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Awesome 👏👏I love ur solutions Sir. Thanks for the work you do.Kindly let me know the software you use for making these videos.
Thank you.It's a Samsung Note
Wow. When I was solving this, I used the same variable (x) when I was using substitution!Anyway, nice video sir!
Thank you 🙏
That's very interesting equation. I have never seen n! in the quadratic equation until now.😎😎
Thank you
(n!)^2-4n!-12=0x^2-4x-12=0(x-6)(x+2)=0x+2=0x=-2n!=-2 not possiblex-6=0x=6n!=6That's as far as I can go...
As for n!=6, the inverse operation would be that n should equal to 3 because 3•2•1=6.
Awesome 👏👏
I love ur solutions Sir. Thanks for the work you do.
Kindly let me know the software you use for making these videos.
Thank you.
It's a Samsung Note
Wow. When I was solving this, I used the same variable (x) when I was using substitution!
Anyway, nice video sir!
Thank you 🙏
That's very interesting equation. I have never seen n! in the quadratic equation until now.😎😎
Thank you
(n!)^2-4n!-12=0
x^2-4x-12=0
(x-6)(x+2)=0
x+2=0
x=-2
n!=-2 not possible
x-6=0
x=6
n!=6
That's as far as I can go...
As for n!=6, the inverse operation would be that n should equal to 3 because 3•2•1=6.