In this procedure you should neutral with spherical values in both meridians, for beginners it would be much better to understand. This method is for those who mastered retinoscopy. An expert can use this technique to find the absolute neutral point. But for the beginners they can't justify which meridian is getting neutral at the optical cross.Otherwise this is really useful video.
First time I have seen + Sign is in Red colour & - Sign in black 😂 But Your explanation was really exceptional & useful Sir Thank you & Keep continuing Sir for more videos 👌👌👌👍👍👍🤝🤝🤝🤝
i am confused please correct me. i thought we should get the axis not from the angle of the streak but from angle of the movement of the streak. im a student btw
Correct. Working distance is compensated with sphere only. Suppose if we get -1.00 DC only then after working distance compensation it will be -1.50 DS/-1.00 DC
Sir, I am studying B. Optometry, your video is Very nice and easily understood but have one doubt is how to measurement distance from patient eye to retinoscope?
First step is to find the type of movement then meridian of movement. Mostly we use sphere lens first to neutralize any one meridian. If it’s sphere all meridian will get neutralized with single sphere lens but if it’s astigmatism one meridian will get neutralized but other median will still show movement. At that meridian we have to use cylinder lenses to neutralize.
@@optometryreels then does it mean. Eg In your vid. 135 and 45 axis. So you put sph in 135 * and it neutralised in every axis. So does it mean pt in having sph only and no cyl?
In this procedure you should neutral with spherical values in both meridians, for beginners it would be much better to understand. This method is for those who mastered retinoscopy. An expert can use this technique to find the absolute neutral point. But for the beginners they can't justify which meridian is getting neutral at the optical cross.Otherwise this is really useful video.
Thank you so much 👍🙏
Great graphics.
Very interesting.
Thanks!
please do me a subjective refraction using a trial lens frame.i think i will be good to go👍👍👍
I am amazed why this channel is not getting enough views.
This channel is amazing for last minute preparation
Thank you for your support..
Thanks doc!
Super explained sir understood
Very well keep it up
Thank you very much for teaching and sharing your knowledge 😊
Excellent 🎉.. Thanks Doc
Dear Sir
Requesting you to make some more Videos on Sphero cylinder values
Thanks sir
Mst explain kiya hy sir ap n topic👌🫶🏻🫶🏻🫶🏻🫶🏻😍😍😇
right now am pressing the bell icon ،
just to watch and support your videos🎉
Thank you for the support! ☺️
@@optometryreels
You Deserve the most appreciation Dear Sir💥
good
Awesome Sir👌👌. Really knowledgeable.
Omg! Thank you so much,this really helped
Baki sab shodo,ladki hai too cute
Thankyou so much sir for your easy way of explanation...🙏 It's help us lots
Thank you for the appreciation
Plz put a video on only cylinder method
First time I have seen + Sign is in Red colour & - Sign in black 😂
But Your explanation was really exceptional & useful Sir
Thank you & Keep continuing Sir for more videos 👌👌👌👍👍👍🤝🤝🤝🤝
Exactly my point 😂😂
That's in their country
The main point is to note the sign mark on the lenses
nicely explained
Why are we only subtracting spherical components not cylinder one ??????
Hi Im just learning about this your explanations is a lot clearer. Thank you.
Do I still need to -1.50 working distance then it become -250?
Excellent.
I learned a lot!
Where did the axis 135 come from?
Secend part ko or issy se samjhaya jay sir
Dr.. Sound is very low.... Please
Nice 👌 😊😊😊🎉
U forgot to light off... can't perform retinoscopy in bright illumination
Oh 1 more qns, how do I know which meridian is a cylinder or a sphere?
You don’t have to know. Just neutralize a meridian with sphere first and remaining with cylinder
I need subjective refraction with retinoscope values with examples to find out the acceptance of patients
didn’t you substract cycloplegic drops value?
Very nice but DR sound is very low please improve
i am confused please correct me. i thought we should get the axis not from the angle of the streak but from angle of the movement of the streak. im a student btw
informative but i am comfused about 1 thing ,,,, sir is me hm difference nhi nikalege sph and cyl ka?
Dear Sir ,
Please let me know How can we decide SPH AND CYL Meridian
I also want to know that
For net cylindrical value we don't need to subtract cylindrical value from sphere value?
Like second-first reading rule?
Correct. Working distance is compensated with sphere only.
Suppose if we get -1.00 DC only then after working distance compensation it will be -1.50 DS/-1.00 DC
@@optometryreels then should -1.50 DS/ -1.00 DC be the final prescription?
Fine
What is difference of taking plane and concave mirror
It changes the nature of glow..
With movement of glow will turn against movement and vice versa.
For neutralize 145 are you using cyl Or sphere
Very nice ❤❤
keep it up
dear Respected sir❤
Assalam alaikum bhai, are you using Welchallyn Retinoscope?
Retinoscope.. kon sa le low price me
This process done by Sphero cylnder method???
Why are you not using spherical on 135 axis
axis is only for cylindrical power
Hi
Sir, when you neutralize one meridian, do you leave that lens in when you're about to do the other meridian or do you take it out?
Sir, I am studying B. Optometry, your video is Very nice and easily understood but have one doubt is how to measurement distance from patient eye to retinoscope?
@@DipankarManna-tz3hv Thank you! measure using rular scale or measuring tape..
@@optometryreels thank you sir
How will i know which one is sph which one is cyl bcos both have axis eg . 135* and 45*
First step is to find the type of movement then meridian of movement.
Mostly we use sphere lens first to neutralize any one meridian.
If it’s sphere all meridian will get neutralized with single sphere lens but if it’s astigmatism one meridian will get neutralized but other median will still show movement. At that meridian we have to use cylinder lenses to neutralize.
@@optometryreels then does it mean. Eg In your vid. 135 and 45 axis. So you put sph in 135 * and it neutralised in every axis. So does it mean pt in having sph only and no cyl?
@@blooms2396 I used sphere at 45 and cylinder at 135
@@optometryreels okay sir. So then does it mean if it neutralises in 45 in every meridian. Then the pt is having only a sph power ?
I am confused??
Are we not deducting WD from cyl value???
No. Only from sphere..
Why?
The way she is blinking during the test is making me so uncomfortable 😫😫😫
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