Astrophysics: Binary Star System (9 of 40) Velocity Curves of a Binary Star System

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  • Опубліковано 1 жов 2024
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    In this video I will explain the velocity curves of a binary star system.
    Next video in this series can be found at:
    • Astrophysics: Binary S...

КОМЕНТАРІ • 25

  • @novalynnleilashea
    @novalynnleilashea 5 років тому +10

    I have no reason to learn astrophysics and used to be afraid of math but here I am, learning all of this just because I was brought here through taking a college astronomy lab. What a superb professor, you have a social sciences person learning astrophysics and comprehending it. Bravo.

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +1

      Good for you! Enjoy. There is an amazing universe out there.

  • @Himadri.S.Debnath
    @Himadri.S.Debnath 2 роки тому +2

    Hey, how did you get 40 km/s average speed?

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +1

      The whole system (M1 and m2) are moving away from us at 40 km/hr. The is the average speed of both masses. [(160 km/hr + (- 80 km/hr)] / 2 = 40 km/hr

    • @Himadri.S.Debnath
      @Himadri.S.Debnath 2 роки тому +1

      @@MichelvanBiezen Thanks

  • @deep9277
    @deep9277 4 роки тому +2

    sir, how will you find the velocity of barycentre when the relationship between mass is not given(only the radial velocity plots for both stars are given).

  • @basilazeem974
    @basilazeem974 4 роки тому +1

    Thanks, this question came for an entrance exam for colleges in India!

  • @0219-n1e
    @0219-n1e 5 років тому +1

    I think your jokes are scientifically arranged and calculated for better understanding of the science. Nice

  • @NeeroxFox
    @NeeroxFox Рік тому +1

    I'm not even studying astrophysics (i'm studying languages and history) , but i have a big interest in astronomy. So thank you for sharing this for the public, sir! This is fascinating!!!

    • @MichelvanBiezen
      @MichelvanBiezen  Рік тому +2

      It is indeed amazing how much information they can pull out of the observations we make over such large distances. Enjoy! 🙂

  • @Purple-Hearts
    @Purple-Hearts 2 роки тому +1

    Bless this man. Unfortunately my professor for my PHS class only legitimately lectures on a few slides in class, which leaves to find additional learning resources. Your videos have helped tremendously! Thank you!

  • @prodTyeDye
    @prodTyeDye 3 роки тому +1

    Good video, even though I suck at math the explanations were good enough to make actual sense of things!

    • @MichelvanBiezen
      @MichelvanBiezen  3 роки тому +1

      Then we accomplished what we set out to do. We try to make the videos in such a way such that someone who doesn't like or understand the math can still get the concept. Enjoy!

  • @kathandesai5896
    @kathandesai5896 3 роки тому

    Why velocity of the star which is receding considered as positive and of the star which is approaching considered as negative?

    • @MichelvanBiezen
      @MichelvanBiezen  3 роки тому +1

      It follow the convention of the position vector and the velocity vector with us at the origin in spherical coordinates. That is why "away" becomes the positive direction,

    • @kathandesai5896
      @kathandesai5896 3 роки тому

      @@MichelvanBiezen Thank you very much sir!

  • @shvix_akb8531
    @shvix_akb8531 3 роки тому +1

    can we find out what tangential velocity respect to time is?

    • @MichelvanBiezen
      @MichelvanBiezen  3 роки тому +1

      If we can determine the radius of the orbit, yes.

    • @shvix_akb8531
      @shvix_akb8531 3 роки тому +1

      Michel van Biezen can you explain plz.we have i,p,and a and want the tangential velocity respect to time

    • @MichelvanBiezen
      @MichelvanBiezen  3 роки тому +2

      It depends on a several aspects. If we assume that the we are looking at the binary system in the plane of the system (or nearly in the plane), the the maximum radial velocity will be equal to the tangential velocity. But if the system is at an angle, the we must divide the maximum radial velocity with the cos (angle). There can be a second angle we need to consider, if the perpendicular to the plane of the orbit is also rotated. So you see that it can get quite complicated depending on how the orbit is situated relative to our line of sight.

    • @shvix_akb8531
      @shvix_akb8531 3 роки тому

      @@MichelvanBiezen thank you so much!! and thank you for all your helpful videos

  • @prakashkumarprakashkumar3959
    @prakashkumarprakashkumar3959 5 років тому +1

    Please make video on dark matter and dark energy