@@oscar I shure will man I got the book from my library so I don’t really know how to leave you a review but I would definitely give the book 100 stars it’s such an amazing book and good job
@@oscar Hello Oscar, I'm new to your channel and I love your videos. You posted a video 7 days ago. About your explanation being wrong about the cigrette trick. I guess I got its answer. ua-cam.com/users/shortsQGeaD52guSA?feature=share I think I figured out how the trick was done! There are two tubes. Inner one is white in color and Outer one is transparent. There is some empty space between them where a piece of paper (or plastic) is present, which depicts filter of the cigarette. Whenever the magician flips the cigarette, the piece of paper falls towards gravity; thus creating the illusion. Also the outer tube (transparent one) is soft like plastic, the magician uses this property to close the gap between the two tubes by pressing them so that the filter part does not move when he doesn't want it to move. This makes the act more complex and convincing. That's it. This is my explaination to this trick. What you guys think about it?
You can also do a little variation allowing you to perform the trick twice to the same public (eg: if someone asks to see the trick again) using the same routine but without writing on cards and without repeating the same numbers 18-43 on the jokers. 1) The first time you perfom the trick you don't have to write 18 and 43 on the jokers, but when showing the two face-up cards you tell the public that the jokers are talking to you, and they said "18 and 43", and proceed as you explained. 2) The second time, you surprise the public telling the jokers wanna do something a little different "they said the number 35 and 10 but counting from bottom", so you turn over the deck face up and start counting, the 10th card will be the card of the second guy and the 35th will be the first guy's one.
The thing I really love about tricks like this is that they don't require any slight of hand, manipulation, or misdirection. You just set it up and let _math_ do the rest. Brilliant!
They’re a lot less tricky to perform but they also don’t have that same element of craft nor are they as replicable. Seldom when performing close-up magic is an audience content with seeing just one trick or seeing a trick done only once.
@@word42069 Fair points. Of course, if one knows several of these and is just learning them to wow friends and family at the occasional party or reunion, they're enough. Beyond that, you're right that they're certainly not enough to build a career...or even an adequately entertaining act.
Another incredible trick! Thank you so much Oscar Owen! I have an idea for a patter: You say that you have to train your cards so that they can help you perform tricks. You are working on teaching the jokers to be secret agents. They followed the spectator's cards and can tell you where they are. Now you prove it and say that you helped them a little by telling them where the cards will be beforehand.
I mean... just follow directions and you don't need to "learn" anything. It's a math trick... the jokers simply separate the 3 piles. And then putting them in a stacked order and the jokers pre determined spots... forces the cards they cut to into the spots you already made happen by counting the jokers down in a particular spot. The jokers are basically telling you how many cards up or down the card they cut to is... because you know what spot those jokers are in. (probably explaining it in a terrible way... but you know how many cards down each joker is, then place the cut cards back in a SPECIFIC order, to where the trick works itself out if you follow the directions)
It's a pretty big problem if the spectator cuts the deck where the jokers are. They'll end up displaying the back of the jokers with the numbers on them. Hard to explain that away by saying "we'll return to the jokers in a moment".
I figured it out, but it's not entirely fair because you said at the start that anyone could learn it so I didn't even look for slight of hand. I immediately thought of "mathematical" tricks.
I guess lots of you already do this but I like to use my phone in tricks so before doing the trick, take a picture of the jokers then use the edit function to draw a speech bubble and 18 then repeat with the other joker and 43. you can add some patter like "What's that? You'd already sent me a message to my phone - oh I didn't check." Then pull up a picture of the joker with the number 43 in a speech bubble. You can even email them before the trick begins or post them on your/their social media etc.
OK, only at the 3:40 mark, but my guess is that the key move takes place at 1:22 or thereabouts where the deck is not reassembled in its original order, but what used to be the top of the deck is placed in the middle and what used to be the middle of the deck is placed on top. That has to be intentional. The jokers are probably placed in the deck in some key location that enables the trick to work. Anyway, I'll continue watching and see how this plays out.
For folks confused, think about it this way. For simplicity, let's just think about positioning the second card. After they cut they put their stack facedown on the table, with their card in the bottom of the stack. You don't know how many cards are above it, but you do know how many cards are now below it - zero. That means you just have to put 9 cards underneath it and it will be in the 43rd place. Well, you counted 9 cards to set up the trick, those are the cards above the first jack. So you place those 9 cards under their card and now it's in the 43rd place. So the position of the card went from unknown, to last, to 43rd.
So for those of you saying it doesn't work if you fan the cards left to right simply put the 18 card after the 9th card and the 43 card after the 18th after the first joker and then make sure you put the first spectator (your left) pile on top of the middle first both times. Then it will work.
Cheers Joe... your explanation is exactly how it should be explained! if you get my drift... I spent a while doing the routine thinking that I was making a mistake when all along, the recording was wrong. Thanks
I dont understand at 08.49 you state that 'the two selections are in the 18th and 43rd position' - why is that the case - surely the selections are still in random positions in the deck
Wait, if they cut to the Joker, and the cut gets flipped, they won't see the face of the Joker, they'll see the back, with the number written on it. What about that?
Great demonstration. But i would be very surprised if P&T were really fooled by this, as getting two changes of stack order past Teller's eagle eyes is all but impossible.
Hi, how can i see your webinar . i am interested.. please upload it on this channel, if its finished already. if not then tell me what to de... thanks in advance.. thanks for the free webinar
Great trick, but I don’t know if it’s the correct solution. In original clip, the magician shuffles the deck, putting the jokers in a random order. Then again, it might have been a false shuffle!
This is a great self-working trick. But I do find Penn & Teller's show very disingenuous. The notion that any experienced magician wouldn't immediately recognise and fathom a mathematical method like this is quite daft. There are thousands of card tricks that work along similar principles. Nevertheless, thanks for your hard work making these videos. This is definitely a trick that will fool the majority of lay people.
I've shown this to a few folks, and have a couple of suggestions: When the first spectator cuts their packet off, don't have them look at the face card. Rather, have the other spectator look at the top card on the remainder of the deck, place it on the table, and have the first spectator place their packet on top. Repeat this the other way round for the second selected card. The reason is that, on occasion, someone is likely to cut to the joker, and when they look at their card, instead of a regular card, they'll see the back of a card with a number on it. This not only kinda kills the trick, but it confuses things. The handling above means that can't happen.
My guess with 0 experience is trimmed cards. Edit: WRONG!!! Just simple math combined with forcing their chosen cards into a particular position when stacking them back up.
I honestly I was so confused because every time I do it the a cards are in 9 and 43 not 18 and 43. But then I realized I was fanning the cards in the opposite direction when splitting the packets and pulling out the jokers. So as it turns out, if you want to have a little bit of variation to do it back-to-back You can fan the other way and choose 9 and 43. lol
Thanks man...I can't believe he didn't mention that important detail in the video. Would've been better with a camera from top down, so that the viewer wouldn't have to mirror anything.
This is one of the only magic channels I watch and I even made one of my oldest video from this channel. I didn’t know how you did it at first but learned in 5 minutes when you explained. Definitely recommend this channel for tricks. Amazing!
Actually the numbers on the cards (18 and 43) diminish the magic. Their appearance suggests that the whole thing was gimmicked beforehand. I'd recommend doing the trick without marking the two cards.
I agree 100%. Having the jokers numbered like that makes it obvious that it is self-working. Also, many have commented here that if the participant cuts to the joker and observes the number it ruins the trick. Best to leave them alone for sure!
Great video as usual. Thank you and keep them coming. Could you do me a favour.... when cards are on table ( ie during tutorial)would it be possible to see from your pov? Looking from spectator side I keep getting mixed up when stacks are on left/ right. ( maybe it's just me 🤷♂️, lol)
Don't believe it really fooled P&T. It is a very well known trick published in 2001. It would be nice to inform about the author (and if you own the rights to reveal it).
Not sure this falls into the category of 'magic'. It is simply placing the cards in a certain order and letting 'nature' take its course. However, if and when I pull this off, I will certainly call it 'magic'.
Here's why it works: In the notation below, J1,J2,C1,C2 each denote a single card: Joker 1, Selected card for spectator 1 etc, and other numbers denote that number of cards. Going from bottom to top, the original pile can be denoted as (24,J2,18,J1,10). Let's say the first spectator selects the N-th card below the first joker and the second spectator splits at the M-th cart below the second joker. We then have three piles: pile A: (24-M), pile B: (C2, M-1, J2, 18-N) pile C: (C1, N-1, J1,10). Restacking in the order ACB gives a single pile: (24-M, C1, N-1, J1, 10, C2, M-1, J2, 18-N). Spreading out and removing the jokers now divides these into three groups: group1 (24-M, C1, N-1), group 2 (10, C2, M-1), group 3 (18-N) Again, stacking the piles in the order group 2, group 1, group 3 gives a single pile again: (10, C2, M-1, 24-M, C1, N-1, 18-N) which simplifies mathematically to (10, C2, 23, C1, 17) Now, simply counting from the top it is clear that C1 is at position 18 and C2 at 42.
@@rachavinvitayakovit1408 After the two spectators have made their selections: 1. We have three piles: - Pile A (from the bottom up to where the second spectator split) - Pile B (from where the second spectator split up to where the first spectator selected their card) - Pile C (from the first spectator's selected card to the top) 2. Then, we take these piles and place them on top of each other in a new sequence. We put them in the order: Pile A, Pile C, then Pile B. You’re rearranging the piles to make a new stack, but in a way that lets you know exactly where the two chosen cards are! This specific rearrangement is the key to the trick. Even though it seems random to the spectators, you, the magician, know how it's all set up.
I couldn't get this work to save my life, and I just figured it out. I was fanning my cards, when revealing the jokers, from left to right instead of right to left, which had me picking up the wrong end of the deck, and placing them on top of the centre pile in wrong order, finally got it right. Thank you for a great trick
Im very surprised that Penn and Teller were fooled by this trick. This type of card trick has been around for hundreds of years. Ive seen lots of variations of this trick over the years but they all use the same basic rules.
If you spread the deck normally - as in left to right - than this will only work if you switch the order of which packets you place on top of each other after the joker reveal. So, both times place the first spectators packet on top than the second.
@@stefanoscharalampopoulos It worked for me multiple times after I spread the deck right or reversed the packet stacks at the end. You're mixing something up.
9 Cards + J + X + Y + J + W + Z = 54 (X + Y) = 18 (W + Z) = 25 First Split is to "X", the splits must include the jokers or this doesn't work. 9 Cards + J + X Second Split is to "W". Y + J + W The middle pile is now Z. They are now placed in this ordering: Y + J + W 9 Cards + J + X Z Now you remove the Jokers and Create 3 new piles: Y W + 9 Cards X + Z Now, we replace the ordering: Y X + Z W + 9 Cards Well, we have simply removed the 9 Cards, so we have Y + X = 18 with X having the card as per original split. Then Z + W = 25 and 18 + 25 = 43 with W being the card which we have placed in the right order. So it doesn't matter what card they pick, as long as they pick in the correct range, first needs to be between the jokers so it's X + Y and second needs to be after the second Joker for W + Z range. We can then shift the cards around after we have removed these markers for the ranges and it will always be in the right place.
I don't like that the numbers are written on the cards. It would be a much better trick without that so that the spectators think that it could have been other numbers. With the predefined numbers I immediately know that there is some math and no magic.
I'm apparently slow. I still don't get how just random cuts down can be just piled back on twice to get the 2 chosen cards to actually BE in those two positions. arggggggg.
I remember watching this, and thinking, This is a Simon Aronson routine straight out of the book. So if I'd gone onto Fool Us, I could have fooled Penn & Teller?!?!
Amazing trick, good explanation, worst 4 minutes I've spent in years having to listen to that absolutely awful storytelling in the beginning edit: screw this, not even going to watch the rest with this music
Great trick but I don't get it. If they can pick any card from the pile, each card is in a different position relative to the jokers so simply rearranging the piles will only mean that the chosen cards are still relative to the breaks. One of those things that just works and a better mathematician than me can explain it. Can see why it would fool a magician cos it's not magic, it's crazy maths 😊
I still don/t understand how the cards can come up in positions 18 and 43 when the deck can be cut at any level, that just doesn't make sense to me, and I'm ok with that!!! Super awesome!
Pardon a quibble, please, but it bothers me that your patter contradicts itself. I think you should either stick with the magic jokers communicating to you and drop writing the numbers on them, or else make it a purely a prediction trick about your forecasting abilities.
Thanks for this. What i do not understand is that in Penn and Teller, the magician shuffled the card in the beginning. How were the cards still arranged?
this is what i keep looking for someone to explain. and i think this is the part that actually fooled Penn & Teller. The shuffle rules out all the "math"/self-working approaches.
I haven't seen the episode, but there are many different methods for shuffling a deck that do not in fact shuffle the deck, or don't shuffle a portion of the deck. Although also I'd expect Penn and Teller to spot those. Also, never believe a magician. Penn and Teller will say a trick fooled them even if it didn't for a good story or a sympathetic guest. Or sometimes they'll just come up with a different way the effect could be done and guess wrong.
Hey Oscar, amazing video, I’ve always went to your channel whenever I need a new magic trick to perform. Thank you. Also one question, what is the music that plays when you’re showing the trick called. It sounds really mysterious and cool. Just curious.
Wouldn't the trick actually be a bit ruined if they happened to pick either of the jokers as they are backwards in the deck and they would actually cut to a card with the number on the back? That seems a bit harder to explain away than just we will come back to these numbers. Amazing trick though great stuff!
Great trick and thanks for sharing. However, I find it hard to believe that Penn & Teller were tricked by this. It just seems so simple and you’re just counting cards.
Fantastic trick!!! Thank you. I am trying to convert this trick into a Titanic related card trick. May I ask 2 questions. I'll be using a 31 card deck plus the two jokers. i want the numbers to be 19 and 12. What postions do the jokers need to be in the set-up in order to make this work? Note- I am using a replica deck of the cards comp'd in First class on Titanic. 31 cards - 19 + 12, my patter is that we are using roughly 2/3 of a deck of cards. This represents the number of passengers who perished on the night of the sinking. Thank you so much Oscar for taking my questions. Keep up the fantastic work!
Uh... "inspired by"? "This is my take..."? That's a bit deceptive, and not in a good way. This is beat-by-beat out of the late Simon's book. Why not more truthfully say "This is Prior Commitment by Simon Aronson."?
Mine be.tter. Pick a card, any card. Memorize, place back in deck. (Example: 9 Hearts) I verbally count through deck and the chosen card revealsuit of the card (Hearts). Again counthrough the deck and the second chosen card reveals value (9).
Is there a step missing or am I missing a step? How are the chosen cards in the 18th and 43rd place? They were not moved from their original position in the video, so were not on top of the jokers positions.
It's all in the way the three piles are put back together after the the initial cuts, and also how they are put back together after the jokers are revealed.
Why 18 and 43? There is nothing "magic" about these numbers, but they are probably the best choices to make the trick run smoothly. If there are p cards before the first joker, and q cards between the two jokers, then there are r cards after the second joker, where p+q+r=52. The trick moves the first chosen card to position q, and the second chosen card to position q+r=52-p. Thus if p=9 and q=18, then the cards are in position 18 and 52-9=43. Why is this a good choice? Well, the deck with jokers has 54 cards, so one third of it is 18 cards. We need p to be large enough to fan out the cards without revealing the first joker, but significantly less than 18 so that the first cut includes the first joker: p=9 is midway between 0 and 18. We don't want the first cut to include the second joker so we need p+q to be significantly more than 18, but we want the second cut to include the second joker, so we need p+q to be significantly less than 18+18=36. Here p+q=27 is midway between 18 and 36, so q=18 is a good choice. However the trick will work almost all of the time as long as p is close to 9 and p+q is close to 27. This gives very many variants of the same trick. I would take p=10, so the second card is at position 42, the answer to life the universe and everything :) Then q could be "sweet 16" or "17 again", and you could adapt your patter accordingly.
🔥 Checkout The Free Magic Webinar - go.learnmagic.com/
I just got ur book mind blowing magic tricks and I love it great work
@@Slight0789 Thank you so much - if you could leave a review that would be amazing! Thanks
@@oscar I shure will man I got the book from my library so I don’t really know how to leave you a review but I would definitely give the book 100 stars it’s such an amazing book and good job
@@oscar Hello Oscar, I'm new to your channel and I love your videos.
You posted a video 7 days ago. About your explanation being wrong about the cigrette trick. I guess I got its answer.
ua-cam.com/users/shortsQGeaD52guSA?feature=share
I think I figured out how the trick was done!
There are two tubes.
Inner one is white in color and Outer one is transparent.
There is some empty space between them where a piece of paper (or plastic) is present, which depicts filter of the cigarette.
Whenever the magician flips the cigarette, the piece of paper falls towards gravity; thus creating the illusion.
Also the outer tube (transparent one) is soft like plastic, the magician uses this property to close the gap between the two tubes by pressing them so that the filter part does not move when he doesn't want it to move. This makes the act more complex and convincing.
That's it. This is my explaination to this trick. What you guys think about it?
Osker Owen I want to say that your course is not free it want 149 doller and iam a Indian I can't pay that huge amount
You can also do a little variation allowing you to perform the trick twice to the same public (eg: if someone asks to see the trick again) using the same routine but without writing on cards and without repeating the same numbers 18-43 on the jokers.
1) The first time you perfom the trick you don't have to write 18 and 43 on the jokers, but when showing the two face-up cards you tell the public that the jokers are talking to you, and they said "18 and 43", and proceed as you explained.
2) The second time, you surprise the public telling the jokers wanna do something a little different "they said the number 35 and 10 but counting from bottom", so you turn over the deck face up and start counting, the 10th card will be the card of the second guy and the 35th will be the first guy's one.
Genius!
Genius
wow, great idea
So do you need two set of cards that are "setup" if you doing it this way to the same audience?
@@johnwalker8805 see how Graham did it here ua-cam.com/video/7opT3c0pE2I/v-deo.html
The thing I really love about tricks like this is that they don't require any slight of hand, manipulation, or misdirection. You just set it up and let _math_ do the rest. Brilliant!
@@ninjaguyYT Damn it! I knew that. My bad. Nice catch.
They’re a lot less tricky to perform but they also don’t have that same element of craft nor are they as replicable. Seldom when performing close-up magic is an audience content with seeing just one trick or seeing a trick done only once.
@@word42069 Fair points. Of course, if one knows several of these and is just learning them to wow friends and family at the occasional party or reunion, they're enough. Beyond that, you're right that they're certainly not enough to build a career...or even an adequately entertaining act.
maths
@@word42069 replicateable
Another incredible trick! Thank you so much Oscar Owen! I have an idea for a patter: You say that you have to train your cards so that they can help you perform tricks. You are working on teaching the jokers to be secret agents. They followed the spectator's cards and can tell you where they are. Now you prove it and say that you helped them a little by telling them where the cards will be beforehand.
8:44 was the moment I realized that even though he was trying to explain it to me… I have no chance to learn this wizardry 😂
I mean... just follow directions and you don't need to "learn" anything. It's a math trick... the jokers simply separate the 3 piles. And then putting them in a stacked order and the jokers pre determined spots... forces the cards they cut to into the spots you already made happen by counting the jokers down in a particular spot. The jokers are basically telling you how many cards up or down the card they cut to is... because you know what spot those jokers are in. (probably explaining it in a terrible way... but you know how many cards down each joker is, then place the cut cards back in a SPECIFIC order, to where the trick works itself out if you follow the directions)
It's a pretty big problem if the spectator cuts the deck where the jokers are. They'll end up displaying the back of the jokers with the numbers on them. Hard to explain that away by saying "we'll return to the jokers in a moment".
We can never get “the trick that fooled Oscar Owins”
Owens*
@@CabCKDice Owen* lol
@@kingpantherquizzes4313 oof
Maybe a one mil…
What trick was it
Love these cardtricks. This one works every other time I try. But I'm getting there :-)
Alrighty’ I’m ready too do it too
Another 5⭐ card trick.
I'll have to try this. I used to do a few card tricks in the past.
I figured it out, but it's not entirely fair because you said at the start that anyone could learn it so I didn't even look for slight of hand. I immediately thought of "mathematical" tricks.
Yoooh such a nice trick. I salute. I want to try the app to improve my magic Oscar
I guess lots of you already do this but I like to use my phone in tricks so before doing the trick, take a picture of the jokers then use the edit function to draw a speech bubble and 18 then repeat with the other joker and 43. you can add some patter like "What's that? You'd already sent me a message to my phone - oh I didn't check." Then pull up a picture of the joker with the number 43 in a speech bubble. You can even email them before the trick begins or post them on your/their social media etc.
(It also means you can still use the deck for other tricks)
OK, only at the 3:40 mark, but my guess is that the key move takes place at 1:22 or thereabouts where the deck is not reassembled in its original order, but what used to be the top of the deck is placed in the middle and what used to be the middle of the deck is placed on top. That has to be intentional. The jokers are probably placed in the deck in some key location that enables the trick to work. Anyway, I'll continue watching and see how this plays out.
inspiered me to learn , just to have fun with my grandkids , love it , TY :)
Hi Oscar Owen, you are the best magician in the world!!!
For folks confused, think about it this way. For simplicity, let's just think about positioning the second card. After they cut they put their stack facedown on the table, with their card in the bottom of the stack. You don't know how many cards are above it, but you do know how many cards are now below it - zero. That means you just have to put 9 cards underneath it and it will be in the 43rd place. Well, you counted 9 cards to set up the trick, those are the cards above the first jack. So you place those 9 cards under their card and now it's in the 43rd place. So the position of the card went from unknown, to last, to 43rd.
Thanks for posting
This is so fair , will definitely try it 🔥. Hey can you please make a video for best magic tricks for Instagram .
Writing 18 and 43 at the back of the jokers is a dead giveaway that the trick is self-working.
So for those of you saying it doesn't work if you fan the cards left to right simply put the 18 card after the 9th card and the 43 card after the 18th after the first joker and then make sure you put the first spectator (your left) pile on top of the middle first both times. Then it will work.
Cheers Joe... your explanation is exactly how it should be explained! if you get my drift... I spent a while doing the routine thinking that I was making a mistake when all along, the recording was wrong. Thanks
@@stephenporter7049 No worries mate
Oh they really pick until the Joker😅
I dont understand at 08.49 you state that 'the two selections are in the 18th and 43rd position' - why is that the case - surely the selections are still in random positions in the deck
At 1:45 must you pick up the spread exactly as you did so, in that order?
Wait, if they cut to the Joker, and the cut gets flipped, they won't see the face of the Joker, they'll see the back, with the number written on it. What about that?
What's the original performance? do you have the video? to look at the presentation please
Oh right to left for the spread of cards. Dang it no wonder I was off.
Thank you so much
So….What is the Reason it works.?
youre back !
Great demonstration. But i would be very surprised if P&T were really fooled by this, as getting two changes of stack order past Teller's eagle eyes is all but impossible.
In the original, graham jolley shuffles the cards in the beginning. How would you do that and keep the trick the same??
Oscar Owen you are best
7:11 - When he knew it was the 4 of spades without looking, that's when I realized, this guy has sold his soul to the devil.
Hello. I do as You show and my first spectators card is always 9th from top
I have been watching this channel for a long time I've learned so much from you thanks so much ❤️❤️❤️
great trick. thanks. please lose the obnoxious music bed though!😊
Love it
Hi, how can i see your webinar . i am interested.. please upload it on this channel, if its finished already. if not then tell me what to de... thanks in advance.. thanks for the free webinar
enable the save function pls
Great trick, but I don’t know if it’s the correct solution. In original clip, the magician shuffles the deck, putting the jokers in a random order.
Then again, it might have been a false shuffle!
Damn, the Penn & Teller link is gone. It got stricken for copyright. Is there an official version you can link to?
Will I be as interesting as Oscar Owen?
Very nice. But how exactly does this work out that way. Curious here.
Pls we want some mentalism trick without cards
Bro that is fire♥♦♣♠ he fool me first
❤️❤️❤️❤️
I've been in the same room as someone doing card tricks before, and I'm pretty sure I was still the most interesting person in the room
Can you put the original penn en teller link in here?
Fake shuffling plus good memory with a hint of math
Tried to perform this and the spectator cut to 1 joker revealing the 43 on the back of it😂😂unluckiest moment of life
This is a great self-working trick. But I do find Penn & Teller's show very disingenuous. The notion that any experienced magician wouldn't immediately recognise and fathom a mathematical method like this is quite daft. There are thousands of card tricks that work along similar principles. Nevertheless, thanks for your hard work making these videos. This is definitely a trick that will fool the majority of lay people.
I've shown this to a few folks, and have a couple of suggestions: When the first spectator cuts their packet off, don't have them look at the face card. Rather, have the other spectator look at the top card on the remainder of the deck, place it on the table, and have the first spectator place their packet on top. Repeat this the other way round for the second selected card. The reason is that, on occasion, someone is likely to cut to the joker, and when they look at their card, instead of a regular card, they'll see the back of a card with a number on it. This not only kinda kills the trick, but it confuses things. The handling above means that can't happen.
Really?!? That fooled P & T?!?
What is the name of the music in the intro?
My guess with 0 experience is trimmed cards.
Edit: WRONG!!! Just simple math combined with forcing their chosen cards into a particular position when stacking them back up.
I honestly I was so confused because every time I do it the a cards are in 9 and 43 not 18 and 43. But then I realized I was fanning the cards in the opposite direction when splitting the packets and pulling out the jokers. So as it turns out, if you want to have a little bit of variation to do it back-to-back You can fan the other way and choose 9 and 43. lol
You sure you weren’t accidentally using a 60 card deck? 👀🤔
Thanks mate same problem
@@johnscherer5686 Yup, positive. It's one of the decks I use for doing simple card tricks from time to time.
THANK YOU
Thanks man...I can't believe he didn't mention that important detail in the video. Would've been better with a camera from top down, so that the viewer wouldn't have to mirror anything.
This is one of the only magic channels I watch and I even made one of my oldest video from this channel. I didn’t know how you did it at first but learned in 5 minutes when you explained. Definitely recommend this channel for tricks. Amazing!
Welcome back - and thanks for watching :)
Yes I’ve been watching every video.
Actually the numbers on the cards (18 and 43) diminish the magic. Their appearance suggests that the whole thing was gimmicked beforehand. I'd recommend doing the trick without marking the two cards.
I agree 100%. Having the jokers numbered like that makes it obvious that it is self-working.
Also, many have commented here that if the participant cuts to the joker and observes the number it ruins the trick. Best to leave them alone for sure!
yeah i was thinking the exact same thing
Great video as usual. Thank you and keep them coming.
Could you do me a favour.... when cards are on table ( ie during tutorial)would it be possible to see from your pov? Looking from spectator side I keep getting mixed up when stacks are on left/ right.
( maybe it's just me 🤷♂️, lol)
Best comment here!!! Whenever teaching a trick, you should always refer to the right or left for clarity.
It's not just you 😏
Don't believe it really fooled P&T. It is a very well known trick published in 2001. It would be nice to inform about the author (and if you own the rights to reveal it).
This doesn’t make sense - why are the chosen cards in the 18th and 43rd position - they weren’t next to the joker earlier
You were one of the first Magic channels I started watching. Thank you for leading me and many others into Magic!
Thank you - I appreciate it
Same here!!
Not sure this falls into the category of 'magic'. It is simply placing the cards in a certain order and letting 'nature' take its course. However, if and when I pull this off, I will certainly call it 'magic'.
@@oscar hello
Here's why it works:
In the notation below, J1,J2,C1,C2 each denote a single card: Joker 1, Selected card for spectator 1 etc, and other numbers denote that number of cards.
Going from bottom to top, the original pile can be denoted as (24,J2,18,J1,10).
Let's say the first spectator selects the N-th card below the first joker and the second spectator splits at the M-th cart below the second joker. We then have three piles:
pile A: (24-M), pile B: (C2, M-1, J2, 18-N) pile C: (C1, N-1, J1,10).
Restacking in the order ACB gives a single pile: (24-M, C1, N-1, J1, 10, C2, M-1, J2, 18-N).
Spreading out and removing the jokers now divides these into three groups:
group1 (24-M, C1, N-1), group 2 (10, C2, M-1), group 3 (18-N)
Again, stacking the piles in the order group 2, group 1, group 3 gives a single pile again:
(10, C2, M-1, 24-M, C1, N-1, 18-N) which simplifies mathematically to (10, C2, 23, C1, 17)
Now, simply counting from the top it is clear that C1 is at position 18 and C2 at 42.
Is there a simpler explanation?😅
@@rachavinvitayakovit1408
After the two spectators have made their selections:
1. We have three piles:
- Pile A (from the bottom up to where the second spectator split)
- Pile B (from where the second spectator split up to where the first spectator selected their card)
- Pile C (from the first spectator's selected card to the top)
2. Then, we take these piles and place them on top of each other in a new sequence. We put them in the order: Pile A, Pile C, then Pile B.
You’re rearranging the piles to make a new stack, but in a way that lets you know exactly where the two chosen cards are!
This specific rearrangement is the key to the trick. Even though it seems random to the spectators, you, the magician, know how it's all set up.
I still have't a clue and mentioning the N-th ! now my head hurts
@@rachavinvitayakovit1408 That WAS the simple explanation! LOL
Worst explanation ever
I couldn't get this work to save my life, and I just figured it out. I was fanning my cards, when revealing the jokers, from left to right instead of right to left, which had me picking up the wrong end of the deck, and placing them on top of the centre pile in wrong order, finally got it right. Thank you for a great trick
I have been trying to get this trick to work for over a week now, and just saw this. I can’t believe it was that simple to fix, Thank you!!😁😁😁
ive done it 10 times and i get the wrong card everytime
But if they DO cut to the joker, wont they reveal the back of the card with the number written on it?
How does this ensure that the spectators cards will be in those positions?
I'm not sure how this trick actually works...
same - i cant fathom how the spectators cards are forced into the 18 and 43 positions
Im very surprised that Penn and Teller were fooled by this trick. This type of card trick has been around for hundreds of years. Ive seen lots of variations of this trick over the years but they all use the same basic rules.
If you spread the deck normally - as in left to right - than this will only work if you switch the order of which packets you place on top of each other after the joker reveal. So, both times place the first spectators packet on top than the second.
It doesn't work to me 🤬🤬🤬
Thank you!!! I've been going nuts!!!
@@stefanoscharalampopoulos It hasn't worked for me either
@@sptt144 it worked for me only once.... Luck
@@stefanoscharalampopoulos It worked for me multiple times after I spread the deck right or reversed the packet stacks at the end. You're mixing something up.
9 Cards + J + X + Y + J + W + Z = 54
(X + Y) = 18
(W + Z) = 25
First Split is to "X", the splits must include the jokers or this doesn't work.
9 Cards + J + X
Second Split is to "W".
Y + J + W
The middle pile is now Z.
They are now placed in this ordering:
Y + J + W
9 Cards + J + X
Z
Now you remove the Jokers and Create 3 new piles:
Y
W + 9 Cards
X + Z
Now, we replace the ordering:
Y
X + Z
W + 9 Cards
Well, we have simply removed the 9 Cards, so we have Y + X = 18 with X having the card as per original split.
Then Z + W = 25 and 18 + 25 = 43 with W being the card which we have placed in the right order.
So it doesn't matter what card they pick, as long as they pick in the correct range, first needs to be between the jokers so it's X + Y and second needs to be after the second Joker for W + Z range. We can then shift the cards around after we have removed these markers for the ranges and it will always be in the right place.
I don't like that the numbers are written on the cards. It would be a much better trick without that so that the spectators think that it could have been other numbers. With the predefined numbers I immediately know that there is some math and no magic.
I'm apparently slow. I still don't get how just random cuts down can be just piled back on twice to get the 2 chosen cards to actually BE in those two positions. arggggggg.
I remember watching this, and thinking, This is a Simon Aronson routine straight out of the book. So if I'd gone onto Fool Us, I could have fooled Penn & Teller?!?!
Amazing trick, good explanation, worst 4 minutes I've spent in years having to listen to that absolutely awful storytelling in the beginning
edit: screw this, not even going to watch the rest with this music
Great trick but I don't get it. If they can pick any card from the pile, each card is in a different position relative to the jokers so simply rearranging the piles will only mean that the chosen cards are still relative to the breaks.
One of those things that just works and a better mathematician than me can explain it. Can see why it would fool a magician cos it's not magic, it's crazy maths 😊
I'm 66 and started card tricks a few years ago, you are my first sub! Thank you. 😊
my first card trick sub too, but only started last night :D I bet you're great after a few years?
I still don/t understand how the cards can come up in positions 18 and 43 when the deck can be cut at any level, that just doesn't make sense to me, and I'm ok with that!!! Super awesome!
I have no idea: but I'm not okay with that AJ. This is doing ma head in 😵💫
Too many annoying interruptions in this video. Just explain the damn trick.
Pardon a quibble, please, but it bothers me that your patter contradicts itself. I think you should either stick with the magic jokers communicating to you and drop writing the numbers on them, or else make it a purely a prediction trick about your forecasting abilities.
Thanks for this. What i do not understand is that in Penn and Teller, the magician shuffled the card in the beginning. How were the cards still arranged?
this is what i keep looking for someone to explain. and i think this is the part that actually fooled Penn & Teller. The shuffle rules out all the "math"/self-working approaches.
I haven't seen the episode, but there are many different methods for shuffling a deck that do not in fact shuffle the deck, or don't shuffle a portion of the deck. Although also I'd expect Penn and Teller to spot those.
Also, never believe a magician. Penn and Teller will say a trick fooled them even if it didn't for a good story or a sympathetic guest. Or sometimes they'll just come up with a different way the effect could be done and guess wrong.
But how do you KNOW they are in the 18th and 43rd positions? I'm confused.
Same here. Still seems like black magic.
Hi,
Why is this not working for me ? Following your instructions exactly but only the card at 43 is correct! Card at 18 is nowhere near ☹️
Same with me
Make sure when you spread the cards on the table, you are doing so from right to left.
@@rabidslothgaming4456 - Make sure when you spread the cards you do so from left to right.
@@paulveltum7968 little late
Hello I need help
When I am counting 18 cards it is not what I choose but when I am counting 43 cards it is that card that I Choose
same here. what's up with that? I haven't had the 19th card correct yet???
You just made me ruin my 2 jokers for a trick that doesn’t work I’ve done it 10 times
Got it to work because I put the 1st spectators pack on top both times
I have just done this trick and I'm just as amazed by it because I have no idea how the F it works 😂
The first time I did it, it worked.
But now, every time I do it now the first is wrong, but I'm getting the second one.....what am I doing wrong?
Hey Oscar, amazing video, I’ve always went to your channel whenever I need a new magic trick to perform. Thank you. Also one question, what is the music that plays when you’re showing the trick called. It sounds really mysterious and cool. Just curious.
I can get the 43rd card ok but the other one is always #8 or 9 from the top. Helllllllp!!!
Wouldn't the trick actually be a bit ruined if they happened to pick either of the jokers as they are backwards in the deck and they would actually cut to a card with the number on the back? That seems a bit harder to explain away than just we will come back to these numbers.
Amazing trick though great stuff!
Looks like it didn't work first shot, thats why there is a cut at min 9:08.
The problem here is that the video doesn't show why the trick works.
Magic
Great trick and thanks for sharing. However, I find it hard to believe that Penn & Teller were tricked by this. It just seems so simple and you’re just counting cards.
This is the same as How to draw an owl: 1. Draw two circles 2. Draw the rest of the owl.
Fantastic trick!!! Thank you.
I am trying to convert this trick into a Titanic related card trick. May I ask 2 questions. I'll be using a 31 card deck plus the two jokers. i want the numbers to be 19 and 12.
What postions do the jokers need to be in the set-up in order to make this work?
Note- I am using a replica deck of the cards comp'd in First class on Titanic.
31 cards - 19 + 12, my patter is that we are using roughly 2/3 of a deck of cards.
This represents the number of passengers who perished on the night of the sinking.
Thank you so much Oscar for taking my questions.
Keep up the fantastic work!
Uh... "inspired by"? "This is my take..."? That's a bit deceptive, and not in a good way. This is beat-by-beat out of the late Simon's book. Why not more truthfully say "This is Prior Commitment by Simon Aronson."?
Mine be.tter. Pick a card, any card. Memorize, place back in deck. (Example: 9 Hearts) I verbally count through deck and the chosen card revealsuit of the card (Hearts). Again counthrough the deck and the second chosen card reveals value (9).
Is there a step missing or am I missing a step? How are the chosen cards in the 18th and 43rd place? They were not moved from their original position in the video, so were not on top of the jokers positions.
It's all in the way the three piles are put back together after the the initial cuts, and also how they are put back together after the jokers are revealed.
Why 18 and 43? There is nothing "magic" about these numbers, but they are probably the best choices to make the trick run smoothly. If there are p cards before the first joker, and q cards between the two jokers, then there are r cards after the second joker, where p+q+r=52. The trick moves the first chosen card to position q, and the second chosen card to position q+r=52-p. Thus if p=9 and q=18, then the cards are in position 18 and 52-9=43. Why is this a good choice?
Well, the deck with jokers has 54 cards, so one third of it is 18 cards. We need p to be large enough to fan out the cards without revealing the first joker, but significantly less than 18 so that the first cut includes the first joker: p=9 is midway between 0 and 18. We don't want the first cut to include the second joker so we need p+q to be significantly more than 18, but we want the second cut to include the second joker, so we need p+q to be significantly less than 18+18=36. Here p+q=27 is midway between 18 and 36, so q=18 is a good choice. However the trick will work almost all of the time as long as p is close to 9 and p+q is close to 27. This gives very many variants of the same trick.
I would take p=10, so the second card is at position 42, the answer to life the universe and everything :) Then q could be "sweet 16" or "17 again", and you could adapt your patter accordingly.
I took it to the NEXT NEXT NEXT NEXT LEVEL! Now I am psycho and can't leave this room. DON"t DO IT!!!!!!!!!
what if someone chooses the card right before the joker? what to do then?