What is Circular Motion & Centripetal Acceleration in Physics? - [1-4-14]

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  • Опубліковано 21 лис 2024

КОМЕНТАРІ • 109

  • @righteousness8606
    @righteousness8606 2 роки тому +21

    You have a way of explaining even seemingly complex things and make it easy to understand.

  • @kamilbro6106
    @kamilbro6106 2 роки тому +19

    Thank you for all the help over the years!

  • @sssivaram
    @sssivaram 6 місяців тому +2

    Near 18:00, to claim that when the radius r goes down, the acceleration goes up is INCORRECT. This is because linear velocity v is also a function of r. So, if the centripetal acceleration is written as r*omega^2 (instead of v^2/r), you find that the centripetal acceleration is actually proportional to r. Note that omega (the angular velocity) is independent of r.

  • @anonymoususer4356
    @anonymoususer4356 Рік тому +1

    I have searched for many resources for physics. The way you explain things is PHENOMENAL!! I repeat PHENOMENAL!!

  • @jasaminshirzad317
    @jasaminshirzad317 Рік тому +5

    Love your videos, very detailed and gives everything you need to know, thank you

  • @NutellaGabriella
    @NutellaGabriella 2 роки тому +11

    Congrats on 1 million subs! You deserve it for being an excellent tutor :)

  • @birdman4274
    @birdman4274 Рік тому +1

    Another fantastic emphasis on direction change in the velocity vector providing acceleration. They need to emphasise this in school.

  • @Kashif_Javaid
    @Kashif_Javaid Рік тому +2

    Your’s lessons are getting really polished, a perfect balance of theory, intuition, examples, and derivation.

  • @IBumpg
    @IBumpg 2 роки тому +3

    Beautifully rendered!

  • @MohammadAsif-yi3qs
    @MohammadAsif-yi3qs Рік тому +1

    Definitely the best teacher. Lucky to have you as Physics instructor❤

  • @Moroccanmusic
    @Moroccanmusic 2 роки тому +3

    thank you sir, i really learned a lot from you. thanks again and greetings from Morocco, Africa

  • @lucasriedstra
    @lucasriedstra 2 роки тому +1

    Thank you for this video. The explanation on why the directions of acceleration and velocity can be different was very helpful.

  • @iceyred6668
    @iceyred6668 2 роки тому +1

    ABBRIATOR /3 D cycle/ Elimination DZ DD(uniform.psy8) Roatation/ion.term//nd.D

  • @surajshukla6813
    @surajshukla6813 2 роки тому +1

    This is my favourite channel 😁

  • @WritersDigest-b8f
    @WritersDigest-b8f Рік тому

    One equal angle between the two triangles.
    Angle between r1 r2 is theta where r1 =r2 = r
    is the same as angle between v1 & v2, where v1 = v2.
    One Side equal between the two triangles.
    v2-v1 is equal to r
    Two sides of one triangle are at 90 degree to the corresponding side of the other triangle.

  • @mridulacharya8250
    @mridulacharya8250 2 роки тому +1

    U have very successfully completed a holy 1 million subscriberszzzz
    Manyyyy Congratulations...U don't know how much people like U and khan academy means to students like us!!

  • @navindraarjunaabeyesekera7864
    @navindraarjunaabeyesekera7864 2 роки тому +1

    Excellent. You answered exactly the question I had in my mind: How can you have an acceleration if the velocity is the same
    Thanks a lot

  • @mekamald6328
    @mekamald6328 Рік тому

    My favourite channel way above others.

  • @TheElectromagno
    @TheElectromagno 4 місяці тому

    Very nice lesson. Very well explained.

  • @adrian__4678
    @adrian__4678 2 роки тому +4

    You are a great man!
    You help us so much with your knowledge .

  • @anonymoususer4356
    @anonymoususer4356 Рік тому +1

    Really well done. Thank You!!

  • @justanotherguy469
    @justanotherguy469 2 роки тому

    Your explanations are so easy to see. Thank you.

  • @sirousmohseni4
    @sirousmohseni4 6 місяців тому

    Amazingly well explained.

  • @nadiaalhassoun6832
    @nadiaalhassoun6832 2 роки тому +4

    Thank you

  • @cabdirisaaqcabdulaahimaxam1630
    @cabdirisaaqcabdulaahimaxam1630 2 роки тому +4

    Thank you a lot for your effort ❤

  • @ckcckc8676
    @ckcckc8676 2 роки тому

    The difference of the velocity delta V (= Vb-Va) will be pointing towards the center of the circle even if points A and B are not close by.

  • @Uttamkumarvelentena-q8o
    @Uttamkumarvelentena-q8o Місяць тому

    Sir you body language just very helpful❤

  • @rickshawty
    @rickshawty Рік тому

    PLEASE KEEP MAKING THESE VIDEOS

  • @dakotaswager4588
    @dakotaswager4588 8 місяців тому

    I just told u it's not going to be a perfect circle. Jason is so awesome.

  • @simpleman283
    @simpleman283 2 роки тому +1

    The more you learn, the more you realise that the more you really don't know. That is for sure with me. I know this is way ahead of me, but I still like seeing this kind of stuff.
    Watching this video made me wonder if earth's orbit speeds up as the orbit path narrows.
    Seems like it would.

    • @MathAndScience
      @MathAndScience  2 роки тому +7

      Absolutely the more you learn the more that you know that you really don’t know. This is the truth with me as well none of us really know very much when you really think about it.
      To answer your question the orbits of the planets and the moons of the solar system are almost never perfectly circular. They’re always an ellipse With the sun at one focus.
      And you’ll learn later when you study orbital mechanics that the speed of the planet orbiting does change throughout the orbit. As the object gets closer to the sun it speeds up and then when it reaches the far side of the orbit farther away it slows down.
      This is true of anything opening a body as it gets closer to the surface it has to go faster to maintain orbit and as it gets farther away it slows down. These are called Kepler‘s laws of motion and will learn about them later in physics.
      It’s really better to think about it in terms of potential and kinetic energy. As the planet gets closer and closer to the sun for instance it’s kind of falling inward towards the sun and picking up speed then as it flies around the sun and gets farther and farther away on the backside of the orbit it’s kind of climbing out of the potential energy well I’m slowing down due to gravity pulling on it. So yes it is speeding up and slowing down as it gets closer and farther away from the planet.

  • @SIRK_ICE
    @SIRK_ICE 2 роки тому +1

    1)
    You were trying to demonstrate a body in UNIFORM circular motion which implies the magnitude of its velocity is CONSTANT but the direction is continually changing. Unfortunately, the circular motion you were demonstrating using an object tied to a string and whirled in a VERTICAL circular fashion had CHANGING magnitude and direction of velocity. The tangential velocity is greatest at the bottom, decreases as the object goes up along the circular path, least at the highest point and increases on its way down. Because the direction of velocity is always changing there arises a centripetal acceleration (a = v²/r) and a tangential acceleration (aₜ = ω² r) which is the result of a changing magnitude of tangential velocity.
    2) It would really be much easier to explain the concepts of centripetal acceleration and centripetal force if Newton's Three Laws of Motion has been introduced to students much earlier on. For example, the formula for centripetal acceleration (F= mv²/r) is in fact derived from the formula
    Fₙₑₜ = ma (the 2nd law). Using the 2nd law, it is more meaningful to let students realize the net force causing the centripetal acceleration of a body in curvilinear motion.

  • @genebelcherskeyboard
    @genebelcherskeyboard 3 місяці тому

    ur circles r perfect to me ❤️❤️

  • @cartoonic6039
    @cartoonic6039 11 місяців тому

    I have a very simple but question.
    Why doesnt the object collapse into the point.
    Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre.
    For example:
    The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy.
    But objects in the real world dont have fixed energy level so what keeps them in circular path?
    Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular

  • @amjaddahabreh2168
    @amjaddahabreh2168 2 роки тому +1

    I enjoyed every bit of it. keep up the good work!

  • @munyuconeliusgodblessupyou176

    Am to generously celebrate after the release of my finals but it will be so disappointing that you are not to physically share with me the great joy" EVER PART I SEARCHED FOR" 🤝🤝🤝✍️✍️✍️🥇🎆🎇

  • @kennethijeh-tarila1348
    @kennethijeh-tarila1348 2 роки тому

    Thanks for the explanation

  • @HeavenlyPress
    @HeavenlyPress 2 роки тому +1

    That Proof was so sick 🤝

  • @sheillakamsa3813
    @sheillakamsa3813 2 роки тому

    noticed me sir,, I like your explanation sir🤗🤗

  • @engdoretto
    @engdoretto 2 роки тому +3

    Thanks a lot!

  • @tresajessygeorge210
    @tresajessygeorge210 Рік тому

    THANK YOU... SIR...!!!

  • @Tesla_Of_Golf-nf6fd
    @Tesla_Of_Golf-nf6fd 5 місяців тому

    Help me out here, please, but as you said at 12:40 "always pulling toward the center" can't possibly be true as that wouldn't create any force. What I believe you're actually doing is pulling PAST THE CENTER. If you truly watch what your hand is doing it's moving slightly outside and around the true center and leading the mass around an invisible or virtual cantilever depending on how large the motion of leading or pulling force's radius is, around that center, which oddly the orbit or pulling force is actually creating that center. A true center or singularity could never have a pulling force unless it had some mass or radius in order to wind and therefore apply tension to the tether. If you attempt to move anything by rotating a needle at the center of the tether, the mass at the end will not move because the lack of friction of the needle which is essentially tantamount to a true singularity and therefore cannot apply any force. There must be some radius which we would know as a hub, around the axis, in order to apply any force to the tether. Therefore, in order to apply force inward there must be a hub and you because there's a hub that force being applied is actually NOT toward the center but beyond the true center, OUTWARD, from the center and using the hub as a fulcrum. So, the leading angle of the power source, moving outward, depends on the rigidity of the tether which would determine the amount of allowable acceleration physically possible before the tether fails. As we all know, if you try to move something too quickly it just breaks.
    So, the idea of "always moving toward the center cannot be true." If it were true, you'd quickly find that true center and all force would stop.
    No, the more I think about this the more I think you're incorrect. Picture a mass on a rope, tethered by a pin - you apply force to the mass to create a velocity vector which will cause the mass to rotate around the center because of it's tether. The tether is truly pulling inward because of it's tensile strength but it's true center is not moving and has an essential singularity point, therefore no more force is or will be applied because there is no more "inward" physically, therefore to produce the force you're talking about here there must be force that is beyond the center and therefore OUTWARD of the center and leading the mass by ~181º or more depending on the rigidity of the tether.
    Wait, so if this is true, there can never be a true center. A true center would always result in a singularity and therefore no force. There must always be a hub in order to apply any velocity vector, and a hub means that the force is actually outward and beyond the center. Even if the tether is not physical it could never apply force from a true center and if it didn't have a true center then it must have a virtual hub or some sort of force by which leverage or force can be applied.
    Your planetary orbit model would suggest that at some point in time all planets will collide ... if gravity is pulling them toward the sun and there's nothing other than inertia preventing it, it will inevitable happen someday.
    When you talk about speed of rotation you're then assuming a constant by which you're judging two things, but what if that constant didn't exist? That constant of course is "time" but without that, literally everything is improvable and incorrect. All of this is judged against time and "time" is just a concept that we've given a value. Oh, I guess that works because all we're doing is attempting to explain something in a way that can't be disproven, so therefore assumed to correct but literally all of it is just made up stuff that we all agree to. Nothing is really real. There is only what we agree to be real. Ouch, my brain hurts.
    I'm sorry but when you run and turn it's not "pushing on the ground" that's moving you, it's friction. Without it, force is nearly impossible.

  • @got-iit5391
    @got-iit5391 Рік тому

    I have a question and I am not sure how to explain it. I am looking for information on circular motion but I don't know the term used. Here goes. You have a pencil and draw an almost perfect circle. As the circle closes you keep the pencil drawing higher on the page then create another smaller circle above it, to the right and you continue doing this until you make a much larger circle. I don't know the term used for the mathematical symbol. It is also used in music as you go up a scale but then come back down a bit, then go back up the scale a little bit higher then come back down just a bit. and so one... until you end up at the top and reverse the process and slowly come back down the scale again to where you started... does this make sense to anyone? LOL Think of a moon circling a planet that circles the sun... that is the motion. But what is that called? There is a term for it? What is it? LOL

  • @49.SiddharthAdapa
    @49.SiddharthAdapa 6 місяців тому

    I did not understand how the both triangles are similar and pls explain the geometry behind it

  • @namedrop66
    @namedrop66 2 роки тому +3

    Them groundhogs are fast ;)

    • @MathAndScience
      @MathAndScience  2 роки тому +2

      Lol!

    • @simpleman283
      @simpleman283 2 роки тому +1

      I read this comment when this video first came out, but it is even funnier now watching it again.

  • @naderhumood
    @naderhumood 2 роки тому +2

    Thank you v much .

  • @mohamadfazli5575
    @mohamadfazli5575 7 місяців тому

    Hi Jason,but you didn't explain how did you get v square ,,how did you get v square ? Please reply

  • @uwu2250
    @uwu2250 10 місяців тому

    ur the best

  • @drumtwo4seven
    @drumtwo4seven 2 роки тому +1

    Nice 👍
    Notifications are working again 👍

  • @viswanathanpr9443
    @viswanathanpr9443 2 роки тому

    Thanks.
    Chennai.

  • @user-ph1cx9rk8i
    @user-ph1cx9rk8i Рік тому

    Thank u !

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    radius=diameter/2

  • @drumtwo4seven
    @drumtwo4seven 2 роки тому +1

    Does the word Radial pointed inward have any relation to the word Radians used in Trigonometry ?

    • @MathAndScience
      @MathAndScience  2 роки тому

      I never thought of that but probably! I honestly don’t know but sounds plausible!

    • @drumtwo4seven
      @drumtwo4seven 2 роки тому +1

      Thank you
      I've watched this video (second time now) and am picking up on it more and more each time.
      Great video great instructions. Good stuff 👍
      A few more viewings I'll get up to speed.
      I might delete my question eventually as my understanding evolves.
      Thanks for the reply

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=v2/r

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=(15.0m/s)2/r

  • @ARKANGELDIVAISON
    @ARKANGELDIVAISON Місяць тому

    Good

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    15x15

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    diameter 45.0 m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    r=45.0m/2

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    radius

  • @calsrf
    @calsrf 2 роки тому

    Is this angular momentum?

    • @MathAndScience
      @MathAndScience  2 роки тому +2

      It’s related but angular momentum comes later. Physics follows in a specific sequence so these topics are required to understand future topics.

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=10.0m/s

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    scale

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    r=22.5m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    225

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    360 degrees

  • @jamestanny849
    @jamestanny849 Рік тому +1

    Why is it so that when you drive a car in circle your body want to move away from the center?

    • @MathAndScience
      @MathAndScience  Рік тому +2

      It’s just because when you turn the car, your body is wanting to travel in a straight line. Inside the car, this appears that you’re forced to the outside of the turn, but if you look from overhead all that’s happening is your body is wanting to move in a straight line in the car with surround you is curving until you’re popping into the side.

    • @jamestanny849
      @jamestanny849 Рік тому

      @@MathAndScience i was so confused, but of course it is the Velocity vector. You’ve been drawing it the entire time, now I feel stupid haha. I imagined it was a totally different vector because in life i’ve always felt like it was the direct reverse of the center vector. Thanks again, amazing lectures as always!

  • @alicegoodman4544
    @alicegoodman4544 2 роки тому

    H2'0 is water.

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    45.0 m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    formula

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    accelerate

  • @petevenuti7355
    @petevenuti7355 2 роки тому

    I'm still confused how it's really an acceleration, if it was really accelerating wouldn't the angular momentum constantly be going up(or down)?
    If you use some polar coordinate system, or combine the x and y coordinates in some way, that makes it obvious that the amount of force pulling to the center is constant, as well as the instantaneous velocity, you can obviously see nothing is increasing(decreasing) overall.
    It seems like you're just trading the change in direction in a circle for the change in position of something moving in a straight line.
    Does that mean that the definitions just lead to this misleading terminology?

    • @MathAndScience
      @MathAndScience  2 роки тому +2

      No, with respect you are overthinking it. Acceleration is the change in velocity compared to time. It is NOT correct to say that in a circle nothing is changing. It is true the speed doesn’t change but the DIRECTION is ALWAYS changing as you move around the circle. So the velocity is changing because the direction is changing. Remember velocity is a vector, equal part speed and equal part direction. So if the direction changes that’s all that’s needed to say the velocity is changing.
      It goes against common sense but this is truth. Don’t bring angular momentum into this because it isn’t relevant to the definition of acceleration.

    • @petevenuti7355
      @petevenuti7355 2 роки тому

      @@MathAndScience how is that not tied to the coordinate system? The center would always be a right angle to the direction of movement and distance doesn't change..

  • @Mira.Phoenix
    @Mira.Phoenix 27 днів тому

    🥰

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    speed 15.0 m/s

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    m/s

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    asks acceleration dog rounds the turn

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    hahahaha

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    some dog 45.0 m turn running speed 15.0m/s

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=225.0 m/s/22.5 m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=(15.0 m/s)2/22.5 m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    diameter 45.0m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=10.0 m/s2

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a= 30.0 m/s/22.5m

  • @racquelsabesaje4562
    @racquelsabesaje4562 Рік тому

    a=(15.0m/s)2/22.5m