I got a clear conceptual framework from this discussion regarding solving ABSOLUTE VALUE problem, thank you so much for such an outstanding discussion.
I am watching this 7 years later and it is fun to watch :D I hope people who participated in this webinar 7 years ago got into their dream business schools and I hope the ones who follow will do too. Thank you for this fun, insightful session :)
Explained very well! Except watching it as a recording makes it very long. Relevant Content is 20 minutes, but class interaction is very distracting/ interruptive. I learned the concept well. Thanks!
In the last question , we know that x^2 > y^2 , so they have defined places on the number line , so that means if y is negetive it will always mean that it is larger than x always , making the answer D perhaps ???
In the last question (Q. 5), what would be the answer if x= -(1/2) and y= -(1/3)? It agrees with the given constraint that x^2 > y^2. The question stem does not tell about the properties of x and y i.e., whether it is integer or fraction. So if we consider statement 2 only or combine both statements, we dont have any definite answer to the question. X could be greater or less than y. Would not the answer be E? Please clarify.
LAST Q - ans given by teacher is wrong - in option 2 - given x is neg (suppose -ve 3) and since y is not given, so y could be positive 2 for example (-3> 2 is not possible even though 9 > 4 ) so x cannot be greater than y , also if y is -ve then x will be leSS than y (-3
I got a clear conceptual framework from this discussion regarding solving ABSOLUTE VALUE problem, thank you so much for such an outstanding discussion.
I am watching this 7 years later and it is fun to watch :D I hope people who participated in this webinar 7 years ago got into their dream business schools and I hope the ones who follow will do too. Thank you for this fun, insightful session :)
Thank you very much for the wonderful video. The way you explained the concept is awesome. Appreciate that!
Thoroughly grateful for this wonderful lecture
Quick Q, in 2nd last Q , it is given X < Y, so can't we ignore the reflection of Y as X will always be left to Y . Hence, shouldn't the ans be D?
Explained very well! Except watching it as a recording makes it very long. Relevant Content is 20 minutes, but class interaction is very distracting/ interruptive. I learned the concept well. Thanks!
Glad it was helpful!
In the last question , we know that x^2 > y^2 , so they have defined places on the number line , so that means if y is negetive it will always mean that it is larger than x always , making the answer D perhaps ???
Where can I find the other videos from this 740+ webinar series?
In the last question (Q. 5), what would be the answer if x= -(1/2) and y= -(1/3)? It agrees with the given constraint that x^2 > y^2. The question stem does not tell about the properties of x and y i.e., whether it is integer or fraction. So if we consider statement 2 only or combine both statements, we dont have any definite answer to the question. X could be greater or less than y. Would not the answer be E? Please clarify.
Does it belong to gtb nagar
Very nice explanation.
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Please upload more such videos. Or could you please tell me where can I get access to more such webinars?
Hello Sunayana, we conduct such webinars weekly. Register at: www.jamboreeindia.com/Events
Questions and explanation atarte at 10:14
great work
Glad you liked it.
Cant thank you enough for this! :)
Um...could you please edit the webinar videos to cut out the breaks and small talk? Learnt a lot today :) ty for this video :))
Thanks Amrita
LAST Q - ans given by teacher is wrong - in option 2 - given x is neg (suppose -ve 3) and since y is not given, so y could be positive 2 for example (-3> 2 is not possible even though 9 > 4 ) so x cannot be greater than y , also if y is -ve then x will be leSS than y (-3
Good :)
" looking forward for " ?? its "looking for" or "looking forward to" ...... but that aside, nice video!!
Glad you liked this.