That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
@Mariyam Jahangir Hey! 9.8 ms is the value of Earth's gravity. As the objects motion was upwards, the gravity was opposing it. So was used with negative sign .
@Mariyam Jahangir when you drop an object on Earth, it accelerates towards the ground at 9.8ms⁻² (ignoring the effects of air resistance). As for the negative sign, that's called 'sign convention' - deciding which direction is positive and which is negative. I take upwards to be the positive direction. Since objects accelerate downwards (the negative direction), acceleration due to gravity is taken as -9.8ms⁻²
Why would people dislike the truth about the Equations of motion everything is perfect *its slow pace to not fall behind *simple and going through each step *perfect illustration i can't see why people disliked this?
Perfect! Exactly what i was looking for. Most other videos just show how to memorize the equations, this goes under the hood. The equations make perfect sense now.
It's really a good lecture . I was able to understand very efficiently without subtitles . Would you please solve more examples in your video . That would be really helpful . Love form India !!
thank you sir !!!!!that was useful, now iam grateful that i found a teacher like you , i hope your students understand that they HAVE YOU !!!!!many thanks
Thank-you very much. My brain was very confused because of this kinematic equations of Sir Isaac Newton and was about to destroyed because no one was able to explain this concepts in simple way. You explained them very well and help me overcome my physics problems. Thank-you very much buddy!!👍
Dear Mr Smith, I humbly request you to make a video regarding graphs of uniform acceleration etc. I have a lot of trouble reading them and obtaining data from them. This is just a suggestion.
There is a video called 'Velocity-time graphs' - is that any use to you? If you tell me what areas the video would need to cover, it's something which I'm sure I could do at some time because it wouldn't take too much work.
Thank you so much! I couldn't figure out how to get the 3rd equation, but after this explanation the 3rd and 4th seem quite obvious. Of course it's harder if you don't know how you're supposed to get there.
But you are more awesome than me.I am just a student whereas you are a teacher.Not just a normal teacher but an super awesome teacher.Btw you are welcome.
Sir you are the best physics teacher in my life..............simply you can explain fluently .....please doing more video .............we can understand more........sir I am the student of honours 3rd year department of mathematics.......sir you will be able taw solve mechanics 3rd year major courses..............
Wow, thanks a ton. In the exercise only u was given and the rest you had to find out by reading the text carefully and making one assumption (taking upwards as positive). Hadn't known how to do this before watching the vid. Super content!!!
Thanks this halped me alot i have ny paper tomorrow and i was having a lot of trouble understanding this but after watching this video but now its all cleared thankyou mr smith
I have a question, i was doing homework and came across a question that said a ball being thrown vertically upwards at 4ms-1, whats the height of the ball after 2 seconds and i was writing down what i had and used a=-9.8ms-2 which gave a negative displacement, should i have taken acceleration as negative or have i done something wrong?
The full question is “a ball is thrown vertically upwards from the edge of a cliff as shown on the diagram” on the diagram shows the cliff being 33 m tall and the ball being thrown at 4 ms-1 “the effects of friction can be ignored” a) “what is the height of the ball above sea level 2 seconds after being thrown?” Thanks for the help
Excellent video! Could you please tell me how did you make such video containing moving symbols? I really love this approach to show equation derivations.
My school has no space for higher physics so I have to learn it all myself you channel is really helpful thanks hopefully I get to set the prelim and pass 🙏🏾
It's a font in Apple Keynote called 'chalkduster'. I like the look but it doesn't always work when writing equations so I'll probably not use it again.
That's because (ignoring air resistance), the path of the projectile is perfectly symmetrical. The vertical velocity at any height on the way down will be equal to that on the way up.
Thank you- this has helped. Just one ? though, why would v be -20? I understand the direction means that it is negative, but how do you know that it would be going at 20ms-1?
The motion of a projectile (ignoring air resistance) is perfectly symmetrical. This means that, if it is projected upwards at 20ms⁻¹ then when it's at exactly the same height on the way down, its speed will again be 20 ms⁻¹. We also have to apply sign convention: I take upwards as the positive direction which means velocity is +20ms⁻¹ on the way up and -20ms⁻¹ on the way down.
how did you get -9.8 for the acceleration?
please help, thanks
That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
good question
@Mariyam Jahangir Hey! 9.8 ms is the value of Earth's gravity. As the objects motion was upwards, the gravity was opposing it. So was used with negative sign .
@Mariyam Jahangir when you drop an object on Earth, it accelerates towards the ground at 9.8ms⁻² (ignoring the effects of air resistance). As for the negative sign, that's called 'sign convention' - deciding which direction is positive and which is negative. I take upwards to be the positive direction. Since objects accelerate downwards (the negative direction), acceleration due to gravity is taken as -9.8ms⁻²
@@MrSmithsPhysicsonline you use calculator for these. We don't use calculator in india for such small problems.
Why would people dislike the truth about the Equations of motion everything is perfect
*its slow pace to not fall behind
*simple and going through each step
*perfect illustration
i can't see why people disliked this?
I personally love all my videos, but I guess we're all entitled to an opinion! Thanks for your positive comment.
@@MrSmithsPhysicsonline thx this helped a lot
Perfect! Exactly what i was looking for. Most other videos just show how to memorize the equations, this goes under the hood. The equations make perfect sense now.
Thanks for the comment!
You're an absolute legend. School is closed due to Covid-19 and this is teaching me so much of the higher course for next year. Thank you!
Thank you - I'm working on new videos too. Glad they're helping.
Hi
Me too
Am i only the one watching in 2024 😢😅😅
Thanks for watching - this is my most popular video, so you're not the only one!
@@MrSmithsPhysicsonline thanks 😊
No you aren't my friend
We are here
Nooo
It's really a good lecture . I was able to understand very efficiently without subtitles . Would you please solve more examples in your video . That would be really helpful .
Love form India !!
I'll certainly try to make more videos with worked examples. Thanks for the comment.
Thanks for helping me pass my physics test 🥰
Happy to help!
Excellent.
.
. teaching with nice illustration
Thank you! The illustrations can take a long time so it's nice to know that they're appreciated.
tq uuuuuuuuuuuuuuuuuuuuuu sooooooooooooooooo muchhhhhhhhhhhhhhh sir .the best thing about u is that u r responding all the comments
I'm trying - I really appreciate the feedback. Glad you liked it!
hi sir how are u sir
Bhai thanx kyuki aap sabko comment bhi karte ho aur bdhiya explain bhi krte hoo
Hmesha isi 5rh krna all the best
Bhai you teach good
Thank you! I always try to reply to all comments although some of them seem to get lost at times. Glad you are finding the videos useful.
So glad I found your channel struggling so much with physics and need it for uni
How did you get on in the end?
It's good to see you replying for every comment .
I try to reply to them all so that I can help anyone with a problem. Glad you noticed!
Can do more example of solving problems for these equations..... It really helps us
Will do!
You just completed my 1 week project within 9.11/1.25min
Thank you brother
Excellent - all in a day's work!
Got a new student, very well explained. This video is really helpful.Thank you sir
Thanks for the comment!
@@MrSmithsPhysicsonline welcome, sir.
My teacher never explained how to extract these, thanks so much now I can easily remember equations of motion
You don't need to know the derivations any more but I feel that it's still useful to know where they come from.
Good videos
I like it
Good I will like your suggestion
thank you sir !!!!!that was useful, now iam grateful that i found a teacher like you , i hope your students understand that they HAVE YOU !!!!!many thanks
Thank you! Glad that you're finding the videos helpful. All the best!
Thank-you very much. My brain was very confused because of this kinematic equations of Sir Isaac Newton and was about to destroyed because no one was able to explain this concepts in simple way. You explained them very well and help me overcome my physics problems. Thank-you very much buddy!!👍
Thanks for the lovely comment - all the best!
Thank You very much sir. I've found good use of UA-cam.
Glad to hear that - all the best!
Dear Mr Smith, I humbly request you to make a video regarding graphs of uniform acceleration etc. I have a lot of trouble reading them and obtaining data from them. This is just a suggestion.
There is a video called 'Velocity-time graphs' - is that any use to you? If you tell me what areas the video would need to cover, it's something which I'm sure I could do at some time because it wouldn't take too much work.
Thank you so much! I couldn't figure out how to get the 3rd equation, but after this explanation the 3rd and 4th seem quite obvious. Of course it's harder if you don't know how you're supposed to get there.
Glad the video helped. What other topics would you like to see covered?
Why did you get so many dislikes when it's the clearest video explaining the equations 🤔
Nobody likes the truth! Each to their own, I suppose.
Such an amazing lecture I've heard ever, i was facing problem in understanding the equations of motion but after this i got all of that.
Thank you very much - glad you found it useful.
Saw many videos on this but perfectly understood this one.
Thank you Sir for such a great explanation.
I would love to be your student
Thank you
Thanks and welcome - glad that it helped.
Seriously, this is the best explanation ever.
That's the best comment ever! Thanks.
You are my favourite teacher
You're too kind!
@@MrSmithsPhysicsonline thank you sir
Wow your teaching is amazing I loved it we’ll make more videos like this ❤
Moree videos in the pipeline!
Your video is unexplicably amazing!!!!!!
Thank you so much!!!!!!
You've obviously got good taste!
Clear and brief! Also helpful example question at the end! Thank you very much!
You're very welcome! Glad you found it helpful.
Very good 📔📔📔📔📔📕📕📕📕📖📖📖📖📓📓📚📚📚📚📚📚📚📚& helpful📚📚📚📚📚📚📚📗📗📘📗📘📗📘 video
Cheers - love the emojis!
Thank you! This explanation was all i needed. Keep making more videos!❤
Thank you - glad you found it useful!
This teacher just solved my problems.
Glad to help - who's going to sort my problems?
Thank you so much for this video, it was very useful!! I'm trying to learn these equations for the first time for my BMAT exam, you definitely helped!
Glad to have helped - good luck!
What is bmat exam ?
Hallooo army 😊
Glad! I found this video,my teacher is not so good . So I wasn't able to understand it, but you cleared all doubts
Glad it was helpful!
the girl who threw the ball should be a pro athlete
Maybe she is - I'll ask.
Thanks for helping me a day before my class test...🙏
Glad you found the channel in time for the test - hope it helped.
Tomorrow is my exam thanks for helping
Good luck!
Thanks a lot, sir!!!
You're very welcome!
Congrats for the great explanation! I’m 100% sure I’ll get good marks in tomorrow’s physics exam because of you sir! Love from india ❣
Hope everything went well with the exam!
Great! I got the results and got 20/25 🤩🤩🤩
how do you study??😭 i need help omg
Thank you sir 🥰... from Bangladesh 🇧🇩
Thank you too!
You are awesome.I understood it in one watch.
Thank you - you are awesome too!
But you are more awesome than me.I am just a student whereas you are a teacher.Not just a normal teacher but an super awesome teacher.Btw you are welcome.
Thank you Sir! Your video really helped me in solving numericals!
Excellent - glad it helped!
thanks! This is what I need for knowing the concept of the formula
Glad you found it useful - thank you!
The explanation was great ,helped me a lot in my assignment again ,thx for helping 🔥🔥
Glad it helped!
very interested...
......
.......
.....
nice way of teaching
.......
excellent teacher
Glad you liked it!
Sir you are the best physics teacher in my life..............simply you can explain fluently .....please doing more video .............we can understand more........sir I am the student of honours 3rd year department of mathematics.......sir you will be able taw solve mechanics 3rd year major courses..............
Thanks for the comment - I'm working on new videos to bring out this term.
I found this video very helpful, thank you!
Thanks. BTW I love a good meme too.
Wow, thanks a ton. In the exercise only u was given and the rest you had to find out by reading the text carefully and making one assumption (taking upwards as positive). Hadn't known how to do this before watching the vid. Super content!!!
Glad it helped! Thank you for the kind comment.
Thank you Mr. Smith, it was very helpful!
Glad it helped!
Super, reminds me of o level physics which I am beginning to need again.....thank you, very clear and helpful
O level - those were the days!
Am I only one watching in 2024
You're doing well - I'm still living in the 1980s.
@@MrSmithsPhysicsonline😂 nicee
Na
this is the first time I comment on UA-cam and thx so much bro cuz tomorrow is my exam and this video really help me a lot
All the best with the exam! Glad it's helped you.
Thanks for explaing it sir
Thank you - keep watching!
thank you for the example.helped a lot:D
Glad it helped!
Thanks sir for the proof of kinematic equation it's really helpful
Glad you found it helpful
Thanks this halped me alot i have ny paper tomorrow and i was having a lot of trouble understanding this but after watching this video but now its all cleared thankyou mr smith
Good luck tomorrow - fingers crossed!
Sooo nice its clear my all doubts its help me a lot.... Thanku
Glad you found it useful - thank you!
I have a question, i was doing homework and came across a question that said a ball being thrown vertically upwards at 4ms-1, whats the height of the ball after 2 seconds and i was writing down what i had and used a=-9.8ms-2 which gave a negative displacement, should i have taken acceleration as negative or have i done something wrong?
I get an answer of -11.6m which means that the object would be 11.6m below its starting position (if possible). What's the full question?
The full question is “a ball is thrown vertically upwards from the edge of a cliff as shown on the diagram” on the diagram shows the cliff being 33 m tall and the ball being thrown at 4 ms-1 “the effects of friction can be ignored” a) “what is the height of the ball above sea level 2 seconds after being thrown?” Thanks for the help
Joe?
Great Mr. SMITH
You explained it very well.
Thanks very much!😇
Glad to help!
I have a higher physics autumn assessment tomorrow on odu, thanks for these videos they are really helpful for revising
Good luck - you can do it!
OMG MY SAVIOUR...I SAW THIS AND WAS CRYING CUZ I DIDNT UNDERSTAND..MY UNDERSTANDING IN PHYSICS SUCKS....TYTY SO MUCH!!!
Physics has that effect on people sometimes - glad to help!
Wonderful sir!!!
Mind blowing derivation SMITH sir....
Thank you - glad you found it useful!
@@MrSmithsPhysicsonline it's ok sir
Alright
Thanks a lot sir ,well explained☺☺☺
Thanks!
I have a test tomorrow. Thanks for the help
Good luck - hope it goes well!
Thank you so much!
Glad you liked it!
You are a legend my friend
Thanks - takes one to know one!
Very helpful 😀Thankx!
Thanks, Astrophile!
By watching this I have cleared all my doubts 👍👍👌☝️
That's great - glad it helped.
perfect ....well done
Thank you - glas you found the video helpful.
This video was really helpful for me. Thanks a lot for making this video
Glad it was helpful!
nice video and your vice is nice
Thank you - I'm glad that it's been helpful.
SIR YOURE THE GOAT TYSM!!
You're too kind!
Relative motions plz
I'll hopefully have one soon on relative motion - a past paper solution video.
Thanks ,I caught up all my work 👍 now I'm on track 😊
Magic - glad that it helped.
Can you please become my physics teacher.
I can be your UA-cam Physics teacher - that's probably better than having me as a teacher in real life!
thanks a ton ,this is something you dont usually get on yt.thank you for sharing this video .love from india:D
My pleasure! I'm keen to make more videos with example questions - are there other topics you'd like to see covered?
Thank you very much mr. Smith
Glad it helped - thank you!
Excellent video! Could you please tell me how did you make such video containing moving symbols? I really love this approach to show equation derivations.
I use Keynote on an iMac for the animations. It takes a long time for each video but i'm happy with the results.
@@MrSmithsPhysicsonline thx，helps a lot
Really vry helpful thanks
Thank you!
Studying for my GAMSAT and this helped so much - thanks!
Glad it's helped - good luck!
Thanks 🐯
Glad you liked it!
Thank you!! You made it so easy to understand. And I understood 🤯🤯🤯🤯
Glad it helped!
thanks .it was helpful .
Great - glad that you found it helpful.
@@MrSmithsPhysicsonline i commented 3yrs back xd i m in 12th now and now i got the reply haha
Thank you kind sir
Your help will be recognized
👍👍👍
Happy to help - that's why I make the videos.
sir how we will get to know that v- u in height of triangle?
It might be easier to imagine some values - say u=6m/s and v=10m/s. The height of the triangle must be 4 ie 10-6. Hope this helps!
thanks sir you are the best teacher in the world
I agree!
Mr Smith.. u r awesome...😊😊..
My school has no space for higher physics so I have to learn it all myself you channel is really helpful thanks hopefully I get to set the prelim and pass 🙏🏾
Good luck to you - just ask in the comments if you need help.
So helpful
Cheers - it's taken me a while to respond, but I got there!
All the best!
May i know what is the font you are using for the presentation. It looks good .
It's a font in Apple Keynote called 'chalkduster'. I like the look but it doesn't always work when writing equations so I'll probably not use it again.
verreeey helpfull and easy
Easy - you've obviously understood it well!
might be 7 years old but still helping my ass out going into leaving cert higher level physics 😭 tysm for these vids man
Good luck & all the best!
Please save me from higher physics hell
Save yourself - if you've started revising now then you've got time to get some serious revision in and turn it around. Good luck!
how do u consider initial and final velocity of the ball be the same? ( although der is difference in sign due difference in direction)
That's because (ignoring air resistance), the path of the projectile is perfectly symmetrical. The vertical velocity at any height on the way down will be equal to that on the way up.
thanks :)
You're Albert Einstein why are you here. You should be teaching HIM not the other way around.
ha ha ^^
Thanks for all your work, Albert - it's been an inspiration!
Thank you- this has helped. Just one ? though, why would v be -20? I understand the direction means that it is negative, but how do you know that it would be going at 20ms-1?
The motion of a projectile (ignoring air resistance) is perfectly symmetrical. This means that, if it is projected upwards at 20ms⁻¹ then when it's at exactly the same height on the way down, its speed will again be 20 ms⁻¹. We also have to apply sign convention: I take upwards as the positive direction which means velocity is +20ms⁻¹ on the way up and -20ms⁻¹ on the way down.
@@MrSmithsPhysicsonline Thank you, that makes sense!
good sir
Good comment - thanks!
excellent explanation!
Thank you - glad you liked it.
hey he's foreign that's lit
From Scotland - ya dancer!
What is meant by displacement? The distance covered from original position? Hope you can help!
Have a look at this video of definitions, where displacement is covered...
ua-cam.com/video/5YF8dZfrtvo/v-deo.html
from nepal😍
Welcome from sunny Scotland!
thanks for this epic vid understood how to derive thanks to you
No problem! It's a tricky job deriving the equations but I think the animations help.