i’m trying to find the function for force applied to the handles to the clamp force. for one pound of force, is it that value divided by 5 (the amount of force applied in the problem)?
when you solve for NA, in your moment at B you mulitplied the x component by the horizontal distance and y component by the verticle when shouldnt it be the other way
Pay attention to the direction of the angle. Since the angle its related to the vertical axis, that means that (Na*Cos) is the vertical component and that is being multiplied by the horizontal distance which is 1.5. Same on the other component of (Na*Sin) is the horizontal component and multiplied by the vertical distance 0.75. I hope this clarifies. (The trick is that the angle is not with respect to the horizontal axis, thats why the change in cos and sines for each component.)
It was a small mistake in which I draw the force Ex going to the right on the second FBD. The force Ex should be going left because should be in the opposite direction from the first FBD. Therefore, that moment of Ex around point B should be negative (clockwise direction) and when you solve and pass it to the right side of the equal sign gives a positive value. An apology for the confusion :)
At 10:18 on the bottom jaw _Ex_ must be to the left,right?
Sir for the bottom jaw shouldn't Ey and Ex be in the opposite direction to the bottom handle due to Newton's third law??
i’m trying to find the function for force applied to the handles to the clamp force. for one pound of force, is it that value divided by 5 (the amount of force applied in the problem)?
why is Ex and Ey facing upwards :) ?
Hello Nabil, when I am drawing the FBD I usually draw my forces assuming positive direction, however, it is more of a preference for each person!
Also, if my answer is negative that means that the direction should be opposite.
when you solve for NA, in your moment at B you mulitplied the x component by the horizontal distance and y component by the verticle when shouldnt it be the other way
Pay attention to the direction of the angle. Since the angle its related to the vertical axis, that means that (Na*Cos) is the vertical component and that is being multiplied by the horizontal distance which is 1.5. Same on the other component of (Na*Sin) is the horizontal component and multiplied by the vertical distance 0.75.
I hope this clarifies. (The trick is that the angle is not with respect to the horizontal axis, thats why the change in cos and sines for each component.)
@@LearningbyTeaching I see thank you! Good thing this homework is due in two days and not tomorrow
@@kosmonavt5125 I am glad the video helped
How did you change the -60 to 60 at the last step when solving for Na?
It was a small mistake in which I draw the force Ex going to the right on the second FBD. The force Ex should be going left because should be in the opposite direction from the first FBD. Therefore, that moment of Ex around point B should be negative (clockwise direction) and when you solve and pass it to the right side of the equal sign gives a positive value. An apology for the confusion :)