Thank you for everything, i’ve an exam in 2 hours and it’s not just that i was struggling with critical values that you’ve helped with. But the calming and soothing way of teaching is what made me at ease. Again thank you so much of this :)
Sorry, I have a question about the Z test. Why did you find the critical value depends on the standard deviation of 0.025 instead of 0.05? Is it about one tailed test and two tailed test? Thank you!
When the Alternate Hypothesis is "not equal to" the population mean, then we use a two tailed distribution. In a z or t test for a two tailed distribution, we find the z score or a t score for "alpha/2" because the critical value lies on each side of the mean. So if the Confidence Level is 0.95, then the Level of Significance is 0.05. Then alpha/2 = 0.05/2 = 0.025. If the Alternate Hypothesis is a "less then" population mean kinda scenario, we use a left tailed distribution. Then the level of significance is not divided by 2. So it just remains alpha. And we calculate the z and t test for alpha. Hope this helps...
Thank you for your question. I think what you're asking is why do we use the degrees of freedom when calculating the critical value and not the t-value. The reason we use degrees of freedom to find the critical value is because the t-distribution's shape changes depending on how large the sample size is. As the sample size increases (degrees of freedom increases), the certainty of the estimate increases which leads to less spread in the distribution.
Hi! thank you for the very clear explanation. One question though, in the t-test we took 'Null Hypothesis as price = 2.45', can we also take it as 'price
It depends on your confidence level. In some question the confidence level was 95 % which is 0.95 in decimals. 1 minus 0.95 is 0.05 , in a one tail test. If it’s a two tailed test it’s 0.05 divide by 2 which means it’s 0.025 on each tail. In another case 99% is 0.99 in decimals. Hence 1 minus 0.99 is 0.01 in a one tail test and 0.005 in a two tail test because 0.01 divided by 2 is 0.005. Hope this helps
I have a question for the second problem, shouldn't we be using the value corresponding to df=24 and CI=99%? Why did you use the CI value within the 98% CI?
Bear in mind that this is a one-tail test, therefore our significance level is calculated from doing 1 - CL of 99% = 0.01. If it were a two-tail test we would find 0.005 (0.01/2). Hence, we use the degrees of freedom found (24) and our signif level of 0.01 to find a critical value of 2.49.
8:28 we cannot reject the hypothesis that the value is 75. Alright. But I would have loved for you to involve the 95%. That means that you can be 95% sure that the age of women in the US is 75. Right?
I don't think 95 can be involved anymore. 95% would have been the confidence interval in case we rejected, which means that if we sample the population enough times, 95% of the times the mean of the ages will give you an answer which is NOT 75. The number 95 says nothing about the original average of 75 years The confidence interval is to support the rejection, but says nothing about confidence of the null hypothesis data
You are able to make learning so stressless. Thank you.
I had never seen such an amazing explanatio , thank you so much!!!!!
Thanksssss for such a crisp n clear explanation!!!
your explanation is indeed flawless ...Thank youy so much
crisp and clear. Thanks for the simplification
Glad it was helpful!
Thank you for everything, i’ve an exam in 2 hours and it’s not just that i was struggling with critical values that you’ve helped with.
But the calming and soothing way of teaching is what made me at ease.
Again thank you so much of this :)
I got it now. What a nice tutorial
Sorry, I have a question about the Z test. Why did you find the critical value depends on the standard deviation of 0.025 instead of 0.05? Is it about one tailed test and two tailed test? Thank you!
When the Alternate Hypothesis is "not equal to" the population mean, then we use a two tailed distribution. In a z or t test for a two tailed distribution, we find the z score or a t score for "alpha/2" because the critical value lies on each side of the mean. So if the Confidence Level is 0.95, then the Level of Significance is 0.05. Then alpha/2 = 0.05/2 = 0.025.
If the Alternate Hypothesis is a "less then" population mean kinda scenario, we use a left tailed distribution. Then the level of significance is not divided by 2. So it just remains alpha. And we calculate the z and t test for alpha.
Hope this helps...
Bravo…please make more videos…you make the complicated easier to understand!!! TY
Great video! This really helped me understand my statistics homework so much better 🎉
Glad it helped!
For exercise 2, what if i state the null hypothesis as less or equal to 2.45
ig it doesnt matter the thing which matter is alternative hypothesis
but the thing which u said should be correct
Thank you so much i appreciate it. this is very easy to understand
Ur insane this made it so clear unlike my lecturer who made it so convoluted
Great to-the-point explanation 🙂Many thanks
Thank you very much!
Good explanation
I'm confused, what if we are dealing with sample standard deviations yet the sample size is more than 30, what's the statistical test
I think it’s just depending on if we know the population variation. If yes use Z if not use T
This is great, thank you
Beautiful video! Thanks a lot!
More explanation on how to determine a null and alternative hypothesis
null hypothesis:what is said from begining ,alternative:what reseraschs gonna do
im new to stats...did you mean to write u-1 instead of n-1 fkr the degrees of freedom, or am I confused
Excuse my hand-writing but I did indeed write n-1 although it looks like u-1 :) n stands for sample size. Thank you!
Unable to understand 😭😞😭😞
Really? I found this one is really clear
Thank you it's useful
when calculating for the t-value, why is the degree of freedom not applicable (n-1)?
Thank you for your question. I think what you're asking is why do we use the degrees of freedom when calculating the critical value and not the t-value. The reason we use degrees of freedom to find the critical value is because the t-distribution's shape changes depending on how large the sample size is. As the sample size increases (degrees of freedom increases), the certainty of the estimate increases which leads to less spread in the distribution.
Thanks alot 🙏🏾🙏🏾but please what's that chart called
All doughs cleared Man ❤😊
what if the mean is not given? how do i calculate?
Thankyou for clear explanation ❤
Hi! thank you for the very clear explanation.
One question though, in the t-test we took 'Null Hypothesis as price = 2.45', can we also take it as 'price
Absolutely, you can also choose to state the null hypothesis as
@@pax_academy thank yo very much, for responding :)
So helpful Thankyeww so muchhhhh❤️
Thank you
It’s really helpful
Thank you sir.
Well expantiated and understood😊
Thank you so much
Sirrr thankkk youuuuu🥹so muchhh
Day before the exam and here I am
My exam is after 2hrs😂
3 hourse before the viva and I'm here😂
How did u get 0.01 in the rejection region and 0.025 in the rejection region
It depends on your confidence level. In some question the confidence level was 95 % which is 0.95 in decimals. 1 minus 0.95 is 0.05 , in a one tail test. If it’s a two tailed test it’s 0.05 divide by 2 which means it’s 0.025 on each tail. In another case 99% is 0.99 in decimals. Hence 1 minus 0.99 is 0.01 in a one tail test and 0.005 in a two tail test because 0.01 divided by 2 is 0.005. Hope this helps
I have a question for the second problem, shouldn't we be using the value corresponding to df=24 and CI=99%? Why did you use the CI value within the 98% CI?
Because of the degree of freedom, i guess
Bear in mind that this is a one-tail test, therefore our significance level is calculated from doing 1 - CL of 99% = 0.01. If it were a two-tail test we would find 0.005 (0.01/2). Hence, we use the degrees of freedom found (24) and our signif level of 0.01 to find a critical value of 2.49.
@@pax_academy Oh okay, I understand now, thank you very much. Hope you continue making educational videos on Statistics!
You helped me a lot thanks
No problem!
Thank you so much it really helped me
I'm glad it helped!
Thank you so much ❤❤❤❤
AMAZING 🎉
Why 1.43 mine is 1.428
What test is used when n>30 but then pop. variance is know
Thank you for your question. The test used when the sample size is higher than 30 or if the pop. variance is known is the z-test.
So helpful
Thanks a lot for sharing🎉❤
My pleasure !
very helpful thank you
Glad it was helpful!
8:28 we cannot reject the hypothesis that the value is 75. Alright. But I would have loved for you to involve the 95%. That means that you can be 95% sure that the age of women in the US is 75. Right?
I don't think 95 can be involved anymore.
95% would have been the confidence interval in case we rejected, which means that if we sample the population enough times, 95% of the times the mean of the ages will give you an answer which is NOT 75.
The number 95 says nothing about the original average of 75 years
The confidence interval is to support the rejection, but says nothing about confidence of the null hypothesis data
thank you
Very comprehensive
Thank you very much!
Could you avail your concept on linear programming & break-even analysis thank you@@pax_academy
Great 👌
Thank you!
informative video 😃
Thank you!
thank you thanj u!!!!!!!!!
Life saver 😊
Thank you! :)
YOU ARE AGREAT TEACHER
Thank you!
First question sample sd is given not population sd, so should not we go for the t-test?
Unfortunately no as the sample size is of greater importance. As n is higher than 30, we must use the t-test. Thank you for your question!
@@pax_academy I don't get it😭
❤
thank u
You're welcome!
great great great