This was extremely helpful. I'm doing college physics right now without having taken high school physics so I really need videos this helpful. Thank you so much.
I'm from another country but your lecture satisfied me much than my school teacher. Thanks for this explanation. I hope i can give my best in my physics test :')
With the equations of motion, there is often more than 1 equation you could use. You just have to pick one where you know every quantity apart fro the one that you're trying to find out.
As Mr. Smith points out, there is often more than one equation applicable, to different questions. You can also sometimes use two equations, that is, in both questions one and two you can calculate the time, t , using the equation s = ( u + v / 2 ) t , and then substitute u , v , and t , into v = u + at to calculate the acceleration. Making a (the acceleration) the subject, such that, a = v - u / t sometimes makes the calculation very clear. Just some suggestions. 😊
9.8ms⁻² is the acceleration due to gravity on Earth. I take the upwards direction as positive so, since objects accelerate downwards (the negative direction), this means that a=-9.8ms⁻².
These are the equations used for the vertical component in projectile motion - if you're happy using them then that's half the battle. Check out my past paper solution video on projectiles for some helpful tips.
I'm afraid that's knowledge beyond Higher Physics that you'd need to ask elsewhere - there may be a reason for choosing a dopant with lower ionisation level or it could be related to the shifting energy levels which form bands when the intrinsic semiconductor is formed (something that won't occur with the dopant due to its low concentration).
Please sir i have reversed this video many times and I still don't know how you got _9.8 or is it the way it's given in the exam script that we are going to put it??
How does we understand that in which questions we have to prove which equation that's a big problem and also tomorrow is my exam of physics.may god help me
Finding the correct equation is just a matter of noting which variables we know and which one we're trying to calculate. Pick an equation with all those terms in it.
i’m doing the 2020 higher pass paper questions and on question 3, for equations of motion, the marking scheme specified that the heigh and acceleration have to have the same sign. why is this?
I don't have access to the 2020 paper but if displacement and acceleration are both the same sign then they must be in the same direction. Since acceleration is downwards, it must be that the object is falling downwards which is why it's also taken as negative.
In Higher Physics, pupils get a relationship sheet with all the equations written on it. The skill is in identifying which equation to use and in manipulating it in order to solve the problem. In my day, we had to memorise the equations although I'm happier with the situation now.
One question asks you to calculate the time to maximum height whereas the other asks for time to go up then back down to the initial height. The initial velocities are also different.
It's really helped me a lot...... THANK YOU VERY MUCH......... but I have still one confusion how we know which formula we have to use especially 2nd motion of equation...... I'm really confused where I should use 2nd equation of motion plzzzzzzzzzz help 😕😥
It's the same process with that equation as any other - choose an equation that contains the property you are trying to work out. This should be the only unknown as you should know all other quantities.
is it possible for the displacement to be a negative value because in question 3 for the sign convention i made down positive (cause i was taught to do so..) it gave me the same answer but just negative. should i switch the signs at the end or leave it as it is? also this video was really helpful
I didn't understand the third question as well as the first and second!!! Any solution to make it easier to understand.. Btw nice teaching I understand everything you say but I am not sure where all that information is coming from that's all I want to know
Some of the information, acceleration due to gravity, is given in a data sheet at the start of the exam (in Scotland, at least). Apart from that, all values will be given in the question apart from vertical velocity at max. height. Glad it helped.
From a previous reply - "This is a value which is given at the start of the Higher Physics examination on the 2nd page - the 'data sheet'. It doesn't need to be calculated." I'm also taking upwards as the positive direction which is why it's negative.
That's the acceleration due to gravity on Earth. The value is given in the data sheet at the start of the Higher Physics paper. In the question, I take the upwards direction as positive, making acceleration negative (objects accelerate downwards).
Yes - you can use that equation as well. There is often more than one way to work out an equations of motion question. I didn't want to show all possible methods here though. Well spotted!
At the projectile's maximum height, its vertical velocity is zero. Before this point, it will have a positive velocity (if taking upwards as the positive direction) and after that point, it will have a negative velocity.
In the lesson video I go over the 4 equations of motion. As far as equation selection goes, you just have to select one where the only unknown is the quantity you're trying to calculate. There are other points such as knowing the acceleration due to gravity, applying sign convention (which direction to take as positive) and the fact that a projectile's vertical velocity is 0 at maximum height. If you've got any questions - just ask!
Sir but we can do it without even taking the help of equation of motion. So can you show that in what cases we must have to take the help of equation motion
That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
I take it you're talking about question 3? At maximum height, the vertical velocity is zero. Taking upwards as positive, vertical velocity decreases from its initial value to zero (at maximum height) on the way up.
I'm in the process of trying to add Hindi subtitles to the 'Equations of motion' video. Hopefully this will help more students get something out of it.
Brushing up on yr.11 Physics and this is the best UA-cam channel I've found :)
Thank you! Good luck with any exams you have coming up.
@@MrSmithsPhysicsonline Thank you :)
This was extremely helpful. I'm doing college physics right now without having taken high school physics so I really need videos this helpful. Thank you so much.
Hope the studies are going well.
tysm If it wasnt for ur video i would've failed my Physics quiz! Could not have done it without u!!!
you are insannnne thank u so much u saved me for my test
I'm taking that as an insannnne compliment!
I'm from another country but your lecture satisfied me much than my school teacher. Thanks for this explanation. I hope i can give my best in my physics test :')
N.B. : In our country, we take upwards as negative and downwards as positive [in primary] but when we get in Higher then it will be vise-versa 🙂
You are most welcome!
Are you from India
this actually really helps. Thanks G. saved my life for this test. u a real 1
Thanks G - you a real 1 too!
😒😒😒😏😏
Good job Mr.Smith.
Merci beaucoup!
Tq very much it is very use full to me
Thank you - would another examples video be useful?
Yes
best physics explaining channel
That would be nice! Thank you for the compliment. All the best.
Sir this was awesome; please make another on relative velocity.
There is a past paper question on relative velocity - take a look at my other videos.
I always have a problem with finding out which equations to use any methods to figure it out, also thanks for the videos it’s a great help
With the equations of motion, there is often more than 1 equation you could use. You just have to pick one where you know every quantity apart fro the one that you're trying to find out.
As Mr. Smith points out, there is often more than one equation applicable, to different questions.
You can also sometimes use two equations, that is, in both questions one and two you can calculate the time, t , using the equation
s = ( u + v / 2 ) t , and then substitute u , v , and t , into v = u + at to calculate the acceleration.
Making a (the acceleration) the subject, such that, a = v - u / t sometimes makes the calculation very clear.
Just some suggestions. 😊
Thank you very much
Thanks sir,this video helps me lot to understand this equation.thankyou so much sir for making such video
Thanks for the nice comment!
Hello i need your help how you get -9.8? And why -ve and the ball thrown upwards (its reach max. Hight)
9.8ms⁻² is the acceleration due to gravity on Earth. I take the upwards direction as positive so, since objects accelerate downwards (the negative direction), this means that a=-9.8ms⁻².
Thank you 😊💕
You're welcome 😊
Nice way of teaching 😘😘😘😘
Thanks!
Thanks I just love your videos
You have great taste!
great help to me, you wont believe how long i have been failing to get these right. Now i need projectile motion equations
These are the equations used for the vertical component in projectile motion - if you're happy using them then that's half the battle. Check out my past paper solution video on projectiles for some helpful tips.
Thanks sir
Glad you found it useful - all the best!
thank u God u r like my God who teaches me physics
I'm just a simple Physics Teacher!
HUGE THANKS
Thanks for the comment
great work dude
Thanks dude!
Sir please make more videos i am your big fan make videos on graphical representation of equations
Which equations?
Newton first second and third equation of motion
thank you.. your videos very helpful.
I'm afraid that's knowledge beyond Higher Physics that you'd need to ask elsewhere - there may be a reason for choosing a dopant with lower ionisation level or it could be related to the shifting energy levels which form bands when the intrinsic semiconductor is formed (something that won't occur with the dopant due to its low concentration).
Thank you sir.....
Please make more videos related to "BODIES PROJECTED VERTICALLY UPWARDS"
That's a good suggestion - I'm planning a series of examples videos and this is a good topic to cover.
Gold!
You know it!
Nice ways
Thanks - glad you liked it!
Thnxx alot it helped me and my frnds
Cool - glad it helped.
Man nice explanation keep going on
Cheers! Glad you liked it.
Good explanation ❤
Glad you liked it
Interesting
Well, hopefully it helped. Thanks for the comment.
Thanks ❤
No problem
Awesome sir!!Thankuuuuuu.
Thank you - glad you liked it!
you are awesome
Thank you - glad you liked the video!
Thank you so much.. You've helped me a lot
Thanks for the comment!
Thanks a lot.
No worries - glad you found it helpful.
Legend
I am but a humble Physics teacher.
very useful..thanks
Thank you!
Thankyou so much for this amazing video ❤️
Glad you liked it!!
Thanks
You're welcome!
Please sir i have reversed this video many times and I still don't know how you got _9.8 or is it the way it's given in the exam script that we are going to put it??
The value for the acceleration due to gravity is given in the data sheet for the Higher Physics exam.
Thanks for the video! it helped me a lot^^
Glad you found it useful.
thats was awesome sir
Thank you - glad you liked it.
Thank you from India❤️
Thank YOU from sunny Scotland! Glad you liked the video.
Thank you sir it helped me so much for my 8th class physics?😊😊😊👍👍🙏🙏
Most welcome 😊
Thank you soooooooooo much
Very nice video
You are soooooooooo welcome!
thanks for the help
No problem!
Very helpful ty so much ❤❤❤
Glad you liked it - thank you!
This is soo neat and well done thanks so much also what is the source of these questions?
I wrote the questions myself. At some point, I'd like to produce more and put them in a book or on my website.
@@MrSmithsPhysicsonline that is amazing and it would be even more amazing if a book would be produced!thanks again
so much better than my physics teacher
No comment (I might know them!).
hello, I just rearrange the equation then sub in the known values. i think this would be easier than how you do it.
the reason he does it this way is if you make a mistake rearranging, you get 1/3 but by subbing in values you get 2/3 if the final answer is wrong
That's exactly what I was going to say! Good comment, Paul.
Tnx u helped me
Glad you found it of use!
How does we understand that in which questions we have to prove which equation that's a big problem and also tomorrow is my exam of physics.may god help me
Finding the correct equation is just a matter of noting which variables we know and which one we're trying to calculate. Pick an equation with all those terms in it.
i’m doing the 2020 higher pass paper questions and on question 3, for equations of motion, the marking scheme specified that the heigh and acceleration have to have the same sign. why is this?
I don't have access to the 2020 paper but if displacement and acceleration are both the same sign then they must be in the same direction. Since acceleration is downwards, it must be that the object is falling downwards which is why it's also taken as negative.
In question 2 the s = 1.20 you taked 1.2
It could be worse - I could have taken it as 7.39
thank yooouuuu
Glad you liked it & found it helpful! All the best.
Why was it to the power -2
If you take a look at my 'equations of motion' video, you'll see the derivation for the equation and where that comes from.
Where did you get 0.5 in the third questions in part B
That's just the ½ in the equation s=ut+ ½at²
hey really liked the video but was wondering what type of pen you were using
It's a Pentel sign pen - luckily I still have it so was able to check.
Mr Smith's Physics online thank you very much
How to you know which formulas to use?
In Higher Physics, pupils get a relationship sheet with all the equations written on it. The skill is in identifying which equation to use and in manipulating it in order to solve the problem. In my day, we had to memorise the equations although I'm happier with the situation now.
Please in the 3rd question were did the -9.8ms comes from
That's the acceleration due to gravity on earth - it's found in the data sheet at the front of the exam paper.
Exactly;
Thank you for your teaching.
Please make your videos translation of other languages
I'm not exactly sure how to do that, but I'll look into it.
what the difference between question 3 in this video and the last question in the previous video
One question asks you to calculate the time to maximum height whereas the other asks for time to go up then back down to the initial height. The initial velocities are also different.
It's really helped me a lot...... THANK YOU VERY MUCH......... but I have still one confusion how we know which formula we have to use especially 2nd motion of equation...... I'm really confused where I should use 2nd equation of motion plzzzzzzzzzz help 😕😥
It's the same process with that equation as any other - choose an equation that contains the property you are trying to work out. This should be the only unknown as you should know all other quantities.
is it possible for the displacement to be a negative value because in question 3 for the sign convention i made down positive (cause i was taught to do so..) it gave me the same answer but just negative. should i switch the signs at the end or leave it as it is? also this video was really helpful
You should work through the calculation until you get the negative value then, at the end, you could write that the velocity is ... m/s upwards.
I didn't understand the third question as well as the first and second!!!
Any solution to make it easier to understand..
Btw nice teaching I understand everything you say but I am not sure where all that information is coming from that's all I want to know
Some of the information, acceleration due to gravity, is given in a data sheet at the start of the exam (in Scotland, at least). Apart from that, all values will be given in the question apart from vertical velocity at max. height. Glad it helped.
How did you get 9.8 for acceleration in question 3?
From a previous reply - "This is a value which is given at the start of the Higher Physics examination on the 2nd page - the 'data sheet'. It doesn't need to be calculated." I'm also taking upwards as the positive direction which is why it's negative.
Alright Thankyou also this is a very helpful video👍
Where did you get the -9,8 on question 3
That's the acceleration due to gravity on Earth. The value is given in the data sheet at the start of the Higher Physics paper. In the question, I take the upwards direction as positive, making acceleration negative (objects accelerate downwards).
what pen are you using?
A few people have asked me that - it's a 'Pentel sign pen'. I tried others but this looks good on camera (don't worry - I'm not being advertised!).
thank you. useful video too
For the 3rd question, is it ok to use the formula s= 1/2(u+v)t ? The answer’s still the same
Yes - you can use that equation as well. There is often more than one way to work out an equations of motion question. I didn't want to show all possible methods here though. Well spotted!
From where did u get 0.5 in the last question pls tell me anyone
The 0.5 is part of the equation s = ut + ½ at²
10:07 how did u know that final velocity is zero
At the projectile's maximum height, its vertical velocity is zero. Before this point, it will have a positive velocity (if taking upwards as the positive direction) and after that point, it will have a negative velocity.
how we can know that this equation we can take for this problem i am so confused
In the lesson video I go over the 4 equations of motion. As far as equation selection goes, you just have to select one where the only unknown is the quantity you're trying to calculate. There are other points such as knowing the acceleration due to gravity, applying sign convention (which direction to take as positive) and the fact that a projectile's vertical velocity is 0 at maximum height. If you've got any questions - just ask!
can these examples be considered as uniform acceleration examples other than two
The equations only work for a uniform (constant) acceleration.
Sir but we can do it without even taking the help of equation of motion. So can you show that in what cases we must have to take the help of equation motion
Which equations / methods could you use to answer these questions other than the equations of motion?
I hope it not too late to ask I don't know how the acceleration in the third video became 9•8
That's the acceleration due to gravity on Earth - it's given in the data sheet for Higher Physics.
For number 3 you didn't show us how you got 9.8 ms_2
Please answer
9.8ms⁻² is the acceleration due to gravity on Earth - it's a value that pupils are told in a data sheet, supplied with the SQA examination.
sir how did you find that acceleration @10:36
That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
I did not see anything the writing on the screen is blocking me
Shame - it's a great video!
I got it important to help my boy child
Hope it's helped!
I am in class 8 and it helpful to me
Good stuff - what level is that ? National 5, GCSE? I'm hoping to do videos which help with various courses - what topics would be useful?
some might not be clear why V is 0 ..u gotta explain such
I take it you're talking about question 3? At maximum height, the vertical velocity is zero. Taking upwards as positive, vertical velocity decreases from its initial value to zero (at maximum height) on the way up.
yes thank you.
Please make videos in hindi
The only problem is that I don't speak Hindi, so I'm not able to do that I'm afraid.
I'm in the process of trying to add Hindi subtitles to the 'Equations of motion' video. Hopefully this will help more students get something out of it.
Just a big hand
Glad it's helping!
Okay 😪the questions i have are difficult
You have some equation of motion questions?
Oh acceleration due to gravity
Yes - in the Higher Physics examination, there is a page of constants where g=9.8ms-2 is stated.
Thanks
Glad you liked it - all the best!