Hey Chad, this kinetics series has been BOSS! Specially when you showed how to derive the rate law a few days ago. That was really helpful. So thank you!
Thank you so much for making these videos! I can not tell you how confused I was about this section and watching your video really cleared things up and clicked ideas into place. I look forward to watching the rest of the series. Again thank you, thank you, THANK YOU!!!!
I just discovered your channel right before the gen chem 2 final, and I feel like I am finally understanding the content! Please make ochem videos, these will be a lifesaver next semester!!!
Thank you for these videos and making them easy to understand !! I have my midterm exam and I was so lost before watching your series haha. God bless you
Hey Chad, this kinetics series has been BOSS! Specially when you showed how to derive the rate law a few days ago. That was really helpful. So thank you!
Glad it was helpful, Peyman!
I wanted to stop by and say thank you for your brilliant explanation. You were clear, concise, and straight to the point. Keep up the great work!
Thank you - appreciate all the feedback!
Thank you so much for making these videos! I can not tell you how confused I was about this section and watching your video really cleared things up and clicked ideas into place. I look forward to watching the rest of the series. Again thank you, thank you, THANK YOU!!!!
That is great to hear - You are welcome and Thank you.
You are the best chemistry teacher i have ever watched. The way you slowly and orderly explain things is very helpful.
Thank you!
I just discovered your channel right before the gen chem 2 final, and I feel like I am finally understanding the content! Please make ochem videos, these will be a lifesaver next semester!!!
Glad you found us. You should check out my playlists...already have ochem videos! Happy Studying!
Thank you for these videos and making them easy to understand !! I have my midterm exam and I was so lost before watching your series haha. God bless you
You're welcome - glad the channel is helping you and hope you excel on your midterm!
Your videos, as always, have greatly helped me understand the concepts at hand. Thank you.
Excellent - thanks for saying so!
I cannot thank you enough for all of your content! It has been incredibly helpful for my semester!
Excellent!
This video was extremely helpful! Thank you for the amazing effort and making things easier!
You're very welcome!
First things, these vedios require a lot more attention. And also thank you so much for making this so easy by your explanation. Huge respect
You're welcome and Thank You - glad you found us.
I undated easily than @organic chemistry tutor 😂i really like the way chad teaches
Glad to hear it!
Thank you Lord for Chad!! 🙌🏼
Thanks for saying so!
Thank you for the information Sir
You are welcome!
Yooo what a chad!!! I really appreciate your from of teaching!
Glad the channel is helping you.
I like your teaching so much…yo are the best teacher in the world
Glad to hear it - Thanks for saying so!
watching this right after the superbowl for a test and hearing him at 4:25 is hilarious
Hope you do well on your test!
This is brilliant thank you very for this wonderful explanation
You're very welcome!
In our lecture, the teacher represented 0.693 as ln(2). That is a much easier way to remember it!
Excellent!
anyone get a diff value for integration problem on second order?
Hey Chad, thanks for the Clarity provided on these different orders of reaction. But I'm somehow confused on deriving ln e-
Hi, i'm just a little confused on how you get the constant rate k=0.001 reply ASAP 3:10
i think its given in the question
thank you so much for this
Very welcome
This guy is the goat
Happy Studying!
How did you get 0.44 for the zero order?
Thanks so much....I am really getting some facts that were confusing
Glad the channel is helping you - Happy Studying!
Hy can you share the link for the video where you do derivations
ua-cam.com/video/YHrydv1sJcU/v-deo.html
Thank you so much
You're welcome.
Gréât explanation!
Thank you!
Thanks so much !
You're welcome!
I don't understand how he went from .753 to .47M. I don't know how to find the e^ on the calculator.
I figured it out I was leaving off the negative!
@@valv1377 but how did you use the e i cant find it either
you are amazing
😊
Thanks!
Practical of chemical kinetics
I swear chemistry isn't science, its just math
You could see it that way