I solved it differently as for the equilateral triangular load, I said that 1/2(500lb/ft)(12ft) = 3000lb acting right in the middle of the beam since it is equally and symmetrically distributed along member AC
It could be a great idea, I just knew how to solve right triangles as loading and that is the reason why I decided to split that triangle as two right triangles. :)
thank you very much. I appreciate how you go through every step even if its small. Thank you
Thank you! I am happy the video help you out.
Why did you take 2 thirds of the distance instead of 1 third??
I solved it differently as for the equilateral triangular load, I said that 1/2(500lb/ft)(12ft) = 3000lb acting right in the middle of the beam since it is equally and symmetrically distributed along member AC
this video is PERFECT! thank you
Thank you. I am happy to help.
wouldn't the moment about B also be an unknown? Why isn't it considered an unknown?
it's a smooth pin, it doesn't have a moment reaction force as by definition it is free to rotate.
but how do you know there is a moment reaction at A?
lease let me know if you have any comments or suggestions and also if you have any other problem you would like to go over with.
great video
Thank you!
thank you, this video was very helpful
I am happy it was helpful!
great video i solved it myself, but wanted to confirms my answer.
Thank you so much! this is so helpful😁
Hi Michael, happy to help!
why did you split the 500 lb/ft load ? could you just use the full triangle since it is symetrical?
It could be a great idea, I just knew how to solve right triangles as loading and that is the reason why I decided to split that triangle as two right triangles. :)
What a loser@@LearningbyTeaching
My doctor told us we could split it into two parts using bar CD
If I am not wrong he meant something similar to what we did in this problem :)
Good luck passing statics buddy
My bad bro u were right.
Ur the GOAT!!!!
Thanks Kana, keep it up!