A Nice Algebra Problem

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  • Опубліковано 1 січ 2025
  • Let's solve a question on Algebra!
    #simplification #factorization #algebra #algebratricks #algebraformula #mathsolympiad #icseboard #icse #icsemathematics #cbsemaths #cbseboard #squareroot #simplification_with_tricks #simplification_tricks #simplify #simplifyingsquareroots #cbsemaths #maths #matholympiadproblem #mathematics #mathstricks #unitedstates #unitedkingdome #canada #indonesia
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КОМЕНТАРІ • 3

  • @9990010
    @9990010 Місяць тому +1

    👏

  • @Ramkabharosa
    @Ramkabharosa Місяць тому +2

    bc = 200 & ca = 300 implies b/a = 2/3. So a = 3b/2. Since ab = 100,
    (3b/2).b = 100 which implies b² = 200/3 = 600/9. So b = 10√6/3.
    ∴ a = 3(10√6/3)/2 = 5√6 & c = 300/a = 300/5√6 = 300√6/30 = 10√6.
    Hence a + b + c = 5√6 + 10√6/3 + 10√6 = (55√6)/3 .