Easiest way to solve Op-amp questions/ Op-amp nodal analysis.
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- Опубліковано 14 жов 2024
- In this lesson, you will learn how to solve op-amp circuit problems that have two op-amp. The Op-Amps are ideal.
The best way to solve op amp question is to use nodal analysis. Pick any node and consider all the currents are either incoming or outgoing. then add the voltage difference between two node divided by resistance between these two nodes.
Consider the circuit at the input of an op amp. The current flowing toward the input pin is equal to the current flowing away from the pin (since no current flows into the pin due to its infinite input impedance). The same cannot be said for the output, since the op amp can source or sink current.
#Op-amp
node analysis
#opamp solved example
#Analog integrated circuit
#analog
How did 1/2000 + 1/1000 + 1/2000 made up to 2000? Shouldn't it be equal to 1/500?
You’ll still get the same answer, but leave it in terms of k
Very well explained ma'am! Thank you...
Thanks! This is an absolute hack. Great job
Amazing Vid on Op-Amps was struggling a lot and now I got 98% on my Op-Amp exam. I can't thank you enough?
Thank you. Please like and subscribe my channel.
Thank you very very much! what an amazing nice cool video!
Very helpful....but plz improve volume
Ok next time
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Va=1V,Vb=0V, Vx=2V, then for thw middle 2Kohm resistor, there should a 1mA current from the right to left. However in the former part we know the current for the upper 2Kohm is from left to right and it is 0.5mA. How to understand here?
Thanks sister, keep up the good work
very helpful thank you
Glad it was helpful!
Thank you this was very helpful
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This is an inverting op-amp .... answer will be in negative??
This Circuit has two inverting amplifiers. so output will be positive.
Thank you very much!
Thanks 😊👍🙏💯
👍
Thank you ma'am
Just learn LTspice and would do that and much more, and far faster, but to learn manual is good to understand matter.
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can u give me the pdf of this solved problems
You should understand first what is the circuit doing before applying any equation....the way you are explaining that is the academic way but in reality or industry nobody understands this way