I cannot thank you enough. I've looked all over for a good explanation with no luck. This whole time I just needed 14 minutes of clear instructions for it to click. thank you thank you.
You're an amazing teacher, I'm so grateful to have discovered this channel in the beginning of my statics course. Thank you so much ! P.s. you're really funny. I appreciate your livelihood and humor. Blessings unto you sir. 😍😍
hi, for ideal truss the connection shall be pinned , but in steel trusses practically some times the connection are welded with gusset plates , so a welded connection will remain a ideal truss connection or it will have some rigidity and moment?, please explain
Thank you sir for posting these tutoriald. It really helped me alot during my time in taking Statics of Rigid Bodies and Mechanics of Deformable Bodies
thank you for your videos i appreciate it, but i think I need even the little details in every time you solve any problem like how did the moment of point a be positive you sir just wrote it , i really didn't master the whole thing yet thank you very mutch
Thank you for the great video! I am just a little lost when it comes to decided whether to put + or - in these equations at the end. Can someone please explain how this works? Thanks in advance!
Point A is a pin connection. Point B doesn't allow it to rotate clockwise so it must rotate counterclockwise. The forces acting upon pushing it clockwise are therefore negative. Point B (By) pushes it counterclockwise hence why it's positive.
Oh thank you so much man. So does that mean the rotation is always going to the side the By is pointing to. Like it would be clockwise if the By is pointing down and counterclockwise if its pointing up(assuming that we have the same situation of course)
no, its the shortest perpendicular distance, if u extend the LOA of the 200 force backward and then take the perpendicular distance from a it comes to 200(3)
You are definitely very confused, so take a few steps back to review the basics. a.) True the pin connection creates zero reaction moment. (if it were "fixed", then yes it creates moment...then you must "add" a variable "Ma" to the FBD). b.) You can take a moment about any "arbitrary point" that you like. Typically, you take a point that can eliminate some variables. Thus, using "point A" as the reference point for your moment, then you "eliminate" variables Ax and Ay in your sum of the moment @ A =0 equation, since there is "no moment arm" for those forces. Hope this make sense and you can catch up.
I cannot thank you enough. I've looked all over for a good explanation with no luck. This whole time I just needed 14 minutes of clear instructions for it to click. thank you thank you.
Thank you for such a brilliant video! I was stuck on this subject until I watched. It's actually really simple. Thank you again!
Thanks you Mr. Hanson i was so lost in my statics course before i found your videos. You are amazing!
" You can't resist me"😹😹😹😹I love your sense of humour,sirrrr. Your videos are helpful too
I do not know why my professor never explained me like this. This video is very helpfull, Thank you Sir.
Amazingly helpful and hilarious. Thank you, Dr. Hanson, for saving us mech e students!
DR. Hanson ,thank you for brilliant introduction to 2d Reactions at Supports., which is another classic topics in mechanics.
This video is truly so helpful, thank you so much Mr. Hanson!
The real mechanics teacher for me ever. i like it, keep it up.👍👍👍
You've helped me so much Mr. Hanson, thank you very much. I wish you health and a lot of luck in life! Warm regards from Indonesia.
You're an amazing teacher, I'm so grateful to have discovered this channel in the beginning of my statics course. Thank you so much ! P.s. you're really funny. I appreciate your livelihood and humor. Blessings unto you sir. 😍😍
Good luck in your semesters guys!
Chapter 5!
It would help if you included the chapter numbers on the titles of each videos. Very well explained
Thank you Dr. You are the best. I making things so simple and easy to understand.
hi, for ideal truss the connection shall be pinned , but in steel trusses practically some times the connection are welded with gusset plates , so a welded connection will remain a ideal truss connection or it will have some rigidity and moment?, please explain
Thank you sir for posting these tutoriald. It really helped me alot during my time in taking Statics of Rigid Bodies and Mechanics of Deformable Bodies
thank you for your videos i appreciate it, but i think I need even the little details in every time you solve any problem like how did the moment of point a be positive you sir just wrote it , i really didn't master the whole thing yet thank you very mutch
Great
Thanks for sharing this lecture Dr
you made everything so much simpler to understand. thank you!!
Thanks man, you helped me with my class pre-work!
You're such an amazing prof.!
very nice video, and also a very nice shirt! im a sucker for automobile related stuff, and AMG is no exception!
If there wasn't two unknowns in the equition wouldn't have to use the dimensions so is using them by choice perhaps?
OMG thank you so muchhh, such a clear explanation and easy to catching up.
Love your teaching
This dude is way better than my college teacher
Love your videos thanks. I have only one complaint....so many ads...other than that, you are awesome
5:33 I am not surprised that possesses a strong grasp of Engineering.
Awesome videos Jeff!! These are a great resource!
Thank you very much sir. At the 'fixed support' the reaction Ma is clockwise or counterclockwise?
Noticed that too. I was looking for this comment. I think he drew it wrong. Should be counterclockwise
Thank you so much for the jokes in between your explanations.
Sir why on equation of Ma on 200 you Put minus sign but on sum of force you put positive sign?
The 200# is in the positive x-axis and generates a clockwise moment which is negative.
Thank u so much! Very easy to understand.
best one ever in statics thanks!
hats off sir 💖💖💖💖
Thank you for the great video! I am just a little lost when it comes to decided whether to put + or - in these equations at the end. Can someone please explain how this works? Thanks in advance!
Point A is a pin connection. Point B doesn't allow it to rotate clockwise so it must rotate counterclockwise. The forces acting upon pushing it clockwise are therefore negative. Point B (By) pushes it counterclockwise hence why it's positive.
Oh thank you so much man. So does that mean the rotation is always going to the side the By is pointing to. Like it
would be clockwise if the By is pointing down and counterclockwise if its pointing up(assuming that we have the same situation of course)
Amazing stuff Professor!!!!!!!!!!
Thanks Sir!
This is exactly what I was looking for ! :D Amazing !thanks!
Thank you from Iraq
Thank you soo much sir.Much Appreciated
Why don't you teach calculus too 😭😭 your vidoes on statics and dynamics are super helpful but I'm struggling in a few topics in calc
shouldn't it be -200(4.5) instead of -200(3) while writing the equation for M(a) ?
no, its the shortest perpendicular distance, if u extend the LOA of the 200 force backward and then take the perpendicular distance from a it comes to 200(3)
if you choose By ,then 200 (4.5) that is make a result 550 ans
@@husseindahirabdulle382 Even if you take the moment at B, it should be -200(3).
I agree. it is 4.5 instead of 3
I think the distance multiplied by 200 pounds is 4.5 not 6 for the sum of moment about point A
I meant 3 instead of 6
very helpful. Thankyou
more videos please
Thanks, you're a great teacher :)
thanks, it really helps.
so helpful!
What about rolling friction?
It's assumed that all of the surfaces in these cases are smooth
You just said pins rotate so no moment then you use a moment equation at point A which is a pin. Could you please explain that?
You are definitely very confused, so take a few steps back to review the basics.
a.) True the pin connection creates zero reaction moment. (if it were "fixed", then yes it creates moment...then you must "add" a variable "Ma" to the FBD).
b.) You can take a moment about any "arbitrary point" that you like. Typically, you take a point that can eliminate some variables. Thus, using "point A" as the reference point for your moment, then you "eliminate" variables Ax and Ay in your sum of the moment @ A =0 equation, since there is "no moment arm" for those forces.
Hope this make sense and you can catch up.
Why is Ma is equal to zero?
cos the body is not moving
Civil engineering ??
you cant resist me right, (laugh) nice pun
5:28💀
you gotta lower your into music please hahaha
Sorry you
AYO MR WHITE
I said the same thing 😂😂😂 called him "engineering walter"
Finally i got it yeeeah 🤏