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Marvelous
Don't we have a vertical asymptot at x=pi/2 making the integral diverges ?
Yes, but it so turns out that this integral is in fact convergent despite there being an issue in the upper limit. You can check in Wolfram Alpha as well to verify.
Int_0^inf u^2/(1+u^4) dx = (pi/5) csc(3pi /5)What did i do wrong?
It's hard to say without anymore context, though your answer is similar to something utilizing the Euler Reflection Formula.
Very sorry. I made mistakes. Thanks for your kind reply. Your right answer.
answer = pi / (2 sqrt(2)) ?
Sorry i was wrong
Marvelous
Don't we have a vertical asymptot at x=pi/2 making the integral diverges ?
Yes, but it so turns out that this integral is in fact convergent despite there being an issue in the upper limit. You can check in Wolfram Alpha as well to verify.
Int_0^inf u^2/(1+u^4) dx = (pi/5) csc(3pi /5)
What did i do wrong?
It's hard to say without anymore context, though your answer is similar to something utilizing the Euler Reflection Formula.
Very sorry. I made mistakes. Thanks for your kind reply. Your right answer.
answer = pi / (2 sqrt(2)) ?
Sorry i was wrong