As someone who is learning both mathematics and physics on my own at 39 years old, your instruction is by far, my favorite. Thank you for your passion to teaching and creating these videos.
Im doing the same thing at 56 years old. Its amazing we can get an education like this. At our own pace. I feel a little guilty its all here for free, but ill contribute a bit soon.
Ja sam ovo učio pre 50 godina (osnovna , srednja, faks)... i dan danas sam u ovim sferama nauke... I studied this 50 years ago (primary, high school, college...)... and to this day I am in these spheres of science... Very well video! Thanks
As a former active duty USMC artillery officer, you just made my year by publishing this video. I studied physics at the Naval Academy before I was commissioned and then attended the Field Artillery Officers' Basic Course at Fort Sill after I graduated from The Basic School for Marine officers at Quantico. This video brings back a lot of memories and is inspiring me to relearn trigonometry and calculus. Thank you!!!!!!
This really clear and concise. I have a science degree and going over stuff that I learned from inadequate people. I wish I had had access these explanations. It would have saved me a lot of grief.
In the exact same boat here 39, doing a degree in engineering and this is by far the clearest explanation of this principle. Its something that ive struggled to get my head around and no one seems to be able teach in a way that simplifies it like you have. Thank you!!
This Sir is an amazing teacher. I wish all my teachers were like him. I would have been a lot more successful in life a lot earlier. Learning here from Trinidad in the Caribbean.🙂
OH MY GOD! THIS IS SUCH A HUGE HELP!!! THANK YOU SO SO MUCH!!!! I got an upcoming exam, and I've been extremely anxious until I saw your videos! THANK YOU!!!
Super! Outstanding teaching skills. It's amazing to see how physics, trig and calculus are connected together to understand/interpret a physical phenomena
Out of all videos that Ive watched, this one's the only one that made me understand this topic😭 Most videos are leaned into the 'memorizing' part and never the 'understanding' part. Which is why I really loved your video more💕 Thank you so muchhhh ur such a blessing^^
Excellent lesson. I have always been interested in the motion of an object in a gravitational force field since my college days of studying orbital mechanics.
Thank you for making this video, I really don't like math that much but when I am watching your videos is making me start liking math again. Cause I use to like math but I don't like it anymore even though we use it every day! I bet your students likes you for teaching them! Thanks a lot for the videos man!. You are a very good teacher, God bless you
Hi ' This is helping me to explain to my Grandson of projectile in his physics class. Keep up the good work there are a lot of people out there that wish you were their teacher in school.
Thank you sir , it was crystal clear but can u cover the other equations like 'time of flight' , 'range' , 'maximum height' and 'equation of trajectory' ?
Wow ! That's is amazing . So If I shoot a high power bullet velocity, at say 4000fps the bullet will hit the ground at the same time as if I was to just drop it from the same height at 0 velocity. That is difficult to understand. But this is true .however, you would have to drop the bullet from the top of the arch hieght. Excellent teaching. I've purchased 2 of your DVDs about 6 years ago. Great to see that your still teaching
Well another helpful lesson, helping me fill the gaps in my distance learning degree material in engineering. Don't suppose you have any books you'd recommend for someone studying engineering ?
2nd equation is confusing cus the equations of motion I w know are V = U + at V² = U² + 2aS S = Ut + ½at² S = ½(U+V)t Where S is the distance V is final velocity U is initial velocity a is acceleration ❓
You are right, but this is where you have missed it. S=ut+1/2at^2. S in the above equation is change in displacement, which can be replaced as Xf-Xi. Substituting the above for S you will now have Xf-Xi=ut+1/2at^2 (making Xf the subject of the formula you will now have) Xf=Xi+ut+1/2at^2.💯💯💯
I have a comment you should tell the students, that the Sign of G, depende on your frame of reference, or datum. If your on top of a platform throwing kicking or dropping a ball, you could use G as positive, but if it's on the ground then you could use Y as positive up and then G will be negative, so it all depends on your frame of reference, and the equations as well will change. Gravity always points down, so if you choose your frame of reference for Y positive up, your G will be negative, if you use your frame of reference for Y positive down, your G will be positive as well. But you put such passion in what you are doing, thar you are truly a great professor. I congratulate you. I wish I had while I was in College professor like you.
Mr. Jayson, from your videos on resolution of forces and trigonometry, I had sensed what might be happening in projectile motion before I watched your this video. Anyways I would like to genuinely thank you for your commitment! I do have a question in my mind regarding the acceleration in the x direction that why the acceleration in the x direction was not included or mentioned in the video that was applied in the first place by the person hurling the object in projectile motion. I mean there has to be an acceleration because a force was applied otherwise there wouldn't be any motion in the x direction, or was it so negligible that we ditched it completely?
Can you please create videos for BioChemistry. I am not able to find a good video for Biochem. Math and Physis chemistry you are best. Please create biochem also.
@@akinyelemorounfoluabdurahm5005 it is the older system of measurements, uses feet, yards, miles, gallons, pounds and so on. For a comprensive explanation, Google for the answer.
Realno, zato što postoji otpor kretanju projektila (trenje u vazduhu), stoga je trajektorija modufikovana faktorom e^-kt, (k zavisi od otpora sredine). Realistically, because there is resistance to the movement of the projectile (friction in the air), therefore the trajectory is modified by the factor e^-kt, (k depends on the resistance of the medium).
@@josip.harasic The "resistance of air" depends on a lot of parameters including the form of the projectile, its bearing, on the velocity itself (supersonic or not)... In any case it can't be neglected, we never assume that a trajectory is parabolic, unless you do not care about killing people far from your target.
As usual the diagram is grossly misleading. Firearms books use this almost exact demo to explain the path of a projectile from a firearm. The correct path is a drooping arc with the droop rapidly steepening as it gets further form the gun. Books show the projectile traveling through the path described here and much of the firearms community believe a projectile leaves the muzzle and rises above the "line of departure". This is not so.
I’m not sure what you’re going on about but I never mentioned firearms in this lesson. The diagram is not misleading, the diagram is that of throwing an object up from the ground at an angle that is why it rises up and then comes down.
@@MathAndScience Firearms publications are full of misconceptions concerning the path of a projectile after leaving the barrel. Most people believe the projectile rises---when it does not and it is because of diagrams as we see here. All firearms publications use this same diagram to explain the behavior of a projectile. The original path of the projectile would be "line of departure" which it never gets above. Would you discuss this and clarify the confusion?
![Solving 2D Velocity & Acceleration Problems in Physics - [1-4-3]](http://i.ytimg.com/vi/Rsy1dcta5GU/mqdefault.jpg)
![Solving 2D Velocity & Acceleration Problems in Physics - [1-4-3]](/img/tr.png)
![What is Circular Motion & Centripetal Acceleration in Physics? - [1-4-14]](http://i.ytimg.com/vi/cg9blNCbVKc/mqdefault.jpg)
![Solving Projectile Motion Problems in Physics - [1-4-7]](/img/n.gif)
As someone who is learning both mathematics and physics on my own at 39 years old, your instruction is by far, my favorite. Thank you for your passion to teaching and creating these videos.
Wow, thanks!
We are in the same boat.
Well am in my 40th hhhhhhhh
Im doing the same thing at 56 years old. Its amazing we can get an education like this. At our own pace. I feel a little guilty its all here for free, but ill contribute a bit soon.
Ja sam ovo učio pre 50 godina (osnovna , srednja, faks)... i dan danas sam u ovim sferama nauke... I studied this 50 years ago (primary, high school, college...)... and to this day I am in these spheres of science... Very well video! Thanks
As a former active duty USMC artillery officer, you just made my year by publishing this video. I studied physics at the Naval Academy before I was commissioned and then attended the Field Artillery Officers' Basic Course at Fort Sill after I graduated from The Basic School for Marine officers at Quantico. This video brings back a lot of memories and is inspiring me to relearn trigonometry and calculus. Thank you!!!!!!
That is awesome and you are very welcome!
You have really done a lot in the life of this Nigerian 🇳🇬🇳🇬🇳🇬. Thanks a lot. More grace and favor.
Once again thank you.
This really clear and concise. I have a science degree and going over stuff that I learned from inadequate people. I wish I had had access these explanations. It would have saved me a lot of grief.
In the exact same boat here 39, doing a degree in engineering and this is by far the clearest explanation of this principle. Its something that ive struggled to get my head around and no one seems to be able teach in a way that simplifies it like you have. Thank you!!
This Sir is an amazing teacher. I wish all my teachers were like him. I would have been a lot more successful in life a lot earlier. Learning here from Trinidad in the Caribbean.🙂
OH MY GOD! THIS IS SUCH A HUGE HELP!!! THANK YOU SO SO MUCH!!!! I got an upcoming exam, and I've been extremely anxious until I saw your videos! THANK YOU!!!
Thankyou
Inspite of the fact that I’m a teacher I got lots of benefits while I’m lestening to your videos
I don’t have eough words to say thank you
Thank you so much.
He answers the part that the books do not reveal at all . I love watching these lectures. Thankyou sir
You are literally saving students here. Love from Philippines!
Super! Outstanding teaching skills. It's amazing to see how physics, trig and calculus are connected together to understand/interpret a physical phenomena
Out of all videos that Ive watched, this one's the only one that made me understand this topic😭
Most videos are leaned into the 'memorizing' part and never the 'understanding' part. Which is why I really loved your video more💕
Thank you so muchhhh ur such a blessing^^
Zambia 🇿🇲 is learning
True it and it's helping out alot.
Very much
I don't suggest you to use small capitals.
Excellent lesson. I have always been interested in the motion of an object in a gravitational force field since my college days of studying orbital mechanics.
Thank you for making this video, I really don't like math that much but when I am watching your videos is making me start liking math again. Cause I use to like math but I don't like it anymore even though we use it every day! I bet your students likes you for teaching them! Thanks a lot for the videos man!. You are a very good teacher, God bless you
Thank you so much for these videos....I was so lost in class until I come across your teaching....so much appreciation ❤🎉
As a student in Papua Nea Guinea and taking science advanced maths and physics ,this as been a great help 👍
You look healthy and strong!! Im so happy when you post videos man!
Wow thanks so much! More to come!
Hi '
This is helping me to explain to my Grandson of projectile in his physics class. Keep up the good work there are a lot of people out there that wish you were their teacher in school.
Honestly Thank You so much!! Best teacher to explain it simply to me.
Thank you sir , it was crystal clear but can u cover the other equations like 'time of flight' , 'range' , 'maximum height' and 'equation of trajectory' ?
What a wonderful teaching style watching from nepal.please complete whole course of physics
Thank you so much!
You are a blessing to me ooh, sir
Hi prof thanks everything u've been teaching us!!!
You are very welcome!
Hey! Plz post more parts on UA-cam ! You’d def get lots of views !
Wow ! That's is amazing . So If I shoot a high power bullet velocity, at say 4000fps the bullet will hit the ground at the same time as if I was to just drop it from the same height at 0 velocity. That is difficult to understand. But this is true .however, you would have to drop the bullet from the top of the arch hieght. Excellent teaching. I've purchased 2 of your DVDs about 6 years ago. Great to see that your still teaching
Thank you so much professor! Nice lecture
Well another helpful lesson, helping me fill the gaps in my distance learning degree material in engineering. Don't suppose you have any books you'd recommend for someone studying engineering ?
Gratitude from India 🎉
I really really love your lectures
These are sooo helpful
Love from Pakistan 💚
I don't know enough English, but I understood you better than my professor who speak the same language than me.
doing god's work THANK YOU
Thanks for the wonderful explanation!
Great video, very clear, thank you.
Very knowledgeable.. An excellent tutor..
Glad you think so!
Excellent teaching
2nd equation is confusing cus the equations of motion I w know are
V = U + at
V² = U² + 2aS
S = Ut + ½at²
S = ½(U+V)t
Where S is the distance
V is final velocity
U is initial velocity
a is acceleration
❓
You are right, but this is where you have missed it.
S=ut+1/2at^2.
S in the above equation is change in displacement, which can be replaced as Xf-Xi.
Substituting the above for S you will now have
Xf-Xi=ut+1/2at^2 (making Xf the subject of the formula you will now have)
Xf=Xi+ut+1/2at^2.💯💯💯
I have a comment you should tell the students, that the Sign of G, depende on your frame of reference, or datum. If your on top of a platform throwing kicking or dropping a ball, you could use G as positive, but if it's on the ground then you could use Y as positive up and then G will be negative, so it all depends on your frame of reference, and the equations as well will change. Gravity always points down, so if you choose your frame of reference for Y positive up, your G will be negative, if you use your frame of reference for Y positive down, your G will be positive as well. But you put such passion in what you are doing, thar you are truly a great professor. I congratulate you. I wish I had while I was in College professor like you.
this is such a huge help
you are a really good instructor thank you
This man lecture is funny and at the same time very understanding
Mr. Jayson, from your videos on resolution of forces and trigonometry, I had sensed what might be happening in projectile motion before I watched your this video. Anyways I would like to genuinely thank you for your commitment!
I do have a question in my mind regarding the acceleration in the x direction that why the acceleration in the x direction was not included or mentioned in the video that was applied in the first place by the person hurling the object in projectile motion. I mean there has to be an acceleration because a force was applied otherwise there wouldn't be any motion in the x direction, or was it so negligible that we ditched it completely?
I LOVE THIS MAN!!!!
I really love this lecture ❤❤
You are just amazing sir.
Lots of love and respect from Pakistan❤
Thanks a ton
👏👏👏 Brilliant explanation, I get it now
Ooh thanks, watching from kenya
We all know he's the best
Enjoyable lecture
Thank you Sir
For you are not Despising our warmHeart of Africa 🙇🏇🏇🏇🏇
32 feet per second per second.
Can you please create videos for BioChemistry. I am not able to find a good video for Biochem. Math and Physis chemistry you are best. Please create biochem also.
Thanks this was so useful
Thank you sir for the video
Amazing explanation thank bro
Excellent
Nice 👍
Thank you!
ok, i have to go back, i missed something. I LOVE THIS!
Thank you so much 😊😊😊
THANK YOU... SIR...!!!
Thank you❤
Thank you so much enlightening
You are so welcome
So helpful to be honest
It is nice to hear a US tutor use the metric system of measurements as opposed to imperial system of measurements 😀
What's the imperial system
@@akinyelemorounfoluabdurahm5005 it is the older system of measurements, uses feet, yards, miles, gallons, pounds and so on. For a comprensive explanation, Google for the answer.
Thank you. Please allow the cc, the auto subtitle.
10xfor your committiment sir!
Thank you! C:
Sir, why is the acceleration negative?
This topic seemed to hard till today after l play this video
Billy Mays did physics?
Dear Sir, Please give link to buy marker pen.
How are you
I’m good how are you doing?
Thank you so much for this amazing video😊 I've been struggling and your explanation really helped💙 Thank you very very much
🇿🇲🇿🇲🇿🇲🇿🇲 Zambia is online
I love you
We are learning New things every day 😂
What is Vo
My country students are safe that am watching this on their behalf ☺️
Hello
Zoooooper
What language are you typing in?
we all know that a projectile trajectory (on earth) is never a parabola
Realno, zato što postoji otpor kretanju projektila (trenje u vazduhu), stoga je trajektorija modufikovana faktorom e^-kt, (k zavisi od otpora sredine). Realistically, because there is resistance to the movement of the projectile (friction in the air), therefore the trajectory is modified by the factor e^-kt, (k depends on the resistance of the medium).
@@josip.harasic The "resistance of air" depends on a lot of parameters including the form of the projectile, its bearing, on the velocity itself (supersonic or not)... In any case it can't be neglected, we never assume that a trajectory is parabolic, unless you do not care about killing people far from your target.
@@gide5489 That´s right, absolutely...👍
What language are you typing in?
@@YujiuWang-qc8bn Bosnian ?
🇪🇹is learnig
As usual the diagram is grossly misleading. Firearms books use this almost exact demo to explain the path of a projectile from a firearm. The correct path is a drooping arc with the droop rapidly steepening as it gets further form the gun. Books show the projectile traveling through the path described here and much of the firearms community believe a projectile leaves the muzzle and rises above the "line of departure". This is not so.
I’m not sure what you’re going on about but I never mentioned firearms in this lesson. The diagram is not misleading, the diagram is that of throwing an object up from the ground at an angle that is why it rises up and then comes down.
@@MathAndScience Firearms publications are full of misconceptions concerning the path of a projectile after leaving the barrel. Most people believe the projectile rises---when it does not and it is because of diagrams as we see here. All firearms publications use this same diagram to explain the behavior of a projectile. The original path of the projectile would be "line of departure" which it never gets above. Would you discuss this and clarify the confusion?
@@MathAndScience Understood. This is a good explanation.
te pup 😘
What language are you typing in?
Abdul is learing
What language are you typing in?
Parabola comes from the Arabic language.
The word "parabola" comes from the Arabic language.
🇿🇲
he should explain gailei transformations