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Hello, could you please explain how you would figure out Ka by solving using the first method you mentioned? im not getting the same value.
Kb = 10^(-4.87) = 1.35 x 10^-5Ka = Kw/Kb = 7.4 x 10^-10And 10^-9.13 = 7.4 x 10^-10
Can u do a problem where it's a base I'm confused
Thanks for this video. I have a question. How do I calculate the pH of different salt waters (KCl, NaCl, MgCl2, and CaCl2) at different pressure, temperature, and molality? I have need experimental data, or correlation or general formula.
This seems like a trick question... is this an assignment that you were given for a class? If so, I think your instructor is trying to be "tricky".
Nice cat!
Hello, could you please explain how you would figure out Ka by solving using the first method you mentioned? im not getting the same value.
Kb = 10^(-4.87) = 1.35 x 10^-5
Ka = Kw/Kb = 7.4 x 10^-10
And
10^-9.13 = 7.4 x 10^-10
Can u do a problem where it's a base I'm confused
Thanks for this video. I have a question. How do I calculate the pH of different salt waters (KCl, NaCl, MgCl2, and CaCl2) at different pressure, temperature, and molality? I have need experimental data, or correlation or general formula.
This seems like a trick question... is this an assignment that you were given for a class? If so, I think your instructor is trying to be "tricky".
Nice cat!