Yet another Chinese Diesel Heater installation... With Electrocution!

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  • Опубліковано 8 січ 2025

КОМЕНТАРІ • 13

  • @Looneyintheboonies
    @Looneyintheboonies 22 дні тому

    I'm a middle-aged female mountain dweller from the Appalachian Mountains of SW VA, and I confess to rewinding the part where you got zapped for a 2nd viewing! 🤔😬 For every ignorant husband and boyfriend I had that considered looking at instructions to be a last resort when all else failed, and inevitably it did, for every time I had to hear that the recommended safety precautions were for candy-arses, and for every time damage was caused or I ended up hurt because of someone who always looked for shortcuts, not bothering to consider that there are more often times than not, reasons, and dang good ones, for the orderly steps listed for tasks, I admit you put a gleeful smile on my face and made me shamefully chuckle out loud merrily! I was halfway asleep, and jerked to attention at the sound of a zap and a yelp, and sure enough, it was what I thought it was! 🙄 😁💃😃 I had to rewind it... I'm not proud of myself, and I'm glad you appear to be not permanently injured (I checked, you said you got some marks on your finger, which will serve as a reminder, hopefully), and I know it hurt, so I hope you feel better. I just had to say thanks for the giggles and humor, warped as it might be... Be careful, sir, and Merry Christmas! 😂🤣🎄💃

    • @HollisDoesStuff
      @HollisDoesStuff  21 день тому

      @@Looneyintheboonies haha thanks for the comment! There was no point being upset about it, no permanent damage lol. Merry Christmas to you too!

  • @barney1941
    @barney1941 Місяць тому

    if you want to decrease amps and keep power (the same) the voltage must increase as amps increase voltage decreases assuming power (watts is same) the main formula is P=I x E or PIE P/I=E I= P/E power(watts)/volts=amps watts=volts x amps watts/amps=volts thats why 14 volts will draw less amps than 12 volts assuming watts remains constant (same) great vidja mr.

  • @unijabnx2000
    @unijabnx2000 Місяць тому +1

    Just saw someone that was checking out a small diesel heater that was for a water loop. With something like that you could run it outside and just bring the heated water into a radiator to heat a small bldg. When he measured its output it was close to 3kw than it was to the 5kw it was "rated" for.

    • @HollisDoesStuff
      @HollisDoesStuff  Місяць тому +2

      Yeah, mine is "5 to 8kw", I really have no idea. I saw DeBoss garage compare a 5kw to an 8kw, there was literally no physical difference. I feel like the output has more to do with the fuel pump and controller than anything.

  • @unijabnx2000
    @unijabnx2000 Місяць тому

    I bet if you wanted to use the cig outlet.. you could use a small 12v (like a small 6ah one for a UPS) sealed battery in line with the cig outlet... so if it wanted more than 120w the outlet is rated for.. it could pull the rest from the small battery.

    • @HollisDoesStuff
      @HollisDoesStuff  Місяць тому +1

      I considered that option, using a cig outlet plus "jumping" it with a jump box to get it going. One the glow plug shuts off they only take 20 or 30 watts.

  • @barney1941
    @barney1941 Місяць тому

    would an old school jumper pack be a good choice? 550 CCA the 25-30 lb ones

  • @barney1941
    @barney1941 Місяць тому

    was there a capacitor with some juice stored up?

    • @HollisDoesStuff
      @HollisDoesStuff  Місяць тому

      Yes, capacitor left 2 marks on my finger when I grabbed the circuit board lol

  • @barney1941
    @barney1941 Місяць тому

    if P = 250 watts max current is 20.8 amps. you cant drive all circuits at max amps. it must be circuit A or B not both.

    • @HollisDoesStuff
      @HollisDoesStuff  Місяць тому

      I'm testing a new power supply from another PC, it has 3 "rails", one 18 amps, another 18 and the third 15. Where it's DC, I should, in theory, be able to wire those together, no?

  • @barney1941
    @barney1941 Місяць тому

    P=I x E and I= P/E or I= 20.8 amp if 250 watts if that helps anyone P/E=I p = power in watts or jouls E = volts I = amps