Pulley Physics Problem - Finding Acceleration and Tension Force

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  • Опубліковано 4 січ 2025

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  3 роки тому +61

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      @@Wolfspine824 9.8 is the force of gravity on Earth, it's always 9.8

    • @Galaxyskyys
      @Galaxyskyys 2 місяці тому

      @@n.d.1975In some cases it’s rounded to 10

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    • @hareecionelson5875
      @hareecionelson5875 2 роки тому +2

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      @kristiyansyarov3076 Рік тому +1

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    @JohnDoe-hk7ix 3 роки тому +22

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  • @American_2
    @American_2 2 роки тому +1

    Wow, this solved all the confusion I had when trying to find Tension.

  • @OluwafemiFaith-mk6hp
    @OluwafemiFaith-mk6hp 12 днів тому +1

    Please sir can you explain how to get the formula of a pulley system on an inclined plane

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    @mahichowdhury1974 2 роки тому

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    @hopehart5687 2 роки тому

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  • @algirdasltu1389
    @algirdasltu1389 Рік тому +1

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    @Arbiter24 26 днів тому +1

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  • @vedantjhawar7553
    @vedantjhawar7553 3 роки тому +12

    Hi, there's something I'm confused about. When considering the rotational inertia of the pulley and doing a problem with it, it becomes apparent that each side of the rope has its own unique tension that is not equal to each other. In this case, doesn't the method to solve problems without the consideration of pulleys violate this principle? What assumptions are made in order to solve it like this? If it's the existence of the pulley itself that causes the uneven tension, what exactly is the pulley doing to the string to essentially split apart its effects?

    • @usernoneofyourbusiness
      @usernoneofyourbusiness 2 роки тому +3

      (the assumption made, by the rope being massless, is that tension is evenly distributed in the rope)

    • @johnpereira3675
      @johnpereira3675 2 роки тому +2

      Frictionless pulley; massless and perfectly inelastic rope

    • @isequalto_klasses
      @isequalto_klasses Рік тому +2

      Massless pulleys to be added to the assumptions

  • @RinaNewhouse
    @RinaNewhouse 2 роки тому

    In 5:42, how come a_x is +, a_y is +, but m2ay -? Is it just becausethe m2g vector is pointing downward, or is there another reason?

  • @ayamo8720
    @ayamo8720 Місяць тому

    Thanks a lot 🌸🌸😭

  • @pranavtigura1568
    @pranavtigura1568 3 роки тому +11

    Great video, although, my main problem in understanding was when solving for tension. When we made the tension equation, why couldn't we plug in the value at that moment itself?

    • @carlakemtch8765
      @carlakemtch8765 2 роки тому +2

      when he was solving for the acceleration he used T= to make two equations to set the whole solving part up. at that point we did not know the tension, which is what he solved for later

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    @恩子-t1u Рік тому

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    @malikhaider7102 Рік тому

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    @donnikwels1337 2 дні тому

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    @riojeno5328 3 роки тому +14

    Yo this is what I've been finding yesterday...how to find the acceleration

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    @hermeschi Рік тому

    Very helpful video

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    @hayatzeynu7795 3 роки тому

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  • @shreyas235
    @shreyas235 2 роки тому +1

    isn't net force always addition so for the pulley problem around 3:29, net force for Y should equal T + m2g?

    • @ggmegagg
      @ggmegagg Рік тому

      No because they go in different directions T goes up and m2g goes down for exemple let's say you took 3 steps to the right and then 2 steps to the left the final spot from the start is 1 steps to the right because 3-2=1 so it should be T-m2g. Dont know if I explained it well hope you understood

    • @shreyas235
      @shreyas235 Рік тому

      got it thanks@@ggmegagg

  • @American_2
    @American_2 2 роки тому +1

    so then a = (m2g - T)/m2 and a = (T - Mkm1g)/m1 also work if you have tension. That's pretty cool. But because we haven't found T, we're substituting the T instead.

  • @baekhyunnanny4877
    @baekhyunnanny4877 2 роки тому

    Thank you so much, life saver

  • @mudhalvanm.s2897
    @mudhalvanm.s2897 11 місяців тому

    Pardon me. 14:44 How the Fk=(constant) m1(g). How is that the force is accompanied with g? Isn't that it is some kind of (a)?

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    @KemohConteh-e6o 2 місяці тому

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    @NsGaming21 Рік тому

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    @socheatlong2048 16 днів тому

    Thanks you so much

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    @NotTooStraight 2 роки тому +1

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  • @riazijabar5296
    @riazijabar5296 Рік тому

    hello i appreciate your work here but my question in the first 01:00 is ,can we consider T as being greater than th force acting on the 5kg object? i have an assumption that because m1 weighs 15kg its tension on 5kg would be greater than the force pulling the 5kg object am i right?

    • @earvinchen
      @earvinchen Рік тому +1

      It’s greater because the force of tension is a positive value while the force of the object is negative(5*-9.8 due to gravity acting in the negative/downwards direction).

  • @ghaidah1858
    @ghaidah1858 2 роки тому +1

    The tension force is the same for all rope right? that’s why we can calculate it with any one of the two equations?

    • @NnnHyyu
      @NnnHyyu 2 роки тому

      Yes, same as the acceleration

    • @luluthecreator44
      @luluthecreator44 2 роки тому

      yes. you can choose any of the two