Digital SAT Math: How To Prepare For The Harder Second Module
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- Опубліковано 4 жов 2024
- Does the second, harder Math Module on the Digital SAT feel impossible to you? Do you get to questions 15-22 on the second harder math module and feel completely stumped for how to even start the questions? Preparing for the second harder math section of the Digital SAT is a huge challenge for many students as most books, resources, and practice tests are not representative of what you'll see on test day. In this video, I am going to discuss what I have done to help many students get perfect or near perfect scores and prepare for the second, harder math module.
Details about the steps I recommend can be found at the bottom.
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If you found the 1st math module relatively easy and the 2nd harder module much more difficult, I would recommend 3 things to get you ready for a much better score on your next SAT that have worked quite well for many students:
1. Get A Copy of The PrepPros Complete Guide to Digital SAT Math and sign up for the the Ultimate Digital SAT Math Course.
2. Work through all of the Level 3 and Level 4 Questions in The PrepPros Complete Guide To Digital SAT Math. These are the levels of questions that you need to master if you want to excel on the harder second module of Math.
3. Complete my Advanced Digital SAT Math Course For Students Aiming For An 800. This course has 150 expert level questions and is designed to expose you to ALL of the most challenging types of questions that you will see on the second harder module and teach you the most effective strategies to solve them. If you find yourself getting stuck on questions 15-22 on the second Module, this course and the level 4 questions will be incredibly helpful for improving your score. You can purchase the Advanced Digital SAT Math Course for $75 (but we have a bundle that offers a better deal...keep reading for that).
If you only need to improve your SAT Math score, we would recommend purchasing our Ultimate Digital SAT Math Course. This course has over 50 hours of content and includes:
On-Demand video explanations to all 1,500 questions in the book
Tutorials on how to use Desmos to solve many of the hardest questions on the test
Lessons for all of the most advanced content that can appear on the Math modules
Advanced Digital SAT Math Course for Students Aiming for an 800. This course has 150 expert level questions that will prepare you to ace the hardest math question on the Digital SAT.
In depth explanations to all of the questions in the Math modules of the 6 bluebook practice tests
This full course is only $49.99/month when you enter a secret discount code from the front of your copy of the PrepPros Complete Guide To Digital SAT Math.
If you want to maximize your math score, you need to know how to solve questions in the most efficient way possible. Time management is crucial on the second harder module, so solving questions correctly but in a very round about way can have a significant impact on your score.
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If you only want to work on the hardest SAT Math questions, our new Advanced Digital SAT Math Course has 150 Expert Level Questions for students aiming for 700+ on Digital SAT Math. These questions feel just like the hardest ones on Module 2 of the Digital SAT and have already helped more than 20 of our students score a perfect 800 on the Digital SAT in 2024! Try the first 8 questions for free: preppros.teachable.com/p/150-hard-math-questions
For the first exponential problem, just enter the given points into a table on desmos, then do the regression y1~ab^(x1/n). All the values for a, b, and n are solved for you. Then just type g(x)=ab^(x/n) and finally type g(9). Answer is 1215. Done. 20 seconds tops.
I did exactly what you said and got 1. 🥲
This is so true, there are so little resources for the content that are on the same level as the second harder math module.
Watching your videos really helped elevate my score. I was able to prepare for the harder math module. I got a 770 on math. Thank you!
I think an easier/time efficient way to solve for #3 is by writing (x+3a)(3x + b) and let b be some number that we solve for. 3a * b will give us the c of a quadratic equation and since we know the c for all the choices is 18a, we can set 3ab equal to 18a and find that b = 6. Thus, the factored equation is (x+3a)(3x+6) and we can foil and find the answer. By plugging in numbers starting from 1, the only answer choice that will satisfy the terms for a is d
That is really helpful man, thank you so much!
Much easier for sure. Also, you don' have to plug in numbers from 1. Because we know that b term is 6+3a, And only 24 would work if a is positive integer
Very time efficient!
Given (x+3a)(3x+6) which is easy to find, the middle term (coefficient of x) then becomes 9a+6.
Possible x coefficients are 15, 24, 33 etc.
It seems like the author is not aware of this. He is using brute force.
or just plug in the equations in desmos add a slider for a and since a is a positive integer it should be 1,2,3,4..... and since a is positve integer consatgnt the correct equation should have a negative integer as a solution for a value of a all of the equations when a is 1,2 or more do not have that negative integer zero except for d
thank you so much, these were nearly the exact questions that confused me on the may sat
Glad it was helpful!
you can use regression on desmos to solve first one
could you explain how?
@@araj3992 just create a table by adding the two points. then type in y1~ab^x and you will get a value for a and b. then just write that as a regular exponential equation, plugging in 9 for x and giving u 1215
@@araj3992 make a table of (4,5) and (7,135) then type out y1~ab^x1/n and itll give you values for a, b, and n. Then just plug in 9 with those values and it gives 1215.002 because of rounding error, but you can assume its 1215
@@Sansarii_Minecraft how do you not get an error when putting ab^x1/n into the table
@@weebtales865.
Can you show ways we can solve these through Desmos?
desmos for that last question makes it so easy, just type in each equation, and have a slider for a , and x+3a written out. Move the slider around, and if a is positive (not 0) while intercepting the graph at a x coordinate, than it is right. If it only intersects when a=0 or a negative number, then it is wrong. Really easy to do, and it will save a lot of time.
But in Desmos C) has also positive integer a, doesn’t it? I want to solve this exercise in desmos but am a bit confused😅
I'm really interested in this course but i'm already working a full time summer job to help out my family with bills and grocceries
Lol I see myself in that email. Thanks for your help on the last SAT!
So glad I was able to help you make that improvement!
for qn 4, what i did was, since x +3a is one factor then in the ans choices all of the x^2 term has a constant of 3. so, another factor shoukd be (3x + 6) , '6" because all the choices has 18 as the coeffcient of 'a'. by doing that we get 9a+6 =24 (comparing correspinding vales of x), and boom a=2 (which is indeed a positive integer).
In the first question you don't need to do such a huge work just find the multiplication factor. So in the question g(4)=5 and g(7)=135 lets pretend this a geometric series and find the common ratio in this case 135/5 = 27 in a step of 3 points so cbrt(27) = 3 . This means that for every single step increased there is a multiplication of 3. To find g(9) just do 135*3*3 this gets us 1215 our ANSWER!!
ohh that's how i got my answer, but I didn't realize this was a geometric series LOL, I forgot
Thankyouuu so geniusssssssss wowowowowowowowowoow
@@SupriyaBhandari-yb8lb You're welcome😊😊
i mean, the que doesnt mention that b and n are integers. it worked on this one but maynot work everytime
Amazingggggggggg pls do more videos for june plssss.I wish i could get 1500🙏🙏🙏
I'm giving the June Sat too. Best luck we got this ❤️✨
Goodluck guys, we can do this fr. Manifesting a high score (and also putting in the work).
Thank you for the video! Is there any way to use Desmos to solve this equation? I have SAT on June 1st.
He looks like if Chris Kratt and Ryan Reynolds had a baby
but this was very helpful tysm
10:59 is C, 11:02 is x=2, 11:08 is 666 (not 100% sure about that one), and 11:14 is b=11.
I got 10800 for 11:08
@@unarmedleader3719 same
@@unarmedleader3719 me too!
In the question in which we've to find g(9), can't we just find the value of g(2) by square rooting g(4)? Then g(9) can be solved by multiplying g(2) and g(7). This gives the answer 135 underroot 5.
g(2)*g(7)=g(9) in this case
No, that does not work because of the ab since there are two variables. For example, if you pop the function f(x)=(2)(3)^x into desmos you'll see f(2) is not the square root of f(4)
idk if this is an easier or tougher way to solve but here's how i solved q2: q^11=x. px+r is a factor of the quadratic so, f(px+r) = 0, x = -r/p = A. therefore, 34A^2 -bA +60=0. now using the usual method of factorisation, 34*60 = 2040, (sum of factors of 2040 =b) out of all factors of 2040, 1 and 2040 will obviously have the greatest value and hence ans = 2041
What did u mean by x=-r/p??
Thank you
For the first question you can also solve the whole thing with desmos. Thanks for video
Yes, you can in 3 simple steps. The regression tool is the very overpowered piece of Desmos. I always try to teach the conceptual way in my youtube videos so that students can understand how to solve related questions but make sure to cover all the desmos shortcuts in my courses as well.
@@prepprosyeah I am curious now how would u solve this with desmos? Can u make a video showing all the desmos tricks! Thanks ur work is appreciated
@@ethanaarvig1174 please tag me in that video
@@ethanaarvig1174 you can make a table, and use the regression function
@@preppros how would you use desmos to solve the first question?
For question number 3 can I do (x+3a)(3x+6) and then 9ax + 6x, set it equal to each one 9ax + 6x = 24, substitute random value 1 for x, 9a + 6 = 24 9a = 18 a = 2, if we do any other equation it won't be both a positive integer (B and C would be positive but not an integer), so we knows it's D. Does this solution work as well?
yeh this is a way better solution and the method I used too
Thank you so much for the video! I had one question - for the second question, what if we were looking for the smallest value of b? What trick could we use then? Bless 🙏🙏🙏
Hi, it would end up being a discriminant question then.
@@preppros Could you elaborate on what that would look like?
qno 2 makes no sense to me. Help me if anyone can solve the question.
7:52 what if it was asking for the least possible value
for the first question about the g(x). isnt 1/3*27=9. I see you put it as 3. Unless Im stupid and did something wrong on my end 😅
Hi, I took the third root aka the cubic root.
@preppros oh mb alright thanks
What is it ask for minimum value of B?
Can you recommend a book for reading and writing section?
for the first problem can't i use systems of equations or would that be incorrect?
hi, im having trouble loading question 5 (under the advanced digital sat math course) in the free trial, im wondering if the problem is on my end. its an awesome course btw! very very helpful
Should have just fixed the issue! Glad to hear it!
@@preppros yeah it works now, thanks!!
Questions here seem to be modeled after ones from the May exam. Do you have questions modeled after the ones that appeared on the March exam?
Yes, the entire Advanced Math course is modeled to be reflective of the types of questions that have and could be showing up on Digital SATs. It will be consistently updated to be reflective of trends on the test.
wow, the same type of question 3 was on my may sat, The only question I had no clue. So our only option is to put -3a and test the choices?? It is so time consuming I hope someone figures out how to solve it using desmos
I've spent time trying to figure out a desmos workaround but I do not think there is a reliable method as you cannot solve for a using the regression tool and you cannot plug in values for a as that will affect finding the correct answer. You could get lucky depending on what you plug in but we don't want to rely on that.
@@preppros I tried to get factor them, like 18a would be 3a and 6 , so 3a+18=24 and a=2. it's just a bit faster because I didn't have to discriminate it
for the question that flashes on the screen at 10:59, the answer is C right? and at 12:08, it's D?
You missed one of those. You can find the explanations and the answers in the free trial
@@preppros the only thing I will enter my card information for are my internet, water, and electricity bills.
You don't need to enter any sort of card info in for our free trial
10:59 is C and 12:08 is B.
@@48hoursaroundtheworld thanks, and all the best for your SAT!
Does anyone know the foundations for these equations because i can barely follow along.
need to know your algebra
How would we do the second question if lowest possible value of b is asked?
Hi, it would turn into a discriminant question which would be quite a bit easier. b^2-4(34)(60)=0
Would it not work using this-
(34x+60)(x+1), then it would be 94
yes, if the question stated that they must be integers. They would most likely do so if this variety came up!
@@prepproshi! Sorry I know this is two months later but why would you set the discriminat to zero? How would that minimize b?
for #3, could i use a linear regression to plot it instead?
how?
Would there be any where it asks for the lowest value of b?
Hi, that definitely could be a possible variation in the future!
I think it could be 94. Let's say you use this expression to factor: (34x+60) (x+1). I used 60 and 1 in that way because when multiplied out it becomes 34x^2 + 34x+60x + 60. So the bigger number in the first parentheses and the smaller one in the second pair of parentheses but one would have to use two numbers like that and in that manner for it to be the smallest possible value of b.
The way Mike did it is perfect for maximising the value of b. So, do it like that to maximise the value of b but to minimise the value of b you just switch the order of where you put the two numbers bring multiplied to make the c value.
Good concepts to know as I saw on reddit that this question exactly or nearly came like this on the May S.A.T.
I also solved the third question instantaneously by making x=2 and just deciding to factor the last answer choice since all the coefficients could be divided by three which turned out to be 3(x+6)(x+2) and that worked out flush on the first go.
The first question is one that I will fully commit to memory for the future. Mike is really aiding us. We should all support him in some way.
why was my moduel 1 harder than my moduel 2
you may have gotten the easier module if you got too many wrong on the first one
how to solve the question that flashes on the screen at 12:03 (In the given system of equations...)?
You can find the answers and explanations at the bottom of the free trial: preppros.teachable.com/p/ultimate-sat-course-free-trial
@@preppros thanks!
how did you get 3 from dividing 7/n into 4/n?
properties of exponents.
im cooked
yeah, same here