when you said the jacobian could be shown in a different video, I got sad cause that's what I wanted to see lol otherwise, this was cool to watch :) I've used the gaussian integral a bit recently in my physics classes, but never really knew where it came from. Also, sqrt(pi)/2 is (1/2)! I assume they're related.
The matrix was likely used to compute the Jacobian. The determinant of the Jacobian matrix yields the scale factor of the linear transformation essentially.
Would be interesting to recollect how Jacobian is introduced, and how it's inferred in general
Great explanation. One wouldn’t even need to know multivariable calculus to understand this.
I agree
Very smart. The result sqrt(pi) is related to circle or polar coordinates. Coordinates conversion simplifies the solution.
The Best! I'm a Brazilian fan!
Your explanations are perfect!
Great explanation and blackboard technique!
Great videos!
Does that mean I have to watch like 2 other videos just to understand the full concept?
when you said the jacobian could be shown in a different video, I got sad cause that's what I wanted to see lol
otherwise, this was cool to watch :)
I've used the gaussian integral a bit recently in my physics classes, but never really knew where it came from.
Also, sqrt(pi)/2 is (1/2)! I assume they're related.
For the first person tanks for an other video ..teacher
This is really the way to do it !
Ur greatest funny mathematican
Respect! Multumesc din Romania!
I remember when I thought this technique smacked of trickery. Then I learned of Feynmann's technique and the world stopped making sense altogether.
We shall visit Feynmann soon 😆
One thing that is passed without saying explicitly is that Z is an integer in this derivation. This is therefore not a general definition
You are so so great guy!! Thank you :))
Thanks for arranging this.
Prove that dx.dy=rdr.d(Theta)
Great explanation!
Recently is solved by Double integral and transfer it to polar ordinance and no need use IxI ?
Из 3,14 а частицы начинают с 2.
Bless You!
I saw a sped up proof of this and it was going into matrices and all sorts, has anyone come across that before?
The matrix was likely used to compute the Jacobian. The determinant of the Jacobian matrix yields the scale factor of the linear transformation essentially.
Great❤
Nice 🌵
Yoooooo.... super cool
How can I integrate (1/(1+e^x))dx
Multiply both the numerator and the denominator by e^(-x), equivalent to multiplying by 1. After that, a substitution will be very obvious.
ua-cam.com/video/hUIfJt4k0Hg/v-deo.html
@@znhait You're right, a substitution did become obvious.