.excellent 👍👍👍
Good. Loved it
Well done Engr. I am new to your channel but I found it very useful. Keep it up.
Awesome, thank you!
I have created a course, structural design of buildings using Etabs software which includes structural analysis and design of a five-sorey RCC building(Real project) and is now available on udemy.
Kindly use the below link to avail the full course.
www.udemy.com/course/structural-design-of-buildings-using-etabs-software/?referralCode=14883FDBBD95A1ADAC02
thanks teacher ❤
Good explanation
You r always good ...
Superbly explained
Thank you 🙂
Very good explanation.
Glad it was helpful!
Very good
Thank you mam
Thank you very much mam
Ma'am, how to calculate load distribution when sides are all equal
Ly and lx are from centre of support to centre of support or these are from edge to edge of slab
thankyou very important
You're welcome!
Ma'am from where we got that formula for Distributing the load on Trapezoidal portion
I think there could be a better logic for load per unit length that:
so to obtain the load per unit length, you need to consider the distribution of the load along the length of the material. The load per unit length is essentially the force or load applied to the material per unit distance along its length.
To Determine the load per unit area on the slab. This value is typically provided by design codes or specifications.
Measure the width of the slab, which is the dimension perpendicular to the load or force being applied.
Multiply the load per unit area by the width of the slab to obtain the load per unit length.
Mathematically, the relationship can be expressed as:
Load per Unit Length = (Load per Unit Area) x (Width)
Thanks for your reply. I got through with the calculation.
Do you have a video on how you calculate the amount of Reinforcement required for a beam and column knowing the load that the beam and column will be carrying?
Please refer to the below link
ua-cam.com/video/NV5k1RjrPiM/v-deo.html
ua-cam.com/video/CdPXPj9KWFk/v-deo.html
ua-cam.com/video/qQTCzaM9VF8/v-deo.html
@@CivilEngineeringMastery Thank you for your latest reply to me. Can you tell me what safe live load per square foot you would recommend when designing a concrete wharf for commercial use?
Please refer to the code IS-875 Part-2 for live loads depending on the building type. There is no standard safe live load for commercial use.
Load on shorter direction is less than that of longer beam but why do we provide main bars in shorter direction rather than longer one?
The beam load is different and the load on the slab is different (B1-5.64 kN/m, B2- 4.416 kN/m).
The load on the slab is 6.625 kN/m2 on both the one-way and two-way slabs. When load is applied on the slab it tends to bend in a shorter direction, so the main reinforcement is provided in the shorter direction to resist the bending.
Could you please explain a little more how you arrived at the answer for the weight of the Trapezoidal load distribution on beam B1 in your video, as when I use the figures you used, I do not get the answer you have for the load on B1. Thanks in advance, and looking forward to an early reply.
To calculate the trapezoidal load the formula is wlx/2(1-1/3k^2), where w is the total load on a slab, lx is the shorter span distance and k is the ratio between ly & lx. Please apply all the values in the given formula you will get the answer 5.64 kN/m on B1. Hope this clears your query.
What if ly by lx is equal to 1? Use two way slab calculation?
if beam is 7 mtr long how we calculate load on beam
please detail explain
Well
How to take crank length and continues one ways and two way slab how much extra length rod provided in Continues slab joining for resisting negative bending moment ..
one way slab load calculation =( tributary area *total area load) the tributary area taken lx*(ly/2)*(total area load)
Thanks for the explanation. Please give me reference in IS Code and BS 8110 Code (if you do have it) for trapezoidal load from Slab to UDL Load on Beam. Also I wanted to know more about k (the aspect ratio). Clearly the standard is Ly/Lx to determine whether the slab is one-way or two-way. However, in some formula regarding trapezoidal load covnersion I see Lx/Ly in some I see Ly/Lx also load itelf is sometimes represented by n, w and the UDL sometimes represented by Wu or P. Your thoughts on this will be much appreciated. My formula is (n.lx)/6 x (3 - k^2) where k is Lx/Ly.
The aspect ratio is Ly/Lx to determine whether the slab is one-way or two-way. The load can be represented by P or W(unfactored), whereas Pu & Wu represents the factored load.
@@CivilEngineeringMastery Thank you. I did not know you answered my question. I got it that you are talking about triangular, rectangular and trapezoidal load distribution and not their equivalent UDL. Apparently you can get moments directly from those load distribution and no need to conversion to UDL which seemingly makes thing easier. Please correct me if I am wrong. I also gott the source for the conversion. It is in Reynold. Again, thank you very much.
Madam, can this verified in ETABS?? Please show it in ETABS.