Sir I try to relate the energy with universal gravitational constant G Let derivation The same concept E inversely proportional to lambda × velocity Therefore E=k/lambda×velocity Dimension formula for k is K = ML⁴/T³ = (M^-1L³T^-3)(M²L/T) since(M¹= M^-1×M²) Therefore K=G×mass of the larger object ×mass of the smaller object which revolve around larger object×velocity of the smaller object Therefore E=GMmv/lambda×v Where M is represent the larger mass m is represent the smaller mass v is the velocity of smaller object Therefore E =GMm/lambda as canceling the v Now consider that the satellite revolve around earth then energy of the satellite is represented as E* Therefore E*=GMm*/(lambda)* Where M is represented as earth E* is represented as satellite m* is represented as satellite mass lambda* is represented as wave nature of satellite Now sub the value of lambda in this equation therefore Lambda*=h/p* In this condition the momentum of the satellite is not a linear it is angular momentum therefore Lambda*r/r =hr/(mvr)* as the linear momentum is converts to angular momentum so I multiply r/r in both sides therefore Lambda* = hr/L as L=mvr Sub it in this eq therefore E*=GMm*/hr/L* Therefore it gives E*=GMm*L*/hr Therefore in the above eq gives one such constant G/h (universal gravitational constant divided by Planck constant) therefore it consider as a new constant which represent as beta constant (ß) therefore it is expressed as ß=G/h.......therefore the eq form as E*=GMm*L*/hr E*=ßMm*L*/r........ This formula may be suitable for satellite, moon , earth ,and another such planets I supposed Sir please see my pervious comment that the vedio of Nobel price winners according to physics and that comment I try to relate the energy with power and also with momentum sir please reply for that comment and also reply to this comment I waiting for your reply
Hi sir I am a student in Tamil Nadu , I'm studying in higher secondary school. In my district a college announced to conduct a science competition. I choose this concept to explain but they told me to do a model . So can you please tell me how to do a model easily sir please .
ராசா ...வாய்பில்லை...இது போல் விளக்கம் சொல்ல ..வேறு யாராலும் முடியாதய்யா .. தொடரட்டும் உங்கள்பணி
Sir pls tell particle physics vs Theoretical physics
Bro , we are waiting your vlog post.. hope you are busy . But we r expecting …
எளிமையாக சொல்வது ஒரு கலை.அது உங்களுக்கு வாய்க்கப் பெற்றுள்ளது
Sir explain vectors calculus in physical form please
Sir are you busy? No videos yet
You are a good teacher sir thnx a lot
♥️♥️
Excellent
Thankyou prof
உலகில் அற்புதத்தை, வழங்கிய மனிதர்கள். நோபலுக்கு உரியவர்கள்.
Ryt bro
Interesting sir
Why you are not upload your science findings? Are you at india? Expecting your postings wish you all the best science with sam
அருமை! மிக மிக அருமை!!!
Super inspirational video 😊
Sir, quantum mechanics lecture-9 post pannunga
After a big interview science with sam postings seen
Ungal Oda video ellam super ha irukku bro 🎉🎉🎉
Ellamey easy ha puriyara mathiri soldringa bro
Thanks 🙏
Video adhigama podunga bro 🎉
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Great scientist ❤
God bless him and best wishes to our narrating bro🎉
Nice sir. Informative with motivation for youngsters. Please do similar scientific information with motivation videos.
Thank you very much for your kind words sir ♥️♥️
Sir I try to relate the energy with universal gravitational constant G
Let derivation
The same concept E inversely proportional to lambda × velocity
Therefore
E=k/lambda×velocity
Dimension formula for k is
K = ML⁴/T³
= (M^-1L³T^-3)(M²L/T) since(M¹= M^-1×M²)
Therefore K=G×mass of the larger object ×mass of the smaller object which revolve around larger object×velocity of the smaller object
Therefore
E=GMmv/lambda×v
Where M is represent the larger mass
m is represent the smaller mass
v is the velocity of smaller object
Therefore
E =GMm/lambda as canceling the v
Now consider that the satellite revolve around earth then energy of the satellite is represented as E*
Therefore E*=GMm*/(lambda)*
Where M is represented as earth
E* is represented as satellite
m* is represented as satellite mass
lambda* is represented as wave nature of satellite
Now sub the value of lambda in this equation therefore
Lambda*=h/p*
In this condition the momentum of the satellite is not a linear it is angular momentum therefore
Lambda*r/r =hr/(mvr)* as the linear momentum is converts to angular momentum so I multiply r/r in both sides therefore
Lambda* = hr/L as L=mvr
Sub it in this eq therefore
E*=GMm*/hr/L* Therefore it gives
E*=GMm*L*/hr
Therefore in the above eq gives one such constant G/h (universal gravitational constant divided by Planck constant) therefore it consider as a new constant which represent as beta constant (ß)
therefore it is expressed as
ß=G/h.......therefore the eq form as
E*=GMm*L*/hr
E*=ßMm*L*/r........
This formula may be suitable for satellite, moon , earth ,and another such planets
I supposed
Sir please see my pervious comment that the vedio of Nobel price winners according to physics and that comment I try to relate the energy with power and also with momentum sir please reply for that comment and also reply to this comment I waiting for your reply
Super bro
Super Sir.
How to create a CAS NO formula for all chemical names And what does a 3 digit number represent?
Hi anna, Prince Rupert's drop science sollunga anna.
You rock always ❤
Bro imaginary and complex numbers paathi solugha
Precious words sir 👍
Excellent job, Sam!
Thank you Professor ♥️
Thank bro
Thanks sir ❤
எத்தணை அருமை கணணே...நல்ல பதிவு கண்ணு மிக்க நன்றிங்க வாழ்த்துக்கள்❤❤❤
♥️
Hi sir I am a student in Tamil Nadu , I'm studying in higher secondary school. In my district a college announced to conduct a science competition. I choose this concept to explain but they told me to do a model . So can you please tell me how to do a model easily sir please .
Sir, i asking you after the long time, please explain the 4th and 5th diamention
I talked about space time
Good explanation Sam. Thanks. Keep it up.
Thank you Ananth ♥️🙏
Amazing story sam sir.❤
Wonderful explanation sir. Expecting more videos
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🎉
சார் நம் பிரபஞ்சத்தில் ஈர்ப்புவிசை என்பது கிடையாது நம் பிரபஞ்சம் முழுக்க மழுக்க உந்து விசையால் இயங்குகிறது...
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Sir distance la ug padichu pg direct ah college la padikalama sir
Don't know. Check in some colleges
Not audible
ua-cam.com/video/oSCX78-8-q0/v-deo.htmlsi=7euSk44_gg3xIn_N
Atom movie... pathuttu 10 yrs monnadi epdi archive pannangannu sollunga sir plss
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