I cannot thank you enough. I've looked all over for a good explanation with no luck. This whole time I just needed 14 minutes of clear instructions for it to click. thank you thank you.
You're an amazing teacher, I'm so grateful to have discovered this channel in the beginning of my statics course. Thank you so much ! P.s. you're really funny. I appreciate your livelihood and humor. Blessings unto you sir. 😍😍
Thank you sir for posting these tutoriald. It really helped me alot during my time in taking Statics of Rigid Bodies and Mechanics of Deformable Bodies
hi, for ideal truss the connection shall be pinned , but in steel trusses practically some times the connection are welded with gusset plates , so a welded connection will remain a ideal truss connection or it will have some rigidity and moment?, please explain
no, its the shortest perpendicular distance, if u extend the LOA of the 200 force backward and then take the perpendicular distance from a it comes to 200(3)
thank you for your videos i appreciate it, but i think I need even the little details in every time you solve any problem like how did the moment of point a be positive you sir just wrote it , i really didn't master the whole thing yet thank you very mutch
I know this is 1 year ago, but for those who scroll by and have the same question. Its positive if you spin it counterclock wise and negative if the force moves clockwise im comparison to the pin.
Thank you for the great video! I am just a little lost when it comes to decided whether to put + or - in these equations at the end. Can someone please explain how this works? Thanks in advance!
Point A is a pin connection. Point B doesn't allow it to rotate clockwise so it must rotate counterclockwise. The forces acting upon pushing it clockwise are therefore negative. Point B (By) pushes it counterclockwise hence why it's positive.
Oh thank you so much man. So does that mean the rotation is always going to the side the By is pointing to. Like it would be clockwise if the By is pointing down and counterclockwise if its pointing up(assuming that we have the same situation of course)
You are definitely very confused, so take a few steps back to review the basics. a.) True the pin connection creates zero reaction moment. (if it were "fixed", then yes it creates moment...then you must "add" a variable "Ma" to the FBD). b.) You can take a moment about any "arbitrary point" that you like. Typically, you take a point that can eliminate some variables. Thus, using "point A" as the reference point for your moment, then you "eliminate" variables Ax and Ay in your sum of the moment @ A =0 equation, since there is "no moment arm" for those forces. Hope this make sense and you can catch up.
I cannot thank you enough. I've looked all over for a good explanation with no luck. This whole time I just needed 14 minutes of clear instructions for it to click. thank you thank you.
" You can't resist me"😹😹😹😹I love your sense of humour,sirrrr. Your videos are helpful too
The man who is created for teaching, I have no word to explain my gratitude for you, thank you sir 😍😍😍😘😘😘😘😘
You're the best teacher, thank you so much, I got 80 out of 100 on my statics final exam, all because of you. Thank you so much!
Thank you for such a brilliant video! I was stuck on this subject until I watched. It's actually really simple. Thank you again!
Thanks you Mr. Hanson i was so lost in my statics course before i found your videos. You are amazing!
The real mechanics teacher for me ever. i like it, keep it up.👍👍👍
Amazingly helpful and hilarious. Thank you, Dr. Hanson, for saving us mech e students!
DR. Hanson ,thank you for brilliant introduction to 2d Reactions at Supports., which is another classic topics in mechanics.
I do not know why my professor never explained me like this. This video is very helpfull, Thank you Sir.
This video is truly so helpful, thank you so much Mr. Hanson!
You're an amazing teacher, I'm so grateful to have discovered this channel in the beginning of my statics course. Thank you so much ! P.s. you're really funny. I appreciate your livelihood and humor. Blessings unto you sir. 😍😍
You've helped me so much Mr. Hanson, thank you very much. I wish you health and a lot of luck in life! Warm regards from Indonesia.
Chapter 5!
It would help if you included the chapter numbers on the titles of each videos. Very well explained
very nice video, and also a very nice shirt! im a sucker for automobile related stuff, and AMG is no exception!
Thank you sir for posting these tutoriald. It really helped me alot during my time in taking Statics of Rigid Bodies and Mechanics of Deformable Bodies
hi, for ideal truss the connection shall be pinned , but in steel trusses practically some times the connection are welded with gusset plates , so a welded connection will remain a ideal truss connection or it will have some rigidity and moment?, please explain
Good luck in your semesters guys!
Awesome videos Jeff!! These are a great resource!
you made everything so much simpler to understand. thank you!!
5:33 I am not surprised that possesses a strong grasp of Engineering.
Thank you Dr. You are the best. I making things so simple and easy to understand.
Thanks man, you helped me with my class pre-work!
You're such an amazing prof.!
OMG thank you so muchhh, such a clear explanation and easy to catching up.
Great
Thanks for sharing this lecture Dr
This is exactly what I was looking for ! :D Amazing !thanks!
Amazing stuff Professor!!!!!!!!!!
hats off sir 💖💖💖💖
Sir why on equation of Ma on 200 you Put minus sign but on sum of force you put positive sign?
The 200# is in the positive x-axis and generates a clockwise moment which is negative.
best one ever in statics thanks!
Love your videos thanks. I have only one complaint....so many ads...other than that, you are awesome
If there wasn't two unknowns in the equition wouldn't have to use the dimensions so is using them by choice perhaps?
Love your teaching
Thank you so much
Thank u so much! Very easy to understand.
Thanks, you're a great teacher :)
Thank you very much sir. At the 'fixed support' the reaction Ma is clockwise or counterclockwise?
Noticed that too. I was looking for this comment. I think he drew it wrong. Should be counterclockwise
Thank you so much for the jokes in between your explanations.
shouldn't it be -200(4.5) instead of -200(3) while writing the equation for M(a) ?
no, its the shortest perpendicular distance, if u extend the LOA of the 200 force backward and then take the perpendicular distance from a it comes to 200(3)
if you choose By ,then 200 (4.5) that is make a result 550 ans
@@husseindahirabdulle382 Even if you take the moment at B, it should be -200(3).
I agree. it is 4.5 instead of 3
thank you for your videos i appreciate it, but i think I need even the little details in every time you solve any problem like how did the moment of point a be positive you sir just wrote it , i really didn't master the whole thing yet thank you very mutch
I know this is 1 year ago, but for those who scroll by and have the same question. Its positive if you spin it counterclock wise and negative if the force moves clockwise im comparison to the pin.
Thanks Sir!
Thank you for the great video! I am just a little lost when it comes to decided whether to put + or - in these equations at the end. Can someone please explain how this works? Thanks in advance!
Point A is a pin connection. Point B doesn't allow it to rotate clockwise so it must rotate counterclockwise. The forces acting upon pushing it clockwise are therefore negative. Point B (By) pushes it counterclockwise hence why it's positive.
Oh thank you so much man. So does that mean the rotation is always going to the side the By is pointing to. Like it
would be clockwise if the By is pointing down and counterclockwise if its pointing up(assuming that we have the same situation of course)
very helpful. Thankyou
more videos please
Thank you soo much sir.Much Appreciated
What about rolling friction?
It's assumed that all of the surfaces in these cases are smooth
Why don't you teach calculus too 😭😭 your vidoes on statics and dynamics are super helpful but I'm struggling in a few topics in calc
thanks, it really helps.
This dude is way better than my college teacher
so helpful!
Thank you from Iraq
You just said pins rotate so no moment then you use a moment equation at point A which is a pin. Could you please explain that?
You are definitely very confused, so take a few steps back to review the basics.
a.) True the pin connection creates zero reaction moment. (if it were "fixed", then yes it creates moment...then you must "add" a variable "Ma" to the FBD).
b.) You can take a moment about any "arbitrary point" that you like. Typically, you take a point that can eliminate some variables. Thus, using "point A" as the reference point for your moment, then you "eliminate" variables Ax and Ay in your sum of the moment @ A =0 equation, since there is "no moment arm" for those forces.
Hope this make sense and you can catch up.
I think the distance multiplied by 200 pounds is 4.5 not 6 for the sum of moment about point A
I meant 3 instead of 6
5
Why is Ma is equal to zero?
cos the body is not moving
5:28💀
you cant resist me right, (laugh) nice pun
Civil engineering ??
you gotta lower your into music please hahaha
AYO MR WHITE
I said the same thing 😂😂😂 called him "engineering walter"
Sorry you
Finally i got it yeeeah 🤏