GLOBEBUSTER'S Wonky Flat-Earth Solar Eclipse Conundrum

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  • Опубліковано 15 січ 2025

КОМЕНТАРІ • 14

  • @macfarmer3972
    @macfarmer3972 8 років тому +2

    Another great job. "Lunatic By definition". Funny . and of course Luna Tic(ed) refers to those who are crazed by that body (and "they" seem to be ticked by all other bodies, physical and otherwise, and myopically partial to their own and their necessitatedly contrived mommies, like infants). The FEers may not be ready to leave the security of their impenetrable looping thought processing, so for now your small choir will enjoy your creative contributions to thinking without emotional boundaries.

  • @TheEclipsonaut
    @TheEclipsonaut 8 років тому +1

    Just for showing the principle, your calculations are spot on.
    Alas, even if your results were of by only one millimeter these guys would not be satisfied.
    Good job, thank you.

    • @thequagmire3164
      @thequagmire3164  8 років тому +1

      Yeah, I know it's probably futile. I'm doing this partially for personal entertainment though, just as an intellectual exercise. I'm actually making an addendum video that will include some other adjustments as well as apogee-perihelion and perigee-aphelion results.

  • @thequagmire3164
    @thequagmire3164  8 років тому +1

    I made a follow-up to this video. See: ua-cam.com/video/DLYwTUoubvk/v-deo.html
    Basically, I adjusted the Sun-Moon distances slightly by subtracting the Earth-Moon distances from the Earth-Sun distances. This has minimal effect, reducing my previously calculated 71 mile shadow diameter to about 65 miles.
    Then I considered asymmetric cases: Apogee-perihelion and perigee-aphelion. I should have done this originally, since the perigee-aphelion gives the greatest shadow size of 133.9 miles.
    I also made some new diagrams to try to better illustrate what I was talking about, and provided the formula I used along with the spreadsheet values if anyone would like to play with the math.

  • @SqueakerAlpha
    @SqueakerAlpha 8 років тому +1

    excellent job. you would have to take axial tilt into account for distance from earth to the moon. your result was extremely good.

    • @thequagmire3164
      @thequagmire3164  8 років тому +1

      I'm working on an addendum video. Although I'm not taking the axial tilt into account, I'm doing the calculations for apogee-perihelion and perigee-aphelion. I didn't stop to realize before that these are kind of working against each other and that the perigee-aphelion is what gives the largest shadow. With this in mind, it seems like the 2017 eclipse will be a pretty average.

    • @SqueakerAlpha
      @SqueakerAlpha 8 років тому +1

      The Quagmire
      just a thought but stellarium gives a bunch of info on sun and moon positions and distances.

  • @SqueakerAlpha
    @SqueakerAlpha 8 років тому +1

    try a light thats bigger than the object - you get a smaller shadow.

  • @heiknuuwter
    @heiknuuwter 8 років тому

    all hands on deck glenn.
    did you sign off on this. if even the research guy have to make video's now. you know there in trouble. good tech in the video but it was'nt great.
    keep on trucking