I have added the PDF file in the description, you can download it for free for your studies. Feel free to comment and ask questions! Update: On time 4:18 there is a mistake The formula will be: s = { (v+u)/2 }÷t
idk man, maybe i am underrated cause i can only give one video per month. don't worry, i will make this channel a library of important topic wise explanations!
ThatPhysicsGuy ilysm You have opened my mind to never before known concepts. You're way of teaching has made me ascent to the heavens above of the physics world.
please make more videos!! you are the first youtuber i’ve watched and actually explained this to me so i understand! everyone i’ve seen explains why and what is it without actually explaining how to answer the questions! i would literally pay to make more videos like this
Truly the BEST video i have seen about kinematics. Honestly, I was first a bit skeptical but I was so surprised how well i understood it after struggling for 2 years with this topic. Please upload more such videos especially focusing on grade 12 topics. THANK YOU
Dude tysm! I was really woried about my physics exam that was coming up and this video helped me understand many things, you should make more videos since you are such a great teacher! Subscribed.
Finally i understood why sometimes sin is used for the horizontal axis and cos for the vertical! And also why the value of g is negative in some projectile motions even when the ball is going downwards. Not even my textbooks made these things clear. Thank you so much!! I have my A-level physics exams in 10 days and you have clarified everything! ❤️
i love this so much. i never comment on videos, but this actually helped me. i'm an ib student with almost 0 prerequisites in physics. in every other video i watched, they always pick the easy questions to showcase the "process of solving" but this one actually shows harder questions and how to solve them! love it :3
You sir are an amazing person. The way you explained it with so much ease made me understand everything that my teacher did not teach. Thank you very much❤
at 11:00 I understand the approach to calculate the time according to how long it takes to fall since the acceleration is constant. But if it takes 1.75s and the ball's horizontal velocity is 30m/s then wouldnt it have traveled 52.5 meters horizontally before it reaches the ground?
in the question time 6:00 i have written down 78° in this example the angle was given. if the question comes that the angle was not given then you have to use SOH CAH TOA or other trigonometry formulas to find it
hey i had a question.. at 10:55 when finding the time of flight. why cant we use velocity = displacement/ time even though we have the horizontal displacment and velocity
that formula is definitely accepted and applicable, but here i am showing how to use only the 4 suvat formulas for any sutuation. the formula you mentioned has limitations, that is, the projectile must start and end at the same height.
Can you make such videos of different chapters such as straight line, circular motion,etc. It will be really helpful and this video also really helped me a lot 😃👍
As a student I wanna suggest you that upload videos of every chapters And now kinematics is more important so do 1-D ,2-D,3-D all chapters video and very good contents such a mind blowing video loved it ❤
i try to comment fast. i have a small audience and mainly you guys might ask questions that needs explanation. making a video takes time but replying takes literally seconds
When the ball is the rising up and falling down in both the cases the gravity is acting down then why is the sign negative when the ball is rising up 2:49
In 2:49, i have taken any upward velocity as negative and downward velocity as positive. In that case, the downward pull of gravity will also be positive. But when we calculate moving up and then down, then we use acceleration as negative.
in 14:49 where acceleration is 0 because it doesn't affect the horizontal component, why (in the equation) does 1/2 disappear and time remains, wouldn't it be = 1/2 x 0 x 6.02^2??? how come you seperate the 0 and put it outside and then make the ut + 1/2at^2 into ut x 2t? Need an answer here or I will be confused.
@@ThatPhysicsGuy AHaaaa I guess that makes sort of sense, as then you end up with + 0 on the outside, however why multiply ut with t^2. how did we go from addition to multiplication there?
Sir in 5:17 question -at what vertical speed is the ball landing on the water? Why we only took the velocity which was at max. height i.e. 0 can't we take the initial velocity as 8.5m/s as it was initially and take the displacement as 30m ??
yeah you can do 8.5 m/s too. then you have to keep in mind that the initial velocity os pointing upward and the final velocity is pointing downward. so the values will have different signs. ok?
@ThatPhysicsGuy some other videos I've seen have used the horizontal and vertical velocities as the base and leg of a right triangle and found the final angle as arc tangent opposite/adjacent. This seems to work in most instances. However the situation in the video seems to be an exception as you do not get 78⁰ using this method.
thank you for the video! Can you make an in depth discussion about magnetic and electric fields? Or a video expanding on everything you said in the unit 4 need to know videos regarding magnetic and electric fields? It is the topic I struggle with the most in Unit 4 IAL Edexcel. Thanks!!! :)
Yeah sure! I am working on AS electricity now, i will start A2 magnetic and electricity field right after that, ok? also, if you have specific questions you can email me on the channel's email so that i can provide better answers and provide you with more links and worksheets
In video at 9:27 if you consider acceleration negative then value of (s) or height answer will be also become negative. There is a mistake in calculatjon . Please explain 9:27
in this part, then ball is moving up and then down again. moving up the acceleration is -ve and moving down the acceleration is +ve. so always remember, when we have a projectile motion moving in both directions on after another we will always use negative. this is explained in time: 9:15
- as angle increases from 0° to 45° the range increases - after 45° the range decreases - at 90° there is no range. the ball basically moved vertically upward and moves downward
suppose in a projectile (which ends at diff height) we are asked to find the time taken to reach max height and also the time taken to reach the ground. If we use 'S' as positive while calculating time for max height then do we need to use 'S' as negative while calculating time taken to reach ground.
The two vectors a and in the figure have equal magnitudes of 12.9 m and the angles are 01 = 28° and 02 = 109º Find (a) the x component and (b) the y component of their vector sum 7, (c) the magnitude of 7, and (d) the angle 7 makes with the positive direction of the x axis.
pls pls pls post international AS lvl cambridge syllabus topics!! i respect u sm for this video sir, would love to see more but with newer revelant topics!
I HAVE A QUESTION, In 5:14 to find max height, why didn't you add the 30 meters too( of that cliff) because the projectile is 33.6 meters above the sea, so isn't that the max height? Doesn't that include in the height of the projectile's path? I have physics exam tomorrow so help would be appreciated 👍
I have added the PDF file in the description, you can download it for free for your studies.
Feel free to comment and ask questions!
Update:
On time 4:18 there is a mistake
The formula will be:
s = { (v+u)/2 }÷t
thank you so much for making high quality and concise education free for us. ❤
welcome!
The best video I've ever seen on yt. Thanks alot❤🎉😢
@@ThatPhysicsGuy thanks a lot brother
On 6.56 I got 26.28 instead of 28.28 but how
How is this guy soo underrated? Lecturers often use formulas out of Nowhere and do not say the reason why? This guy is literally the best 😤
idk man, maybe i am underrated cause i can only give one video per month.
don't worry, i will make this channel a library of important topic wise explanations!
@@ThatPhysicsGuy try to keep uploading good sir
Got my kinematics test today, this is unironically the best yt video on AP Physics
thanks!
ThatPhysicsGuy ilysm You have opened my mind to never before known concepts. You're way of teaching has made me ascent to the heavens above of the physics world.
you have complimented my videos in a way no one has as of now! thank you!!!
please make more videos!! you are the first youtuber i’ve watched and actually explained this to me so i understand! everyone i’ve seen explains why and what is it without actually explaining how to answer the questions! i would literally pay to make more videos like this
i am trying. working on another video which will come in January
This is legit the best vid out there on projectile motion questions ..... unique and short explaination saved a lot of my time ... thanks..
thank you! your comment will help a lot. now more students can watch this on their homepage!
I will keep posting chapter-wise content so subscribe!
Truly the BEST video i have seen about kinematics. Honestly, I was first a bit skeptical but I was so surprised how well i understood it after struggling for 2 years with this topic. Please upload more such videos especially focusing on grade 12 topics. THANK YOU
i will upload videos slowly. Thanks a lot for thr comment!!
Dude tysm! I was really woried about my physics exam that was coming up and this video helped me understand many things, you should make more videos since you are such a great teacher! Subscribed.
Honestly just please keep posting, this was so helpful in every single aspect. Thank you so much.
i am trying my best!
Finally i understood why sometimes sin is used for the horizontal axis and cos for the vertical!
And also why the value of g is negative in some projectile motions even when the ball is going downwards.
Not even my textbooks made these things clear.
Thank you so much!! I have my A-level physics exams in 10 days and you have clarified everything! ❤️
welcome! and thanks for the comment!
Keep uploading bro you make concepts way easier to understand
I will try my best
i love this so much. i never comment on videos, but this actually helped me. i'm an ib student with almost 0 prerequisites in physics. in every other video i watched, they always pick the easy questions to showcase the "process of solving" but this one actually shows harder questions and how to solve them! love it :3
thank you! i am trying to add more and more videos and in the future will add tough maths too so that you guys can do better
Thankyou so much for explaining so effortlessly😊
Happy to help!
you just got a subscriber man! WHAT A GREAT VIDEO!!! This is literally the best video on projectile motion on youtube. Keep it up!
Thanks for the sub!
10/10 video i hope your channel blows up, keep up the good work
thanks!!
This is an absolutely amazing video about covering projectile motion, youve gained a subscriber! Ill be waiting for the day some more topics come out
thanks! working on it!
dude u are like a ✨knight in the shining armor✨ for students . Great work man!!
Thanks! 😃
my guy seriously you deserve more love and attention like seriously no joke
hopefully this channel will get some!
Keep going ❤
You literally owned many of our respect
thanks! this means a lot!!
Soo grateful that I found this channel 💓
Hats off sirs this is the best projectile motion video on earth unlike the others who make you memorize stuff
this means a lot! thanks!
Please make a-level physics videos you're so good at explaining and teaching.😭
THanks man. Just started als and this vid is truly helpful. KEep makin more plss!!
will do!
this is the best video available on projectile motion, pls upload more videoss on different topic ;) your new subscriber
thank you for subscribing!
i will slowly upload for all topics
This is insane man 🗣️💥💥💥
I hope this video helps!
You are way better than our physics teacher 😂 love your vids ❤
You sir are an amazing person. The way you explained it with so much ease made me understand everything that my teacher did not teach. Thank you very much❤
welcome!
best projectile motion videos ever found on youtube bro. keep posting long videos bro please
i will keep going!!
Explained it better than my teacher! ❤
Glad it helped!
I love ur video! I can see u getting more popular!
yeah i can see that too!!!
thanks btw!
Thank you so much. I had difficulties in understanding the concept, but after seeing your lecture I feel so confident. Thank you once again 😊😊😊
welcome!!
Bro amazing work you have done there!! Keep going!
How I didn't get you before my 11th started you are too good. 😮
crazy vid bro. I have been failing physics rn and this makes so much more sense.
thanks!!
You are doing a great job ,bro full support 💪
thanks
Good work my fellow Mathematician ❤ keep growing I have subscribed
thank you! i have subscribed too!
Pls make more and more such videos and THANKS A TON for clearing my doubts in projectile motion
welcome! i will keep going!
Bro you and your explanation is very awesome❤, I just randomly clicked this video and I fully revised projectile motion 😀
Please make videos on topic Newton's laws of motion
i am making the next video on momentum and the newton's laws.
@@ThatPhysicsGuy ok thanks 😊
@@ThatPhysicsGuy still waiting for that video 😐
best video ever on projectiles
Thank you so much!! It was a great video about projectile motion
Bro you explained this better than my teacher, my midterms are in a few days and I couldnt understand anything, tysmmm
welcome!!
the tip for cos was so helpful
Great content for the students, thank you ❤
Plzz make more such videos .... will be waiting for these videos 😊
thanks! i am working on it!
legit saved my physics exam thanks man
Good job brother, u made it very easy to understand through visuals... pls make more vidios like this in future 🤗🤗
Already liked and subscribed
thanks!! working on it!
Thank you so much Sir 🫡 May God richly bless you 🙏
THANK YOU SO MUCH 😭😭😭😭😭😭
thats, truly a better one. keep up!
thanks!
Happy to be the 700th subscriber ❤
Thanks!!
at 11:00 I understand the approach to calculate the time according to how long it takes to fall since the acceleration is constant. But if it takes 1.75s and the ball's horizontal velocity is 30m/s then wouldnt it have traveled 52.5 meters horizontally before it reaches the ground?
yes!
So clear man ❤ good
The way you teach is incredibly good. Try uploading new videos. You can also create playlist on certain topics .❤
Waittt a minnnnnn. ,…….omggggg can you pleaseeeee makeeee more videooooooosssssssssssssssss this is toooo gooooooddd❤❤❤❤❤
thanks! i will upload slowly
thanks! i will upload surely but slowly
I need more videos youre too good 😭
working on it!
Thanks brother for your wonderful video now I understood the topic more clearly
thank you so much, i finally understand the topic!
thanks for solving my query
Watching from malawi.. great job,,, 😮
hello there! thanks!
Goated video plz bring it on more chapters
thanks! will do!
at 6:28, can someone explain how he brought that 78 degree angle? [please]
in the question time 6:00 i have written down 78°
in this example the angle was given. if the question comes that the angle was not given then you have to use SOH CAH TOA or other trigonometry formulas to find it
Hey man loved your videos. You should start uploading more!!!!
thanks man! really trying but my day job is taking up my time. but i really appreciate the comments!!
So helpful. Thanks Sir.
and thank you for the comment!
Thanks so much sir please keep your videos understanding simple as its in others topics 👍💕 also thanks for yours pdf
welcome! i will keep uploading pdfs
hey i had a question.. at 10:55 when finding the time of flight. why cant we use velocity = displacement/ time even though we have the horizontal displacment and velocity
yeah you can do that too. i just gave an example
Hi, 11:01 why is the formula for time of flight 2usin{theta}/g not applicable here?
that formula is definitely accepted and applicable, but here i am showing how to use only the 4 suvat formulas for any sutuation.
the formula you mentioned has limitations, that is, the projectile must start and end at the same height.
Can you make such videos of different chapters such as straight line, circular motion,etc. It will be really helpful and this video also really helped me a lot 😃👍
working on momentum video. will do all eventually!
As a student I wanna suggest you that upload videos of every chapters
And now kinematics is more important so do 1-D ,2-D,3-D all chapters video and very good contents such a mind blowing video loved it ❤
this is an awesome advice, i will definitely look into this then. THANKS!
@@ThatPhysicsGuy Thank you for listening to me😊 but be fastt tooo....👍
i try to comment fast. i have a small audience and mainly you guys might ask questions that needs explanation. making a video takes time but replying takes literally seconds
AMAZING VIDEO KEEP GOING BROTHA
Thanks! Will do!
When the ball is the rising up and falling down in both the cases the gravity is acting down then why is the sign negative when the ball is rising up 2:49
In 2:49, i have taken any upward velocity as negative and downward velocity as positive.
In that case, the downward pull of gravity will also be positive.
But when we calculate moving up and then down, then we use acceleration as negative.
You HAD to upload this after my AS physics exam lol, but regardless great video (:
sad. trying to upload faster but my schedule is SO booked.
in 14:49 where acceleration is 0 because it doesn't affect the horizontal component, why (in the equation) does 1/2 disappear and time remains, wouldn't it be = 1/2 x 0 x 6.02^2??? how come you seperate the 0 and put it outside and then make the ut + 1/2at^2 into ut x 2t? Need an answer here or I will be confused.
actually 1/2 doesn't disappear
1/2 x 0 x t^2
= 0
anything to multiplier by zero is zero, right? so thus i took a short cut and wrote zero there
@@ThatPhysicsGuy therefore t^2is zero as well, right?
the whole of (1/2 x a x t^2) is zero
the t^2 isn't zero btw, but it gets cancelled out because of the zero being multiplied
@@ThatPhysicsGuy AHaaaa I guess that makes sort of sense, as then you end up with + 0 on the outside, however why multiply ut with t^2. how did we go from addition to multiplication there?
nope, I didn't multiply
just added them up. as it's a zero so there is nothing to add and the answer remains the same
Sir in 5:17 question -at what vertical speed is the ball landing on the water?
Why we only took the velocity which was at max. height i.e. 0 can't we take the initial velocity as 8.5m/s as it was initially and take the displacement as 30m ??
yeah you can do 8.5 m/s too. then you have to keep in mind that the initial velocity os pointing upward and the final velocity is pointing downward.
so the values will have different signs. ok?
@@ThatPhysicsGuysir but the answer isn't coming.
v²=u²+2as
v²=(-8.5)² + 2x(-9.81)x30 = 22.7 ?
But the actual answer is 25.7
Here before it blows up some day 🎉
thanks my man!
Ngl best vid ob projectile motion
thank you!
6:06 What if you weren't given the angle of 78 degrees? How would you find that?
if you weren't given the angle i would say you cannot find the final velocity.
you can ONLY find horizontal or vertical velocity in that case
@ThatPhysicsGuy some other videos I've seen have used the horizontal and vertical velocities as the base and leg of a right triangle and found the final angle as arc tangent opposite/adjacent. This seems to work in most instances. However the situation in the video seems to be an exception as you do not get 78⁰ using this method.
Respect for you 💯 ❤
thank you for the video! Can you make an in depth discussion about magnetic and electric fields? Or a video expanding on everything you said in the unit 4 need to know videos regarding magnetic and electric fields? It is the topic I struggle with the most in Unit 4 IAL Edexcel. Thanks!!! :)
Yeah sure! I am working on AS electricity now, i will start A2 magnetic and electricity field right after that, ok?
also, if you have specific questions you can email me on the channel's email so that i can provide better answers and provide you with more links and worksheets
I have a doubt at 5:47 as to what u² is zero? Please clear
at the very top, the velocity is zero.
@@ThatPhysicsGuy but then u is the starting velocity right? And v is the velocity at the max height right?
@@ThatPhysicsGuyI got 26.28 at 6:56 how
How would I find the initial velocity and angle if given just the horizontal component of the velocity and time
you NEED the angle. or else you cannot change horizontal/vertical components to initial velocity.
Dude you are the best
love the compliments
how do you find the horizontal displacement from the top to the ground?
use vertical velocity for vertical height, as top to the ground is vertical height
You're the best😭
Awesome, thanks ❤
you made it sooo easy! Can you make a video on stress-strain graphs.
I am slowly covering all of the topics. Soon you will find everything here!
In video at 9:27 if you consider acceleration negative then value of (s) or height answer will be also become negative. There is a mistake in calculatjon . Please explain 9:27
in this part, then ball is moving up and then down again.
moving up the acceleration is -ve and moving down the acceleration is +ve. so always remember, when we have a projectile motion moving in both directions on after another we will always use negative.
this is explained in time: 9:15
Thank you sir for this amazing video , can you please do a video about projectiles where it hits a wall and rebounds ?
I saw a question where a projectile hit a wall with a 90 degree angle then we assumed the vertical speed at this moment is 0 why is that ?
that's a good question. i will keep this in mind and try to include this too
when something moved horizontally, the vertical component is zero. that's why
Pls tell me in a horizontally launched projectile as the angle theta increases , does the range increase , decease or remians same ???
- as angle increases from 0° to 45° the range increases
- after 45° the range decreases
- at 90° there is no range. the ball basically moved vertically upward and moves downward
suppose in a projectile (which ends at diff height) we are asked to find the time taken to reach max height and also the time taken to reach the ground. If we
use 'S' as positive while calculating time for max height then do we need to use 'S' as negative while calculating time taken to reach ground.
exactly. different directions will need different signs!
Thank you sooooo much for this❤please make a such video on rotational Motion🙏
i will do then!
man you are a gem
please start a unit 1 course on physics Alevels
I am working on it!
at 4:15 shouldnt the last equation be s=(v+u)/2*t because it's s=mean velocity*t
THANK YOU for pointing this out!
This was my mistake, i gave 't' twice.
The two vectors a and in the figure have equal magnitudes of 12.9 m and the angles are 01 = 28° and 02 = 109º Find (a) the x component and (b) the y component of their vector sum 7, (c) the magnitude of 7, and (d) the angle 7 makes with the positive
direction of the x axis.
what is your question??
Pls make a video on rotational motion and centre of mass as well ❤
keeping this on the list then!
Could you do one for Newton laws of motion too?? And circular motion?
working on it!
At time 7.48 why upward vertical velocity is positive? Where as we assumed downward is positive. Please explain
then you also have to change the acceleration sign too. then your answer will match
pls pls pls post international AS lvl cambridge syllabus topics!! i respect u sm for this video sir, would love to see more but with newer revelant topics!
hello! i will post topics that will be relevant to any grade 11 and 12 courses like Edexcel, Cambridge, AQA etc.
@@ThatPhysicsGuy thank u sm truly! waiting for those videos to come out
Sir, would you mind sharing some knowledge on momentum and it's applications as well? Would mean so much
working on it!
I HAVE A QUESTION,
In 5:14 to find max height, why didn't you add the 30 meters too( of that cliff) because the projectile is 33.6 meters above the sea, so isn't that the max height? Doesn't that include in the height of the projectile's path?
I have physics exam tomorrow so help would be appreciated 👍
that's according to the question. if they ask the max height, you can give 33.6 m
if they ask the max height above the clif, you can give 3.6 m
@@ThatPhysicsGuy Ok, thank you so much !
can u make videos on forces? (buoyancy friction drag etc) this video was incredible
working on it, will take some time but i will upload them all