Russia | Math Olympiad Problem

[@คนคํานวณ]

A+3 = {a/(b+c) +1} + {b/(c+a) +1} + {c/(a+b) +1}
= (a+b+c){1/(b+c) + 1/(c+a) + 1/(a+b)}
= 7*7/10
-> A = 19/10

[@2sljmath]

Yes. Thank you. 🙏⚘🙏

[@PrithwirajSen-nj6qq]

Enjoyed

[@philcowdall9399]

blimey! just multiply the two equations together and you get A+3=49/10 ! job done A=19/10

[@77redmax77redmax]

For 19 coz my fav no.

[@PrithwirajSen-nj6qq]

1/(a+b) +1/(b+c) + 1/(c+a)=7/10
> (a+b+c)/(a+b)+(a+b+c)/(b+c) + (a+b+c)/(c+a)
= (a+b+c)*7/10
=7*7/10=49/10
>a/(b+c) +b/(c+a)+ c/(a+b) +3 =49/10
>a/(b+c) + b/(c+a)+ c/(a+b) =49/10 -3=19/10

[@2sljmath]

Very nice thank you.

[@SaurabhGupta-fh7nn]

Very easy ....solved in mid only

[@rashpalsingh7421]

Bc