another alternative form is sec²(x)/2 + ln |cos(x)| + C, which is equal but moved by a factor of 1/2 in the y direction, with u = cos x, and converting tan³(x) to sin³(x)/cos³(x)
Nice presentation again! Thank you very much! Interesting you call yourself The Organic Chemistry Tutor but you have so much Math and Physics in here. And what about Physical and Inorganic Chemistry? hahaha Maybe you started with Organic Chemistry and then expanded to the other fields? You are helping a lot of people that way. Great!
@@HaMza-sh1hl both are right. if you change the secx^2 term to 1+tanx^2 then distribute 1/2 to each one of them the result is 0.5+0.5tanx^2+lnIcosxI+C1. Now combine 0.5 and C1 to make a new C2. Then the result is the same as the video. Both are valid methods. But in the interest of time, substituting secx to u might be slightly faster.
You are a blessing upon this world. I pray that the gods take notice upon your good deeds and protect you against any and all harm. Good day
another alternative form is sec²(x)/2 + ln |cos(x)| + C, which is equal but moved by a factor of 1/2 in the y direction, with u = cos x, and converting tan³(x) to sin³(x)/cos³(x)
Nice presentation again! Thank you very much!
Interesting you call yourself The Organic Chemistry Tutor but you have so much Math and Physics in here. And what about Physical and Inorganic Chemistry? hahaha
Maybe you started with Organic Chemistry and then expanded to the other fields? You are helping a lot of people that way. Great!
sec^2x/2 - log(sec x) + c
is it correct?
yess absolutely
Put the limit in the above solved query 0 to π/2 Nd then find value ...?
Thank you very much 🥰🥰 ❤️ ❤️
Thanks a lot for this video
do the integral of: tan^1/4 ( x ) dx
You are wrong it is sec x^2 / 2 not tan x^2 / 2
No he is right...I dont know how I am getting 2 different result?
@@HaMza-sh1hl both are right. if you change the secx^2 term to 1+tanx^2 then distribute 1/2 to each one of them the result is 0.5+0.5tanx^2+lnIcosxI+C1. Now combine 0.5 and C1 to make a new C2. Then the result is the same as the video. Both are valid methods.
But in the interest of time, substituting secx to u might be slightly faster.
@@doctor12sonic28 thanks a lotttttt!!
Yeahi i did it totally wroong and i though i was right😂😢