[August SAT Math] These 3 Questions were JUST added
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- Опубліковано 11 лип 2024
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Where did you study - Emory University
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![[August SAT Math] 3 ACTUALLY Hard Questions](http://i.ytimg.com/vi/1hnSLONl2KY/mqdefault.jpg)
![[August SAT Math] 3 ACTUALLY Hard Questions](/img/tr.png)
![[August SAT] Last Minute REVIEW - 8 Parabola Question Tested on SAT](http://i.ytimg.com/vi/wkLGsN6zeK8/mqdefault.jpg)
![[DIGITAL SAT] These 3 MUST Be Solved With DESMOS](/img/n.gif)
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Parabola Concepts for SAT Math
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for circle questions like those, you can also just plug the entire equation into desmos and find out if any of the x values in the choices fall within the circle
Good point. For clarity, as long as the x-coordinate is one of the x-values of the circumference, it will work.
Desmos works (and I admit, it's faster) for this question, but it's valuable to learn the equation method for other SAT questions. Thanks for sharing.
bro can u show me how to do that i have my exam in 3 days
@@shlattrt same omg!! just started to study:)
@@shlattrtI do too, good luck! If you haven’t figured it out already you can quite literally just type the exact equation into Desmos and it will graph the circle for you. Then from there the question can be a quick process of elimination. If you haven’t practiced using Desmos I highly recommend using some time you have left to check it out.
can you explain how did you solve last question?
For the circle question at 0:59, since they're only asking for the X-Coordinate, you could do -4 (X-coordinate of the center) ± 11 (radius, square root of the right side of the equation), and get that the X-Coordinate must be from -15 to 7, which only answer B fulfills.
same thing I did here bro . I got B ..but what I watched on.. boom!!. I saw that I was wrong
Another valid method! Thanks for sharing.
Where have you been John come on we need you... You're our brother this family mustn't be lost ❤ more vids more..
Ur videos are so helpful, they are thorough and easy to follow!❤ well explained thank u
for the first question (22), it would be much simpler and time-saving to just throw the circle equation into desmos and check for the possible x-intercepts.
That's what I did. I just made the equation, x=a, and set a range of values a could be. I then tested each value, and only b fulfilled the answer.
@@R4PT0Rhe circled a and b. Is b the correct answer
You can also enter the circle equation into desmos and eyeball it or enter x= -16 which lets you create a slider from -16 to 19 with step 1. Drag the slider around to see which x value actually works. It seems that the digital SAT loves to reinforce that an (x,y) ordered pair satisfies the equation that it is a solution for. Love the way you did the circle question and the way you emphasized the logic. ACT used to include these questions often.
All 3 questions can be done fairly quickly in Desmos although the 3rd is not quite as intuitive. However, the first 2 are very easy and can be done in under 30 secs. No reason to spend 2-4 mins doing all the work by hand esp on #1.
Can u explain how #2 can be put in desmos?
@@NtS785 Yes. Create a table and type in the 3 highlighted points (-2, 6) (-1, 8) (0, -6). Do a quadratic regression y1~ax1^2 + bx1 + c. It will give you values for a, b, c. Type b*c (or just do it in your head).
@@jwmathtutoring thank uuuu
bro how to put q3 in desmos
For the last question I think using point slope form would be better. If you like only having y on the left then u can simply add over the y1 so u get y = m(x-x1) + y1. It makes it a lot easier bc then u can plug it into desmos as a function without needing to solve for b
finally.thanks for video
Thank you, Father
😂😂
@@YasminaMuzaffarova hey!! he's more present in my education than my dad LOL
@@fvehed same)
for the graph equestion you can put the values on desmos and use the slider value until you get it right
thats what i did its alot faster
I enjoyed your solution to the 2nd Problem 7:08
I used Vietta's formula
Sum of Roots/Solutions = -b/a
Product of Roots = c/a
Find c and b and then Multiply
I would have used ur method. Wanted to Try this formula out
That's a valid method. Good work!
For the second question, you can use the sum of roots and product of roots formula. Sum of roots is -b/a, and product of roots is c/a, so you just find the sum of the roots which is -2, and the product of the roots which is -3. Then you plug it into the formula. -b/2 has to equal -2, so b is 4. And c/-2 has to equal -3, so c is 6. Then you just multiply to get your answer of -24.
i love your videos,and i solved all the three
da kerm kada
For the second question can you also do it by figuring out the y int from graph for c value and then use a point from the graph say (-2,-6) and then plug it into the equation provided for the b value and then multiply it together(b and c)?
Did John just call himself an "average Joe?" 13:27 Yeah, right. 😂😂😂
for the last q, couldn't you have just used the inverse of slope from the centre of the circle to the point of tangent instead of finding the entire line ? as both the point of tangent and the new point would need to have the same slope ?
you are the cutest thank you
couldnt you see for the circle question if it is inside out outside the range. since the radius is 11, -4+11=7 and -4-11=-15. so 16, 11, and 19 dont work.
Show us how we can use Desmond on the tangent question, please!
How are they still allowing Desmos on the SAT's, when AI tools exist?
1. Create a table with the 2 given points
2. Linear regression on those points: y1~mx1 + b; this gives you the slope of the radius to the point of tangency, m = =-.83333333333
3. Create a new table with 5, -4
4. Linear regression on that new table (the 1 point) with the slope entered as the opp recriprocal of the value from 2 above: y2~(1/.8333333333)x2 + b
5. Look at which points are on the graph or you can type in the points and see if they fall on the line.
Hi John... I took a bluebook practice test yesterday and I got 740 in maths (5 questions incorrect). But when I compared my score with a practice test I had taken earlier, I saw that I had gotten a 780 in that test with the same amount of incorrect answers. What do you think could be the reason for this?
Hello, it’s because the questions on mdoule 1 are worth more than questions on module 2, of you have before gotten 2 questions wrong on module 2 it will result in 800-2(10)= 780 but now maybe you have got 2 questions wrong on module 1 which can result in 800-2(30)= 740
Hope this helps
The test is adaptive. Bomb an easy question, lose more marks. Solve a tough one, win a lot more marks. Some questions do not even carry marks (generally the toughest ones). Bomb those, lose nothing. Try to solve the easiest questions first, and try not to bomb them.
John I would like to know if using your program can get a +700 if on my last SAT, I got a 650
If you're ready to put in the work with the program, I guarantee you'll get 700+, or I'll give you a refund.
I really miss your video
Before you start solving the questions, i tried them and I got answers to all of them without even knowing the formulas. With the help of DESMOS i got the answers in 20-40 seconds...
how can u do the first question on desmos
@@shlattrt I typed the equations on the graph and pointed the options on the x-axis like this (-16,0) (-14,0) (11,0) (19,0) and labeled them. then i saw that X-Coordinate must be from -15 to 7 so only -14 can be placed on circle and others are outside of the circle.
ngl, I don't remember any formulas but i used my brain and some tricks and Desmos, i got like 700+ in math practice test.
@@shlattrtwrite the equation and check the biggest and smallest x value. you’ll understand if you write the equation.
@@shlattrt enter the formula in and test y= as the different answer choices, option B will work because its the only one that hits the circle
How did you solve the third question in desmos?
can someone explain how to do q3 in desmos
bro are you just in youtube or are you selling sat math tutor
and if you are a tutor how can i be your student
There's an online course. You either score 700+ or get a refund.
You can learn more about it here : www.admissionhackers.com/sma
@@JohnSAT are you guarantee my score are right around 600 right now
@@AlperG35 absolutely. we do it all the time.
Good afternoon, John.
Is the first circle question not -14?
it is
my test is tomorrow 😭😭😭
i think vertex form is easier for question 2
🔥🔥🔥
pov ur running out of content
ez done 3/3
Man, your solutions are so confusing. You just need to start solving based on fundamental concepts. And if you do that, then you easily determine where the center of a circumference is - it is at (-4;19), then you know the radius is 11. Then, imagine the circumference centered at (-4;19) with radius 11. The border x coordinates will be at -15 and 7. You immediately throw choices (A), (C), and (D) away. The only (B) is in this domain of [-15, 7]. But if you want to be extra confident, just plug choice (B) into that equation, and you will find out the corresponding "y" value.
Your method of solving these types of problems could mislead and take extra time, which is not a good strategy for an SAT framework.