Pulley Physics Problem - Finding Acceleration and Tension Force

This physics video tutorial explains how to calculate the acceleration of a pulley system with two masses with and without kinetic friction. It also discusses how determine the tension in the rope as well. The formulas and equations are all provided in the two practice problems & examples presented in this tutorial. The full version of this video also explains how to solve the pulley problem with two hanging masses as well as how to determine the direction in which the system will move. It also explains how to solve pulley problems with inclined planes.
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PDF Worksheet - 8 Problems:
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Full 1 Hour 28 Minute Video:
• Pulley Physics Problem...

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Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
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Full 1 Hour 28 Minute Video: www.patreon.com/MathScienceTutor
Direct Link to The Full Video: bit.ly/3QdBavj

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[@vedantjhawar7553]

Hi, there's something I'm confused about. When considering the rotational inertia of the pulley and doing a problem with it, it becomes apparent that each side of the rope has its own unique tension that is not equal to each other. In this case, doesn't the method to solve problems without the consideration of pulleys violate this principle? What assumptions are made in order to solve it like this? If it's the existence of the pulley itself that causes the uneven tension, what exactly is the pulley doing to the string to essentially split apart its effects?

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(the assumption made, by the rope being massless, is that tension is evenly distributed in the rope)

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Frictionless pulley; massless and perfectly inelastic rope

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Massless pulleys to be added to the assumptions

[@PenandPaperScience]

For those that want some more practice on pulley problems, I've uploaded a video where I solve such problems step-by-step! It might help some of you out there :) ua-cam.com/video/y7g9gHchOIk/v-deo.html

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Great video, although, my main problem in understanding was when solving for tension. When we made the tension equation, why couldn't we plug in the value at that moment itself?

[@carlakemtch8765]

when he was solving for the acceleration he used T= to make two equations to set the whole solving part up. at that point we did not know the tension, which is what he solved for later

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so then a = (m2g - T)/m2 and a = (T - Mkm1g)/m1 also work if you have tension. That's pretty cool. But because we haven't found T, we're substituting the T instead.

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why was gravity (9.8) positive? If the box is going downward, wouldn't it be negative?

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The tension force is the same for all rope right? that’s why we can calculate it with any one of the two equations?

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