I watched this video this morning because i forgot how to do back titrations and no text book explained it as well as you did. To my pleasure a back titration came up in the exam i sat in the afternoon and got it correct thanks to your method!!! Many many thanks for uploading this video sir
I would personally want to know why the equation was actually having ions in it and the like. In short why do we have hydroxide ion and Ammonium ion as reactants instead of Ammonium Sulphate and Sodium Hydroxide???? Please elaborate on that
7:50 so when exactly does potassium sulphate come in the working out, or is it not needed. If that is the case, how would you know what information isn't needed?
Best Video on back titration. Coming from a examination website. I'm cheating lol.. I had my butt saved from the titration section in my online examination. Learnt What my teacher was teaching for one semester in 11 min. coolz.
I want to know why the equation was actually having ions in it and the like. In short why do we have hydroxide ion and Ammonium ion as reactants instead of Ammonium Sulphate and Sodium Hydroxide????
many thanks for ur explanation i have a question about the first example why u devided the moles of used HCl by 2 , even these moles 0.0121 all consumed by CaCO3 to get the mass of CaCO3 = 0.0121 * 50 (Eq wt of CaCO3) = 0.606 gm my point is the one mole of CaCO3 already consumed all amount of 0.0121 moles of HCl I knew 1 mole CaCO3 equal to 2 moles of HCl, but 2 moles HCl equal 0.0121 mole which will be equivallent to 1 mole of CaCO3 regards
You can find the excess HCl from the moles of NaOH used. The excess did not react with the CaCO3. The initial; moles of HCl minus excess HCl reacted with CaCO3
Have an amount of substance test today wish me luck... will update how many marks I got Edit 19/11/2023 : I got a grade 9 in chemistry a few years ago lol
@@ChemistryTuition I have checked w a calculator and the final equation which I believe to be (0.141/1.455) * 100 comes out as 9.69072... I am right to think this is the correct calculation isn't it?
@@thomasmeeson6902 Hi, yes I think it is a rounding error. If you go through the calc keeping your value in the calculator you should get the same answer.
Hey man just letting you know you had a miscalculation in your last question. 0.288x10.9/1000= 3.1392x10^-3, NOT 2.49x10^-3. Otherwise everything else was correct and great vid.
The best video I've found on Back Titrations for A-level! Clear and concise! Thank you!!
Thank you!
back titration was hardest part of chem for me until I watchd this video. Thanks a lot for the best explanation
You are welcome!
what u got in your a levels
I watched this video this morning because i forgot how to do back titrations and no text book explained it as well as you did. To my pleasure a back titration came up in the exam i sat in the afternoon and got it correct thanks to your method!!!
Many many thanks for uploading this video sir
What exam board do u do for chem?
@@CptMaahir, do you like turtles?
@@menakarajavel7796 yh why?
@@CptMaahir Cause i've got about ten and i wanted to give it you
@@menakarajavel7796 yeah give me some plz
my guy coming in clutch
Legit was doing this for some questions my teacher set and by the second question I’d realized she’d just chosen these questions and mixed them up
literally saved my life for my prelab omg thank you a million
Thanks, this video was very helpful for A Level chemistry. Concise and thoroughly detailed.
This video has genuinely helped me so much! Thank you so much!
i watched and read so much on this topic for weeks now and yet couldnt get it, but now thansk to you i finally understood!!
STILL CONFUSED I CAN DO THE CALCULATIONS BUT I NEED UNDERSTANDING ON ALL YOUR EXAMPLES(EXPLANATION)
I would personally want to know why the equation was actually having ions in it and the like. In short why do we have hydroxide ion and Ammonium ion as reactants instead of Ammonium Sulphate and Sodium Hydroxide???? Please elaborate on that
Its just an ionic equation of the full equation
Thanks so much man! Was confused in class but I understand it now!!
Thank you so much. This helped alot. I understand this now. And luckily for me you did the same questions I was set for work. Thank youuu!
Glad it helped!
7:50 so when exactly does potassium sulphate come in the working out, or is it not needed. If that is the case, how would you know what information isn't needed?
i also would like to know even though this is a year later
@@Charlotte-hf5jz im at uni watching this back still have no clue 😂
@@Charlotte-hf5jzdid you ever find an answer 😪
This is THE SINGLE GREATEST VIDEO on this topic. The others were all rubbish and not useful. Great work!
when u breeze through the practice but the exam was on steroids'
Best Video on back titration. Coming from a examination website. I'm cheating lol.. I had my butt saved from the titration section in my online examination. Learnt What my teacher was teaching for one semester in 11 min. coolz.
Glad it helped
really good vid sir but @6 mins how did you form that ammonium equation as there are 2 reactants in fertiliser reacting with NaOH ?
thanks
How do you know when you should do an ionic equation sor an actual full equation in order to balance the moles in the ratio?
I literally love u, u saved my life
this is so cool
How do you know NaOH is being titrated with HCl? Isn't it being titrated with CaCl2
Such a good video, thank you !
ohhhh thank you man this video helped me to understand titration
7:15 could also just write out the full balanced eq. between ammonium sulphate and sodium hydroxide to get this
yeah i thought this, seems a lot easier
I FINALLY UNDERSTAND. THANK YOU SIR!
I want to know why the equation was actually having ions in it and the like. In short why do we have hydroxide ion and Ammonium ion as reactants instead of Ammonium Sulphate and Sodium Hydroxide????
many thanks for ur explanation
i have a question about the first example
why u devided the moles of used HCl by 2 , even these moles 0.0121 all consumed by CaCO3
to get the mass of CaCO3 = 0.0121 * 50 (Eq wt of CaCO3) = 0.606 gm
my point is the one mole of CaCO3 already consumed all amount of 0.0121 moles of HCl
I knew 1 mole CaCO3 equal to 2 moles of HCl, but 2 moles HCl equal 0.0121 mole which will be equivallent to 1 mole of CaCO3
regards
Thank you really good video, i got there in the end !
Hi are these calculations used in as level? Thanks
That’s amazing, thank you so much
brilliant video.
2:36 shouldn't that final value calculated be the excess not the moles used? (since the moles used are the same as the moles of NaOH)
You can find the excess HCl from the moles of NaOH used. The excess did not react with the CaCO3. The initial; moles of HCl minus excess HCl reacted with CaCO3
You just got yourself a new subscriber mate 😏😌
why divide by thousand
Very clear thank you!!
Great video
Have an amount of substance test today wish me luck... will update how many marks I got
Edit 19/11/2023 : I got a grade 9 in chemistry a few years ago lol
hope it went well!
How did it go?
i have one on wednesday
I have one on Friday. Very scared
yo are you gonna give the update?
Amazing
How do you know the equations for each titration? Do you work them out or get given them?
You will generally be given them.
this is a late reply but sometimes you have to write the equations yourself so you have to remember the chemical formulas
Thank you so much!!
Where did the 100.1 come from?
It is the molar mass of calcium carbonate
@@ChemistryTuition thank you so much you're doing a great work
Thank you!!
Thanks alot for the video
Amazing lad
update: failed my mock
whats the difference between back titration and simple titration
This should explain ua-cam.com/video/zJmAprcH_d8/v-deo.html
Can you explain how you got 9.67% for the second question, I got 9.69% and double checked it. Is it an error you made?
Hi Thomas, I have run through the calc again and come up with the same answer of 9.669%
@@ChemistryTuition I have checked w a calculator and the final equation which I believe to be (0.141/1.455) * 100 comes out as 9.69072... I am right to think this is the correct calculation isn't it?
@@thomasmeeson6902 Hi, yes I think it is a rounding error. If you go through the calc keeping your value in the calculator you should get the same answer.
But otherwise so far so good. all is going well really
Thank you so much very helpful
Glad it helped
Could these questions be tested in the OCR A exams?
hiya won't the value for hcl used be 0.02371 because it is 0.025-0.00129
The volume is 0.025 - 0.0129
Nice
goat buv
Man thank u just saved my ass
thank you xxx
Glad it helped.
186937f4
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Hey man just letting you know you had a miscalculation in your last question. 0.288x10.9/1000= 3.1392x10^-3, NOT 2.49x10^-3. Otherwise everything else was correct and great vid.
great video. I also noticed this error it affected the whole calculation. did you get a % purity of 87.2427% Zayad?
The concentration of NaOH in the question is actually 0.228 moldm^-3, not 0.288 that you used in your calculation.