@@oscar I shure will man I got the book from my library so I don’t really know how to leave you a review but I would definitely give the book 100 stars it’s such an amazing book and good job
@@oscar Hello Oscar, I'm new to your channel and I love your videos. You posted a video 7 days ago. About your explanation being wrong about the cigrette trick. I guess I got its answer. ua-cam.com/users/shortsQGeaD52guSA?feature=share I think I figured out how the trick was done! There are two tubes. Inner one is white in color and Outer one is transparent. There is some empty space between them where a piece of paper (or plastic) is present, which depicts filter of the cigarette. Whenever the magician flips the cigarette, the piece of paper falls towards gravity; thus creating the illusion. Also the outer tube (transparent one) is soft like plastic, the magician uses this property to close the gap between the two tubes by pressing them so that the filter part does not move when he doesn't want it to move. This makes the act more complex and convincing. That's it. This is my explaination to this trick. What you guys think about it?
You can also do a little variation allowing you to perform the trick twice to the same public (eg: if someone asks to see the trick again) using the same routine but without writing on cards and without repeating the same numbers 18-43 on the jokers. 1) The first time you perfom the trick you don't have to write 18 and 43 on the jokers, but when showing the two face-up cards you tell the public that the jokers are talking to you, and they said "18 and 43", and proceed as you explained. 2) The second time, you surprise the public telling the jokers wanna do something a little different "they said the number 35 and 10 but counting from bottom", so you turn over the deck face up and start counting, the 10th card will be the card of the second guy and the 35th will be the first guy's one.
The thing I really love about tricks like this is that they don't require any slight of hand, manipulation, or misdirection. You just set it up and let _math_ do the rest. Brilliant!
They’re a lot less tricky to perform but they also don’t have that same element of craft nor are they as replicable. Seldom when performing close-up magic is an audience content with seeing just one trick or seeing a trick done only once.
@@word42069 Fair points. Of course, if one knows several of these and is just learning them to wow friends and family at the occasional party or reunion, they're enough. Beyond that, you're right that they're certainly not enough to build a career...or even an adequately entertaining act.
I couldn't get this work to save my life, and I just figured it out. I was fanning my cards, when revealing the jokers, from left to right instead of right to left, which had me picking up the wrong end of the deck, and placing them on top of the centre pile in wrong order, finally got it right. Thank you for a great trick
Here's why it works: In the notation below, J1,J2,C1,C2 each denote a single card: Joker 1, Selected card for spectator 1 etc, and other numbers denote that number of cards. Going from bottom to top, the original pile can be denoted as (24,J2,18,J1,10). Let's say the first spectator selects the N-th card below the first joker and the second spectator splits at the M-th cart below the second joker. We then have three piles: pile A: (24-M), pile B: (C2, M-1, J2, 18-N) pile C: (C1, N-1, J1,10). Restacking in the order ACB gives a single pile: (24-M, C1, N-1, J1, 10, C2, M-1, J2, 18-N). Spreading out and removing the jokers now divides these into three groups: group1 (24-M, C1, N-1), group 2 (10, C2, M-1), group 3 (18-N) Again, stacking the piles in the order group 2, group 1, group 3 gives a single pile again: (10, C2, M-1, 24-M, C1, N-1, 18-N) which simplifies mathematically to (10, C2, 23, C1, 17) Now, simply counting from the top it is clear that C1 is at position 18 and C2 at 42.
@@rachavinvitayakovit1408 After the two spectators have made their selections: 1. We have three piles: - Pile A (from the bottom up to where the second spectator split) - Pile B (from where the second spectator split up to where the first spectator selected their card) - Pile C (from the first spectator's selected card to the top) 2. Then, we take these piles and place them on top of each other in a new sequence. We put them in the order: Pile A, Pile C, then Pile B. You’re rearranging the piles to make a new stack, but in a way that lets you know exactly where the two chosen cards are! This specific rearrangement is the key to the trick. Even though it seems random to the spectators, you, the magician, know how it's all set up.
If you spread the deck normally - as in left to right - than this will only work if you switch the order of which packets you place on top of each other after the joker reveal. So, both times place the first spectators packet on top than the second.
@@stefanoscharalampopoulos It worked for me multiple times after I spread the deck right or reversed the packet stacks at the end. You're mixing something up.
This is one of the only magic channels I watch and I even made one of my oldest video from this channel. I didn’t know how you did it at first but learned in 5 minutes when you explained. Definitely recommend this channel for tricks. Amazing!
I honestly I was so confused because every time I do it the a cards are in 9 and 43 not 18 and 43. But then I realized I was fanning the cards in the opposite direction when splitting the packets and pulling out the jokers. So as it turns out, if you want to have a little bit of variation to do it back-to-back You can fan the other way and choose 9 and 43. lol
Thanks man...I can't believe he didn't mention that important detail in the video. Would've been better with a camera from top down, so that the viewer wouldn't have to mirror anything.
I stopped the video at 3:54, b4 you revealed the secret - my initial guess is that the 2 jokers are 'cut short' (have one or both ends trimmed off a fraction of an inch), then placed in the deck at the 18 & 43 position, after having those numbers written on them, and placing the 'selected' cards at the 17th and 42nd positions respectively. Now just do a false shuffle/cut, place the deck on the table, and the spectator will automatically cut to either of the jokers (that's why you have to say 'top third' then 'half'. The 'selected' cards will be the card that is just above the joker in the deck.
Not sure this falls into the category of 'magic'. It is simply placing the cards in a certain order and letting 'nature' take its course. However, if and when I pull this off, I will certainly call it 'magic'.
Another incredible trick! Thank you so much Oscar Owen! I have an idea for a patter: You say that you have to train your cards so that they can help you perform tricks. You are working on teaching the jokers to be secret agents. They followed the spectator's cards and can tell you where they are. Now you prove it and say that you helped them a little by telling them where the cards will be beforehand.
In principle you are rearanging the cards such, that on top are the 18 cards that were originally between the two jokers, with the first cut card at 18, below that are the 25 cards originally below the second joker, with the second cut at 25 (18+25=43). This is done by reordering the stacks after cutting, first at the cuts (indicated by "|"), then at the separations where the jokers are (indicated by ";"), brackets indicate the card after (if left of a "-") / before (if right a "-") the card in the brackets in the original sequence. original order: 1-j1-c1|(c1)-j2-c2|(c2)-e after cutting and switching the top stacks: (c1)-j2-c2|1-j1-c1|(c2)-e after removing the jokers and switching the bottom stacks: (c1)-(j2);(j1)-c1|(c2)-e;(j2)-c2|1-(j1) Do the trick with a sorted deck to see how it works, it's really clever application of a bit of mathematics.
I see no brackets, nor do I understand the meaning of j1, j2 c1 and c2. Obviously, they represent jokers 1 and 2 and cut cards 1 and 2, but, numerically are they equal to 1? Is "e" to be determined?
Great video as usual. Thank you and keep them coming. Could you do me a favour.... when cards are on table ( ie during tutorial)would it be possible to see from your pov? Looking from spectator side I keep getting mixed up when stacks are on left/ right. ( maybe it's just me 🤷♂️, lol)
Actually the numbers on the cards (18 and 43) diminish the magic. Their appearance suggests that the whole thing was gimmicked beforehand. I'd recommend doing the trick without marking the two cards.
I agree 100%. Having the jokers numbered like that makes it obvious that it is self-working. Also, many have commented here that if the participant cuts to the joker and observes the number it ruins the trick. Best to leave them alone for sure!
I remember watching this, and thinking, This is a Simon Aronson routine straight out of the book. So if I'd gone onto Fool Us, I could have fooled Penn & Teller?!?!
OK, only at the 3:40 mark, but my guess is that the key move takes place at 1:22 or thereabouts where the deck is not reassembled in its original order, but what used to be the top of the deck is placed in the middle and what used to be the middle of the deck is placed on top. That has to be intentional. The jokers are probably placed in the deck in some key location that enables the trick to work. Anyway, I'll continue watching and see how this plays out.
Question. Would you be willing to take on someone who has already been a professional before but just feels there is room for improvement in his skills? Said person has been performing for almost 2 decades but has abandoned sleight of hand almost completely. Asking for a friend.
9 Cards + J + X + Y + J + W + Z = 54 (X + Y) = 18 (W + Z) = 25 First Split is to "X", the splits must include the jokers or this doesn't work. 9 Cards + J + X Second Split is to "W". Y + J + W The middle pile is now Z. They are now placed in this ordering: Y + J + W 9 Cards + J + X Z Now you remove the Jokers and Create 3 new piles: Y W + 9 Cards X + Z Now, we replace the ordering: Y X + Z W + 9 Cards Well, we have simply removed the 9 Cards, so we have Y + X = 18 with X having the card as per original split. Then Z + W = 25 and 18 + 25 = 43 with W being the card which we have placed in the right order. So it doesn't matter what card they pick, as long as they pick in the correct range, first needs to be between the jokers so it's X + Y and second needs to be after the second Joker for W + Z range. We can then shift the cards around after we have removed these markers for the ranges and it will always be in the right place.
Fantastic trick!!! Thank you. I am trying to convert this trick into a Titanic related card trick. May I ask 2 questions. I'll be using a 31 card deck plus the two jokers. i want the numbers to be 19 and 12. What postions do the jokers need to be in the set-up in order to make this work? Note- I am using a replica deck of the cards comp'd in First class on Titanic. 31 cards - 19 + 12, my patter is that we are using roughly 2/3 of a deck of cards. This represents the number of passengers who perished on the night of the sinking. Thank you so much Oscar for taking my questions. Keep up the fantastic work!
This is an amazing self-worker. Thank you for making this available to us. In all magic effects, we stand on the shoulders of those who came before us and created effects, and we also stand on the shoulders of those who might have taken an effect and improved upon it. This card effect didn't come out of nowhere. Therefore some crediting acknowledgements would have been nice at the end of the video. Thank you again and best wishes. (Liked. Subscriber.)
I guess lots of you already do this but I like to use my phone in tricks so before doing the trick, take a picture of the jokers then use the edit function to draw a speech bubble and 18 then repeat with the other joker and 43. you can add some patter like "What's that? You'd already sent me a message to my phone - oh I didn't check." Then pull up a picture of the joker with the number 43 in a speech bubble. You can even email them before the trick begins or post them on your/their social media etc.
The magician's name on P&T is Graham Jolley (it's in the description). On UA-cam you can find the performance, but for some strange reason you cannot find the footage of P&T actually admitting they were fooled at the end of it. It's like they have become highly embarrassed at being fooled by a self working card trick (understandably) and have had that footage removed!
For folks confused, think about it this way. For simplicity, let's just think about positioning the second card. After they cut they put their stack facedown on the table, with their card in the bottom of the stack. You don't know how many cards are above it, but you do know how many cards are now below it - zero. That means you just have to put 9 cards underneath it and it will be in the 43rd place. Well, you counted 9 cards to set up the trick, those are the cards above the first jack. So you place those 9 cards under their card and now it's in the 43rd place. So the position of the card went from unknown, to last, to 43rd.
I mean... just follow directions and you don't need to "learn" anything. It's a math trick... the jokers simply separate the 3 piles. And then putting them in a stacked order and the jokers pre determined spots... forces the cards they cut to into the spots you already made happen by counting the jokers down in a particular spot. The jokers are basically telling you how many cards up or down the card they cut to is... because you know what spot those jokers are in. (probably explaining it in a terrible way... but you know how many cards down each joker is, then place the cut cards back in a SPECIFIC order, to where the trick works itself out if you follow the directions)
Just practising and following along with the vid for the first time. When he said 'They cut half the deck and remember the ace of spades' I cut half my deck and the ace of spades came up!!! (Damn this guy is good).
Thanks for this. What i do not understand is that in Penn and Teller, the magician shuffled the card in the beginning. How were the cards still arranged?
this is what i keep looking for someone to explain. and i think this is the part that actually fooled Penn & Teller. The shuffle rules out all the "math"/self-working approaches.
I haven't seen the episode, but there are many different methods for shuffling a deck that do not in fact shuffle the deck, or don't shuffle a portion of the deck. Although also I'd expect Penn and Teller to spot those. Also, never believe a magician. Penn and Teller will say a trick fooled them even if it didn't for a good story or a sympathetic guest. Or sometimes they'll just come up with a different way the effect could be done and guess wrong.
Such a pathetic reason to study magic indeed... At least you are a small kid, most of the " grownups" I know, have unfortunately the same motive. Sad, to say the least...
Hey Oscar, amazing video, I’ve always went to your channel whenever I need a new magic trick to perform. Thank you. Also one question, what is the music that plays when you’re showing the trick called. It sounds really mysterious and cool. Just curious.
I still don/t understand how the cards can come up in positions 18 and 43 when the deck can be cut at any level, that just doesn't make sense to me, and I'm ok with that!!! Super awesome!
Great trick and thanks for sharing. However, I find it hard to believe that Penn & Teller were tricked by this. It just seems so simple and you’re just counting cards.
This is a great video. Even after watching the tutorial I still can’t understand how the cards can come out like that. I’m going to have to practice this one and see if I can make it happen. Once again, great tutorial Oscar and thanks so much for sharing. 💯💯🔥🔥🔥🔥
I had to try this out on paper. The 2 jokers separate the deck like this: -9 cards -joker 43 -18 cards -joker 18 -25 cards First person cuts somewhere between joker 43 and joker 18 to make this pile: -9 cards -joker 43 -x cards Second person cuts somewhere after joker 18 and makes this pile: -18 - x cards -joker 18 -y cards The remaining pile contains 25 - y cards Put the first person's pile on top of the remaining pile then the second person's: -18 - x cards -joker 18 -y cards -9 cards -joker 43 -x cards -25 - y cards Now you take out the jokers to make 3 piles: -18 - x cards -y cards -9 cards -x cards -25 - y cards Put the third pile on top of the second one then add the first one: -18 - x cards -x cards -25 - y cards -y cards -9 cards There you go, you just cancelled out the unknowns. The card of the first person will be at position 18. The card of the second person at position 25 + 18 = 43.
@@carolineprenoveau7655 when i saw it, i too had to work it out to see why, but i never considered trying to explain it to someone else. Very well done!
@@carolineprenoveau7655 Yes, except write out what happens when spectator 1 doesn’t pay attention and cuts improperly (e.g., beyond second joker or above first joker). Try explaining to them why you NEED them to do it differently and chose a different card.
Im very surprised that Penn and Teller were fooled by this trick. This type of card trick has been around for hundreds of years. Ive seen lots of variations of this trick over the years but they all use the same basic rules.
So for those of you saying it doesn't work if you fan the cards left to right simply put the 18 card after the 9th card and the 43 card after the 18th after the first joker and then make sure you put the first spectator (your left) pile on top of the middle first both times. Then it will work.
Cheers Joe... your explanation is exactly how it should be explained! if you get my drift... I spent a while doing the routine thinking that I was making a mistake when all along, the recording was wrong. Thanks
As someone who dabbled in magic in my youth, what you say at 10:45 is paramount. Even the most simple tricks in the world are great to see in the hands of someone engaging.
Great video. My only observation is that if they do cut to the Joker, they'll see not the Joker itself but the back of the card with the number written on it. You can gloss over it, but it would somewhat ruin the end of the trick.
Yeah, if they cut to the joker face you can pretend you knew they'd cut there and take the joker out, later have him "call" his friend in the deck. If they cut to have their card be the joker the trick is kinda ruined, I'm not a magician so I don't know how one could salvage that
Ah, but when it works... it really works ; ) When I was a kid I'd say ... _"I want to do a card trick, but I don't have any cards with me. So... I want you to imagine a card as clearly as you can, and don't tell ANYONE - but, please, not an easy one like Ace of Spades or Queen of hearts... something really hard to guess. Done that?"_ _"Okay... now I'll put my hand out and you try to imagine it, lying face up in my hand... done that?"_ Then I'd place my other hand with a palmed 3c over the top of my hand with the imaginary card... and ask them to keep concentrating on their card being IN my hands. Then I'd slowly blow into the gap between my wrists whilst slowly separating my hands to reveal a REAL card. Then I'd say, _"Your card ?"_ Now, usually, it's 'no' ... and I just giggle and say, _"yeah, that figures... but once every 52 times it IS the right card... and when that happens, it's f***ing mind-blowing!"_ They laugh, and that's that : ) It was so dumb. But when it DID work... OMFG! I was a fricken God! People were shaken! One girl it worked with was almost in tears. Why am I saying this? Well... usually the trick in this video is flawless! So, who cares if once in a while it looks a little clumsy? The point is, when it goes off perfectly, it's freaking awesome... and, luckily for you, that's most of the time : )))) I still say, my childhood trick is better... I just had to play the long game and wait for the payoffs, but BOY were they worth the wait ; )
It's a pretty big problem if the spectator cuts the deck where the jokers are. They'll end up displaying the back of the jokers with the numbers on them. Hard to explain that away by saying "we'll return to the jokers in a moment".
You could add some elements of mentalism by revealing what the card is when the participants cut to their selection by having the deck marked & stack the deck into si-stebens. They cut 1/3 and peek the maked card below & already have a mental picture of what the participant sees. Thanks for this! Not only was the prediction was correct but you also knew what card they were going to cut too 😃
I didn't get the hang of it, until I realized that I think you're left-handed. It's a trick to record from behind, but I finally got it and I'm very grateful.
I have been practicing this trick for a couple of days now. But, the card that should be at position 18 is always wrong and the actual card is usually at position 9. The card for position 43 is always correct. Any ideas?
two fixes for you either 1 fan the cards from right to left after you remove the jokers or 2 both times you place the seperate packets back together go first spectator first instead of switching. Either of these will fix the problem doing both will not
Hi, how can i see your webinar . i am interested.. please upload it on this channel, if its finished already. if not then tell me what to de... thanks in advance.. thanks for the free webinar
Mine be.tter. Pick a card, any card. Memorize, place back in deck. (Example: 9 Hearts) I verbally count through deck and the chosen card revealsuit of the card (Hearts). Again counthrough the deck and the second chosen card reveals value (9).
I have an even better variation. I put the 2 jokers 25 card apart from each other and ask my spectators a number between 1 and 10. Then cut the deck anywhere with their choice (you can add up, subtract, whatever u want) and perform the trick, knowing you would have to do 52-x (=y) and y-25 to get card of your spectators
🔥 Checkout The Free Magic Webinar - go.learnmagic.com/
I just got ur book mind blowing magic tricks and I love it great work
@@Slight0789 Thank you so much - if you could leave a review that would be amazing! Thanks
@@oscar I shure will man I got the book from my library so I don’t really know how to leave you a review but I would definitely give the book 100 stars it’s such an amazing book and good job
@@oscar Hello Oscar, I'm new to your channel and I love your videos.
You posted a video 7 days ago. About your explanation being wrong about the cigrette trick. I guess I got its answer.
ua-cam.com/users/shortsQGeaD52guSA?feature=share
I think I figured out how the trick was done!
There are two tubes.
Inner one is white in color and Outer one is transparent.
There is some empty space between them where a piece of paper (or plastic) is present, which depicts filter of the cigarette.
Whenever the magician flips the cigarette, the piece of paper falls towards gravity; thus creating the illusion.
Also the outer tube (transparent one) is soft like plastic, the magician uses this property to close the gap between the two tubes by pressing them so that the filter part does not move when he doesn't want it to move. This makes the act more complex and convincing.
That's it. This is my explaination to this trick. What you guys think about it?
Osker Owen I want to say that your course is not free it want 149 doller and iam a Indian I can't pay that huge amount
You can also do a little variation allowing you to perform the trick twice to the same public (eg: if someone asks to see the trick again) using the same routine but without writing on cards and without repeating the same numbers 18-43 on the jokers.
1) The first time you perfom the trick you don't have to write 18 and 43 on the jokers, but when showing the two face-up cards you tell the public that the jokers are talking to you, and they said "18 and 43", and proceed as you explained.
2) The second time, you surprise the public telling the jokers wanna do something a little different "they said the number 35 and 10 but counting from bottom", so you turn over the deck face up and start counting, the 10th card will be the card of the second guy and the 35th will be the first guy's one.
Genius!
Genius
wow, great idea
So do you need two set of cards that are "setup" if you doing it this way to the same audience?
@@johnwalker8805 see how Graham did it here ua-cam.com/video/7opT3c0pE2I/v-deo.html
The thing I really love about tricks like this is that they don't require any slight of hand, manipulation, or misdirection. You just set it up and let _math_ do the rest. Brilliant!
@@ninjaguyYT Damn it! I knew that. My bad. Nice catch.
They’re a lot less tricky to perform but they also don’t have that same element of craft nor are they as replicable. Seldom when performing close-up magic is an audience content with seeing just one trick or seeing a trick done only once.
@@word42069 Fair points. Of course, if one knows several of these and is just learning them to wow friends and family at the occasional party or reunion, they're enough. Beyond that, you're right that they're certainly not enough to build a career...or even an adequately entertaining act.
maths
@@word42069 replicateable
I couldn't get this work to save my life, and I just figured it out. I was fanning my cards, when revealing the jokers, from left to right instead of right to left, which had me picking up the wrong end of the deck, and placing them on top of the centre pile in wrong order, finally got it right. Thank you for a great trick
I have been trying to get this trick to work for over a week now, and just saw this. I can’t believe it was that simple to fix, Thank you!!😁😁😁
Holy shit let’s go
Here's why it works:
In the notation below, J1,J2,C1,C2 each denote a single card: Joker 1, Selected card for spectator 1 etc, and other numbers denote that number of cards.
Going from bottom to top, the original pile can be denoted as (24,J2,18,J1,10).
Let's say the first spectator selects the N-th card below the first joker and the second spectator splits at the M-th cart below the second joker. We then have three piles:
pile A: (24-M), pile B: (C2, M-1, J2, 18-N) pile C: (C1, N-1, J1,10).
Restacking in the order ACB gives a single pile: (24-M, C1, N-1, J1, 10, C2, M-1, J2, 18-N).
Spreading out and removing the jokers now divides these into three groups:
group1 (24-M, C1, N-1), group 2 (10, C2, M-1), group 3 (18-N)
Again, stacking the piles in the order group 2, group 1, group 3 gives a single pile again:
(10, C2, M-1, 24-M, C1, N-1, 18-N) which simplifies mathematically to (10, C2, 23, C1, 17)
Now, simply counting from the top it is clear that C1 is at position 18 and C2 at 42.
Is there a simpler explanation?😅
@@rachavinvitayakovit1408
After the two spectators have made their selections:
1. We have three piles:
- Pile A (from the bottom up to where the second spectator split)
- Pile B (from where the second spectator split up to where the first spectator selected their card)
- Pile C (from the first spectator's selected card to the top)
2. Then, we take these piles and place them on top of each other in a new sequence. We put them in the order: Pile A, Pile C, then Pile B.
You’re rearranging the piles to make a new stack, but in a way that lets you know exactly where the two chosen cards are!
This specific rearrangement is the key to the trick. Even though it seems random to the spectators, you, the magician, know how it's all set up.
I still have't a clue and mentioning the N-th ! now my head hurts
@@rachavinvitayakovit1408 That WAS the simple explanation! LOL
Worst explanation ever
I'm 66 and started card tricks a few years ago, you are my first sub! Thank you. 😊
my first card trick sub too, but only started last night :D I bet you're great after a few years?
If you spread the deck normally - as in left to right - than this will only work if you switch the order of which packets you place on top of each other after the joker reveal. So, both times place the first spectators packet on top than the second.
It doesn't work to me 🤬🤬🤬
Thank you!!! I've been going nuts!!!
@@stefanoscharalampopoulos It hasn't worked for me either
@@sptt144 it worked for me only once.... Luck
@@stefanoscharalampopoulos It worked for me multiple times after I spread the deck right or reversed the packet stacks at the end. You're mixing something up.
This is one of the only magic channels I watch and I even made one of my oldest video from this channel. I didn’t know how you did it at first but learned in 5 minutes when you explained. Definitely recommend this channel for tricks. Amazing!
Welcome back - and thanks for watching :)
Yes I’ve been watching every video.
I honestly I was so confused because every time I do it the a cards are in 9 and 43 not 18 and 43. But then I realized I was fanning the cards in the opposite direction when splitting the packets and pulling out the jokers. So as it turns out, if you want to have a little bit of variation to do it back-to-back You can fan the other way and choose 9 and 43. lol
You sure you weren’t accidentally using a 60 card deck? 👀🤔
Thanks mate same problem
@@johnscherer5686 Yup, positive. It's one of the decks I use for doing simple card tricks from time to time.
THANK YOU
Thanks man...I can't believe he didn't mention that important detail in the video. Would've been better with a camera from top down, so that the viewer wouldn't have to mirror anything.
Thanks!
I stopped the video at 3:54, b4 you revealed the secret - my initial guess is that the 2 jokers are 'cut short' (have one or both ends trimmed off a fraction of an inch), then placed in the deck at the 18 & 43 position, after having those numbers written on them, and placing the 'selected' cards at the 17th and 42nd positions respectively. Now just do a false shuffle/cut, place the deck on the table, and the spectator will automatically cut to either of the jokers (that's why you have to say 'top third' then 'half'. The 'selected' cards will be the card that is just above the joker in the deck.
You were one of the first Magic channels I started watching. Thank you for leading me and many others into Magic!
Thank you - I appreciate it
Same here!!
Not sure this falls into the category of 'magic'. It is simply placing the cards in a certain order and letting 'nature' take its course. However, if and when I pull this off, I will certainly call it 'magic'.
@@oscar hello
Another incredible trick! Thank you so much Oscar Owen! I have an idea for a patter: You say that you have to train your cards so that they can help you perform tricks. You are working on teaching the jokers to be secret agents. They followed the spectator's cards and can tell you where they are. Now you prove it and say that you helped them a little by telling them where the cards will be beforehand.
In principle you are rearanging the cards such, that on top are the 18 cards that were originally between the two jokers, with the first cut card at 18, below that are the 25 cards originally below the second joker, with the second cut at 25 (18+25=43).
This is done by reordering the stacks after cutting, first at the cuts (indicated by "|"), then at the separations where the jokers are (indicated by ";"), brackets indicate the card after (if left of a "-") / before (if right a "-") the card in the brackets in the original sequence.
original order: 1-j1-c1|(c1)-j2-c2|(c2)-e
after cutting and switching the top stacks: (c1)-j2-c2|1-j1-c1|(c2)-e
after removing the jokers and switching the bottom stacks: (c1)-(j2);(j1)-c1|(c2)-e;(j2)-c2|1-(j1)
Do the trick with a sorted deck to see how it works, it's really clever application of a bit of mathematics.
I see no brackets, nor do I understand the meaning of j1, j2 c1 and c2. Obviously, they represent jokers 1 and 2 and cut cards 1 and 2, but, numerically are they equal to 1? Is "e" to be determined?
WHAT THE HELL 😮 BRO LOL 😂
At 1:45 must you pick up the spread exactly as you did so, in that order?
Your trick will be a fine addition to my collection.
Great video as usual. Thank you and keep them coming.
Could you do me a favour.... when cards are on table ( ie during tutorial)would it be possible to see from your pov? Looking from spectator side I keep getting mixed up when stacks are on left/ right.
( maybe it's just me 🤷♂️, lol)
Best comment here!!! Whenever teaching a trick, you should always refer to the right or left for clarity.
It's not just you 😏
I'll have to try this. I used to do a few card tricks in the past.
I like to practice your tricks with the card in question face up so I can follow the card and how it works. :)
Actually the numbers on the cards (18 and 43) diminish the magic. Their appearance suggests that the whole thing was gimmicked beforehand. I'd recommend doing the trick without marking the two cards.
I agree 100%. Having the jokers numbered like that makes it obvious that it is self-working.
Also, many have commented here that if the participant cuts to the joker and observes the number it ruins the trick. Best to leave them alone for sure!
yeah i was thinking the exact same thing
Thanks for sharing knowledge freely and nice music
I remember watching this, and thinking, This is a Simon Aronson routine straight out of the book. So if I'd gone onto Fool Us, I could have fooled Penn & Teller?!?!
OK, only at the 3:40 mark, but my guess is that the key move takes place at 1:22 or thereabouts where the deck is not reassembled in its original order, but what used to be the top of the deck is placed in the middle and what used to be the middle of the deck is placed on top. That has to be intentional. The jokers are probably placed in the deck in some key location that enables the trick to work. Anyway, I'll continue watching and see how this plays out.
Question. Would you be willing to take on someone who has already been a professional before but just feels there is room for improvement in his skills? Said person has been performing for almost 2 decades but has abandoned sleight of hand almost completely. Asking for a friend.
We can never get “the trick that fooled Oscar Owins”
Owens*
@@CabCKDice Owen* lol
@@kingpantherquizzes4313 oof
Maybe a one mil…
What trick was it
i found this channel a year ago and it really helped me progress so thank you oscar owen🙏
9 Cards + J + X + Y + J + W + Z = 54
(X + Y) = 18
(W + Z) = 25
First Split is to "X", the splits must include the jokers or this doesn't work.
9 Cards + J + X
Second Split is to "W".
Y + J + W
The middle pile is now Z.
They are now placed in this ordering:
Y + J + W
9 Cards + J + X
Z
Now you remove the Jokers and Create 3 new piles:
Y
W + 9 Cards
X + Z
Now, we replace the ordering:
Y
X + Z
W + 9 Cards
Well, we have simply removed the 9 Cards, so we have Y + X = 18 with X having the card as per original split.
Then Z + W = 25 and 18 + 25 = 43 with W being the card which we have placed in the right order.
So it doesn't matter what card they pick, as long as they pick in the correct range, first needs to be between the jokers so it's X + Y and second needs to be after the second Joker for W + Z range. We can then shift the cards around after we have removed these markers for the ranges and it will always be in the right place.
Fantastic trick!!! Thank you.
I am trying to convert this trick into a Titanic related card trick. May I ask 2 questions. I'll be using a 31 card deck plus the two jokers. i want the numbers to be 19 and 12.
What postions do the jokers need to be in the set-up in order to make this work?
Note- I am using a replica deck of the cards comp'd in First class on Titanic.
31 cards - 19 + 12, my patter is that we are using roughly 2/3 of a deck of cards.
This represents the number of passengers who perished on the night of the sinking.
Thank you so much Oscar for taking my questions.
Keep up the fantastic work!
This is an amazing self-worker. Thank you for making this available to us. In all magic effects, we stand on the shoulders of those who came before us and created effects, and we also stand on the shoulders of those who might have taken an effect and improved upon it. This card effect didn't come out of nowhere. Therefore some crediting acknowledgements would have been nice at the end of the video. Thank you again and best wishes. (Liked. Subscriber.)
This guys magic is out of this world
❤️❤️
Ty!❤️🔥 This is so cool to show to people 😊❤
I can get the 43rd card ok but the other one is always #8 or 9 from the top. Helllllllp!!!
I guess lots of you already do this but I like to use my phone in tricks so before doing the trick, take a picture of the jokers then use the edit function to draw a speech bubble and 18 then repeat with the other joker and 43. you can add some patter like "What's that? You'd already sent me a message to my phone - oh I didn't check." Then pull up a picture of the joker with the number 43 in a speech bubble. You can even email them before the trick begins or post them on your/their social media etc.
(It also means you can still use the deck for other tricks)
I really like how you express yourself
Its really impressive
The magician's name on P&T is Graham Jolley (it's in the description). On UA-cam you can find the performance, but for some strange reason you cannot find the footage of P&T actually admitting they were fooled at the end of it. It's like they have become highly embarrassed at being fooled by a self working card trick (understandably) and have had that footage removed!
I LOVE math tricks! This is insane!
For folks confused, think about it this way. For simplicity, let's just think about positioning the second card. After they cut they put their stack facedown on the table, with their card in the bottom of the stack. You don't know how many cards are above it, but you do know how many cards are now below it - zero. That means you just have to put 9 cards underneath it and it will be in the 43rd place. Well, you counted 9 cards to set up the trick, those are the cards above the first jack. So you place those 9 cards under their card and now it's in the 43rd place. So the position of the card went from unknown, to last, to 43rd.
8:44 was the moment I realized that even though he was trying to explain it to me… I have no chance to learn this wizardry 😂
I mean... just follow directions and you don't need to "learn" anything. It's a math trick... the jokers simply separate the 3 piles. And then putting them in a stacked order and the jokers pre determined spots... forces the cards they cut to into the spots you already made happen by counting the jokers down in a particular spot. The jokers are basically telling you how many cards up or down the card they cut to is... because you know what spot those jokers are in. (probably explaining it in a terrible way... but you know how many cards down each joker is, then place the cut cards back in a SPECIFIC order, to where the trick works itself out if you follow the directions)
Just practising and following along with the vid for the first time. When he said 'They cut half the deck and remember the ace of spades' I cut half my deck and the ace of spades came up!!!
(Damn this guy is good).
Love these cardtricks. This one works every other time I try. But I'm getting there :-)
Another 5⭐ card trick.
Thanks for this. What i do not understand is that in Penn and Teller, the magician shuffled the card in the beginning. How were the cards still arranged?
this is what i keep looking for someone to explain. and i think this is the part that actually fooled Penn & Teller. The shuffle rules out all the "math"/self-working approaches.
I haven't seen the episode, but there are many different methods for shuffling a deck that do not in fact shuffle the deck, or don't shuffle a portion of the deck. Although also I'd expect Penn and Teller to spot those.
Also, never believe a magician. Penn and Teller will say a trick fooled them even if it didn't for a good story or a sympathetic guest. Or sometimes they'll just come up with a different way the effect could be done and guess wrong.
Brilliant keep up the good work 👍
I am so grateful. I showed this trick to my friends and all the popular kids in my school literally became my friends. Wow! Thanks Oscar!
Such a pathetic reason to study magic indeed... At least you are a small kid, most of the " grownups" I know, have unfortunately the same motive. Sad, to say the least...
@jestergreekgamer1275 "magic? Pathetic?" *Or just u mad because u cant do it?*
Hey Oscar, amazing video, I’ve always went to your channel whenever I need a new magic trick to perform. Thank you. Also one question, what is the music that plays when you’re showing the trick called. It sounds really mysterious and cool. Just curious.
I still don/t understand how the cards can come up in positions 18 and 43 when the deck can be cut at any level, that just doesn't make sense to me, and I'm ok with that!!! Super awesome!
I have no idea: but I'm not okay with that AJ. This is doing ma head in 😵💫
Thanks. This is spectacular
inspiered me to learn , just to have fun with my grandkids , love it , TY :)
Great trick and thanks for sharing. However, I find it hard to believe that Penn & Teller were tricked by this. It just seems so simple and you’re just counting cards.
Wow Very Nice. Thanks
ඔබට බොහොම ස්තූතියි
I love your magic tricks
Thank you (and you were first comment!)
This is a great video. Even after watching the tutorial I still can’t understand how the cards can come out like that. I’m going to have to practice this one and see if I can make it happen. Once again, great tutorial Oscar and thanks so much for sharing. 💯💯🔥🔥🔥🔥
It's basically a math problem
I had to try this out on paper.
The 2 jokers separate the deck like this:
-9 cards
-joker 43
-18 cards
-joker 18
-25 cards
First person cuts somewhere between joker 43 and joker 18 to make this pile:
-9 cards
-joker 43
-x cards
Second person cuts somewhere after joker 18 and makes this pile:
-18 - x cards
-joker 18
-y cards
The remaining pile contains 25 - y cards
Put the first person's pile on top of the remaining pile then the second person's:
-18 - x cards
-joker 18
-y cards
-9 cards
-joker 43
-x cards
-25 - y cards
Now you take out the jokers to make 3 piles:
-18 - x cards
-y cards
-9 cards
-x cards
-25 - y cards
Put the third pile on top of the second one then add the first one:
-18 - x cards
-x cards
-25 - y cards
-y cards
-9 cards
There you go, you just cancelled out the unknowns. The card of the first person will be at position 18. The card of the second person at position 25 + 18 = 43.
@@carolineprenoveau7655 when i saw it, i too had to work it out to see why, but i never considered trying to explain it to someone else. Very well done!
@@carolineprenoveau7655 Yes, except write out what happens when spectator 1 doesn’t pay attention and cuts improperly (e.g., beyond second joker or above first joker). Try explaining to them why you NEED them to do it differently and chose a different card.
I knew a smart person in the comments will take the time to explain it. Thanks @@carolineprenoveau7655
I have been subscribed to your channel for 6 months now, and great magic tricks.
Yoooh such a nice trick. I salute. I want to try the app to improve my magic Oscar
Im very surprised that Penn and Teller were fooled by this trick. This type of card trick has been around for hundreds of years. Ive seen lots of variations of this trick over the years but they all use the same basic rules.
So for those of you saying it doesn't work if you fan the cards left to right simply put the 18 card after the 9th card and the 43 card after the 18th after the first joker and then make sure you put the first spectator (your left) pile on top of the middle first both times. Then it will work.
Cheers Joe... your explanation is exactly how it should be explained! if you get my drift... I spent a while doing the routine thinking that I was making a mistake when all along, the recording was wrong. Thanks
@@stephenporter7049 No worries mate
Mr. Oscar OwenThank You
Awesome fun! Liked, subscribed.
Wow! Oscar Owen has been my best channel to watch since day one. U explain the tricks properly... To more life of magic💞
That's tricks so amazing , I love it
Thanks Nam
Wonderful effect. Thank you Sir.
As someone who dabbled in magic in my youth, what you say at 10:45 is paramount. Even the most simple tricks in the world are great to see in the hands of someone engaging.
Great video. My only observation is that if they do cut to the Joker, they'll see not the Joker itself but the back of the card with the number written on it. You can gloss over it, but it would somewhat ruin the end of the trick.
Yeah, if they cut to the joker face you can pretend you knew they'd cut there and take the joker out, later have him "call" his friend in the deck. If they cut to have their card be the joker the trick is kinda ruined, I'm not a magician so I don't know how one could salvage that
Ah, but when it works... it really works ; )
When I was a kid I'd say ... _"I want to do a card trick, but I don't have any cards with me. So... I want you to imagine a card as clearly as you can, and don't tell ANYONE - but, please, not an easy one like Ace of Spades or Queen of hearts... something really hard to guess. Done that?"_
_"Okay... now I'll put my hand out and you try to imagine it, lying face up in my hand... done that?"_
Then I'd place my other hand with a palmed 3c over the top of my hand with the imaginary card... and ask them to keep concentrating on their card being IN my hands.
Then I'd slowly blow into the gap between my wrists whilst slowly separating my hands to reveal a REAL card. Then I'd say, _"Your card ?"_
Now, usually, it's 'no' ... and I just giggle and say, _"yeah, that figures... but once every 52 times it IS the right card... and when that happens, it's f***ing mind-blowing!"_ They laugh, and that's that : )
It was so dumb.
But when it DID work... OMFG! I was a fricken God! People were shaken! One girl it worked with was almost in tears.
Why am I saying this? Well... usually the trick in this video is flawless! So, who cares if once in a while it looks a little clumsy? The point is, when it goes off perfectly, it's freaking awesome... and, luckily for you, that's most of the time : ))))
I still say, my childhood trick is better... I just had to play the long game and wait for the payoffs, but BOY were they worth the wait ; )
This video was fire!! 🔥🔥 Thanks for sharing!
Alrighty’ I’m ready too do it too
Fantastic brother, thank you so much
It's a pretty big problem if the spectator cuts the deck where the jokers are. They'll end up displaying the back of the jokers with the numbers on them. Hard to explain that away by saying "we'll return to the jokers in a moment".
thanks man i appreciate this trick! im subscribing
Hi Oscar Owen, you are the best magician in the world!!!
one of the best tricks you can do in no time, cheers buddy
lets go guys
lets get him over 1000000 subscribers
don't you think that he would appreciate that
I believe he can get that
Stunningly beautiful what a trick, Oscar you always out do yourself thanks so much for your willingness to share your talent with us.
Omfg this is amaaaaazing ❤️❤️ thank you Oscar!!! My fav magic channel ❤️
Thanks a lot. May the magic STAY with you! ;)
you are very good and although I am 78, I am having great fun learning your tricks. Dont limit your audience to 75!!!!
y yo, 72!
Your doin this great man! I‘ll try to do it :) Thank You!
Hi,
Why is this not working for me ? Following your instructions exactly but only the card at 43 is correct! Card at 18 is nowhere near ☹️
Same with me
Make sure when you spread the cards on the table, you are doing so from right to left.
@@rabidslothgaming4456 - Make sure when you spread the cards you do so from left to right.
@@paulveltum7968 little late
Thank you! A good explanation!
Another fantastic content! Thanks!
Hello. I do as You show and my first spectators card is always 9th from top
You could add some elements of mentalism by revealing what the card is when the participants cut to their selection by having the deck marked & stack the deck into si-stebens.
They cut 1/3 and peek the maked card below & already have a mental picture of what the participant sees.
Thanks for this!
Not only was the prediction was correct but you also knew what card they were going to cut too 😃
I'm not gonna use trick decks or something that will make them figure it out.
Good idea, don't need to mark the jokers either then
Thanks for bringing. The Trick that fooled. Back
Looks like it didn't work first shot, thats why there is a cut at min 9:08.
I didn't get the hang of it, until I realized that I think you're left-handed. It's a trick to record from behind, but I finally got it and I'm very grateful.
Thanks for posting
Very cool and easy Magic trick
Thank you Zinedine
@@oscar thanks for you✌️😀
As you have no control over the cuts how does the math work to produce the right numbers/cards?
love this type of card trick thanks for sharing
We are fooled by your magic tricks and you are so lucky that you are a magician.
love frm india ❤❤❤ Namaste
I have been practicing this trick for a couple of days now. But, the card that should be at position 18 is always wrong and the actual card is usually at position 9. The card for position 43 is always correct. Any ideas?
two fixes for you either 1 fan the cards from right to left after you remove the jokers or 2 both times you place the seperate packets back together go first spectator first instead of switching. Either of these will fix the problem doing both will not
Hello Oscar🙂🙂 very good trick(Prior commitment by Simon Aronson)My favorite tricks Is Quantum deck by Graig Petty Oscar Very very good trick👍👍👍👍👍😀😀😀
How does this ensure that the spectators cards will be in those positions?
I'm not sure how this trick actually works...
same - i cant fathom how the spectators cards are forced into the 18 and 43 positions
Hi, how can i see your webinar . i am interested.. please upload it on this channel, if its finished already. if not then tell me what to de... thanks in advance.. thanks for the free webinar
Very good presentation
Mine be.tter. Pick a card, any card. Memorize, place back in deck. (Example: 9 Hearts) I verbally count through deck and the chosen card revealsuit of the card (Hearts). Again counthrough the deck and the second chosen card reveals value (9).
This is so fair , will definitely try it 🔥. Hey can you please make a video for best magic tricks for Instagram .
Nice. Small problem: if the spectator DOES lift the joker, they will not see the joker but its back side with the number... 6:56 oopsy.
I have an even better variation. I put the 2 jokers 25 card apart from each other and ask my spectators a number between 1 and 10. Then cut the deck anywhere with their choice (you can add up, subtract, whatever u want) and perform the trick, knowing you would have to do 52-x (=y) and y-25 to get card of your spectators
Oh ye clean and fair