You actually don’t understand how much you helped me, I struggled with this theory for about 2 weeks until I came across this video. Thank you very much.
im looking at this after 11 years of you posting it and i just want to say from the bottom of my heart, tysm for posting this and i fucking love you man
This video may turn 10 years old this year but it is still relavent. You sir have my respect and thanks. I hope you see this and know that you have given me hope in my organic chemistry class.
I was struggling on an ALEKS assignment for hours and after watching this I had no problem. That’s the God I serve!! He made a way out of no way!!! Won’t he do it !! Hallelujah. Yes, I am hyped.
i spent my whole life trying to understand this concept but really got to understand this in some few minutes. your video is very insightful. Thank you!
Holy Crap, this is the ONLY VIDEO I have found in the last three hours that actually made any sense!!!!!! I have a final exam tomorrow for university and i have been staring at this stuff for the last three weeks and had no idea what was happening!!!
Omg you people were there before 11 years itself!!now it is of great use for me.... I'm a NEET aspirant.... Thank you so much.......may I know where you are from?
Unfortunately, this method only works with elements that follow the octet rule. Expanded octets, boron, beryllium, etc. would not work for this approach.
I have a good trick FOR ANYONE STRUGGLING - In this trick you will consider atoms as well as lone pairs, U will consider any bond (double, triple, single) all as ONE and any lone pair as ONE. WHEN YOU DO THIS u will add the lone pairs and the atoms (any bond) -1 to get the hybridization. For instance in the first carbon hybridized in the video, there were 4 bonds/atoms no lone pairs -1=sp3. For the O on this video there was 1 (we dont care if its double or single we count as one) and there was 2 lone pairs=3 total number. Minus that by 1 to get sp2 hybridization
Ohh... you great....!! this same thing was taught by our teacher for years.... bt jzt before the exm i watchd this.... and it's so simple... ur smthng great....!!
This is not correct unfortunately the nitrogen is sp2 hybridised, its a bit too much of a simplistic overview. You need to think about resonance and effect of lone pairs, as this is more true to the actual structure
You have to be careful because resonance my make a single bond more like a double bond causing an atom that appears SP3 to actually be SP2; ex. molecular structure of triazole appears to have 2 nitrogens to be sp2 and 1 nitrogen to be sp3 but all are sp2 hybridized due to resonance on the lone pair. This is important when identifying if a molecule is aromatic or not.
***** I'm a month too late, but take an amide for example (Nitrogen bonded to a Carbon with a carbonyl group). Although the Nitrogen has all single bonds, its lone pair of electrons are able to participate in resonance. This involves the formation of a pi-bond and thus the Nitrogen atom is actually sp2 hybridized.
My dear the lone pairs on nitrogen makes it hav 4 grps around it hence sp3 He is absolutely right on everything because even when i use my method like how many groups are sorrounding the atom i get the same answers 4 grps... Sp3 3 grps... Sp2 2 grps... Sp 1grp.... S
Mate......What I have learned in your video in 5 min I could not learn in a 2 years!!!!!!! God bless you!!!!!!!!
joata souza
Lol
Hahaha best comment
Ss it's true
Sir thanks u
Broooo😂😂this is so true
You actually don’t understand how much you helped me, I struggled with this theory for about 2 weeks until I came across this video. Thank you very much.
That was so much simpler than how my professor taught it
Yeah really chemistNATE is epic
@speedo Fr 💀💀
Exactly
why can't it always be simplified and explained this easy !!! THANK YOU SO MUCH
im looking at this after 11 years of you posting it and i just want to say from the bottom of my heart, tysm for posting this and i fucking love you man
So glad to have helped
n=no. of sigma bond + no. of coordinate bond + lone electron pair
if n=2 then sp
n=3 sp2
n=4 sp3
n=5 sp3d
n=6 sp3d2
n=7 sp3d3
Yeah that's BS, the base of my confusion.
Uar a legend mate✔️💪
This video may turn 10 years old this year but it is still relavent. You sir have my respect and thanks. I hope you see this and know that you have given me hope in my organic chemistry class.
Dude made a video in 2011 and I am watching it right now for my midterm. Simply amazing.
I was struggling on an ALEKS assignment for hours and after watching this I had no problem. That’s the God I serve!! He made a way out of no way!!! Won’t he do it !! Hallelujah. Yes, I am hyped.
Oh my god i can't believe it was super easy
I was finding problem in cyclic compounds hybridization class 11 organic
But dude u are awsome❤
wow this video is incredibly simplified. no extra nonsense. straight to the point.
This just made half of this semester make so much more sense right before exams, loved the way you taught wish you stayed another year
2024 Undergrad Student Here and I am THANKING YOU SO MUCH!! YOU have no idea how much this clarified for me.
THANK YOU SOOO MUCH!!! I have a test tomorrow and this was super helpful! Keep making videos like this :)
Thank you so much this has really helped me.
i spent my whole life trying to understand this concept but really got to understand this in some few minutes. your video is very insightful. Thank you!
Will the bond's in benzene will be considered as double bonds
This was amazing, highly recommend to anyone that is confused about hybridization.
U make everything soo simple...please keep these videos coming Nate!
Learned more in 5min than I did in my 50min college lecture on this
Are you a graduate now? :D
Holy Crap, this is the ONLY VIDEO I have found in the last three hours that actually made any sense!!!!!! I have a final exam tomorrow for university and i have been staring at this stuff for the last three weeks and had no idea what was happening!!!
You are Professor by PROFESSION. Thanks for your proFfessional simplicity!
This is actually the reason why I aced my test!! Thank you❤️❤️❤️
*MINDBLOWN* This is such a simple way to remember it!!! Thank you sooooo much!
I paused and found the hybridization after you told how to do so, and for the first time, I finally got something in my good ol' brain :)
Anyone after 12 yearss🎉🎉
Still here !
I was soo confused about this hybridization, but this video made it so simple! now I can go to the exam with full confidance!! thank you soo much!!!
Very good explanation.....That's very easy
life saver 12 years later
Didnt know it was soo simple, I was doing my head in ! chem exam tomoz and you saved me from failing, thanks!
Great job my friend! Congrats
thank you!!!! you just saved my life!
11 years later, still helping a great amount!
The Best Explaination EVER!!! U deserve a subscribe sir!!!
this video is such a lifesaver
Omg you people were there before 11 years itself!!now it is of great use for me.... I'm a NEET aspirant.... Thank you so much.......may I know where you are from?
Hey i am also preparing for neet 2025
at least once a year when i gotta learn chem stuff u help me figure something out i had no clue how to do. ur awesome nate keep it up.
thanks alot.. now i understand what hybridization is. you have no idea how much you helped. thanks again
Best. you helped me learn this in 3 mins, what I've been wondering for about 2 years.
i answered my quiz after i saw this. TOTALLY WORKED! 100% for me :)
The best video for knowing the hybridization ,
This makes my life so much more easier
This is the best comment of my life. Congratulations on the spelling award you never won. Oh snap!
O WOW This method is Soooo easy, u have earned my sub even though its been 9 years
In a second, your tutorial thought me what I have struggled for long to understand. Thank you
Unfortunately, this method only works with elements that follow the octet rule. Expanded octets, boron, beryllium, etc. would not work for this approach.
Thanks for pointing that out, BeH2 would be sp3 per this video, but it’s actually sp
Duly noted. I’m just starting my Orgo 1 class so this will prove useful I believe
@@nathanielboddy Hey Nate,Will the bond's in benzene will be considered as double bonds
Super explanation 👍👍👍👍👏
I have a good trick FOR ANYONE STRUGGLING - In this trick you will consider atoms as well as lone pairs, U will consider any bond (double, triple, single) all as ONE and any lone pair as ONE.
WHEN YOU DO THIS u will add the lone pairs and the atoms (any bond) -1 to get the hybridization. For instance in the first carbon hybridized in the video, there were 4 bonds/atoms no lone pairs -1=sp3. For the O on this video there was 1 (we dont care if its double or single we count as one) and there was 2 lone pairs=3 total number. Minus that by 1 to get sp2 hybridization
U Simplicity is awesome man
Ohh... you great....!! this same thing was taught by our teacher for years.... bt jzt before the exm i watchd this.... and it's so simple... ur smthng great....!!
Many thanks from a new organic chemistry student! Your explanation much better than my TA's explanation of hybridization...
This is not correct unfortunately the nitrogen is sp2 hybridised, its a bit too much of a simplistic overview. You need to think about resonance and effect of lone pairs, as this is more true to the actual structure
It is correct. Nitrogen has a lone pair, but it does not participate in resonance.
Zemzem is correct. Nitrogen is sp2 hybridized because it participates in resonance with the carbonyl. This video is incorrect.
I just checked with my orgo professor. That is sp3 not 2
True only use this video in inorganic chem. It goes wrong when it comes to Org Chem
Yeah.
u made this so simple thank you omg ive been confused about this for years
BeH2 would be sp3 per this video, but it’s actually sp. As Nate mentioned, it works for C,O,N, but not every element
You have to be careful because resonance my make a single bond more like a double bond causing an atom that appears SP3 to actually be SP2; ex. molecular structure of triazole appears to have 2 nitrogens to be sp2 and 1 nitrogen to be sp3 but all are sp2 hybridized due to resonance on the lone pair. This is important when identifying if a molecule is aromatic or not.
I have an o chem exam tomorrow and nomenclature and hybridization were giving me trouble. Thank you for all your help! :)
you are a genius teacher
You are a life saver. Thanks so much from the bottom of my heart.
You saved me lot of time. THANK YOU!
You made it a lot Simple.... thanks a lot....
Thank you so much boss; you're a national treasure.
Thanks for explaining this much easier
This was just what I were looking for!
you're so goated for this bro
This makes so much sense!
This should be recommended to me UA-cam!!!
Why didn't you?????????????
thank you so much! i can't believe its so easy, i never understood this!
I didn't know it was this easy. Thanks mate!
Speechless...its... genius
People who know to simplify shit like this are the real superheroes.
His sketch pens are so good!
literally Dollarama
THANK YOU FOR EXPLAINING EVERYTHING SIMPLE AND UNDERSTANDABLE !!!!!!!!!!!!!!!
Thankyou god cause I have my first organic chem exam ina few hours!
What about an empty orbital, or unpaired electron? Do the same rules apply?
YOU ARE THE GOAT THANK YOU
You made it so much simpler than my teacher and the textbook.
You are so clear and concise!! I really appreciate this video... thank you!!
thank you so much for making it that easy
ty! New favourite youtube-explainer
Very helpful sir...
Thanks you so much.You make it look so easy..I have a BA in chemistry ..when i took this 7yrs ago, I never understood them but now I do..
lucky to find your video!! thanks man
Should come in handy in my exam tomorrow. Thank you :)
This was an amazing video man I learned a lot this five minutes that I struggled to learn in an hour long classroom session!
Thank you so much Nate
Just what I was looking for. Thank you so much!
your chart doesn't always work just so you know. If you have pi bonds in conjugation with a carbon atom that has lone pairs it changes.
Honestly I can't remember but I know it's not as simple as what is shown in this video
***** I'm a month too late, but take an amide for example (Nitrogen bonded to a Carbon with a carbonyl group). Although the Nitrogen has all single bonds, its lone pair of electrons are able to participate in resonance. This involves the formation of a pi-bond and thus the Nitrogen atom is actually sp2 hybridized.
My dear the lone pairs on nitrogen makes it hav 4 grps around it hence sp3
He is absolutely right on everything because even when i use my method like how many groups are sorrounding the atom i get the same answers
4 grps... Sp3
3 grps... Sp2
2 grps... Sp
1grp.... S
Thank you! You made it so much easier for me!!
you made this sooooo simple! thank you so much!
Best explanation
really helpful thanks
You're better than my professor
You just saved my life! Thank you so much!
Great explanation! I completely understand this now!!!!
Omg thank you so much!!!! im going to be so much more confident for my first midterm!!! THANK YOU!!
This was helpful but it would be nice if you could explain the reasoning as to why no multiple bonds = sp3, one bond = sp2.
+Badri Baskaran That's what class is for ;)
+Badri Baskaran If you watch his other video where he explains hybridization and the concepts of it, you'll understand why!
Thanks so much, first time I got it right
Dude you are great !! I have a final today and your videos are so helpful ! Thanks !!!!
This is so helpful!!
Thank u so much!! That was just enough, precise and easy to understand ❤️
Quick question will this only work for carbon nitrogen and oxygen or will it work for the other atoms to ?