Thank you thank you so much. I'm in a testing company and for so many years I was the grunt. This video course has helped me learn more about vectors using the calculator.
Sure! When you put things in to the argument of inverse tan it is tan^-1(opposite/adjacent) ... most calculators have no way of knowing if you're trying to put tan^-1(+opp/+adj) or tan^-1(-opp/-adj) and the same with tan^-1(+opp/-adj) or tan^-1(-opp/+adj) ... so those calculators will only give you an answer between 0 and 180 degrees and expect you to take the extra step to decide if you need to add 180 degrees or not. Hope this helps, I know it's confusing to write out!
this is really helpful, but i am not quite getting to grips with 15 angle (5pi/8) i already have the magnatude, but not the angle or the other 2 elements, how do you rearrange to work this out?
If the vector is at an angle then we have to use theta and the unit circle. If the vector is just going WEST or EAST we can simply say that WEST or EAST is the direction and not worry about theta. Some physics teachers do not use theta and the unit circle, they instead use something called "bearings" for example, 30 degrees West of North. I don't have a video using bearings but it's pretty easy to find one. Hope this helped!
Vectors don't have x and y intercepts, only magnitude and direction. You can, however, move a vector anywhere you want on an x vs y graph. This is often used for adding vectors. This video might be helpful: ua-cam.com/video/_uGb80Bcuts/v-deo.html
Using the Pythagorean theorem you use 3 for each side (x and y) then solve for the hypotenuse. To do this you have to square each side then add them together (3^2 + 3^2 = 18). This is equal to the hypotenuse SQUARED so you have to take the SQUARE ROOT of 18 to get the actual hypotenuse which is 4.24. We use this procedure to find the magnitude of any vector by using its X and Y components to form a triangle with the vector itself as the hypotenuse. Hope this helps!
"I commit crimes with both direction and magnitude."
Magnificent
OHHH YEAAAAHHHH
Piranha GUN OH YEAAHH
VECTOR! TAHTS ME, BECOUSE IM COMMITING CRIMES WITH DIRECTION AND MAGNITUDE, *O H Y E A H*
Hahaha exactly!
Thank you thank you so much. I'm in a testing company and for so many years I was the grunt. This video course has helped me learn more about vectors using the calculator.
Glad this helped!
I looked up how to vector your physics teacher, was not disappointed…
Thank you so much I wish you were my physical science teacher this was really helpful 🤗
Thank you for the kind words! Good luck with physical science!
@@HowToPhysics lol
O H Y EA H you knew this was coming.
Whoever you helped (which will probably be me) thank you so much
Hahaha happy to help! OH YEAAHHH
WITH DIRECTION AND MAGNITUDE OOOOHHHH YYYYEEEAHHHG
Exactly.
thank you so much ahh, you seriously help me a lot. You were able to clear my confusing head, so thank you a lottttt.
YOURE LITERALLY AN ANGEL,, THANM YOU SO MUCH
i can't thank you enough
This helped a lot!!
Thanks u have helped me a lot, keep up the gud work
Thank you so much hopefully i dont fail another PHY quiz tomo! ill lyk
Thank you! This helped me a lot 💓
Glad it helped!
Very helpful and ur voice is cool! Thank u! I subscribed!
Thanks for subbing!
Nice teaching 👍
Thank you so much
No problem!
You are the GOAT
He is not messi
Thank you it was helpful
No problem!
this is so helpful! thank you so much :)
Glad it was helpful!
Could you summarize the rule of why tan^-1 giving negative angles only work in the 1st and 4th quadrants
Sure! When you put things in to the argument of inverse tan it is tan^-1(opposite/adjacent) ... most calculators have no way of knowing if you're trying to put tan^-1(+opp/+adj) or tan^-1(-opp/-adj) and the same with tan^-1(+opp/-adj) or tan^-1(-opp/+adj) ... so those calculators will only give you an answer between 0 and 180 degrees and expect you to take the extra step to decide if you need to add 180 degrees or not. Hope this helps, I know it's confusing to write out!
thank you so much. I have a question I need help with physics and I was wondering do you do the full lecture of physics
Thank you 😊 so much . It help me a lot
Glad to help!
Can you please guide me about O level studies?
Thank you too
this is really helpful, but i am not quite getting to grips with 15 angle (5pi/8) i already have the magnatude, but not the angle or the other 2 elements, how do you rearrange to work this out?
Great help 🎉
Glad to help!
Thank you! But how can I determine where the position of theta is going to be?
Typically we put theta at the origin and use the positive x-axis as a reference for zero degrees.
You just got....
V E C T O R E D
COMMITTING CRIMES WITH BOTH DIRECTION AND MAGNITUDE
O H Y E A H
This comment warms my cold dying heart.
Thanks very very much
This helped me with my first problem, but how would we find the magnitude of vectors that dont become right angled triangles?
If the two vectors don't make a right triangle you would use the component method: ua-cam.com/video/GOB0P-PyD3g/v-deo.html
@@HowToPhysics alright thankks
Super sir thanks
No problem!
Thank u so much...
You are welcome!
Thanks
hello, why is the angle theta always equal to the direction of the vector?
If the vector is at an angle then we have to use theta and the unit circle. If the vector is just going WEST or EAST we can simply say that WEST or EAST is the direction and not worry about theta. Some physics teachers do not use theta and the unit circle, they instead use something called "bearings" for example, 30 degrees West of North. I don't have a video using bearings but it's pretty easy to find one. Hope this helped!
@@HowToPhysics this cleared everything up. Thanks!
ngl this is not useful in real-life situations we need to break out of the matrix😭😭😭
hello, may i ask a question? are the angles the angle of the triangles?
Yes! The angles at the origin are the angles we are using for triangles.
@@HowToPhysics thank you so much!
thxxxxx
How do you know that the x component and y component are 3? 7:34
He counted the squares
OH YEAHHHHH
OH YEAH!!!!!!
What happens if the magnitude and the angle are the given, but the x and y intercept are missing?
Vectors don't have x and y intercepts, only magnitude and direction. You can, however, move a vector anywhere you want on an x vs y graph. This is often used for adding vectors. This video might be helpful: ua-cam.com/video/_uGb80Bcuts/v-deo.html
PIRAHNA GUN! OH YEAAHHH!
smh you got the title in the complete opposite order!
also OHHH thats where the name and quote comes from!
OH YEAH!😂
I don't still understand, I feel like crying 😢
Lol how did u get 4.24. Please help.
Using the Pythagorean theorem you use 3 for each side (x and y) then solve for the hypotenuse. To do this you have to square each side then add them together (3^2 + 3^2 = 18). This is equal to the hypotenuse SQUARED so you have to take the SQUARE ROOT of 18 to get the actual hypotenuse which is 4.24. We use this procedure to find the magnitude of any vector by using its X and Y components to form a triangle with the vector itself as the hypotenuse. Hope this helps!
While making video first swallow your saliva and speak