Converting from Parametric to Cartesian Form (How to) - Algebra Tips

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  • Опубліковано 7 лют 2025
  • Looking for college credit for Algebra? Enroll at btfy.me/6cbfhd with StraighterLine. Converting from Parametric to Cartesian Form (How to) - Algebra Tips. Cartesian to Parametric: • Converting from Cartes... Given a set of parametric equations, convert them into a Cartesian equation or vice versa.

КОМЕНТАРІ • 11

  • @lukemiller1664
    @lukemiller1664 9 років тому +12

    Thank you. That helps a lot. My teacher did not teach us this, so I had to learn this on my own.

  • @danieldoremus6431
    @danieldoremus6431 10 років тому +1

    My professors only went over how to work with trigonometric identities to solve these. Never once was it stated to solve for t and set them equal to each other! This is so much simpler than they made it!

  • @timomenz6901
    @timomenz6901 27 днів тому

    There exists a general way for cartesian to parametric: f(x) -> (x = t, y=f(t))
    But is there no general way for the other way around (parametric to cartesian)? if i have a parametric equation with x = a(t) and y = b(t), there's no way to generally describe this in cartesian form as f(x)?

  • @zecorezecron
    @zecorezecron 11 років тому

    This is pretty useful. Thanks for the help.

  • @SchoolAndUniversity
    @SchoolAndUniversity 12 років тому

    thanx for this share enjoyed a every bit of it

  • @jakevalencia427
    @jakevalencia427 9 років тому

    Very helpful! Thank you!

  • @Bryan_K_27435
    @Bryan_K_27435 6 років тому +2

    2D ones are pretty straightforward, need help with 3D ones. Back to google search!

    • @Dish.Washer
      @Dish.Washer 3 роки тому +3

      yoooo I'm looking for that exact method. Did you ever find out 2 years ago

    • @Sandwich3
      @Sandwich3 Рік тому

      @@Dish.Washer same, did you ever find out 2 years ago?

  • @melisha4640
    @melisha4640 8 років тому

    Thanks, was never learnt this now I know.

  • @jaydonmiller4770
    @jaydonmiller4770 6 років тому

    This was really helpful, thank you!