Astrophysics: Binary Star System (7 of 40) Sun-Jupiter Barycenter
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- Опубліковано 9 кві 2017
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In this video I will explain and calculate the barycenter between the Sun and Jupiter.
Next video in this series can be found at:
• Astrophysics: Binary S...
what do you think about 342000 and electromagnetic inductive cavitation
Thank you!
Very informative. Thanks
Glad it was helpful!
So... Reasking the same ole question: how does having multiple sizeable objects affect a host star's barycenter and is this why orbits are elliptical? I really gotta know! 😲
EDIT: I will watch the rest of the videos. I read some comments and your replies. Still confused, but will watch the videos and hope to untangle my brain. 😂
A good example of that is our own solar system. Earth is being pulled by all the other planets, especially Jupiter and Saturn, in periodic fashion, such that the ellipticity of the Earth's orbit is constantly changing. Thus it is the gravitational pull of other objects in each solar system that in part causes the orbits to be elliptical
@@MichelvanBiezen AhHAAA! I KNEW it was something like that! (Not really 😂) Thanks!
If the sun orbits the barycenter, and we know its initial position from the barycenter, is it then possible to find the initial velocity of the sun as it orbits the barycenter.
I think he mentioned the time it takes the Sun to orbit the barycentre, so with the formula v=∆x/∆t. With ∆x being the distance between the centre of the sun and the barycentre and ∆t being the time it took the sun to orbit the barycentre.
Sorry, it seems that I have been mistaking stating that ∆x equals the distance between the centre of the Sun and the barycentre. ∆x should obviously be the circumference, formula: 2π x r. With r being the distance between the centre of the Sun and the barycentre.
Question, does the sun have multiple barycenters if it has 12 planets? How do you define barycenter of thr sun and another solar system
I think because the other planets are much smaller, the barycenter of all the other planets compared to the sun lies inside the sun. Jupiter is also twice as big as all the other planets combined. So I guess the other planets don't really affect the sun so much because the gravitational pull of Jupiter is too strong. But indeed, maybe someone who has better knowledge could answer this :)
That's a very good question with a quite interesting answer. The barycentre in our solar system (so the point of mass in common between all planets, comets, astroids and sun) changes all time because of the movement of the orbiting bodies.
What if we are looking for the Mass of the Host star? Only given mass of planet, and their distance? no barycenter.
Then use the orbital velocity equation: Vo = sqrt(GM/R) where M is the mass of the star and R is the radius of the orbit. That is by the way how most masses are determined. (The mass of the Earth is determined by the Moon orbiting the Earth).
@@MichelvanBiezen Thanks, never expected for your reply tho glad i commented. i was just so curious coz i encountered a similar problem before it bothered me till now haha
You earned a new subscriber.
Glad to have you on board. Enjoy the videos.
So first you multiply something by nothing? =0 Why? Then add something to nothing? =something
Why not just start with the something that comes after the nothing?
This is done in order to show the general method of finding the center of mass. It is only zero, because we placed the origin of our coordinate system at the center of the Sun.
nobody can calculate such.
Yeah it's hypothetical
You haven't counted other planets in between
They too must be playing role
Yes, we have ignored the other planets, and yes they do play a role as well, and the role of each will be superimposed on the total. In other words you can calculate the effect of each planet separately and then add them together. But the effect of Jupiter is far greater than the effect of the other planets combined. And the purpose was to show the simple example between two bodies, before working with a more complicated system. (One step at a time).
@@MichelvanBiezen can at barycenter properties of mass can be applied
Center of mass
The barycenter is essentially the same as the center of mass of 2 objects.