How to Derive the Equations of Motion (Derivation)

In this video I show you the derivation of the three equations of motion on the Leaving Cert Physics course. They are v=u+at, s=ut+1/2at^2 and v^2=u^2+2as.
0:00 v=u+at
1:08 s=ut+1/2at^2
2:52 v^2=u^2+2as

[@SimpleScienceandMaths]

0:00 v=u+at
1:08 s=ut+1/2at^2
2:52 v^2=u^2+2as

[@durgaard7340]

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[@SimpleScienceandMaths]

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[@SimpleScienceandMaths]

Hi! Thank you so much for taking the time to write such a wonderful comment! I'm glad my videos were able to help you!
All the best, Patrick.

[@stuartbudd4584]

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[@anjaliyadav4905]

Appreciatable explanation ,very clear, in a concise manner and is very helpful for me. Thank a lot...

[@SimpleScienceandMaths]

You're welcome, thanks for watching

[@manukondasambireddy4255]

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Thank you

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[@SimpleScienceandMaths]

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[@SimpleScienceandMaths]

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[@SimpleScienceandMaths]

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Wow ! That was a incredible explaination

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[@HJGamingHJG8305]

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helped me alot
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[@babakebouncer1724]

Thank you sir your explanation is amaging.

[@durgaard7340]

Watch ur spellings it's 'amazing'

[@nomanzaman]

I have a problem in equation 3 if we havr u^2 +2uat+a^2t^2
We have (t) un both sides than why didn’t we make the equation like 2at(vi+1/2at)? Please explain

[@zaidffkhan588]

Well done

[@SatyamBabu-we4cx]

It is very helpful for my exam

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[@SatyamBabu-we4cx]

Thankyou so much sir

[@user-lz8tu8kh3s]

How to derive them with unitary method?

[@EjaxPlus]

In second derivation, I still don't understand how is it okay to substitute normal v equation with v average. I mean it's two different things.

[@deeparajesh8405]

Thank you soooo much man

[@SimpleScienceandMaths]

You're welcome

[@artistic_area1891]

In derivation of 2nd were is the v=u+v/2 =v=u+u+at/2 were is 'v'???

[@prameelaprameela6281]

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[@SimpleScienceandMaths]

Thanks Joe

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Tq help video 👍

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Thanks :)

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Thankyou 😊

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Thank you so much 😇😇 love from India 🇮🇳

[@SimpleScienceandMaths]

You're welcome 😊

[@noelradhakrishnan4423]

You have a good taste in physics

[@bilyaminuahmad8677]

Thank you sir it really helps

[@abhinavn4808]

sir how that at^2 / 2 becomes 1/2

[@zmdesiboy1093]

Same doubt did u get it now..?

[@user-wb5qn5by4n]

Thank you so much

[@SimpleScienceandMaths]

youre welcome!

[@Avighna]

Great video, however, and I don't mean to be pedantic but when you say v = S/t, you really need to specify that this 'v' refers to the average velocity. You still substituted it as the average velocity and got the right answer, but this is pretty important to mention explicitly. Without this detail, you could derive this: v = u + at = S / t S = ut + at^2.

[@SANIDANIEL-t6o]

So helpful, but I still don't get the 3rd eqn.

[@technologyansh]

Carry on.Bro

[@cubicboye8807]

Thank you

[@SimpleScienceandMaths]

You're welcome 😊

[@elonmusk1055]

S=2ut+at²
---------
2
S=ut+ ½at²
How it's possible I don't understand

[@SimpleScienceandMaths]

Take 2 as a factor of the right side

[@iamprimecrit6582]

Help, I'm confused, where does (2uat) come from 3:22

[@gdcurious]

It's formula a² +2ab + b²

[@iamprimecrit6582]

@@gdcurious alr👍

[@DinaTabia]

Sir,Can you explain from where you have taken 2a in the 3rd equation

[@lightshadow-_]

he took 2a As common in that case

[@krstev29]

Thank you sir, you need to know how to derive formulas so you remember them.

[@Designophile]

Simplest explanation

[@KimmannatKim]

But in end why we don't write 2ut ? 😢

[@frizzygamer4028]

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[@pankajgoswami9756]

Tnxx

[@mamatagowda6011]

I didn't understood the third equation

[@mamatagowda6011]

Pls explain

[@yogindras4402]

What didn't you understand

[@yogindras4402]

(u+at)^2 in in the form of (a+b)^2
So it's written as u^2+a^2t^2+2uat

[@mamatagowda6011]

@@yogindras4402 it's ok now im studying 10th Std it was my 9th std doubt ....

[@aayush3332]

In the second step both are squared and u+at is expanded to a²+2ab+b²

[@udhaochavhan6751]

How would you get 1/2at² you just cancelled 2

[@intelblox7354]

we can write it as 2ut/2 + at^2/2 i believe

[@ananya8423]

Thankuuuu

[@sanshorts74184]

Thanks

[@SimpleScienceandMaths]

You're welcome 😊

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[@SimpleScienceandMaths]

Thanks

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[@SimpleScienceandMaths]

Ireland

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Your video helped me a lot
I am your new subscriber 🎉😊

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Who is legend like me I am watching this video 3 hours before exam

[@technologyansh]

That's NYC.

[@user-jc5eh9yv5s]

Wellone

[@MDAshraf-tc7hh]

Bro you should have to check your 3 equation
How can you take 2a as a common bro

[@SimpleScienceandMaths]

That's where the 1/2 comes from

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Xrong method

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[@SimpleScienceandMaths]

You're welcome