Astrophysics: Binary Star System (8 of 40) The Barycenter: A General Approach

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  • Опубліковано 10 кві 2017
  • Visit ilectureonline.com for more math and science lectures!
    In this video I will explain and calculate the barycenter between any 2 stellar objects.
    Next video in this series can be found at:
    • Astrophysics: Binary S...

КОМЕНТАРІ • 34

  • @fatinfatonah
    @fatinfatonah 2 роки тому +10

    The fact tha u guys didnt cut the video is wholesome

  • @mewanan282
    @mewanan282 4 місяці тому +1

    IOAA aspirant here, really being helped out by you sir!

  • @nithin1729s
    @nithin1729s 3 роки тому +2

    Thanks for these lectures!! It helps us a lot 😊

  • @surendrakverma555
    @surendrakverma555 3 роки тому

    Excellent lecture

  • @zakirhussain-js9ku
    @zakirhussain-js9ku 9 місяців тому

    I think free space is an energy field with uniform energy density. Mass changes uniform energy density balance. Energy density increases towards Mass per Inverse Square Law. Difference in energy density induces force field called gravity directed from strong energy density to weaker energy density region i.e. away from mass & not towards Mass. Mass spins & orbits around Point of Minimum Energy Density called center of mass or barycenter. Center/Barycenter of mass pulls the mass, if the mass is in motion it will spin or orbit around this point.

  • @DanielTalla-fv3di
    @DanielTalla-fv3di Рік тому +1

    Very instructive i understood at once

  • @amberi.9083
    @amberi.9083 4 роки тому +2

    How can we find the center mass of a planet and its natural satellites if it, for example, has two moons which have differing X- and Y- frames of reference? How can I find the moons' Y- distances so that I may compute CM(Y)? I cannot find Mars' moons' positions, even on NASA's website.

  • @sharanirt243
    @sharanirt243 3 роки тому

    Useful,thanks🙏

  • @pipertripp
    @pipertripp 5 років тому +2

    What is the justification for equating R1 and the CM. I'm not sure what the rationale is here. Everything that follows makes perfect sense, just not sure how you chose that starting point. Thx. This is a very helpful series.

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +2

      You are correct. That should have been stated R1 is the distance to the CM.

    • @googleyeyes5122
      @googleyeyes5122 2 роки тому

      @@MichelvanBiezen from M1? I replayed this video 3x. It still isn't clear if R1 (bigger mass's distance) is always going to equal CM. For now I am just going to go with it because it is fun learning from you (just discovered your channel like an hour ago). I just need to understand if R2= CM would have produced the same result.
      EDIT: 😔 Yeah, after the 5th time, I finally heard you say that CM was going to be the distance from the M1 to the barycenter. Sorry. I think I continually zoned out for a few seconds at the same part in the video.

  • @johnfairsgoldpanningschool.
    @johnfairsgoldpanningschool. 5 років тому +1

    Simplification.

  • @crehenge2386
    @crehenge2386 7 років тому +2

    What happens to the barycenter if I have a three body system?

    • @MichelvanBiezen
      @MichelvanBiezen  7 років тому +3

      If the system is stationary, the barycenter will stay in place. If the system is moving relative to us, the barycenter will have a constant velocity relative to us. Depending on the masses of the triple system, the force of gravity of each will act on the other two. If there is one large mass (star) and 2 smaller masses (planets) we can ignore the gravitational interaction between the planets.

  • @PhillipSamuel_fsamuel011
    @PhillipSamuel_fsamuel011 5 років тому +1

    Why are the periods of the two objects equal to each other? If they weren't, would the barycenter between them shift as well?

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +1

      Conservation of angular momentum requires the period to be the same, unless an outside force changes the momentum (as is the case in precession).

    • @AngelAlita84
      @AngelAlita84 5 років тому

      @@MichelvanBiezen hello sir, thank you for the video, i would appreciate it if you can really describe the ratio part better with examples. I am kind a confused a bit...thanks in advance sir! god blesses you!

  • @leandromonteiro3002
    @leandromonteiro3002 2 роки тому +1

    i was wondering what will happen if the M1 turns into a black hole and keeps the same r1 and loses mass, but is orbital velocity are the same! Is the binary sytem still gravitationally bound?

    • @MichelvanBiezen
      @MichelvanBiezen  2 роки тому +2

      First, if the object turns into a black hole and does not change its mass, then there would not be any difference in the orbits in the system. Second, if the object changes mass (regardless if it becomes a black hole or not), the orbits in the system would change.

    • @leandromonteiro3002
      @leandromonteiro3002 2 роки тому +1

      @@MichelvanBiezen Thank you! I really love ur videos, keep doing it!

  • @johnfairsgoldpanningschool.
    @johnfairsgoldpanningschool. 5 років тому +1

    So the reason PI is used is because there is not a constant?

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +1

      Yes, the distance around a circular path = 2 x pi x R

  • @ramjanymohammadsalman7713
    @ramjanymohammadsalman7713 5 років тому +1

    what is the barycentre or how to find the barycentre

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +3

      The barycenter is the same as the center of mass. We have videos in the physics playlists that show you how to find it. PHYSICS 14 CENTER OF MASS

  • @bunnyTTtango
    @bunnyTTtango 3 роки тому

    Do you have red shift and blue shift videos

  • @prakashkumarprakashkumar3959
    @prakashkumarprakashkumar3959 5 років тому +1

    It's joke or not

  • @gr8pointsbytanayshah17
    @gr8pointsbytanayshah17 Рік тому +2

    Hello Sir This is Tanay and I have mad a theory about White Holes, can u share me your email so I can send you. And Thank you for very nice videos

    • @MichelvanBiezen
      @MichelvanBiezen  Рік тому +1

      Tanay, my e-mail address is mvanbiezen@elcamino.edu, but at this time I don't have any time to read it. Perhaps some time in the future.