Integral of tan^5(x)

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  • Опубліковано 1 січ 2025

КОМЕНТАРІ • 21

  • @adamhilmi761
    @adamhilmi761 3 роки тому +7

    Thank you so much. This was incredibly helpful. Peace be upon you.

  • @Zer0rouboros
    @Zer0rouboros 5 років тому +5

    Interestingly, this is the answer I kept receiving, yet the solutions manual shows:
    1/4[(tan)^4 x] - [(tan)^2 x] + ln |(sec)^2 x|
    Did they misprint the solution? Where did the 1/2 before the second term disappear to?

    • @creeper4134
      @creeper4134 5 років тому

      It's a indefinite intigration. There can be different solution or you can solve more

  • @R.d.onlysportid
    @R.d.onlysportid 4 роки тому +1

    Extremely good

  • @jacksonmadison9994
    @jacksonmadison9994 Рік тому

    trig reduction formulas make this one easier
    1/(n-1) tan^(n-1)(x) - integral of (tan^(n-2)(x)dx)

  • @amansinghmarkam1686
    @amansinghmarkam1686 3 роки тому

    It was very helpful for me and hope for other's

  • @noshinsharmilytithi6621
    @noshinsharmilytithi6621 Рік тому

    Thany u so much sir..🎉

  • @kaank4295
    @kaank4295 Рік тому +2

    4:03 i did secx=t, secx.tanx.dx=dt instead of yours and i found "sec^4(x)/4 - sec^2(x) - ln(cosx) + c" so am i missing something or both of this are true?
    edit: i searched a bit and yes both of this are true

  • @rotchildteramene2880
    @rotchildteramene2880 2 роки тому

    Thank you sir,

  • @lwazimulela1213
    @lwazimulela1213 9 місяців тому

    I thank God of u sir,l wish to see you physically one day.

  • @markkeep2030
    @markkeep2030 2 роки тому

    Amazing

  • @ebhojayejuliet9728
    @ebhojayejuliet9728 Рік тому

    There's still tan3x why isn't tan2x substituted for it

  • @georgebrighton4299
    @georgebrighton4299 4 роки тому

    Calculus 2,o salute.so difficult

  • @vacancy3885
    @vacancy3885 6 років тому +1

    Mst

  • @ajaymeena1141
    @ajaymeena1141 6 років тому

    A video on underroot tanx plz

  • @maalikserebryakov
    @maalikserebryakov Рік тому

    lemme guess reduction formula

  • @mslk99
    @mslk99 5 років тому +3

    there is an easier way :1- Separate tan^5x to tan^4(tanx)
    2-and then use the identity :sec^2x-1=tanx
    3-let secx=u ...