Amino acid charge at different pH and amino acid titration calculation problems

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  • Опубліковано 15 гру 2024

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  • @nahomelion
    @nahomelion 4 роки тому +78

    His calm demeanor, how he talks, and his accent are some of the qualities of this man. Thank you, sir!

  • @Yakshiii
    @Yakshiii 3 роки тому +20

    this man is a king, explained so concisely what my professor could not explain in two hours... thank you sir!

  • @pntdnails8835
    @pntdnails8835 2 роки тому +2

    just got out of COVID quarantine and my prof didn't explain this at all and the figures were making it really confusing. I skipped ahead to the part I was confused and it took literally a minute and I completely understood this topic. thank you so much for this video that you created like 5 years ago

  • @nephronum
    @nephronum 5 років тому +34

    Can you explain why did you put carboxyl group in ionized state, whereas amino group was not ionized.(in cell conditions both are ionized)

  • @Ceeceelu_
    @Ceeceelu_ 3 роки тому +4

    Thankyou for simplifying this to me I definitely feel more confident for my exam.

  • @siddharthsingh5169
    @siddharthsingh5169 3 роки тому +2

    Shomu Sir , i like your personality and also the way of talking. wow

  • @akankshabhatt3357
    @akankshabhatt3357 4 роки тому +5

    I had a hard time trying to understand this simple concept and finally it all made sense. Bless your soul for making such content, you are helping so many people including me to understand basic fundamentals in biochem/biology/chem.

  • @andreusdagoat9958
    @andreusdagoat9958 4 роки тому +1

    Wow UA-cam has the best teachers!

  • @YourManasi
    @YourManasi 4 роки тому +10

    Thanks a lot Sir,,,,you made it crystal clear....The concept about that become as clean as fresh water.... 🙏🙏🙏Keep going sir....

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому +2

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @raviphougat2474
    @raviphougat2474 3 роки тому +3

    Excellent sir
    God bless you

  • @makayla1774
    @makayla1774 2 роки тому +2

    You made this so simple, thank you.

  • @gargisain5091
    @gargisain5091 3 роки тому +2

    Your explanation is too much good sir ♥

  • @dailydevosinc.4345
    @dailydevosinc.4345 4 роки тому +3

    you've enlightened my understanding better. Thank you very much SIr

  • @1rrrrrrrrrrr544f
    @1rrrrrrrrrrr544f Рік тому

    Eventhough there was a mistake,but thanks because you made me sure about my idea! I concluded the same thing when I studied amino acids alone!

  • @sanjaisrao484
    @sanjaisrao484 2 роки тому +2

    Excellent explanation

  • @Empress426
    @Empress426 2 роки тому +1

    Thank you for giving me some clarity on this topic, I am currently taking a self-taught biochemistry class with a very confusing professor. Thank you.

  • @thisariupamalika9924
    @thisariupamalika9924 5 років тому +5

    Thank you, Sir. Your videos are really helpful for me to understand the concepts of biochemistry. And I'd strongly recommend to anyone to watch your videos to clear their doubts.

  • @Happy6-y7d
    @Happy6-y7d 7 років тому +3

    You are doing great job sir.. God bless you

  • @kristinerosegonzales7276
    @kristinerosegonzales7276 Рік тому +2

    why is the charge of carboxylic acid at pH 7 is -1? why not -1 minus 1? because initially it has a negative 1 charge then after deprotonation you'll subtract 1?

  • @ranarajeshwariba1120
    @ranarajeshwariba1120 7 років тому

    Sir me apke video se hi hamara pura syllabus ache se samaj me aa jata he so tnx and vert good work and very helpful for our study

  • @ujalaabbas1861
    @ujalaabbas1861 5 років тому +2

    Thanks for the video.. cleared the concept ❤️❤️👍👍

  • @pallabisarma8463
    @pallabisarma8463 7 років тому +1

    Thank you is a very small word for your videos sir.. You are great

  • @dikshajha8279
    @dikshajha8279 4 роки тому +1

    Thankyou sir for making the concept easy to understand 🙏

  • @mdbadsha418
    @mdbadsha418 2 роки тому +5

    You are the best! I never understood this topic so clearly before. Same for many other topics you taught in your other videos. Thank you so much!

  • @ankitaarvindbhai1059
    @ankitaarvindbhai1059 4 роки тому +2

    thank you very much sir you're all vidio help me lot

  • @wycliffenyandika9017
    @wycliffenyandika9017 2 роки тому +1

    Damn! You have no idea how long have been going through videos on UA-cam and still couldn't answer a question on this topic ,I'm preparing for MCAT, this will go a long way. Only way to pay you is to share the video

  • @shyambhavi10
    @shyambhavi10 4 роки тому +2

    Thank you sir 👍👍....

  • @skp-official
    @skp-official 7 років тому +1

    Your videos helped me lot in class 12

  • @theimprovist4158
    @theimprovist4158 3 роки тому +1

    You're the best💯

  • @prasadmadane9711
    @prasadmadane9711 4 роки тому +2

    Great sir🤗

  • @somnathchanda1250
    @somnathchanda1250 2 роки тому +1

    will de-protonation of amine happen at pH 10 for developing a negative charge over -NH gr.

  • @sjc5411
    @sjc5411 3 роки тому +1

    He taught the subject better than my professor

  • @israthossain6012
    @israthossain6012 5 років тому +2

    For Glycine when pH is 12 how does the net charge is -1? In N-H because of the deprotonation the charge is -1 and in COO- bond there is -1 charge so the total net charge is supposed to be -2.
    When pH=7 you are counting the charge of COO- is -1 to get the total net charge. Then why when pH=12 you are not counting the charge of COO- group -1 charge to get the total net charge? Can you please explain it?

  • @janvimyadventures1310
    @janvimyadventures1310 4 роки тому +5

    Sir I have some confusion with glycine formula.
    In the video it is NH - CH2- COO-.
    Is it correct.

  • @mashab6374
    @mashab6374 3 роки тому +1

    Thank you so much!! It's so clear to me now!!

  • @misbashabir2063
    @misbashabir2063 Рік тому +1

    Thank you sooo much sir .....

  • @rajwinderdubb3222
    @rajwinderdubb3222 4 роки тому +1

    Omg Thank you so much sir! you explained it very well

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому +1

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @rachna4140
    @rachna4140 6 років тому +3

    sir can u make video on longpolypeptide chain like this. plzz soon becoz it gives idea how can calculate

  • @fizaali6039
    @fizaali6039 2 роки тому +1

    bro ur the best

  • @hasankuliyev4211
    @hasankuliyev4211 6 років тому +3

    is net charge would be -2 at pH 12 since there is already -1 (pH 12 does not change -1 and -1 stays -1) in carbonyl group and very basic condition(pH 12) rips out H from NH which makes -1 as you mentioned, So -1 + -1 =-2 isn`t it?

    • @mytwinze942
      @mytwinze942 5 років тому

      I agree with you ,we need clear this point

  • @taitopotato
    @taitopotato 2 роки тому +1

    Legend! Thank you so much.

  • @arnavdeshpande3764
    @arnavdeshpande3764 4 роки тому

    There should be a Positive Charge over NH . If we consider that, all the answers change. But concept explanation is spot on

  • @philasandexulu3304
    @philasandexulu3304 4 роки тому +3

    Thank you 🤩

  • @meenublossom6860
    @meenublossom6860 6 років тому +12

    Awesome lacture... 👌👌Thank you so much for clearing my concepts with amino acid charge calculation 🙏🙏😊

  • @farooha.s8411
    @farooha.s8411 2 роки тому

    Thanks you so much!! Where can I see the second part of the class? I need to know how to calculate the net charge for a polypeptide

  • @juhishrivastava8725
    @juhishrivastava8725 6 років тому +1

    Very informative sir.

  • @054gomathip7
    @054gomathip7 3 роки тому

    When I get confused in some topic in biology ,I usually watch your videos, it gives clarity.tq sir

  • @kavyap4453
    @kavyap4453 4 роки тому

    Thank you so much for this very simple and informative lecture

  • @she_is_a_hungry_raccoon
    @she_is_a_hungry_raccoon 6 років тому +46

    let me buy a beer for that man

  • @lubnasa3453
    @lubnasa3453 2 роки тому +1

    thank you sooooo much man

  • @pixiepout
    @pixiepout 4 роки тому +3

    Thank you very much for this video it really helped with my studying!!

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому +1

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @somnathchanda1250
    @somnathchanda1250 2 роки тому +1

    Oh! what an explanation

  • @giftnamwanja7715
    @giftnamwanja7715 6 років тому +1

    awesome thanks. God bless

  • @mahaboobbashashaik5219
    @mahaboobbashashaik5219 4 роки тому +1

    nice clarity

  • @surajbhowmik4404
    @surajbhowmik4404 4 роки тому +1

    sir how to find the next class?

  • @arnavdeshpande3764
    @arnavdeshpande3764 4 роки тому

    Thanks for the Video. Please check your calculations before uploading...

  • @omethheenkenda2793
    @omethheenkenda2793 2 роки тому +1

    thank you

  • @alejandrarodriguezcruz227
    @alejandrarodriguezcruz227 3 роки тому +1

    When UA-cam teaches you more than a top University :/

  • @dayangasyiqin2398
    @dayangasyiqin2398 6 років тому +1

    great job!

  • @rabianoor1589
    @rabianoor1589 4 роки тому +1

    Thank you so much sir i completely understand this topic🥰😅

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому +1

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @prakashpawar1503
    @prakashpawar1503 4 роки тому +2

    Nice🔥🔥🔥

  • @kaitlynridgeway1405
    @kaitlynridgeway1405 2 роки тому +1

    god bless your soul

  • @abdulharrison4380
    @abdulharrison4380 3 роки тому

    Thank you soooooooo much Sir!

  • @rudraseth5419
    @rudraseth5419 6 років тому +2

    Sir could you plz elaborate how the molecule are protonated and deprotonated .

  • @20tejas
    @20tejas 7 років тому +2

    please make a detailed video on thermodynamics of protein stability and vant hoffs equation

  • @highrepublic3264
    @highrepublic3264 3 роки тому

    thank you for this video friend

  • @sudiptadhara1983
    @sudiptadhara1983 6 років тому +3

    very informative

    • @shomusbiologyofficial
      @shomusbiologyofficial  6 років тому +1

      Thank you

    • @sudiptadhara1983
      @sudiptadhara1983 6 років тому +1

      sir I am a student of Physiology(b.sc)...IIT jam ka kaise preparation lena chahiye..please inform me.....

  • @nitinchauhan9075
    @nitinchauhan9075 7 років тому +5

    Your videos are really helpful...I m totally dependent on ur videos. Thanks a lot...you are doing a great work

    • @shomusbiologyofficial
      @shomusbiologyofficial  7 років тому

      +Nitin Chauhan thank you. Glad you liked my lectures. Please subscribe and share

    • @nitinchauhan9075
      @nitinchauhan9075 7 років тому

      Shomu's Biology : No concept is difficult with your way of teaching.

  • @somyaagarwal627
    @somyaagarwal627 4 місяці тому +1

    thanks

  • @shonalikrishnani8775
    @shonalikrishnani8775 7 років тому +1

    sir please solve the analytical part of csir net 2017.. your videos help a lot.. thank you so much sir.

  • @riusgallery3397
    @riusgallery3397 4 роки тому +1

    Thank you sir🙏

  • @suro-mallar8031
    @suro-mallar8031 4 роки тому

    In case of titration of a peptide chain, should we start from the fully protonated form of the peptide or the fully deprotonated form?

  • @hamidazizi7658
    @hamidazizi7658 4 роки тому +1

    thanks man, Greetings from Germany :D

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому

      You're welcome. Glad to hear that you're getting benefit from my lectures. Please subscribe and share

  • @kellianbones2079
    @kellianbones2079 5 років тому +1

    Thank you!

  • @sohilausamarabie9631
    @sohilausamarabie9631 4 роки тому +1

    THANK YOU!!!!

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @enashaswa613
    @enashaswa613 3 роки тому

    where can i find part 2? it's not shown to me ,if someone could put its link i'd be thakfull

  • @philomax5657
    @philomax5657 7 років тому +4

    thnks pro

  • @priyapriya.c.g2755
    @priyapriya.c.g2755 4 роки тому +1

    Thank you souch sir

    • @shomusbiologyofficial
      @shomusbiologyofficial  4 роки тому

      You're welcome. Glad to hear that you're getting benefit from my lectures

  • @prachetaghosh2308
    @prachetaghosh2308 5 років тому +1

    Nice video

  • @umaverma9437
    @umaverma9437 2 роки тому

    The pI of glycine is written as 5.97 in books. Is that correct if we take ph 5.97 instead of 7 in this calculation? In books the formula for pI is , 1/2 (pK1+ pK2) i.e., 1/2 (2.34+ 9.6) = 5.97

  • @lynnyuness7160
    @lynnyuness7160 Рік тому +1

    You saved meeeeeeee thank youuuuu watching this video will help a lot of embaressed biochem students because of their stupid professor

  • @elvishernanserrano7736
    @elvishernanserrano7736 2 роки тому

    Where I can find the second video for polypeptide?

  • @rashichaudhary7134
    @rashichaudhary7134 4 роки тому +1

    Sir pls send me link of next video in wich we can calculate pI

  • @sharmisthasharma3587
    @sharmisthasharma3587 2 роки тому

    Sir pls make a video on how to calculate the absorbance of an amino acid ..

  • @bishwabhusankundu2385
    @bishwabhusankundu2385 6 років тому +5

    Are you sure that the pI for glycine is 7 and not 5.97...🤔🤔
    Isn't pI supposed to be calculated as (pKa1+pKa2)/2
    For glycine it would be
    (2.34+9.60)/2=5.97

    • @Rohit.Kashab
      @Rohit.Kashab 3 роки тому

      exactly as we will get zwitterion in between these two ph's so he is wrong on this part

  • @swechhagyanvarsha5702
    @swechhagyanvarsha5702 3 роки тому

    Can someone put in the link for next lecture?

  • @Sunshine-Muskan
    @Sunshine-Muskan 3 роки тому

    Where can I find the second video

  • @Zehra-9809
    @Zehra-9809 4 роки тому

    Where is ur next class regarding this topic.

  • @nandu3110
    @nandu3110 6 років тому +1

    excellent

  • @ivanjurkovic9088
    @ivanjurkovic9088 4 роки тому

    Good afternoon. How many moles of NaOH per mole of histidine should be added to increase 6.5 to 9 pk are given. What will be the charge of histidine at the given pH values, how will it move during electrophoresis? Thanks in advance for your answer.pk1 = ¸3.1, PK2 = 6, PK3 = 8

  • @kavurinissy779
    @kavurinissy779 6 років тому

    Sir pls make vdo on optical properties of aminoacids

  • @tirathjangra257
    @tirathjangra257 6 років тому +2

    How to calculate the charges on acidic Amino acid and basic Amino acid at different ph

  • @Niksonics
    @Niksonics 3 роки тому

    Sir ionizable R grp wale..ka video hai?

  • @randhirkumarbt
    @randhirkumarbt 3 роки тому

    pls make a video to calculate the net charge and PI (isoelectric point) of a polypeptide at different pH. Problem N0.- 11 of Lehninger biochemistry, chapter -3, 4th edition

  • @sambhavmishra1873
    @sambhavmishra1873 6 років тому

    Hello sir, i have a question whether the Pka value would be given in CSIR-net question or we have to memorize??

  • @kalpanadas8693
    @kalpanadas8693 7 років тому +2

    Sir can't understnd when pH=pKa..otherwise wonderful video

  • @Biomaths247
    @Biomaths247 6 років тому

    sir what will be the charge of glycine at pH 4,5,6,7,8, and 9. according to you will be zero.then what is PI value for glycine. it seems all of these ph values will be PI for glycine as well.

  • @jagapradhan552
    @jagapradhan552 6 років тому

    Please send me the link for next video sir of charge of polypeptide

  • @YashSharma-ce1hk
    @YashSharma-ce1hk 3 роки тому +1

    Sir, I'm a JEE aspirant and I recently faced a problem on Biomolecules
    The question had three phases of glycine where
    [A]- Both acid part and -NH part was protonated
    [B]- Only the -NH part was protonated
    [C]- Both the parts was deprotonated
    pKa1=2.3 pKa2=9.7
    The question asked if at pH=2.3, half of [A] is converted to [B] or not?
    So sir, can I consider it to be correct that yes it is converted, on the pretext that half part is protonated and half is deprotonated?
    (I am having confusion in the part where it asked 'converted', and I am not sure that half protonation would result in half conversion of phase [A] to phase [B])

  • @Sahil-fo9nu
    @Sahil-fo9nu 4 роки тому

    Sir, it means for glycine pI ranges from ~3 to 9 ?