Thermodynamics and P-V Diagrams

085 - Thermodynamics and P-V Diagrams
In this video Paul Andersen explains how the First Law of Thermodynamics applies to an ideal gas in a piston. A pressure-volume graph can be used to determine the type of thermodynamic process. Included is a discussion of and P-V diagram for isothermal, isovolumetric, isobaric, and adiabatic process.

[@ECOMMUSK]

Thanks. Having to go to class to learn this is very annoying if you professor isn't good. You've saved me much time.

[@thesyzygy7672]

Mr Anderson I really enjoy your videos. You are a great teacher, sir.

[@urwaimran1487]

Yes that was helpful. You are the best teacher ever.

[@osama_alsafi]

As always, Thank you, Bozeman. Very useful

[@winner1338]

the best explanation i have seen

[@coolsnowstar35]

saved me from confusion! simple n effective..

[@roopalagarwal439]

For the first time I could understand it well! Thanks a lot...

[@scally9341]

Thank you Mr. Andersen very cool

[@matthias3864]

Thank you soo much, very helpful video. Well done!

[@archerdev]

Excellent explanation. Physics bless you sir, Thank you.

[@amirhosseinlashkari]

Awesome, sir. ❤

[@dhananjaysangle7982]

excellent presentation skill sir

[@mpumelelokurata2440]

Very insightful!!! 😇😇👏

[@ezanagebregziabher5981]

all explanations except isobaric are satisfying.

[@pratikprajapati9133]

which software you are used for making pv diagram and other graph?
please give me name of the software

[@AsandaHlongwane-zo4wq]

Its simple and straight forward

[@shaikhamohammed1939]

thank you professor ;)

[@hvactechniquemep4525]

Thanks so much teacher

[@Englishcandy555]

very helpful ,,thnkew

[@haseebh93]

What software are you using for making the graphs

[@RogueNiNja99138]

Mr AndersonThe units in the PV graph are wrong the unit of pressure is pascal and volume has meter cube at 3.56 .Thank you for this helpful videoRegards

[@ottoduke8942]

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@Otto Duke definitely, I've been using instaflixxer for since november myself :D

[@jacobmoje4553]

hello.... please add a video calculating "workdone" at the moving boundary of a simple compressible system.

[@ramzinasereddin8840]

thank you a lot

[@sulekhaharrish5582]

Brilliant video. A quick correction for the example you gave at 1:20. This is an isothermal compression, therefore the work done by the surroundings on the system actually causes heat to exit the system, NOT a change in the internal energy. The internal energy stays constant (0 = Q + W hence -Q = W)

[@maxtruong187]

Thank you i have always ask why deltaU=0 in isothermal. Just know it only for ideal gases :)

[@anilsharma-ev2my]

I pressed an empty closed cold drink 🍼 bottle so how i know work done by me
2 liter empty bottle closed and pressed by me so how i know work done by me ?
Pressure and volume of close bottle are changing but where the volume increased if bottle is closed ??

[@miran3862]

Then there was no work done w=-P∆V
0=x×O
0=0

[@SurajKumar-fy9ok]

it was helpful

[@natubhaidave9035]

Unit of pressure and volume are exchanged in graph in this video

[@Abdulrahman-wo2ob]

Can you explain "polytropic" process, and is it related to "isentropic" process

[@carultch]

Isentropic is a special case of polytropic. Isentropic means constant entropy, which happens for reversible processes with no heat transfer (i.e. adiabatic/quasistatic or adiabatic/reversible).
Polytropic processes are governed by the relationship of P*V^n = constant, where n can be any positive real number including infinity.
For n=0, we have a constant pressure process. V^n reduces to 1 no matter what volume is, implying that P=constant
For n=1, we have a constant temperature process assuming an ideal gas. The process is equally sensitive to changes in volume and pressure, such that pressure and volume each change by each others' reciprocals.
For n=infinity, we have a constant volume process. No matter what P is, V^n will dominate the expression, implying that V is constant.
The case of isentropic processes occurs when n=k (some books use gamma), where k is the heat capacity ratio. k is a substance-specific value. For air and other 2-atom elemental gasses like it, k=1.4. For a single atom gas like helium, k=1.67. It has to do with the ways that the gas molecule can store energy in addition to pure translation.

[@JatinUppal]

the slope of polytropic process will be more or less steeper than adiabatic process??

[@carultch]

Not enough information. We'd have to know where n of the polytropic process is, relative to the adiabatic index k.

[@kinggame6092]

Useful

[@anilsharma-ev2my]

What is total work done by atmospheric pressure at globe level ???

[@carultch]

How much work do you do pushing against a rigid wall? That's how much work a static atmosphere is doing on our planet.

[@ritikjain6114]

thnk u sir

[@mahalakshmikaki1305]

How is more work is done by the isothermal than adiabatic

[@yashd20]

Graph has reversed units of Pressure and Volume

[@elijahgemmill2000]

It's really frustrating when lecture upon lecture teaches you less than this 8 minute video. Thanks.

[@stimulantdaimamld2099]

great

[@jehangirkhankhattak8002]

hello sir, you have a unit mistake on the diagram.

[@Random-om8rq]

DAAAAAAAMN BOIIIIIIIIII Noice stuff

[@afsanakhan470]

Pls make video 💡⏩topic =enthalp❔

[@floriskleinestaarman3200]

I am sorry I say this, but I think you made a mistake in your explanation about internal energy. I have learned that heat is equal to internal energy (dU) + work (dW). So this means instead of dU=Q+W the formula must be dU=Q-W, because of the formula: Q=dU+dW ofcourse. But I could be wrong about this....

[@didyouknowmyname1965]

Well u r right ,the main formula. Is U= q+w but when we put formula for work ie. - P∆v it will become U=q-w

[@DaveShree]

Heat exchange dq is, dq=du + pdv or du=dq+w because w=-pdv.

[@alex_h4833]

My teacher is making us watch this

[@beelapse3711]

got it

[@vaibhavvvvv]

Q= ∆U + W right?

[@BlueDemonBoi]

Vaibhav Rokde It should be Q=U-W

[@carultch]

Depends on what sign convention you assign for the meaning of positive work, positive heat, and change in internal energy. The sign convention is arbitrary, and it is best to always interpret the sign of your results in words, to avoid confusion. And follow the sign convention given in your class.
I'm accustomed to the heat engine sign convention, where heat added to the system is positive, and work done by the system is positive. Thus, Q=deltaU + W is correct in that sign convention.

[@sebastianfritz1943]

Finals tomorrow, this is deal for fial reviewing :D

[@ZimmMr]

Isn't Delta u = Q-W?

[@minukjeong7647]

Yes it is.

[@carultch]

Depends on what sign convention you give for +Q and +W. I'm accustomed to +Q being heat added to the system, and +W being work done by the system.

[@mahalakshmikaki1305]

The sign convention also varies in chem and phy textbook all u need to focus is that when to use when

[@musaibkhurshid1033]

❤️

[@wasihunworkie4683]

NICE VEDIO

[@LateNightRituals]

I love u

[@patelp9701]

My name is Jeff

[@narayanlefty]

Nevermind the fact that you look stoned, but good video.

[@c.dayananda8191]

Why are you so hurry.....be slow.....

[@emmanuelbarango4955]

Too fast not detailed enough

[@kambean777]

wrong equation dude first thermodynamics