I was having that sinking feeling in my stomach after watching my professor’s lecture. The only thing I could think about was failing. Thank you so much for helping us. I learned in 30 minutes what I haven’t in 2 hours with my Professor. Keep up the good work! Thank you, thank you, thank you!! God bless you!
This guy is probably my favorite tutor/instructor! Thank you for the clear explanation and clarity. You have helped me get through several of my courses!
With everything being virtual and being a college student who works, with a professor who honestly isn't that great at teaching. This, is what I needed from the start of my semester. Thank you.
If you want more practice doing exercises of such problems, I recently started uploading videos where I focus on doing math and physics exercises step-by-step. This might help those that want more practice :)
Jason is unique because he explains the nitty-gritty of every bit of problems, he leaves no stone unturned. He is one of the wickedest professor in existence. BIG UP to you father Js.
I just want to understand why we need to learn these crazy stuffs. Why are they useful to human brains and how to be practical with all we get to learn is the reason why I'm here. And this guy, I think he is not doing bad in explaining all these maddness. Salute, Amen!
Thank you so much! I’m super grateful I found your videos!! You’ve helped me so much to clearly understand what everything is and it’s meanings!! I’m taking physics in summer school so the lessons are so rushed and my teacher literally just writes down and narrates the questions instead of having time to explain everything. Thank you so much 😌😌😌😃😃😃
im just half way into The video and i hvae to thank u. The way u get into the nitty gritty and explain everything instead of just asuming we know is 🖐👍👍👍👍. SUBSCRIBED. TATENDA
thank you very much for this lesson, you are the best tutor ever since I started watching your videos I've had a better understanding of most of the chapters i'm supposed to learn and understand in class .,
I never study physics and now I am trying to take college physics in a community college as adult. May I ask any basic knowledge do i need before I start college physics ? I really love your lectures!
Sir, could you please tell me how can I find a full course of this volume? I mean, what is the title of this course on your website? Thanks in advance, I would appreciate your answer!
i hope u understand that you are one of the best teachers in the world that i’ve seen so far at least. this videos especially during this time when online learning is especially challenging for all students trying to teach themselves physics. THANKYOU
Thank you for this video but at 25:11 you comment on how we should be thinking in our minds that SINE will chop for the vertical component and COSINE will chop for the horizontal component. I found this is not true for triangles like yours that are rotated 90 degrees and therefore the COSINE and SINE values are opposite. Instead wouldn't it be best to associate it with the following below? Your scenario will not always be true otherwise. Depending on the orientation of the triangle the Opposite Side and Adjacent Side values can either be Dₓ or Dᵧ. |D|cos(
What are the steps when you aren’t dealing with a right triangle? The resultant vector in the problem I’m working through isn’t oriented head to tail and the angle isn’t starting straight from the x-axis. I’m like two seconds away from withdrawing from my physics course.
Great video! Now I'm looking for your next video but I can't find it. The one for practicing finding component vectors ....could you please send me the link ....thanks sooo much
Thanks a lot u are brillInt your explanation is so much good . Would u make a course of how calculate the shear force & bending moment diagram on a beam
Same exact thing. Nothing changes. Suppose the vector is pointing straight north. That means it is pointing directly ALONG the y-axis. So the angle this vector makes with the x-axis is 90 degrees. So, the X-component of this vector is: (magnitude)*(Cos 90) = (magnitude)(0)=0. So the x-component is zero, which makes sense. Nothing is pointing in the x-direction. The y-component is: (magnitude)(sin 90) = (magnitude)(1) = magnitude. This means that y-component is the full magnitude of the vector. This makes sense because the ENTIRE vector is pointing in the y-direction. I'll leave it for you to work it out for a west pointing vector. Very similar results.
I learn so much more in a 30mins video from him than my 2 hours online lecture. I wish he's my actual teacher. Subscribed!
Awesome!
I was having that sinking feeling in my stomach after watching my professor’s lecture. The only thing I could think about was failing. Thank you so much for helping us. I learned in 30 minutes what I haven’t in 2 hours with my Professor. Keep up the good work! Thank you, thank you, thank you!! God bless you!
it's about time they started assessing folks teaching performance not what letters they have after their name.
This guy is probably my favorite tutor/instructor! Thank you for the clear explanation and clarity. You have helped me get through several of my courses!
With everything being virtual and being a college student who works, with a professor who honestly isn't that great at teaching. This, is what I needed from the start of my semester. Thank you.
If you want more practice doing exercises of such problems, I recently started uploading videos where I focus on doing math and physics exercises step-by-step. This might help those that want more practice :)
Jason is unique because he explains the nitty-gritty of every bit of problems, he leaves no stone unturned. He is one of the wickedest professor in existence.
BIG UP to you father Js.
Learned stats, chemistry, and now physics with you. Thank you Jasonnnnn
i just discovered this channel I would've loved to use this for chemistry because I barley passes
WOW..., I have never seen a teacher like you. You really understand and know
the concept of physics. Thanks lot!!!
Thank you so much ! I’m taking physics over the summer and missed the first day .. was completely lost . Thanks for catching me up
See this video examination in life never give up -ua-cam.com/video/k4w4pak66V0/v-deo.html
@@user-ki6pt2zg1h That is the most random thing i have ever seen xD
The best! More instructors like him are needed on Earth. All students would probably ace Physics. Thank you Sir!❤
I just want to understand why we need to learn these crazy stuffs. Why are they useful to human brains and how to be practical with all we get to learn is the reason why I'm here. And this guy, I think he is not doing bad in explaining all these maddness. Salute, Amen!
It was this guy who really got me over my apprehension toward physics years ago.
The my teacher taught this i was sleeping, than i decided to watch some tutorials, and i found this which really helped me, THANK YOU SOO MUCH 🤗
SIR
Watched yr video on VECTOR COMPONENTS IN PHYSICS--PART1.
1. Well explained and well done.
2. All clear.
THANKS
VATSA INDIA
Srivatsa A.R. NIO BOI HAHAHA m:))
Thank you so much! I’m super grateful I found your videos!! You’ve helped me so much to clearly understand what everything is and it’s meanings!! I’m taking physics in summer school so the lessons are so rushed and my teacher literally just writes down and narrates the questions instead of having time to explain everything.
Thank you so much 😌😌😌😃😃😃
im just half way into The video and i hvae to thank u. The way u get into the nitty gritty and explain everything instead of just asuming we know is 🖐👍👍👍👍. SUBSCRIBED. TATENDA
Thank you so much for this video! I had so much trouble understanding this because my lesson is written and not through a lecture by a teacher.
I was so confused with components but this saved me. He's great at explaining concepts!! Thank you!!
Thanks so much! Good luck!
Math and Science i killed the exam! solid 80 :)
Alexa F congrats!
Your channel is very helpful. You have a way with words that every physics teacher should have. Thank you.
All i have to say is thank you for what you do. These videos r so helpful
You are the best professor!!!! No one does it like you ever.
What a legend, so helpful especially with the smallest details. Thank you.
This guy explains extremely well...thanks
its 3 am and im watching this for my physics class and i can't stop laughing at 10:37 - 10:43 . cutee
Thanks allot sir. This was the only video from which i understood this topic😭🙏
Your lesson was so helpul for me . Love the way you are reducing the stress of physics for millions of students
Thank you so much, am from Uganda, and I have got everything in in time
Thank you very much for this video. It has really helped me a lot. ☺😃😊
Thanks so much for this! I started to fall behind and this is helping me catch up
Just by listening to him, I can tell that he is a very intelligent and sophisticated person.
Thankyou for this video.Very clear and concise in your explanations.
thank you very much for this lesson, you are the best tutor ever since I started watching your videos I've had a better understanding of most of the chapters i'm supposed to learn and understand in class .,
This guy is awesome
I never study physics and now I am trying to take college physics in a community college as adult. May I ask any basic knowledge do i need before I start college physics ? I really love your lectures!
Thanks for the good teaching you are helping alot 👏👏
First thing, amazing. And you have a great handwriting, freehand. Second thing... Is that your door you are writing on??!!
Thanks Mr.You are so powerful
Great video, thank you so much! This lesson was so clear and helped me immensely!
thank you so much professor you are a life saver
This guy was really good ! ‼️
Thanks it's finals week and I really needed this
love the way you explained...
Wow!! Too good.Thank you so much. I have been watching your videos & I learnt a lot from you.Appreciate your effort Sir.
Bravo! he is clear/very elaborate. Thumbs up
Super grateful for your help sir. I like the way you explain things in an easily understandable way 🌺🌺
Welcome!
you are such a good instructor thank you for sharing your knowledge!
For my reference :)
17:14 two dimensional needs 2 numbers
Same goes for 3D needs 3 numbers
Great video, very insightful and essential information. well spoken and the topic was well presented🙂
does pt 2 to this lesson still exist on youtube? If so it would be really helpful to link it in the description❤
I am having the same problem. I love his videos but i never find the part 2.
Thank you soo much, lots of love from india
Nice presentation. I can understand fully.👍🏽
This is so helpful, thanks!
Sir, could you please tell me how can I find a full course of this volume? I mean, what is the title of this course on your website? Thanks in advance, I would appreciate your answer!
i hope u understand that you are one of the best teachers in the world that i’ve seen so far at least. this videos especially during this time when online learning is especially challenging for all students trying to teach themselves physics. THANKYOU
Thank you so much!
actually i wanna give u more than a like and subscribtion to your channel coz of that video, thnx for making everything clear.
You are amazing you helped me a lot about vectors. Thank you!
I'm crying, Thank you very much
What a wonderful tutorial
Amazing explanation, really enjoyed the exercise!
It’s too much helpful lecture 🥀🥀
Thank you sir 🙇🏻♂️
Thank you so much for this explanation
i like how he says "zeee" axis 🥺💙
Thank you for this video but at 25:11 you comment on how we should be thinking in our minds that SINE will chop for the vertical component and COSINE will chop for the horizontal component. I found this is not true for triangles like yours that are rotated 90 degrees and therefore the COSINE and SINE values are opposite.
Instead wouldn't it be best to associate it with the following below?
Your scenario will not always be true otherwise. Depending on the orientation of the triangle the Opposite Side and Adjacent Side values can either be Dₓ or Dᵧ.
|D|cos(
This video is great. Thank you.
Please answer me this : Angle is measured from X axis and bearing is measured from Y axis, correct?
Thank you!! Super clear and helpful
I have subscribed him forever
What are the steps when you aren’t dealing with a right triangle? The resultant vector in the problem I’m working through isn’t oriented head to tail and the angle isn’t starting straight from the x-axis. I’m like two seconds away from withdrawing from my physics course.
Thanks for all your videos
Great video! Now I'm looking for your next video but I can't find it. The one for practicing finding component vectors ....could you please send me the link ....thanks sooo much
Love your videos so much!!! I didn't find part 2 :(
You're the best😊
THANK YOU... SIR...!!!
Thank you for this video ❤️
Thank you for this!
Thank you so much sir it helps to me a lot
Very good professor
Thank you thank you be blessed
look at the guy's bio online...super smart dude.
So happy you liked the lesson. Thanks and good luck in your studies!
What series of physics class is this a part of?
Is the first way can't be detemine which is the x axis and y axis? Please answer my doubt
thank you ! this helped a lot
Welcome!
Jason, MathAndScience.com
Thanks a lot u are brillInt your explanation is so much good . Would u make a course of how calculate the shear force & bending moment diagram on a beam
Thank you so much !!
Thank you 😘
A car travels at 20km due north and 35km in the direction 60° west of north.find the magnitude and direction of the car's resultant vector
Perfect❤❤❤❤
great lesson thanks
this helps!
Good job!
Thank you sooooooooooooooo much OMG again thank you so much
Welcome!
Stupid question - if in 2D case alpha +beta = 90deg, how is in 3D case? is alpha+beta+gamma = 180deg always?
This dudes back must be sore from carrying all the math, physics, and science tutors in the world
Suppose a vector is given directly North or West, how do you break that vector into x and y components?
Same exact thing. Nothing changes. Suppose the vector is pointing straight north. That means it is pointing directly ALONG the y-axis. So the angle this vector makes with the x-axis is 90 degrees. So, the X-component of this vector is: (magnitude)*(Cos 90) = (magnitude)(0)=0. So the x-component is zero, which makes sense. Nothing is pointing in the x-direction. The y-component is: (magnitude)(sin 90) = (magnitude)(1) = magnitude. This means that y-component is the full magnitude of the vector. This makes sense because the ENTIRE vector is pointing in the y-direction. I'll leave it for you to work it out for a west pointing vector. Very similar results.
@@MathAndScience thanx for explaining that
sir thank you so much
Thank you so much sir , I'm a student in srilanka
the vector means a direction right but , why do we need two numbers to calculate a single direction ?
Nice explanation
Thanks!
Thank you
Fantastic!!